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Add test showing bug in mempool packages
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@ -15,22 +15,24 @@ class MempoolPackagesTest(BitcoinTestFramework):
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def setup_network(self):
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self.nodes = []
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self.nodes.append(start_node(0, self.options.tmpdir, ["-maxorphantx=1000", "-relaypriority=0"]))
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self.nodes.append(start_node(0, self.options.tmpdir, ["-maxorphantx=1000", "-relaypriority=0", "-debug"]))
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self.nodes.append(start_node(1, self.options.tmpdir, ["-maxorphantx=1000", "-relaypriority=0", "-limitancestorcount=5", "-debug"]))
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connect_nodes(self.nodes[0], 1)
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self.is_network_split = False
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self.sync_all()
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# Build a transaction that spends parent_txid:vout
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# Return amount sent
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def chain_transaction(self, parent_txid, vout, value, fee, num_outputs):
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def chain_transaction(self, node, parent_txid, vout, value, fee, num_outputs):
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send_value = satoshi_round((value - fee)/num_outputs)
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inputs = [ {'txid' : parent_txid, 'vout' : vout} ]
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outputs = {}
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for i in xrange(num_outputs):
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outputs[self.nodes[0].getnewaddress()] = send_value
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rawtx = self.nodes[0].createrawtransaction(inputs, outputs)
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signedtx = self.nodes[0].signrawtransaction(rawtx)
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txid = self.nodes[0].sendrawtransaction(signedtx['hex'])
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fulltx = self.nodes[0].getrawtransaction(txid, 1)
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outputs[node.getnewaddress()] = send_value
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rawtx = node.createrawtransaction(inputs, outputs)
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signedtx = node.signrawtransaction(rawtx)
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txid = node.sendrawtransaction(signedtx['hex'])
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fulltx = node.getrawtransaction(txid, 1)
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assert(len(fulltx['vout']) == num_outputs) # make sure we didn't generate a change output
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return (txid, send_value)
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@ -46,7 +48,7 @@ class MempoolPackagesTest(BitcoinTestFramework):
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# 100 transactions off a confirmed tx should be fine
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chain = []
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for i in xrange(100):
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(txid, sent_value) = self.chain_transaction(txid, 0, value, fee, 1)
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(txid, sent_value) = self.chain_transaction(self.nodes[0], txid, 0, value, fee, 1)
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value = sent_value
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chain.append(txid)
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@ -69,10 +71,12 @@ class MempoolPackagesTest(BitcoinTestFramework):
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# Adding one more transaction on to the chain should fail.
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try:
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self.chain_transaction(txid, vout, value, fee, 1)
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self.chain_transaction(self.nodes[0], txid, vout, value, fee, 1)
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except JSONRPCException as e:
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print "too-long-ancestor-chain successfully rejected"
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# TODO: check that node1's mempool is as expected
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# TODO: test ancestor size limits
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# Now test descendant chain limits
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@ -82,7 +86,7 @@ class MempoolPackagesTest(BitcoinTestFramework):
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transaction_package = []
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# First create one parent tx with 10 children
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(txid, sent_value) = self.chain_transaction(txid, vout, value, fee, 10)
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(txid, sent_value) = self.chain_transaction(self.nodes[0], txid, vout, value, fee, 10)
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parent_transaction = txid
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for i in xrange(10):
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transaction_package.append({'txid': txid, 'vout': i, 'amount': sent_value})
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@ -90,7 +94,7 @@ class MempoolPackagesTest(BitcoinTestFramework):
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for i in xrange(1000):
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utxo = transaction_package.pop(0)
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try:
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(txid, sent_value) = self.chain_transaction(utxo['txid'], utxo['vout'], utxo['amount'], fee, 10)
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(txid, sent_value) = self.chain_transaction(self.nodes[0], utxo['txid'], utxo['vout'], utxo['amount'], fee, 10)
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for j in xrange(10):
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transaction_package.append({'txid': txid, 'vout': j, 'amount': sent_value})
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if i == 998:
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@ -101,7 +105,74 @@ class MempoolPackagesTest(BitcoinTestFramework):
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assert_equal(i, 999)
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print "tx that would create too large descendant package successfully rejected"
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# TODO: check that node1's mempool is as expected
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# TODO: test descendant size limits
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# Test reorg handling
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# First, the basics:
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self.nodes[0].generate(1)
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sync_blocks(self.nodes)
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self.nodes[1].invalidateblock(self.nodes[0].getbestblockhash())
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self.nodes[1].reconsiderblock(self.nodes[0].getbestblockhash())
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# Now test the case where node1 has a transaction T in its mempool that
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# depends on transactions A and B which are in a mined block, and the
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# block containing A and B is disconnected, AND B is not accepted back
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# into node1's mempool because its ancestor count is too high.
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# Create 8 transactions, like so:
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# Tx0 -> Tx1 (vout0)
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# \--> Tx2 (vout1) -> Tx3 -> Tx4 -> Tx5 -> Tx6 -> Tx7
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#
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# Mine them in the next block, then generate a new tx8 that spends
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# Tx1 and Tx7, and add to node1's mempool, then disconnect the
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# last block.
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# Create tx0 with 2 outputs
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utxo = self.nodes[0].listunspent()
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txid = utxo[0]['txid']
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value = utxo[0]['amount']
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vout = utxo[0]['vout']
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send_value = satoshi_round((value - fee)/2)
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inputs = [ {'txid' : txid, 'vout' : vout} ]
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outputs = {}
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for i in xrange(2):
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outputs[self.nodes[0].getnewaddress()] = send_value
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rawtx = self.nodes[0].createrawtransaction(inputs, outputs)
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signedtx = self.nodes[0].signrawtransaction(rawtx)
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txid = self.nodes[0].sendrawtransaction(signedtx['hex'])
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tx0_id = txid
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value = send_value
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# Create tx1
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(tx1_id, tx1_value) = self.chain_transaction(self.nodes[0], tx0_id, 0, value, fee, 1)
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# Create tx2-7
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vout = 1
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txid = tx0_id
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for i in xrange(6):
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(txid, sent_value) = self.chain_transaction(self.nodes[0], txid, vout, value, fee, 1)
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vout = 0
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value = sent_value
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# Mine these in a block
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self.nodes[0].generate(1)
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self.sync_all()
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# Now generate tx8, with a big fee
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inputs = [ {'txid' : tx1_id, 'vout': 0}, {'txid' : txid, 'vout': 0} ]
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outputs = { self.nodes[0].getnewaddress() : send_value + value - 4*fee }
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rawtx = self.nodes[0].createrawtransaction(inputs, outputs)
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signedtx = self.nodes[0].signrawtransaction(rawtx)
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txid = self.nodes[0].sendrawtransaction(signedtx['hex'])
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sync_mempools(self.nodes)
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# Now try to disconnect the tip on each node...
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self.nodes[1].invalidateblock(self.nodes[1].getbestblockhash())
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self.nodes[0].invalidateblock(self.nodes[0].getbestblockhash())
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sync_blocks(self.nodes)
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if __name__ == '__main__':
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MempoolPackagesTest().main()
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