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contrib: refactor: simplify block header string routine in linearize-data.py

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The string representation of a block header hash is simply the
hexlified byte-reversed double SHA256 hash of its serialization.
This commit is contained in:
Sebastian Falbesoner 2022-02-17 22:15:40 +01:00
parent 922c49a138
commit 3f863cfff1
1 changed files with 2 additions and 37 deletions
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39
contrib/linearize/linearize-data.py
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@ -25,44 +25,9 @@ def hex_switchEndian(s):
pairList = [s[i:i+2].encode() for i in range(0, len(s), 2)] pairList = [s[i:i+2].encode() for i in range(0, len(s), 2)]
return b''.join(pairList[::-1]).decode() return b''.join(pairList[::-1]).decode()
def uint32(x):
return x & 0xffffffff
def bytereverse(x):
return uint32(( ((x) << 24) | (((x) << 8) & 0x00ff0000) |
(((x) >> 8) & 0x0000ff00) | ((x) >> 24) ))
def bufreverse(in_buf):
out_words = []
for i in range(0, len(in_buf), 4):
word = struct.unpack('@I', in_buf[i:i+4])[0]
out_words.append(struct.pack('@I', bytereverse(word)))
return b''.join(out_words)
def wordreverse(in_buf):
out_words = []
for i in range(0, len(in_buf), 4):
out_words.append(in_buf[i:i+4])
out_words.reverse()
return b''.join(out_words)
def calc_hdr_hash(blk_hdr):
hash1 = hashlib.sha256()
hash1.update(blk_hdr)
hash1_o = hash1.digest()
hash2 = hashlib.sha256()
hash2.update(hash1_o)
hash2_o = hash2.digest()
return hash2_o
def calc_hash_str(blk_hdr): def calc_hash_str(blk_hdr):
hash = calc_hdr_hash(blk_hdr) blk_hdr_hash = hashlib.sha256(hashlib.sha256(blk_hdr).digest()).digest()
hash = bufreverse(hash) return blk_hdr_hash[::-1].hex()
hash = wordreverse(hash)
hash_str = hash.hex()
return hash_str
def get_blk_dt(blk_hdr): def get_blk_dt(blk_hdr):
members = struct.unpack("<I", blk_hdr[68:68+4]) members = struct.unpack("<I", blk_hdr[68:68+4])