remove debug output

This commit is contained in:
rootzoll 2021-10-02 01:48:13 +02:00
parent 7d23d2e293
commit 5632ff668f

View file

@ -104,17 +104,16 @@ do
#echo "# blitz.statusscan.sh"
firstStatusScanExists=$(ls /var/cache/raspiblitz/raspiblitz.status | grep -c "raspiblitz.status")
echo "firstStatusScanExists(${firstStatusScanExists})"
#echo "firstStatusScanExists(${firstStatusScanExists})"
if [ ${firstStatusScanExists} -eq 1 ]; then
# run statusscan with timeout - if status scan was not killed it will copy over the
timeout 15 /home/admin/config.scripts/blitz.statusscan.sh ${lightning} > /var/cache/raspiblitz/raspiblitz.status.tmp
result=$?
echo "result(${result})"
#echo "result(${result})"
if [ "${result}" == "0" ]; then
# statusscan finished in under 10 seconds - use results
cp /var/cache/raspiblitz/raspiblitz.status.tmp /var/cache/raspiblitz/raspiblitz.status
echo "cp"
else
# statusscan blocked and was killed - fallback to old results
echo "statusscan blocked (${result}) - fallback to old results"