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[test] make tx6 child of tx5, not tx3, in rbf_tests

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There is no effect on the test results because tx3 and tx5 pay the say
fee, but this was the intended configuration, as the comment suggests.
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glozow 2022-08-11 12:48:04 +01:00
parent 0094ff3947
commit 49db42cdf5
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src/test/rbf_tests.cpp
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@ -76,7 +76,7 @@ BOOST_FIXTURE_TEST_CASE(rbf_helper_functions, TestChain100Setup)
// Create a parent tx5 and child tx6 where both have very low fees
const auto tx5 = make_tx(/*inputs=*/ {m_coinbase_txns[2]}, /*output_values=*/ {1099 * CENT});
pool.addUnchecked(entry.Fee(low_fee).FromTx(tx5));
const auto tx6 = make_tx(/*inputs=*/ {tx3}, /*output_values=*/ {1098 * CENT});
const auto tx6 = make_tx(/*inputs=*/ {tx5}, /*output_values=*/ {1098 * CENT});
pool.addUnchecked(entry.Fee(low_fee).FromTx(tx6));
// Make tx6's modified fee much higher than its base fee. This should cause it to pass
// the fee-related checks despite being low-feerate.