mirror of
https://github.com/bitcoin/bitcoin.git
synced 2024-11-20 10:38:42 +01:00
Add tests for transaction replacement
This commit is contained in:
parent
5891f870d6
commit
0137e6fafd
1
qa/replace-by-fee/.gitignore
vendored
Normal file
1
qa/replace-by-fee/.gitignore
vendored
Normal file
@ -0,0 +1 @@
|
||||
python-bitcoinlib
|
13
qa/replace-by-fee/README.md
Normal file
13
qa/replace-by-fee/README.md
Normal file
@ -0,0 +1,13 @@
|
||||
Replace-by-fee regression tests
|
||||
===============================
|
||||
|
||||
First get version v0.5.0 of the python-bitcoinlib library. In this directory
|
||||
run:
|
||||
|
||||
git clone -n https://github.com/petertodd/python-bitcoinlib
|
||||
(cd python-bitcoinlib && git checkout 8270bfd9c6ac37907d75db3d8b9152d61c7255cd)
|
||||
|
||||
Then run the tests themselves with a bitcoind available running in regtest
|
||||
mode:
|
||||
|
||||
./rbf-tests.py
|
280
qa/replace-by-fee/rbf-tests.py
Executable file
280
qa/replace-by-fee/rbf-tests.py
Executable file
@ -0,0 +1,280 @@
|
||||
#!/usr/bin/env python3
|
||||
# Copyright (c) 2015 The Bitcoin Core developers
|
||||
# Distributed under the MIT software license, see the accompanying
|
||||
# file COPYING or http://www.opensource.org/licenses/mit-license.php.
|
||||
|
||||
#
|
||||
# Test replace-by-fee
|
||||
#
|
||||
|
||||
import os
|
||||
import sys
|
||||
|
||||
# Add python-bitcoinlib to module search path:
|
||||
sys.path.append(os.path.join(os.path.dirname(os.path.abspath(__file__)), "python-bitcoinlib"))
|
||||
|
||||
import unittest
|
||||
|
||||
import bitcoin
|
||||
bitcoin.SelectParams('regtest')
|
||||
|
||||
import bitcoin.rpc
|
||||
|
||||
from bitcoin.core import *
|
||||
from bitcoin.core.script import *
|
||||
from bitcoin.wallet import *
|
||||
|
||||
MAX_REPLACEMENT_LIMIT = 100
|
||||
|
||||
class Test_ReplaceByFee(unittest.TestCase):
|
||||
proxy = None
|
||||
|
||||
@classmethod
|
||||
def setUpClass(cls):
|
||||
if cls.proxy is None:
|
||||
cls.proxy = bitcoin.rpc.Proxy()
|
||||
|
||||
@classmethod
|
||||
def tearDownClass(cls):
|
||||
# Make sure mining works
|
||||
mempool_size = 1
|
||||
while mempool_size:
|
||||
cls.proxy.call('generate',1)
|
||||
new_mempool_size = len(cls.proxy.getrawmempool())
|
||||
|
||||
# It's possible to get stuck in a loop here if the mempool has
|
||||
# transactions that can't be mined.
|
||||
assert(new_mempool_size != mempool_size)
|
||||
mempool_size = new_mempool_size
|
||||
|
||||
def make_txout(self, amount, scriptPubKey=CScript([1])):
|
||||
"""Create a txout with a given amount and scriptPubKey
|
||||
|
||||
Mines coins as needed.
|
||||
"""
|
||||
fee = 1*COIN
|
||||
while self.proxy.getbalance() < amount + fee:
|
||||
self.proxy.call('generate', 100)
|
||||
|
||||
addr = P2SHBitcoinAddress.from_redeemScript(CScript([]))
|
||||
txid = self.proxy.sendtoaddress(addr, amount + fee)
|
||||
|
||||
tx1 = self.proxy.getrawtransaction(txid)
|
||||
|
||||
i = None
|
||||
for i, txout in enumerate(tx1.vout):
|
||||
if txout.scriptPubKey == addr.to_scriptPubKey():
|
||||
break
|
||||
assert i is not None
|
||||
|
||||
tx2 = CTransaction([CTxIn(COutPoint(txid, i), CScript([1, CScript([])]), nSequence=0)],
|
||||
[CTxOut(amount, scriptPubKey)])
|
||||
|
||||
tx2_txid = self.proxy.sendrawtransaction(tx2, True)
|
||||
|
||||
return COutPoint(tx2_txid, 0)
|
||||
|
||||
def test_simple_doublespend(self):
|
||||
"""Simple doublespend"""
|
||||
tx0_outpoint = self.make_txout(1.1*COIN)
|
||||
|
||||
tx1a = CTransaction([CTxIn(tx0_outpoint, nSequence=0)],
|
||||
[CTxOut(1*COIN, CScript([b'a']))])
|
||||
tx1a_txid = self.proxy.sendrawtransaction(tx1a, True)
|
||||
|
||||
# Should fail because we haven't changed the fee
|
||||
tx1b = CTransaction([CTxIn(tx0_outpoint, nSequence=0)],
|
||||
[CTxOut(1*COIN, CScript([b'b']))])
|
||||
|
||||
try:
|
||||
tx1b_txid = self.proxy.sendrawtransaction(tx1b, True)
|
||||
except bitcoin.rpc.JSONRPCException as exp:
|
||||
self.assertEqual(exp.error['code'], -26) # insufficient fee
|
||||
else:
|
||||
self.fail()
|
||||
|
||||
# Extra 0.1 BTC fee
|
||||
tx1b = CTransaction([CTxIn(tx0_outpoint, nSequence=0)],
|
||||
[CTxOut(0.9*COIN, CScript([b'b']))])
|
||||
tx1b_txid = self.proxy.sendrawtransaction(tx1b, True)
|
||||
|
||||
# tx1a is in fact replaced
|
||||
with self.assertRaises(IndexError):
|
||||
self.proxy.getrawtransaction(tx1a_txid)
|
||||
|
||||
self.assertEqual(tx1b, self.proxy.getrawtransaction(tx1b_txid))
|
||||
|
||||
def test_doublespend_chain(self):
|
||||
"""Doublespend of a long chain"""
|
||||
|
||||
initial_nValue = 50*COIN
|
||||
tx0_outpoint = self.make_txout(initial_nValue)
|
||||
|
||||
prevout = tx0_outpoint
|
||||
remaining_value = initial_nValue
|
||||
chain_txids = []
|
||||
while remaining_value > 10*COIN:
|
||||
remaining_value -= 1*COIN
|
||||
tx = CTransaction([CTxIn(prevout, nSequence=0)],
|
||||
[CTxOut(remaining_value, CScript([1]))])
|
||||
txid = self.proxy.sendrawtransaction(tx, True)
|
||||
chain_txids.append(txid)
|
||||
prevout = COutPoint(txid, 0)
|
||||
|
||||
# Whether the double-spend is allowed is evaluated by including all
|
||||
# child fees - 40 BTC - so this attempt is rejected.
|
||||
dbl_tx = CTransaction([CTxIn(tx0_outpoint, nSequence=0)],
|
||||
[CTxOut(initial_nValue - 30*COIN, CScript([1]))])
|
||||
|
||||
try:
|
||||
self.proxy.sendrawtransaction(dbl_tx, True)
|
||||
except bitcoin.rpc.JSONRPCException as exp:
|
||||
self.assertEqual(exp.error['code'], -26) # insufficient fee
|
||||
else:
|
||||
self.fail()
|
||||
|
||||
# Accepted with sufficient fee
|
||||
dbl_tx = CTransaction([CTxIn(tx0_outpoint, nSequence=0)],
|
||||
[CTxOut(1*COIN, CScript([1]))])
|
||||
self.proxy.sendrawtransaction(dbl_tx, True)
|
||||
|
||||
for doublespent_txid in chain_txids:
|
||||
with self.assertRaises(IndexError):
|
||||
self.proxy.getrawtransaction(doublespent_txid)
|
||||
|
||||
def test_doublespend_tree(self):
|
||||
"""Doublespend of a big tree of transactions"""
|
||||
|
||||
initial_nValue = 50*COIN
|
||||
tx0_outpoint = self.make_txout(initial_nValue)
|
||||
|
||||
def branch(prevout, initial_value, max_txs, *, tree_width=5, fee=0.0001*COIN, _total_txs=None):
|
||||
if _total_txs is None:
|
||||
_total_txs = [0]
|
||||
if _total_txs[0] >= max_txs:
|
||||
return
|
||||
|
||||
txout_value = (initial_value - fee) // tree_width
|
||||
if txout_value < fee:
|
||||
return
|
||||
|
||||
vout = [CTxOut(txout_value, CScript([i+1]))
|
||||
for i in range(tree_width)]
|
||||
tx = CTransaction([CTxIn(prevout, nSequence=0)],
|
||||
vout)
|
||||
|
||||
self.assertTrue(len(tx.serialize()) < 100000)
|
||||
txid = self.proxy.sendrawtransaction(tx, True)
|
||||
yield tx
|
||||
_total_txs[0] += 1
|
||||
|
||||
for i, txout in enumerate(tx.vout):
|
||||
yield from branch(COutPoint(txid, i), txout_value,
|
||||
max_txs,
|
||||
tree_width=tree_width, fee=fee,
|
||||
_total_txs=_total_txs)
|
||||
|
||||
fee = 0.0001*COIN
|
||||
n = MAX_REPLACEMENT_LIMIT
|
||||
tree_txs = list(branch(tx0_outpoint, initial_nValue, n, fee=fee))
|
||||
self.assertEqual(len(tree_txs), n)
|
||||
|
||||
# Attempt double-spend, will fail because too little fee paid
|
||||
dbl_tx = CTransaction([CTxIn(tx0_outpoint, nSequence=0)],
|
||||
[CTxOut(initial_nValue - fee*n, CScript([1]))])
|
||||
try:
|
||||
self.proxy.sendrawtransaction(dbl_tx, True)
|
||||
except bitcoin.rpc.JSONRPCException as exp:
|
||||
self.assertEqual(exp.error['code'], -26) # insufficient fee
|
||||
else:
|
||||
self.fail()
|
||||
|
||||
# 1 BTC fee is enough
|
||||
dbl_tx = CTransaction([CTxIn(tx0_outpoint, nSequence=0)],
|
||||
[CTxOut(initial_nValue - fee*n - 1*COIN, CScript([1]))])
|
||||
self.proxy.sendrawtransaction(dbl_tx, True)
|
||||
|
||||
for tx in tree_txs:
|
||||
with self.assertRaises(IndexError):
|
||||
self.proxy.getrawtransaction(tx.GetHash())
|
||||
|
||||
# Try again, but with more total transactions than the "max txs
|
||||
# double-spent at once" anti-DoS limit.
|
||||
for n in (MAX_REPLACEMENT_LIMIT, MAX_REPLACEMENT_LIMIT*2):
|
||||
fee = 0.0001*COIN
|
||||
tx0_outpoint = self.make_txout(initial_nValue)
|
||||
tree_txs = list(branch(tx0_outpoint, initial_nValue, n, fee=fee))
|
||||
self.assertEqual(len(tree_txs), n)
|
||||
|
||||
dbl_tx = CTransaction([CTxIn(tx0_outpoint, nSequence=0)],
|
||||
[CTxOut(initial_nValue - fee*n, CScript([1]))])
|
||||
try:
|
||||
self.proxy.sendrawtransaction(dbl_tx, True)
|
||||
except bitcoin.rpc.JSONRPCException as exp:
|
||||
self.assertEqual(exp.error['code'], -26)
|
||||
else:
|
||||
self.fail()
|
||||
|
||||
for tx in tree_txs:
|
||||
self.proxy.getrawtransaction(tx.GetHash())
|
||||
|
||||
def test_replacement_feeperkb(self):
|
||||
"""Replacement requires overall fee-per-KB to be higher"""
|
||||
tx0_outpoint = self.make_txout(1.1*COIN)
|
||||
|
||||
tx1a = CTransaction([CTxIn(tx0_outpoint, nSequence=0)],
|
||||
[CTxOut(1*COIN, CScript([b'a']))])
|
||||
tx1a_txid = self.proxy.sendrawtransaction(tx1a, True)
|
||||
|
||||
# Higher fee, but the fee per KB is much lower, so the replacement is
|
||||
# rejected.
|
||||
tx1b = CTransaction([CTxIn(tx0_outpoint, nSequence=0)],
|
||||
[CTxOut(0.001*COIN,
|
||||
CScript([b'a'*999000]))])
|
||||
|
||||
try:
|
||||
tx1b_txid = self.proxy.sendrawtransaction(tx1b, True)
|
||||
except bitcoin.rpc.JSONRPCException as exp:
|
||||
self.assertEqual(exp.error['code'], -26) # insufficient fee
|
||||
else:
|
||||
self.fail()
|
||||
|
||||
def test_spends_of_conflicting_outputs(self):
|
||||
"""Replacements that spend conflicting tx outputs are rejected"""
|
||||
utxo1 = self.make_txout(1.2*COIN)
|
||||
utxo2 = self.make_txout(3.0*COIN)
|
||||
|
||||
tx1a = CTransaction([CTxIn(utxo1, nSequence=0)],
|
||||
[CTxOut(1.1*COIN, CScript([b'a']))])
|
||||
tx1a_txid = self.proxy.sendrawtransaction(tx1a, True)
|
||||
|
||||
# Direct spend an output of the transaction we're replacing.
|
||||
tx2 = CTransaction([CTxIn(utxo1, nSequence=0), CTxIn(utxo2, nSequence=0),
|
||||
CTxIn(COutPoint(tx1a_txid, 0), nSequence=0)],
|
||||
tx1a.vout)
|
||||
|
||||
try:
|
||||
tx2_txid = self.proxy.sendrawtransaction(tx2, True)
|
||||
except bitcoin.rpc.JSONRPCException as exp:
|
||||
self.assertEqual(exp.error['code'], -26)
|
||||
else:
|
||||
self.fail()
|
||||
|
||||
# Spend tx1a's output to test the indirect case.
|
||||
tx1b = CTransaction([CTxIn(COutPoint(tx1a_txid, 0), nSequence=0)],
|
||||
[CTxOut(1.0*COIN, CScript([b'a']))])
|
||||
tx1b_txid = self.proxy.sendrawtransaction(tx1b, True)
|
||||
|
||||
tx2 = CTransaction([CTxIn(utxo1, nSequence=0), CTxIn(utxo2, nSequence=0),
|
||||
CTxIn(COutPoint(tx1b_txid, 0))],
|
||||
tx1a.vout)
|
||||
|
||||
try:
|
||||
tx2_txid = self.proxy.sendrawtransaction(tx2, True)
|
||||
except bitcoin.rpc.JSONRPCException as exp:
|
||||
self.assertEqual(exp.error['code'], -26)
|
||||
else:
|
||||
self.fail()
|
||||
|
||||
if __name__ == '__main__':
|
||||
unittest.main()
|
Loading…
Reference in New Issue
Block a user