mirror of
https://github.com/ElementsProject/lightning.git
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12fbb23322
We actually were waiting for l3 to disconnect, not l2.
But in general we should be looking for status rather than grovelling
in the logs where possible, so I changed all those.
```
2021-08-17T04:40:34.9015538Z # l2 leases a channel from l3
2021-08-17T04:40:34.9016520Z l2.rpc.connect(l3.info['id'], 'localhost', l3.port)
2021-08-17T04:40:34.9017570Z rates = l2.rpc.dev_queryrates(l3.info['id'], amount, amount)
2021-08-17T04:40:34.9018724Z l3.daemon.wait_for_log('disconnect')
2021-08-17T04:40:34.9019851Z l2.rpc.connect(l3.info['id'], 'localhost', l3.port)
2021-08-17T04:40:34.9021467Z l2.rpc.fundchannel(l3.info['id'], amount, request_amt=amount,
2021-08-17T04:40:34.9022865Z feerate='{}perkw'.format(feerate), minconf=0,
2021-08-17T04:40:34.9024000Z > compact_lease=rates['compact_lease'])
...
2021-08-17T04:40:34.9103422Z > raise RpcError(method, payload, resp['error'])
2021-08-17T04:40:34.9106829Z E pyln.client.lightning.RpcError: RPC call failed: method: fundchannel, payload: {'id': '035d2b1192dfba134e10e540875d366ebc8bc353d5aa766b80c090b39c3a5d885d', 'amount': 500000, 'feerate': '2000perkw', 'announce': True, 'minconf': 0, 'request_amt': 500000, 'compact_lease': '029a00640064000000644c4b40'}, error: {'code': 400, 'message': 'Unable to connect, no address known for peer', 'data': {'id': '035d2b1192dfba134e10e540875d366ebc8bc353d5aa766b80c090b39c3a5d885d', 'method': 'connect'}}
```
Signed-off-by: Rusty Russell <rusty@rustcorp.com.au>
3288 lines
136 KiB
Python
3288 lines
136 KiB
Python
from fixtures import * # noqa: F401,F403
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from flaky import flaky
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from pyln.client import RpcError, Millisatoshi
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from shutil import copyfile
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from pyln.testing.utils import SLOW_MACHINE
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from utils import (
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only_one, sync_blockheight, wait_for, TIMEOUT,
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account_balance, first_channel_id, closing_fee, TEST_NETWORK,
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scriptpubkey_addr, calc_lease_fee
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)
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import os
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import queue
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import pytest
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import re
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import subprocess
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import threading
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import unittest
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@pytest.mark.developer("Too slow without --dev-bitcoind-poll")
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def test_closing(node_factory, bitcoind, chainparams):
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l1, l2 = node_factory.line_graph(2)
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chan = l1.get_channel_scid(l2)
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fee = closing_fee(3750, 2) if not chainparams['elements'] else 3603
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l1.pay(l2, 200000000)
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assert bitcoind.rpc.getmempoolinfo()['size'] == 0
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billboard = only_one(l1.rpc.listpeers(l2.info['id'])['peers'][0]['channels'])['status']
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assert billboard == ['CHANNELD_NORMAL:Funding transaction locked.']
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billboard = only_one(l2.rpc.listpeers(l1.info['id'])['peers'][0]['channels'])['status']
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assert billboard == ['CHANNELD_NORMAL:Funding transaction locked.']
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bitcoind.generate_block(5)
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wait_for(lambda: len(l1.getactivechannels()) == 2)
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wait_for(lambda: len(l2.getactivechannels()) == 2)
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billboard = only_one(l1.rpc.listpeers(l2.info['id'])['peers'][0]['channels'])['status']
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# This may either be from a local_update or an announce, so just
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# check for the substring
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assert 'CHANNELD_NORMAL:Funding transaction locked.' in billboard[0]
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l1.rpc.close(chan)
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l1.daemon.wait_for_log(' to CHANNELD_SHUTTING_DOWN')
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l2.daemon.wait_for_log(' to CHANNELD_SHUTTING_DOWN')
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l1.daemon.wait_for_log(' to CLOSINGD_SIGEXCHANGE')
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l2.daemon.wait_for_log(' to CLOSINGD_SIGEXCHANGE')
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# And should put closing into mempool.
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l1.daemon.wait_for_log('sendrawtx exit 0')
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l2.daemon.wait_for_log('sendrawtx exit 0')
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# Both nodes should have disabled the channel in their view
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wait_for(lambda: len(l1.getactivechannels()) == 0)
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wait_for(lambda: len(l2.getactivechannels()) == 0)
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assert bitcoind.rpc.getmempoolinfo()['size'] == 1
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# Now grab the close transaction
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closetxid = only_one(bitcoind.rpc.getrawmempool(False))
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billboard = only_one(l1.rpc.listpeers(l2.info['id'])['peers'][0]['channels'])['status']
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assert billboard == [
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'CLOSINGD_SIGEXCHANGE:We agreed on a closing fee of {} satoshi for tx:{}'.format(fee, closetxid),
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]
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bitcoind.generate_block(1)
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l1.daemon.wait_for_log(r'Owning output.* \(SEGWIT\).* txid %s.* CONFIRMED' % closetxid)
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l2.daemon.wait_for_log(r'Owning output.* \(SEGWIT\).* txid %s.* CONFIRMED' % closetxid)
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# Make sure both nodes have grabbed their close tx funds
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assert closetxid in set([o['txid'] for o in l1.rpc.listfunds()['outputs']])
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assert closetxid in set([o['txid'] for o in l2.rpc.listfunds()['outputs']])
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wait_for(lambda: only_one(l1.rpc.listpeers(l2.info['id'])['peers'][0]['channels'])['status'] == [
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'CLOSINGD_SIGEXCHANGE:We agreed on a closing fee of {} satoshi for tx:{}'.format(fee, closetxid),
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'ONCHAIN:Tracking mutual close transaction',
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'ONCHAIN:All outputs resolved: waiting 99 more blocks before forgetting channel'
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])
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bitcoind.generate_block(9)
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wait_for(lambda: only_one(l1.rpc.listpeers(l2.info['id'])['peers'][0]['channels'])['status'] == [
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'CLOSINGD_SIGEXCHANGE:We agreed on a closing fee of {} satoshi for tx:{}'.format(fee, closetxid),
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'ONCHAIN:Tracking mutual close transaction',
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'ONCHAIN:All outputs resolved: waiting 90 more blocks before forgetting channel'
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])
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# Make sure both have forgotten about it
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bitcoind.generate_block(90)
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wait_for(lambda: len(l1.rpc.listchannels()['channels']) == 0)
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wait_for(lambda: len(l2.rpc.listchannels()['channels']) == 0)
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# The entry in the channels table should still be there
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assert l1.db_query("SELECT count(*) as c FROM channels;")[0]['c'] == 1
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assert l2.db_query("SELECT count(*) as c FROM channels;")[0]['c'] == 1
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def test_closing_while_disconnected(node_factory, bitcoind, executor):
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l1, l2 = node_factory.line_graph(2, opts={'may_reconnect': True})
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chan = l1.get_channel_scid(l2)
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l1.pay(l2, 200000000)
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l2.stop()
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# The close should still be triggered afterwards.
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fut = executor.submit(l1.rpc.close, chan, 0)
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l1.daemon.wait_for_log(' to CHANNELD_SHUTTING_DOWN')
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l2.start()
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fut.result(TIMEOUT)
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l1.daemon.wait_for_log(' to CLOSINGD_SIGEXCHANGE')
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l2.daemon.wait_for_log(' to CLOSINGD_SIGEXCHANGE')
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# And should put closing into mempool.
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l1.daemon.wait_for_log('sendrawtx exit 0')
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l2.daemon.wait_for_log('sendrawtx exit 0')
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bitcoind.generate_block(101)
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wait_for(lambda: len(l1.rpc.listchannels()['channels']) == 0)
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wait_for(lambda: len(l2.rpc.listchannels()['channels']) == 0)
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def test_closing_disconnected_notify(node_factory, bitcoind, executor):
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l1, l2 = node_factory.line_graph(2)
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l1.pay(l2, 200000000)
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l2.stop()
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wait_for(lambda: not only_one(l1.rpc.listpeers(l2.info['id'])['peers'])['connected'])
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out = subprocess.check_output(['cli/lightning-cli',
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'--network={}'.format(TEST_NETWORK),
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'--lightning-dir={}'
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.format(l1.daemon.lightning_dir),
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'close',
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l2.info['id'],
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'5']).decode('utf-8').splitlines()
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assert out[0] == '# peer is offline, will negotiate once they reconnect (5 seconds before unilateral close).'
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assert out[1] == '# Timed out, forcing close.'
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assert not any([line.startswith('#') for line in out[2:]])
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def test_closing_id(node_factory):
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"""Test closing using peer ID and full channel ID
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"""
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l1, l2 = node_factory.get_nodes(2)
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# Close by full channel ID.
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l1.rpc.connect(l2.info['id'], 'localhost', l2.port)
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l1.fundchannel(l2, 10**6)
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cid = l2.rpc.listpeers()['peers'][0]['channels'][0]['channel_id']
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l2.rpc.close(cid)
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wait_for(lambda: not only_one(l1.rpc.listpeers(l2.info['id'])['peers'])['connected'])
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wait_for(lambda: not only_one(l2.rpc.listpeers(l1.info['id'])['peers'])['connected'])
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# Close by peer ID.
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l2.rpc.connect(l1.info['id'], 'localhost', l1.port)
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l1.daemon.wait_for_log("Handed peer, entering loop")
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l2.fundchannel(l1, 10**6)
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pid = l1.info['id']
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l2.rpc.close(pid)
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wait_for(lambda: not only_one(l1.rpc.listpeers(l2.info['id'])['peers'])['connected'])
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wait_for(lambda: not only_one(l2.rpc.listpeers(l1.info['id'])['peers'])['connected'])
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@pytest.mark.slow_test
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def test_closing_torture(node_factory, executor, bitcoind):
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# We set up a fully-connected mesh of N nodes, then try
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# closing them all at once.
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amount = 10**6
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num_nodes = 10 # => 45 channels (36 seconds on my laptop)
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if node_factory.valgrind:
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num_nodes -= 4 # => 15 (135 seconds)
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nodes = node_factory.get_nodes(num_nodes)
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# Make sure bitcoind has plenty of utxos
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bitcoind.generate_block(num_nodes)
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# Give them all plenty of UTXOs, make sure they see them
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for i in range(len(nodes)):
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for j in range(i + 1, len(nodes)):
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addr = nodes[i].rpc.newaddr()['bech32']
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bitcoind.rpc.sendtoaddress(addr, (amount + 1000000) / 10**8)
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bitcoind.generate_block(1)
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sync_blockheight(bitcoind, nodes)
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txs = []
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for i in range(len(nodes)):
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for j in range(i + 1, len(nodes)):
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nodes[i].rpc.connect(nodes[j].info['id'], 'localhost', nodes[j].port)
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txs.append(nodes[i].rpc.fundchannel(nodes[j].info['id'], amount)['txid'])
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# Make sure they're all in, then lock them in.
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bitcoind.generate_block(1, wait_for_mempool=txs)
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# Wait for them all to be CHANNELD_NORMAL
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for n in nodes:
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wait_for(lambda: all(p['channels'][0]['state'] == 'CHANNELD_NORMAL' for p in n.rpc.listpeers()['peers']))
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# Start closers: can take a long time under valgrind!
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futures = []
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for i in range(len(nodes)):
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for j in range(i + 1, len(nodes)):
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futures.append(executor.submit(nodes[i].rpc.close, nodes[j].info['id']))
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futures.append(executor.submit(nodes[j].rpc.close, nodes[i].info['id']))
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# Wait for close to finish
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close_txs = set()
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for f in futures:
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# If one side completes closing, we'll get an error here 'Peer has no active channel'
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try:
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close_txs.add(f.result(TIMEOUT)['txid'])
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except RpcError as err:
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assert err.error['message'] == 'Peer has no active channel'
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# Should have one close for each open.
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assert len(close_txs) == len(txs)
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# Get closes confirmed
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bitcoind.generate_block(100, wait_for_mempool=list(close_txs))
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# And make sure they hangup.
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for n in nodes:
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wait_for(lambda: n.rpc.listpeers()['peers'] == [])
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@pytest.mark.slow_test
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def test_closing_different_fees(node_factory, bitcoind, executor):
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l1 = node_factory.get_node()
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# Default feerate = 15000/11000/7500/1000
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# It will start at the second number, accepting anything above the first.
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feerates = [[20000, 11000, 15000, 7400], [8000, 6000, 1001, 100]]
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balance = [False, True]
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num_peers = len(feerates) * len(balance)
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addr = l1.rpc.newaddr()['bech32']
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bitcoind.rpc.sendtoaddress(addr, 1)
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numfunds = len(l1.rpc.listfunds()['outputs'])
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bitcoind.generate_block(1)
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wait_for(lambda: len(l1.rpc.listfunds()['outputs']) > numfunds)
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# Create them in a batch, for speed!
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peers = []
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for feerate in feerates:
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for b in balance:
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p = node_factory.get_node(feerates=feerate)
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p.feerate = feerate
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p.balance = balance
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l1.rpc.connect(p.info['id'], 'localhost', p.port)
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peers.append(p)
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for p in peers:
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p.channel = l1.rpc.fundchannel(p.info['id'], 10**6, minconf=0)['channel_id']
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# Technically, this is async to fundchannel returning.
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l1.daemon.wait_for_log('sendrawtx exit 0')
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bitcoind.generate_block(6)
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# Now wait for them all to hit normal state, do payments
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l1.daemon.wait_for_logs(['update for channel .* now ACTIVE'] * num_peers
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+ ['to CHANNELD_NORMAL'] * num_peers)
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for p in peers:
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if p.balance:
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l1.pay(p, 100000000)
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# Now close all channels (not unilaterally!)
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closes = [executor.submit(l1.rpc.close, p.channel, 0) for p in peers]
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for c in closes:
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c.result(90)
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# close does *not* wait for the sendrawtransaction, so do that!
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# Note that since they disagree on the ideal fee, they may conflict
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# (first one in will win), so we cannot look at logs, we need to
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# wait for mempool.
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wait_for(lambda: bitcoind.rpc.getmempoolinfo()['size'] == num_peers)
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bitcoind.generate_block(1)
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for p in peers:
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p.daemon.wait_for_log(' to ONCHAIN')
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wait_for(lambda: 'ONCHAIN:Tracking mutual close transaction' in only_one(p.rpc.listpeers(l1.info['id'])['peers'][0]['channels'])['status'])
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l1.daemon.wait_for_logs([' to ONCHAIN'] * num_peers)
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@pytest.mark.developer("needs DEVELOPER=1")
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def test_closing_negotiation_reconnect(node_factory, bitcoind):
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disconnects = ['-WIRE_CLOSING_SIGNED',
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'@WIRE_CLOSING_SIGNED',
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'+WIRE_CLOSING_SIGNED']
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l1, l2 = node_factory.line_graph(2, opts=[{'disconnect': disconnects,
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'may_reconnect': True},
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{'may_reconnect': True}])
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l1.pay(l2, 200000000)
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assert bitcoind.rpc.getmempoolinfo()['size'] == 0
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l1.rpc.close(l2.info['id'])
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l1.daemon.wait_for_log(r'State changed from CHANNELD_NORMAL to CHANNELD_SHUTTING_DOWN')
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l2.daemon.wait_for_log(r'State changed from CHANNELD_NORMAL to CHANNELD_SHUTTING_DOWN')
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# Now verify that the closing tx is in the mempool.
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bitcoind.generate_block(6, wait_for_mempool=1)
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sync_blockheight(bitcoind, [l1, l2])
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for n in [l1, l2]:
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# Ensure we actually got a mutual close.
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n.daemon.wait_for_log(r'Resolved FUNDING_TRANSACTION/FUNDING_OUTPUT by MUTUAL_CLOSE')
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@pytest.mark.developer("needs DEVELOPER=1")
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def test_closing_specified_destination(node_factory, bitcoind, chainparams):
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l1, l2, l3, l4 = node_factory.get_nodes(4)
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l1.rpc.connect(l2.info['id'], 'localhost', l2.port)
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l1.rpc.connect(l3.info['id'], 'localhost', l3.port)
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l1.rpc.connect(l4.info['id'], 'localhost', l4.port)
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chan12, _ = l1.fundchannel(l2, 10**6)
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chan13, _ = l1.fundchannel(l3, 10**6)
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chan14, _ = l1.fundchannel(l4, 10**6)
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l1.pay(l2, 100000000)
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l1.pay(l3, 100000000)
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l1.pay(l4, 100000000)
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bitcoind.generate_block(5)
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addr = chainparams['example_addr']
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l1.rpc.close(chan12, None, addr)
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l1.rpc.call('close', {'id': chan13, 'destination': addr})
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l1.rpc.call('close', [chan14, None, addr])
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l1.daemon.wait_for_logs([' to CLOSINGD_SIGEXCHANGE'] * 3)
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# Both nodes should have disabled the channel in their view
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wait_for(lambda: len(l1.getactivechannels()) == 0)
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wait_for(lambda: bitcoind.rpc.getmempoolinfo()['size'] == 3)
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# Now grab the close transaction
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closetxs = {}
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for i, n in enumerate([l2, l3, l4]):
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billboard = only_one(l1.rpc.listpeers(n.info['id'])['peers'][0]['channels'])['status'][0]
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m = re.search(r'CLOSINGD_SIGEXCHANGE.* tx:([a-f0-9]{64})', billboard)
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closetxs[n] = m.group(1)
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bitcoind.generate_block(1)
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sync_blockheight(bitcoind, [l1, l2, l3, l4])
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# l1 can't spent the output to addr.
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for txid in closetxs.values():
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assert not l1.daemon.is_in_log(r'Owning output.* \(SEGWIT\).* txid {}.* CONFIRMED'.format(txid))
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# Check the txid has at least 1 confirmation
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for n, txid in closetxs.items():
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n.daemon.wait_for_log(r'Owning output.* \(SEGWIT\).* txid {}.* CONFIRMED'.format(txid))
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for n in [l2, l3, l4]:
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# Make sure both nodes have grabbed their close tx funds
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closetx = closetxs[n]
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outputs = n.rpc.listfunds()['outputs']
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assert closetx in set([o['txid'] for o in outputs])
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output_num2 = [o for o in outputs if o['txid'] == closetx][0]['output']
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output_num1 = 0 if output_num2 == 1 else 1
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# Check the another address is addr
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assert addr == scriptpubkey_addr(bitcoind.rpc.gettxout(closetx, output_num1)['scriptPubKey'])
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assert 1 == bitcoind.rpc.gettxout(closetx, output_num1)['confirmations']
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|
|
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def closing_negotiation_step(node_factory, bitcoind, chainparams, opts):
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def feerate_for(target, minimum=0, maximum=10000000):
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"""Binary search to find feerate"""
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assert minimum != maximum
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mid = (minimum + maximum) // 2
|
|
mid_fee = closing_fee(mid, 1)
|
|
if mid_fee > target:
|
|
return feerate_for(target, minimum, mid)
|
|
elif mid_fee < target:
|
|
return feerate_for(target, mid, maximum)
|
|
else:
|
|
return mid
|
|
|
|
orate = feerate_for(21000) # closing fee negotiation starts at 21000
|
|
prate = feerate_for(20000) # closing fee negotiation starts at 20000
|
|
opener, peer = node_factory.line_graph(2, opts=[{'feerates': (orate, orate, orate, orate)},
|
|
{'feerates': (prate, prate, prate, prate)}])
|
|
|
|
opener_id = opener.info['id']
|
|
peer_id = peer.info['id']
|
|
|
|
assert bitcoind.rpc.getmempoolinfo()['size'] == 0
|
|
|
|
if opts['close_initiated_by'] == 'opener':
|
|
opener.rpc.close(peer_id=peer_id, fee_negotiation_step=opts['fee_negotiation_step'])
|
|
else:
|
|
assert opts['close_initiated_by'] == 'peer'
|
|
peer.rpc.close(peer_id=opener_id, fee_negotiation_step=opts['fee_negotiation_step'])
|
|
|
|
# Get the proclaimed closing fee from the two nodes' statuses
|
|
|
|
status_agreed_regex = re.compile("agreed on a closing fee of ([0-9]+) satoshi")
|
|
|
|
# [fee_from_opener_status, fee_from_peer_status]
|
|
fees_from_status = [None, None]
|
|
|
|
def get_fee_from_status(node, peer_id, i):
|
|
nonlocal fees_from_status
|
|
peer = only_one(node.rpc.listpeers(peer_id)['peers'])
|
|
channel = only_one(peer['channels'])
|
|
status = channel['status'][0]
|
|
|
|
m = status_agreed_regex.search(status)
|
|
if not m:
|
|
return False
|
|
|
|
fees_from_status[i] = int(m.group(1))
|
|
return True
|
|
|
|
wait_for(lambda: get_fee_from_status(opener, peer_id, 0))
|
|
wait_for(lambda: get_fee_from_status(peer, opener_id, 1))
|
|
|
|
assert opts['expected_close_fee'] == fees_from_status[0]
|
|
assert opts['expected_close_fee'] == fees_from_status[1]
|
|
|
|
# Get the closing transaction from the bitcoind mempool and get its fee
|
|
|
|
mempool = None
|
|
mempool_tx_ids = None
|
|
|
|
def get_mempool_when_size_1():
|
|
nonlocal mempool, mempool_tx_ids
|
|
mempool = bitcoind.rpc.getrawmempool(True)
|
|
mempool_tx_ids = list(mempool.keys())
|
|
return len(mempool_tx_ids) == 1
|
|
|
|
wait_for(get_mempool_when_size_1)
|
|
|
|
close_tx_id = mempool_tx_ids[0]
|
|
fee_mempool = round(mempool[close_tx_id]['fee'] * 10**8)
|
|
|
|
assert opts['expected_close_fee'] == fee_mempool
|
|
|
|
|
|
def test_closing_negotiation_step_30pct(node_factory, bitcoind, chainparams):
|
|
"""Test that the closing fee negotiation step works, 30%"""
|
|
opts = {}
|
|
opts['fee_negotiation_step'] = '30%'
|
|
|
|
opts['close_initiated_by'] = 'opener'
|
|
opts['expected_close_fee'] = 20537 if not chainparams['elements'] else 26046
|
|
closing_negotiation_step(node_factory, bitcoind, chainparams, opts)
|
|
|
|
opts['close_initiated_by'] = 'peer'
|
|
opts['expected_close_fee'] = 20233 if not chainparams['elements'] else 25657
|
|
closing_negotiation_step(node_factory, bitcoind, chainparams, opts)
|
|
|
|
|
|
def test_closing_negotiation_step_50pct(node_factory, bitcoind, chainparams):
|
|
"""Test that the closing fee negotiation step works, 50%, the default"""
|
|
opts = {}
|
|
opts['fee_negotiation_step'] = '50%'
|
|
|
|
opts['close_initiated_by'] = 'opener'
|
|
opts['expected_close_fee'] = 20334 if not chainparams['elements'] else 25789
|
|
closing_negotiation_step(node_factory, bitcoind, chainparams, opts)
|
|
|
|
opts['close_initiated_by'] = 'peer'
|
|
opts['expected_close_fee'] = 20334 if not chainparams['elements'] else 25789
|
|
closing_negotiation_step(node_factory, bitcoind, chainparams, opts)
|
|
|
|
|
|
def test_closing_negotiation_step_100pct(node_factory, bitcoind, chainparams):
|
|
"""Test that the closing fee negotiation step works, 100%"""
|
|
opts = {}
|
|
opts['fee_negotiation_step'] = '100%'
|
|
|
|
opts['close_initiated_by'] = 'opener'
|
|
opts['expected_close_fee'] = 20001 if not chainparams['elements'] else 25366
|
|
closing_negotiation_step(node_factory, bitcoind, chainparams, opts)
|
|
|
|
# The close fee of 20499 looks strange in this case - one would expect
|
|
# to have a number close to 21000. This is because
|
|
# * the range is initially set to [20000 (peer), 21000 (opener)]
|
|
# * the opener is always first to propose, he uses 50% step, so he proposes 20500
|
|
# * the range is narrowed to [20001, 20499] and the peer proposes 20499
|
|
opts['close_initiated_by'] = 'peer'
|
|
opts['expected_close_fee'] = 20499 if not chainparams['elements'] else 25998
|
|
closing_negotiation_step(node_factory, bitcoind, chainparams, opts)
|
|
|
|
|
|
def test_closing_negotiation_step_1sat(node_factory, bitcoind, chainparams):
|
|
"""Test that the closing fee negotiation step works, 1sat"""
|
|
opts = {}
|
|
opts['fee_negotiation_step'] = '1'
|
|
|
|
opts['close_initiated_by'] = 'opener'
|
|
opts['expected_close_fee'] = 20989 if not chainparams['elements'] else 26624
|
|
closing_negotiation_step(node_factory, bitcoind, chainparams, opts)
|
|
|
|
opts['close_initiated_by'] = 'peer'
|
|
opts['expected_close_fee'] = 20010 if not chainparams['elements'] else 25373
|
|
closing_negotiation_step(node_factory, bitcoind, chainparams, opts)
|
|
|
|
|
|
def test_closing_negotiation_step_700sat(node_factory, bitcoind, chainparams):
|
|
"""Test that the closing fee negotiation step works, 700sat"""
|
|
opts = {}
|
|
opts['fee_negotiation_step'] = '700'
|
|
|
|
opts['close_initiated_by'] = 'opener'
|
|
opts['expected_close_fee'] = 20151 if not chainparams['elements'] else 25650
|
|
closing_negotiation_step(node_factory, bitcoind, chainparams, opts)
|
|
|
|
opts['close_initiated_by'] = 'peer'
|
|
opts['expected_close_fee'] = 20499 if not chainparams['elements'] else 25998
|
|
closing_negotiation_step(node_factory, bitcoind, chainparams, opts)
|
|
|
|
|
|
@pytest.mark.developer("needs DEVELOPER=1")
|
|
def test_penalty_inhtlc(node_factory, bitcoind, executor, chainparams):
|
|
"""Test penalty transaction with an incoming HTLC"""
|
|
|
|
# We track channel balances, to verify that accounting is ok.
|
|
coin_mvt_plugin = os.path.join(os.getcwd(), 'tests/plugins/coin_movements.py')
|
|
# We suppress each one after first commit; HTLC gets added not fulfilled.
|
|
# Feerates identical so we don't get gratuitous commit to update them
|
|
l1, l2 = node_factory.line_graph(2, opts=[{'disconnect': ['=WIRE_COMMITMENT_SIGNED-nocommit'],
|
|
'may_fail': True,
|
|
'feerates': (7500, 7500, 7500, 7500),
|
|
'allow_broken_log': True,
|
|
'plugin': coin_mvt_plugin},
|
|
{'disconnect': ['=WIRE_COMMITMENT_SIGNED-nocommit'],
|
|
'plugin': coin_mvt_plugin}])
|
|
|
|
channel_id = first_channel_id(l1, l2)
|
|
|
|
# Now, this will get stuck due to l1 commit being disabled..
|
|
t = executor.submit(l1.pay, l2, 100000000)
|
|
|
|
assert len(l1.getactivechannels()) == 2
|
|
assert len(l2.getactivechannels()) == 2
|
|
|
|
# They should both have commitments blocked now.
|
|
l1.daemon.wait_for_log('=WIRE_COMMITMENT_SIGNED-nocommit')
|
|
l2.daemon.wait_for_log('=WIRE_COMMITMENT_SIGNED-nocommit')
|
|
|
|
# Make sure l1 got l2's commitment to the HTLC, and sent to master.
|
|
l1.daemon.wait_for_log('got commitsig')
|
|
|
|
# Take our snapshot.
|
|
tx = l1.rpc.dev_sign_last_tx(l2.info['id'])['tx']
|
|
|
|
# Let them continue
|
|
l1.rpc.dev_reenable_commit(l2.info['id'])
|
|
l2.rpc.dev_reenable_commit(l1.info['id'])
|
|
|
|
# Should fulfill.
|
|
l1.daemon.wait_for_log('peer_in WIRE_UPDATE_FULFILL_HTLC')
|
|
l1.daemon.wait_for_log('peer_out WIRE_REVOKE_AND_ACK')
|
|
|
|
l2.daemon.wait_for_log('peer_out WIRE_UPDATE_FULFILL_HTLC')
|
|
l1.daemon.wait_for_log('peer_in WIRE_REVOKE_AND_ACK')
|
|
|
|
# Payment should now complete.
|
|
t.result(timeout=10)
|
|
|
|
# Now we really mess things up!
|
|
bitcoind.rpc.sendrawtransaction(tx)
|
|
bitcoind.generate_block(1)
|
|
|
|
l2.daemon.wait_for_log(' to ONCHAIN')
|
|
|
|
# FIXME: l1 should try to stumble along!
|
|
wait_for(lambda: len(l2.getactivechannels()) == 0)
|
|
|
|
# l2 should spend all of the outputs (except to-us).
|
|
# Could happen in any order, depending on commitment tx.
|
|
needle = l2.daemon.logsearch_start
|
|
l2.wait_for_onchaind_broadcast('OUR_PENALTY_TX',
|
|
'THEIR_REVOKED_UNILATERAL/DELAYED_CHEAT_OUTPUT_TO_THEM')
|
|
l2.daemon.logsearch_start = needle
|
|
l2.wait_for_onchaind_broadcast('OUR_PENALTY_TX',
|
|
'THEIR_REVOKED_UNILATERAL/THEIR_HTLC')
|
|
|
|
# FIXME: test HTLC tx race!
|
|
|
|
bitcoind.generate_block(100)
|
|
|
|
sync_blockheight(bitcoind, [l2])
|
|
wait_for(lambda: len(l2.rpc.listpeers()['peers']) == 0)
|
|
|
|
# Do one last pass over the logs to extract the reactions l2 sent
|
|
l2.daemon.logsearch_start = needle
|
|
needles = [
|
|
# The first needle will match, but since we don't have a direct output
|
|
# for l2 it won't result in an output, hence the comment:
|
|
# r'Resolved FUNDING_TRANSACTION/FUNDING_OUTPUT by THEIR_REVOKED_UNILATERAL .([a-f0-9]{64}).',
|
|
r'Resolved THEIR_REVOKED_UNILATERAL/DELAYED_CHEAT_OUTPUT_TO_THEM by our proposal OUR_PENALTY_TX .([a-f0-9]{64}).',
|
|
r'Resolved THEIR_REVOKED_UNILATERAL/THEIR_HTLC by our proposal OUR_PENALTY_TX .([a-f0-9]{64}).',
|
|
]
|
|
matches = list(map(l2.daemon.is_in_log, needles))
|
|
|
|
# Now extract the txids for these responses
|
|
txids = set([re.search(r'\(([0-9a-f]{64})\)', m).group(1) for m in matches])
|
|
|
|
# We should have one confirmed output for each of the above reactions in
|
|
# the list of funds we own.
|
|
outputs = l2.rpc.listfunds()['outputs']
|
|
|
|
assert [o['status'] for o in outputs] == ['confirmed'] * 2
|
|
assert set([o['txid'] for o in outputs]) == txids
|
|
assert account_balance(l2, channel_id) == 0
|
|
|
|
|
|
@pytest.mark.developer("needs DEVELOPER=1")
|
|
def test_penalty_outhtlc(node_factory, bitcoind, executor, chainparams):
|
|
"""Test penalty transaction with an outgoing HTLC"""
|
|
|
|
# We track channel balances, to verify that accounting is ok.
|
|
coin_mvt_plugin = os.path.join(os.getcwd(), 'tests/plugins/coin_movements.py')
|
|
# First we need to get funds to l2, so suppress after second.
|
|
# Feerates identical so we don't get gratuitous commit to update them
|
|
l1, l2 = node_factory.line_graph(2,
|
|
opts=[{'disconnect': ['=WIRE_COMMITMENT_SIGNED*3-nocommit'],
|
|
'may_fail': True,
|
|
'feerates': (7500, 7500, 7500, 7500),
|
|
'allow_broken_log': True,
|
|
'plugin': coin_mvt_plugin},
|
|
{'disconnect': ['=WIRE_COMMITMENT_SIGNED*3-nocommit'],
|
|
'plugin': coin_mvt_plugin}])
|
|
channel_id = first_channel_id(l1, l2)
|
|
|
|
# Move some across to l2.
|
|
l1.pay(l2, 200000000)
|
|
|
|
assert not l1.daemon.is_in_log('=WIRE_COMMITMENT_SIGNED')
|
|
assert not l2.daemon.is_in_log('=WIRE_COMMITMENT_SIGNED')
|
|
|
|
# Now, this will get stuck due to l1 commit being disabled..
|
|
t = executor.submit(l2.pay, l1, 100000000)
|
|
|
|
# Make sure we get signature from them.
|
|
l1.daemon.wait_for_log('peer_in WIRE_UPDATE_ADD_HTLC')
|
|
l1.daemon.wait_for_log('peer_in WIRE_COMMITMENT_SIGNED')
|
|
|
|
# They should both have commitments blocked now.
|
|
l1.daemon.wait_for_log('dev_disconnect: =WIRE_COMMITMENT_SIGNED')
|
|
l2.daemon.wait_for_log('dev_disconnect: =WIRE_COMMITMENT_SIGNED')
|
|
|
|
# Make sure both sides got revoke_and_ack for that commitment.
|
|
l1.daemon.wait_for_log('peer_in WIRE_REVOKE_AND_ACK')
|
|
l2.daemon.wait_for_log('peer_in WIRE_REVOKE_AND_ACK')
|
|
|
|
# Take our snapshot.
|
|
tx = l1.rpc.dev_sign_last_tx(l2.info['id'])['tx']
|
|
|
|
# Let them continue
|
|
l1.rpc.dev_reenable_commit(l2.info['id'])
|
|
l2.rpc.dev_reenable_commit(l1.info['id'])
|
|
|
|
# Thread should complete.
|
|
t.result(timeout=10)
|
|
|
|
# Make sure both sides got revoke_and_ack for final.
|
|
l1.daemon.wait_for_log('peer_in WIRE_REVOKE_AND_ACK')
|
|
l2.daemon.wait_for_log('peer_in WIRE_REVOKE_AND_ACK')
|
|
|
|
# Now we really mess things up!
|
|
bitcoind.rpc.sendrawtransaction(tx)
|
|
bitcoind.generate_block(1)
|
|
|
|
l2.daemon.wait_for_log(' to ONCHAIN')
|
|
# FIXME: l1 should try to stumble along!
|
|
|
|
# l2 should spend all of the outputs (except to-us).
|
|
# Could happen in any order, depending on commitment tx.
|
|
needle = l2.daemon.logsearch_start
|
|
l2.wait_for_onchaind_broadcast('OUR_PENALTY_TX',
|
|
'THEIR_REVOKED_UNILATERAL/DELAYED_CHEAT_OUTPUT_TO_THEM')
|
|
l2.daemon.logsearch_start = needle
|
|
l2.wait_for_onchaind_broadcast('OUR_PENALTY_TX',
|
|
'THEIR_REVOKED_UNILATERAL/OUR_HTLC')
|
|
|
|
l2.daemon.logsearch_start = needle
|
|
l2.daemon.wait_for_log('Ignoring output.*: THEIR_REVOKED_UNILATERAL/OUTPUT_TO_US')
|
|
|
|
# FIXME: test HTLC tx race!
|
|
|
|
# 100 blocks later, all resolved.
|
|
bitcoind.generate_block(100)
|
|
|
|
sync_blockheight(bitcoind, [l2])
|
|
wait_for(lambda: len(l2.rpc.listpeers()['peers']) == 0)
|
|
|
|
# Do one last pass over the logs to extract the reactions l2 sent
|
|
l2.daemon.logsearch_start = needle
|
|
needles = [
|
|
r'Resolved FUNDING_TRANSACTION/FUNDING_OUTPUT by THEIR_REVOKED_UNILATERAL .([a-f0-9]{64}).',
|
|
r'Resolved THEIR_REVOKED_UNILATERAL/DELAYED_CHEAT_OUTPUT_TO_THEM by our proposal OUR_PENALTY_TX .([a-f0-9]{64}).',
|
|
r'Resolved THEIR_REVOKED_UNILATERAL/OUR_HTLC by our proposal OUR_PENALTY_TX .([a-f0-9]{64}).',
|
|
]
|
|
matches = list(map(l2.daemon.is_in_log, needles))
|
|
|
|
# Now extract the txids for these responses
|
|
txids = set([re.search(r'\(([0-9a-f]{64})\)', m).group(1) for m in matches])
|
|
|
|
# We should have one confirmed output for each of the above reactions in
|
|
# the list of funds we own.
|
|
outputs = l2.rpc.listfunds()['outputs']
|
|
|
|
assert [o['status'] for o in outputs] == ['confirmed'] * 3
|
|
assert set([o['txid'] for o in outputs]) == txids
|
|
assert account_balance(l2, channel_id) == 0
|
|
|
|
|
|
@unittest.skipIf(TEST_NETWORK != 'regtest', 'elementsd doesnt yet support PSBT features we need')
|
|
@pytest.mark.openchannel('v2')
|
|
@pytest.mark.slow_test
|
|
@pytest.mark.developer("requres 'dev-queryrates'")
|
|
def test_channel_lease_falls_behind(node_factory, bitcoind):
|
|
'''
|
|
If our peer falls too far behind/doesn't send us an update for
|
|
their blockheight, the lessor fails the channel
|
|
'''
|
|
opts = [{'funder-policy': 'match', 'funder-policy-mod': 100,
|
|
'lease-fee-base-msat': '100sat', 'lease-fee-basis': 100},
|
|
{'funder-policy': 'match', 'funder-policy-mod': 100,
|
|
'lease-fee-base-msat': '100sat', 'lease-fee-basis': 100}]
|
|
l1, l2, = node_factory.get_nodes(2, opts=opts)
|
|
amount = 500000
|
|
feerate = 2000
|
|
l1.fundwallet(20000000)
|
|
l2.fundwallet(20000000)
|
|
|
|
l1.rpc.connect(l2.info['id'], 'localhost', l2.port)
|
|
rates = l1.rpc.dev_queryrates(l2.info['id'], amount, amount)
|
|
wait_for(lambda: len(l1.rpc.listpeers(l2.info['id'])['peers']) == 0)
|
|
l1.rpc.connect(l2.info['id'], 'localhost', l2.port)
|
|
# l1 leases a channel from l2
|
|
l1.rpc.fundchannel(l2.info['id'], amount, request_amt=amount,
|
|
feerate='{}perkw'.format(feerate),
|
|
compact_lease=rates['compact_lease'])
|
|
|
|
# sink the funding transaction
|
|
bitcoind.generate_block(1)
|
|
|
|
# stop l1
|
|
l1.stop()
|
|
|
|
# advance blockchain 1008 blocks, the lessor should drop to chain
|
|
bitcoind.generate_block(1008)
|
|
sync_blockheight(bitcoind, [l2])
|
|
|
|
l2.daemon.wait_for_log('Offline peer is too far behind, terminating')
|
|
|
|
|
|
@unittest.skipIf(TEST_NETWORK != 'regtest', 'elementsd doesnt yet support PSBT features we need')
|
|
@pytest.mark.openchannel('v2')
|
|
@pytest.mark.developer("requres 'dev-queryrates'")
|
|
@pytest.mark.slow_test
|
|
def test_channel_lease_post_expiry(node_factory, bitcoind):
|
|
|
|
opts = {'funder-policy': 'match', 'funder-policy-mod': 100,
|
|
'lease-fee-base-msat': '100sat', 'lease-fee-basis': 100,
|
|
'may_reconnect': True}
|
|
|
|
l1, l2, = node_factory.get_nodes(2, opts=opts)
|
|
|
|
feerate = 2000
|
|
amount = 500000
|
|
l1.fundwallet(20000000)
|
|
l2.fundwallet(20000000)
|
|
|
|
# l1 leases a channel from l2
|
|
l1.rpc.connect(l2.info['id'], 'localhost', l2.port)
|
|
rates = l1.rpc.dev_queryrates(l2.info['id'], amount, amount)
|
|
wait_for(lambda: len(l1.rpc.listpeers(l2.info['id'])['peers']) == 0)
|
|
l1.rpc.connect(l2.info['id'], 'localhost', l2.port)
|
|
l1.rpc.fundchannel(l2.info['id'], amount, request_amt=amount,
|
|
feerate='{}perkw'.format(feerate),
|
|
compact_lease=rates['compact_lease'])
|
|
|
|
est_fees = calc_lease_fee(amount, feerate, rates)
|
|
|
|
# This should be the accepter's amount
|
|
fundings = only_one(only_one(l1.rpc.listpeers()['peers'])['channels'])['funding']
|
|
assert Millisatoshi(est_fees + amount * 1000) == Millisatoshi(fundings['remote_msat'])
|
|
|
|
bitcoind.generate_block(6)
|
|
l1.daemon.wait_for_log('to CHANNELD_NORMAL')
|
|
|
|
wait_for(lambda: [c['active'] for c in l1.rpc.listchannels(l1.get_channel_scid(l2))['channels']] == [True, True])
|
|
|
|
# send some payments, mine a block or two
|
|
inv = l2.rpc.invoice(10**4, '1', 'no_1')
|
|
l1.rpc.pay(inv['bolt11'])
|
|
|
|
# l2 attempts to close a channel that it leased, should fail
|
|
with pytest.raises(RpcError, match=r'Peer leased this channel from us'):
|
|
l2.rpc.close(l1.get_channel_scid(l2))
|
|
|
|
bitcoind.generate_block(6)
|
|
sync_blockheight(bitcoind, [l1, l2])
|
|
# make sure we're at the right place for the csv lock
|
|
l2.daemon.wait_for_log('Blockheight: SENT_ADD_ACK_COMMIT->RCVD_ADD_ACK_REVOCATION LOCAL now 115')
|
|
|
|
# We need to give l1-l2 time to update their blockheights
|
|
bitcoind.generate_block(1000)
|
|
sync_blockheight(bitcoind, [l1, l2])
|
|
l1.daemon.wait_for_log('peer_out WIRE_UPDATE_BLOCKHEIGHT')
|
|
|
|
bitcoind.generate_block(1000)
|
|
sync_blockheight(bitcoind, [l1, l2])
|
|
l1.daemon.wait_for_log('peer_out WIRE_UPDATE_BLOCKHEIGHT')
|
|
|
|
bitcoind.generate_block(1000)
|
|
sync_blockheight(bitcoind, [l1, l2])
|
|
l1.daemon.wait_for_log('peer_out WIRE_UPDATE_BLOCKHEIGHT')
|
|
|
|
bitcoind.generate_block(1000)
|
|
sync_blockheight(bitcoind, [l1, l2])
|
|
l1.daemon.wait_for_log('peer_out WIRE_UPDATE_BLOCKHEIGHT')
|
|
|
|
bitcoind.generate_block(32)
|
|
sync_blockheight(bitcoind, [l1, l2])
|
|
l1.daemon.wait_for_log('peer_out WIRE_UPDATE_BLOCKHEIGHT')
|
|
|
|
# l1<->l2 mutual close should work
|
|
chan = l1.get_channel_scid(l2)
|
|
l2.rpc.connect(l1.info['id'], 'localhost', l1.port)
|
|
l1.rpc.close(chan)
|
|
l2.daemon.wait_for_log('State changed from CLOSINGD_SIGEXCHANGE to CLOSINGD_COMPLETE')
|
|
|
|
|
|
@unittest.skipIf(TEST_NETWORK != 'regtest', 'elementsd doesnt yet support PSBT features we need')
|
|
@pytest.mark.openchannel('v2')
|
|
@pytest.mark.slow_test
|
|
@pytest.mark.developer("requres 'dev-queryrates'")
|
|
def test_channel_lease_unilat_closes(node_factory, bitcoind):
|
|
'''
|
|
Check that channel leases work
|
|
|
|
l1-l2: l1 leases funds from l2; l1 goes to chain unilaterally
|
|
l2-l3: l2 leases funds from l3; l3 goes to chain unilaterally
|
|
'''
|
|
opts = {'funder-policy': 'match', 'funder-policy-mod': 100,
|
|
'lease-fee-base-msat': '100sat', 'lease-fee-basis': 100,
|
|
'funder-lease-requests-only': False}
|
|
|
|
l1, l2, l3 = node_factory.get_nodes(3, opts=opts)
|
|
# Allow l2 some warnings
|
|
l2.allow_warning = True
|
|
|
|
feerate = 2000
|
|
amount = 500000
|
|
l1.fundwallet(20000000)
|
|
l2.fundwallet(20000000)
|
|
l3.fundwallet(20000000)
|
|
|
|
l1.rpc.connect(l2.info['id'], 'localhost', l2.port)
|
|
rates = l1.rpc.dev_queryrates(l2.info['id'], amount, amount)
|
|
wait_for(lambda: len(l1.rpc.listpeers(l2.info['id'])['peers']) == 0)
|
|
l1.rpc.connect(l2.info['id'], 'localhost', l2.port)
|
|
# l1 leases a channel from l2
|
|
l1.rpc.fundchannel(l2.info['id'], amount, request_amt=amount,
|
|
feerate='{}perkw'.format(feerate),
|
|
compact_lease=rates['compact_lease'])
|
|
|
|
# l2 leases a channel from l3
|
|
l2.rpc.connect(l3.info['id'], 'localhost', l3.port)
|
|
rates = l2.rpc.dev_queryrates(l3.info['id'], amount, amount)
|
|
wait_for(lambda: len(l2.rpc.listpeers(l3.info['id'])['peers']) == 0)
|
|
l2.rpc.connect(l3.info['id'], 'localhost', l3.port)
|
|
l2.rpc.fundchannel(l3.info['id'], amount, request_amt=amount,
|
|
feerate='{}perkw'.format(feerate), minconf=0,
|
|
compact_lease=rates['compact_lease'])
|
|
|
|
est_fees = calc_lease_fee(amount, feerate, rates)
|
|
|
|
# This should be the accepter's amount
|
|
fundings = only_one(only_one(l1.rpc.listpeers()['peers'])['channels'])['funding']
|
|
assert Millisatoshi(est_fees + amount * 1000) == Millisatoshi(fundings['remote_msat'])
|
|
|
|
bitcoind.generate_block(6)
|
|
l1.daemon.wait_for_log('to CHANNELD_NORMAL')
|
|
l3.daemon.wait_for_log('to CHANNELD_NORMAL')
|
|
|
|
wait_for(lambda: [c['active'] for c in l1.rpc.listchannels(l1.get_channel_scid(l2))['channels']] == [True, True])
|
|
wait_for(lambda: [c['active'] for c in l3.rpc.listchannels(l3.get_channel_scid(l2))['channels']] == [True, True])
|
|
|
|
# send some payments, mine a block or two
|
|
inv = l2.rpc.invoice(10**4, '1', 'no_1')
|
|
l1.rpc.pay(inv['bolt11'])
|
|
inv = l2.rpc.invoice(10**4, '3', 'no_3')
|
|
l3.rpc.pay(inv['bolt11'])
|
|
|
|
bitcoind.generate_block(6)
|
|
sync_blockheight(bitcoind, [l1, l2, l3])
|
|
# make sure we're at the right place for the csv lock
|
|
l2.daemon.wait_for_log('Blockheight: SENT_ADD_ACK_COMMIT->RCVD_ADD_ACK_REVOCATION LOCAL now 110')
|
|
l2.stop()
|
|
|
|
# unilateral close channels l1<->l2 & l3<->l2
|
|
l1.rpc.close(l2.info['id'], 1)
|
|
l3.rpc.close(l2.info['id'], 1, force_lease_closed=True)
|
|
|
|
# Wait til to_self_delay expires, l1 should claim to_local back
|
|
bitcoind.generate_block(10, wait_for_mempool=2)
|
|
l1.daemon.wait_for_log('Broadcasting OUR_DELAYED_RETURN_TO_WALLET')
|
|
bitcoind.generate_block(1, wait_for_mempool=1)
|
|
l1.daemon.wait_for_log('Resolved OUR_UNILATERAL/DELAYED_OUTPUT_TO_US by our proposal OUR_DELAYED_RETURN_TO_WALLET')
|
|
assert len(l1.rpc.listfunds()['outputs']) == 2
|
|
|
|
l2.start()
|
|
search_start = l2.daemon.logsearch_start
|
|
log = l2.daemon.wait_for_log('adding utxo to watch .* csv 40.*')
|
|
utxo1 = re.match('.* adding utxo to watch (.*), csv .*', log).group(1)
|
|
|
|
l2.daemon.logsearch_start = search_start
|
|
log = l2.daemon.wait_for_log('adding utxo to watch .* csv 1')
|
|
utxo3 = re.match('.* adding utxo to watch (.*), csv 1', log).group(1)
|
|
|
|
# we *shouldn't* be able to spend it, there's a lock on it
|
|
with pytest.raises(RpcError, match='UTXO .* is csv locked'):
|
|
l2.rpc.withdraw(l2.rpc.newaddr()['bech32'], "all", utxos=[utxo1])
|
|
|
|
# we *can* spend the 1csv lock one
|
|
l2.rpc.withdraw(l2.rpc.newaddr()['bech32'], "all", utxos=[utxo3])
|
|
|
|
# This can timeout, so do it in four easy stages.
|
|
for i in range(4):
|
|
bitcoind.generate_block(4032 // 4)
|
|
sync_blockheight(bitcoind, [l2, l3])
|
|
|
|
l2.rpc.withdraw(l2.rpc.newaddr()['bech32'], "all", utxos=[utxo1])
|
|
|
|
# l3 cleans up their to-self after their lease expires
|
|
assert l3.daemon.is_in_log('Broadcasting OUR_DELAYED_RETURN_TO_WALLET')
|
|
|
|
|
|
@unittest.skipIf(TEST_NETWORK != 'regtest', 'elementsd doesnt yet support PSBT features we need')
|
|
@pytest.mark.openchannel('v2')
|
|
@unittest.skipIf(os.getenv('TEST_DB_PROVIDER', 'sqlite3') != 'sqlite3', "Makes use of the sqlite3 db")
|
|
@pytest.mark.developer("requres 'dev-queryrates'")
|
|
def test_channel_lease_lessor_cheat(node_factory, bitcoind, chainparams):
|
|
'''
|
|
Check that lessee can recover funds if lessor cheats
|
|
'''
|
|
opts = [{'funder-policy': 'match', 'funder-policy-mod': 100,
|
|
'lease-fee-base-msat': '100sat', 'lease-fee-basis': 100,
|
|
'may_reconnect': True, 'allow_warning': True},
|
|
{'funder-policy': 'match', 'funder-policy-mod': 100,
|
|
'lease-fee-base-msat': '100sat', 'lease-fee-basis': 100,
|
|
'may_reconnect': True, 'allow_broken_log': True}]
|
|
l1, l2, = node_factory.get_nodes(2, opts=opts)
|
|
amount = 500000
|
|
feerate = 2000
|
|
l1.fundwallet(20000000)
|
|
l2.fundwallet(20000000)
|
|
|
|
l1.rpc.connect(l2.info['id'], 'localhost', l2.port)
|
|
rates = l1.rpc.dev_queryrates(l2.info['id'], amount, amount)
|
|
wait_for(lambda: len(l1.rpc.listpeers(l2.info['id'])['peers']) == 0)
|
|
l1.rpc.connect(l2.info['id'], 'localhost', l2.port)
|
|
# l1 leases a channel from l2
|
|
l1.rpc.fundchannel(l2.info['id'], amount, request_amt=amount,
|
|
feerate='{}perkw'.format(feerate),
|
|
compact_lease=rates['compact_lease'])
|
|
|
|
bitcoind.generate_block(6)
|
|
l1.daemon.wait_for_log('to CHANNELD_NORMAL')
|
|
wait_for(lambda: [c['active'] for c in l1.rpc.listchannels(l1.get_channel_scid(l2))['channels']] == [True, True])
|
|
wait_for(lambda: [c['active'] for c in l2.rpc.listchannels(l2.get_channel_scid(l1))['channels']] == [True, True])
|
|
# send some payments, mine a block or two
|
|
inv = l2.rpc.invoice(10**4, '1', 'no_1')
|
|
l1.rpc.pay(inv['bolt11'])
|
|
|
|
bitcoind.generate_block(1)
|
|
|
|
# make database snapshot of l2
|
|
l2.stop()
|
|
l2_db_path = os.path.join(l2.daemon.lightning_dir, chainparams['name'], 'lightningd.sqlite3')
|
|
l2_db_path_bak = os.path.join(l2.daemon.lightning_dir, chainparams['name'], 'lightningd.sqlite3.bak')
|
|
copyfile(l2_db_path, l2_db_path_bak)
|
|
l2.start(wait_for_bitcoind_sync=True)
|
|
l1.rpc.connect(l2.info['id'], 'localhost', l2.port)
|
|
sync_blockheight(bitcoind, [l2])
|
|
|
|
# push some money from l2->l1, so the commit counter advances
|
|
inv = l1.rpc.invoice(10**5, '2', 'no_2')
|
|
l2.rpc.pay(inv['bolt11'])
|
|
|
|
# stop both nodes, roll back l2's database
|
|
l2.stop()
|
|
l1.stop()
|
|
copyfile(l2_db_path_bak, l2_db_path)
|
|
|
|
# start l2 and force close channel with l1 while l1 is still offline
|
|
l2.start()
|
|
sync_blockheight(bitcoind, [l2])
|
|
l2.rpc.close(l1.info['id'], 1, force_lease_closed=True)
|
|
bitcoind.generate_block(1, wait_for_mempool=1)
|
|
|
|
l1.start()
|
|
sync_blockheight(bitcoind, [l1])
|
|
l1.daemon.wait_for_logs(['Broadcasting OUR_PENALTY_TX',
|
|
' Propose handling THEIR_REVOKED_UNILATERAL/DELAYED_CHEAT_OUTPUT_TO_THEM by OUR_PENALTY_TX'])
|
|
|
|
bitcoind.generate_block(1, wait_for_mempool=1)
|
|
# l2 sees that l1 has spent their coins!
|
|
l2.daemon.wait_for_log('Unknown spend of OUR_UNILATERAL/DELAYED_OUTPUT_TO_US by')
|
|
|
|
|
|
@unittest.skipIf(TEST_NETWORK != 'regtest', 'elementsd doesnt yet support PSBT features we need')
|
|
@pytest.mark.openchannel('v2')
|
|
@unittest.skipIf(os.getenv('TEST_DB_PROVIDER', 'sqlite3') != 'sqlite3', "Makes use of the sqlite3 db")
|
|
@pytest.mark.developer("requres 'dev-queryrates'")
|
|
def test_channel_lease_lessee_cheat(node_factory, bitcoind, chainparams):
|
|
'''
|
|
Check that lessor can recover funds if lessee cheats
|
|
'''
|
|
opts = [{'funder-policy': 'match', 'funder-policy-mod': 100,
|
|
'lease-fee-base-msat': '100sat', 'lease-fee-basis': 100,
|
|
'may_reconnect': True, 'allow_broken_log': True},
|
|
{'funder-policy': 'match', 'funder-policy-mod': 100,
|
|
'lease-fee-base-msat': '100sat', 'lease-fee-basis': 100,
|
|
'may_reconnect': True}]
|
|
l1, l2, = node_factory.get_nodes(2, opts=opts)
|
|
amount = 500000
|
|
feerate = 2000
|
|
l1.fundwallet(20000000)
|
|
l2.fundwallet(20000000)
|
|
|
|
l1.rpc.connect(l2.info['id'], 'localhost', l2.port)
|
|
rates = l1.rpc.dev_queryrates(l2.info['id'], amount, amount)
|
|
wait_for(lambda: len(l1.rpc.listpeers(l2.info['id'])['peers']) == 0)
|
|
l1.rpc.connect(l2.info['id'], 'localhost', l2.port)
|
|
# l1 leases a channel from l2
|
|
l1.rpc.fundchannel(l2.info['id'], amount, request_amt=amount,
|
|
feerate='{}perkw'.format(feerate),
|
|
compact_lease=rates['compact_lease'])
|
|
|
|
bitcoind.generate_block(6)
|
|
l1.daemon.wait_for_log('to CHANNELD_NORMAL')
|
|
wait_for(lambda: [c['active'] for c in l1.rpc.listchannels(l1.get_channel_scid(l2))['channels']] == [True, True])
|
|
wait_for(lambda: [c['active'] for c in l2.rpc.listchannels(l2.get_channel_scid(l1))['channels']] == [True, True])
|
|
# send some payments, mine a block or two
|
|
inv = l2.rpc.invoice(10**4, '1', 'no_1')
|
|
l1.rpc.pay(inv['bolt11'])
|
|
|
|
bitcoind.generate_block(1)
|
|
|
|
# make database snapshot of l1
|
|
l1.stop()
|
|
l1_db_path = os.path.join(l1.daemon.lightning_dir, chainparams['name'], 'lightningd.sqlite3')
|
|
l1_db_path_bak = os.path.join(l1.daemon.lightning_dir, chainparams['name'], 'lightningd.sqlite3.bak')
|
|
copyfile(l1_db_path, l1_db_path_bak)
|
|
l1.start()
|
|
l1.rpc.connect(l1.info['id'], 'localhost', l1.port)
|
|
sync_blockheight(bitcoind, [l1])
|
|
|
|
# push some money from l2->l1, so the commit counter advances
|
|
inv = l1.rpc.invoice(10**5, '2', 'no_2')
|
|
l2.rpc.pay(inv['bolt11'])
|
|
|
|
# stop both nodes, roll back l1's database
|
|
l1.stop()
|
|
l2.stop()
|
|
copyfile(l1_db_path_bak, l1_db_path)
|
|
|
|
# start l1 and force close channel with l2 while l2 is still offline
|
|
l1.start()
|
|
sync_blockheight(bitcoind, [l1])
|
|
l1.rpc.close(l2.info['id'], 1, force_lease_closed=True)
|
|
bitcoind.generate_block(1, wait_for_mempool=1)
|
|
|
|
l2.start()
|
|
sync_blockheight(bitcoind, [l2])
|
|
l2.daemon.wait_for_logs(['Broadcasting OUR_PENALTY_TX',
|
|
' Propose handling THEIR_REVOKED_UNILATERAL/DELAYED_CHEAT_OUTPUT_TO_THEM by OUR_PENALTY_TX'])
|
|
|
|
bitcoind.generate_block(1, wait_for_mempool=1)
|
|
# l2 sees that l1 has spent their coins!
|
|
l1.daemon.wait_for_logs(['Grinding for to_remote',
|
|
'Unknown spend of OUR_UNILATERAL/DELAYED_OUTPUT_TO_US by'])
|
|
|
|
|
|
@pytest.mark.developer("needs DEVELOPER=1")
|
|
@unittest.skipIf(os.getenv('TEST_DB_PROVIDER', 'sqlite3') != 'sqlite3', "Makes use of the sqlite3 db")
|
|
@pytest.mark.slow_test
|
|
def test_penalty_htlc_tx_fulfill(node_factory, bitcoind, chainparams):
|
|
""" Test that the penalizing node claims any published
|
|
HTLC transactions
|
|
|
|
Node topology:
|
|
l1 <-> l2 <-> l3 <-> l4
|
|
|
|
l4 pushes money to l1, who doesn't fulfill (freezing htlc across l2-l3)
|
|
we snapshot l2
|
|
l2 pushes money to l3 (updating state)
|
|
l2 + l3 go offline; l2 is backed up from snapshot
|
|
l1 fails the channel with l2, fulfilling the stranded htlc onchain
|
|
l2 comes back online, force closes channel with l3
|
|
|
|
block chain advances, l2 broadcasts their htlc fulfill tx
|
|
l3 comes back online, sees l2's cheat. takes funds from htlc fulfill tx.
|
|
some blocks are mined. the dust settles.
|
|
|
|
we check the accounting.
|
|
"""
|
|
|
|
# We track channel balances, to verify that accounting is ok.
|
|
coin_mvt_plugin = os.path.join(os.getcwd(), 'tests/plugins/coin_movements.py')
|
|
|
|
l1, l2, l3, l4 = node_factory.line_graph(4,
|
|
opts=[{'disconnect': ['-WIRE_UPDATE_FULFILL_HTLC'],
|
|
'may_reconnect': True,
|
|
'dev-no-reconnect': None},
|
|
{'plugin': coin_mvt_plugin,
|
|
'disable-mpp': None,
|
|
'dev-no-reconnect': None,
|
|
'may_reconnect': True,
|
|
'allow_broken_log': True},
|
|
{'plugin': coin_mvt_plugin,
|
|
'dev-no-reconnect': None,
|
|
'may_reconnect': True,
|
|
'allow_broken_log': True},
|
|
{'dev-no-reconnect': None,
|
|
'may_reconnect': True}],
|
|
wait_for_announce=True)
|
|
|
|
channel_id = first_channel_id(l2, l3)
|
|
|
|
# push some money so that 1 + 4 can both send htlcs
|
|
inv = l2.rpc.invoice(10**9 // 2, '1', 'balancer')
|
|
l1.rpc.pay(inv['bolt11'])
|
|
l1.rpc.waitsendpay(inv['payment_hash'])
|
|
|
|
inv = l4.rpc.invoice(10**9 // 2, '1', 'balancer')
|
|
l2.rpc.pay(inv['bolt11'])
|
|
l2.rpc.waitsendpay(inv['payment_hash'])
|
|
|
|
# now we send one 'sticky' htlc: l4->l1
|
|
amt = 10**8 // 2
|
|
sticky_inv = l1.rpc.invoice(amt, '2', 'sticky')
|
|
route = l4.rpc.getroute(l1.info['id'], amt, 1)['route']
|
|
l4.rpc.sendpay(route, sticky_inv['payment_hash'], payment_secret=sticky_inv['payment_secret'])
|
|
l1.daemon.wait_for_log('dev_disconnect: -WIRE_UPDATE_FULFILL_HTLC')
|
|
|
|
wait_for(lambda: len(l2.rpc.listpeers(l3.info['id'])['peers'][0]['channels'][0]['htlcs']) == 1)
|
|
|
|
# make database snapshot of l2
|
|
l2.stop()
|
|
l2_db_path = os.path.join(l2.daemon.lightning_dir, chainparams['name'], 'lightningd.sqlite3')
|
|
l2_db_path_bak = os.path.join(l2.daemon.lightning_dir, chainparams['name'], 'lightningd.sqlite3.bak')
|
|
copyfile(l2_db_path, l2_db_path_bak)
|
|
l2.start()
|
|
sync_blockheight(bitcoind, [l2])
|
|
|
|
# push some money from l3->l2, so that the commit counter advances
|
|
l2.rpc.connect(l3.info['id'], 'localhost', l3.port)
|
|
inv = l3.rpc.invoice(10**4, '1', 'push')
|
|
# Make sure gossipd in l2 knows it's active
|
|
wait_for(lambda: [c['active'] for c in l2.rpc.listchannels(l2.get_channel_scid(l3))['channels']] == [True, True])
|
|
l2.rpc.pay(inv['bolt11'])
|
|
|
|
# stop both nodes, roll back l2's database
|
|
l2.stop()
|
|
l3.stop()
|
|
copyfile(l2_db_path_bak, l2_db_path)
|
|
|
|
# start l2 and force close channel with l3 while l3 is still offline
|
|
l2.start()
|
|
sync_blockheight(bitcoind, [l2])
|
|
l2.rpc.close(l3.info['id'], 1)
|
|
l2.daemon.wait_for_log('sendrawtx exit 0')
|
|
|
|
# reconnect with l1, which will fulfill the payment
|
|
l2.rpc.connect(l1.info['id'], 'localhost', l1.port)
|
|
l2.daemon.wait_for_log('got commitsig .*: feerate 11000, blockheight: 0, 0 added, 1 fulfilled, 0 failed, 0 changed')
|
|
l2.daemon.wait_for_log('coins payment_hash: {}'.format(sticky_inv['payment_hash']))
|
|
|
|
# l2 moves on for closed l3
|
|
bitcoind.generate_block(1)
|
|
l2.daemon.wait_for_log('to ONCHAIN')
|
|
l2.daemon.wait_for_logs(['Propose handling OUR_UNILATERAL/DELAYED_OUTPUT_TO_US by OUR_DELAYED_RETURN_TO_WALLET .* after 5 blocks',
|
|
'Propose handling OUR_UNILATERAL/THEIR_HTLC by OUR_HTLC_SUCCESS_TX .* after 0 blocks'])
|
|
|
|
l2.wait_for_onchaind_broadcast('OUR_HTLC_SUCCESS_TX',
|
|
'OUR_UNILATERAL/THEIR_HTLC')
|
|
|
|
bitcoind.generate_block(1)
|
|
l2.daemon.wait_for_log('Propose handling OUR_HTLC_SUCCESS_TX/DELAYED_OUTPUT_TO_US by OUR_DELAYED_RETURN_TO_WALLET .* after 5 blocks')
|
|
|
|
# l3 comes back up, sees cheat, penalizes l2 (revokes the htlc they've offered;
|
|
# notes that they've successfully claimed to_local and the fulfilled htlc)
|
|
l3.start()
|
|
sync_blockheight(bitcoind, [l3])
|
|
l3.daemon.wait_for_logs(['Propose handling THEIR_REVOKED_UNILATERAL/OUR_HTLC by OUR_PENALTY_TX',
|
|
'Propose handling THEIR_REVOKED_UNILATERAL/DELAYED_CHEAT_OUTPUT_TO_THEM '
|
|
'by OUR_PENALTY_TX',
|
|
'Resolved THEIR_REVOKED_UNILATERAL/OUR_HTLC by OUR_HTLC_FULFILL_TO_THEM',
|
|
'Propose handling OUR_HTLC_FULFILL_TO_THEM/DELAYED_CHEAT_OUTPUT_TO_THEM'
|
|
' by OUR_PENALTY_TX'])
|
|
l3.wait_for_onchaind_broadcast('OUR_PENALTY_TX',
|
|
'OUR_HTLC_FULFILL_TO_THEM/DELAYED_CHEAT_OUTPUT_TO_THEM')
|
|
bitcoind.generate_block(1)
|
|
l3.daemon.wait_for_log('Resolved OUR_HTLC_FULFILL_TO_THEM/DELAYED_CHEAT_OUTPUT_TO_THEM '
|
|
'by our proposal OUR_PENALTY_TX')
|
|
l2.daemon.wait_for_log('Unknown spend of OUR_HTLC_SUCCESS_TX/DELAYED_OUTPUT_TO_US')
|
|
|
|
# 100 blocks later, l3+l2 are both done
|
|
bitcoind.generate_block(100)
|
|
l3.daemon.wait_for_log('{}.*: onchaind complete, forgetting peer'.format(l2.info['id']))
|
|
l2.daemon.wait_for_log('{}.*: onchaind complete, forgetting peer'.format(l3.info['id']))
|
|
|
|
assert account_balance(l3, channel_id) == 0
|
|
assert account_balance(l2, channel_id) == 0
|
|
|
|
|
|
@pytest.mark.developer("needs DEVELOPER=1")
|
|
@unittest.skipIf(os.getenv('TEST_DB_PROVIDER', 'sqlite3') != 'sqlite3', "Makes use of the sqlite3 db")
|
|
@pytest.mark.slow_test
|
|
def test_penalty_htlc_tx_timeout(node_factory, bitcoind, chainparams):
|
|
""" Test that the penalizing node claims any published
|
|
HTLC transactions
|
|
|
|
Node topology:
|
|
l1 <-> l2 <-> l3 <-> l4
|
|
^---> l5
|
|
|
|
l1 pushes money to l5, who doesn't fulfill (freezing htlc across l2-l3)
|
|
l4 pushes money to l1, who doesn't fulfill (freezing htlc across l2-l3)
|
|
we snapshot l2
|
|
l2 pushes money to l3 (updating state)
|
|
l2 + l3 go offline; l2 is backed up from snapshot
|
|
l1 fails the channel with l2, fulfilling the stranded htlc onchain
|
|
l2 comes back online, force closes channel with l3
|
|
|
|
block chain advances, l2 broadcasts the timeout htlc_tx + fulfill htlc_tx
|
|
both of which have a delay. l2 goes ahead and 'steals back' their
|
|
output + the htlc they fulfill
|
|
|
|
l3 comes back online, sees l2's cheat. takes funds from htlc timeout tx
|
|
some blocks are mined. the dust settles.
|
|
|
|
we check the accounting.
|
|
"""
|
|
|
|
# We track channel balances, to verify that accounting is ok.
|
|
coin_mvt_plugin = os.path.join(os.getcwd(), 'tests/plugins/coin_movements.py')
|
|
|
|
l1, l2, l3, l4, l5 = node_factory.get_nodes(
|
|
5,
|
|
opts=[
|
|
{
|
|
'disconnect': ['-WIRE_UPDATE_FULFILL_HTLC'],
|
|
'may_reconnect': True,
|
|
'dev-no-reconnect': None,
|
|
}, {
|
|
'plugin': coin_mvt_plugin,
|
|
'dev-no-reconnect': None,
|
|
'may_reconnect': True,
|
|
'allow_broken_log': True,
|
|
}, {
|
|
'plugin': coin_mvt_plugin,
|
|
'dev-no-reconnect': None,
|
|
'may_reconnect': True,
|
|
'allow_broken_log': True,
|
|
}, {
|
|
'dev-no-reconnect': None,
|
|
}, {
|
|
'disconnect': ['-WIRE_UPDATE_FULFILL_HTLC'],
|
|
'may_reconnect': True,
|
|
'dev-no-reconnect': None,
|
|
'allow_broken_log': True,
|
|
}
|
|
]
|
|
)
|
|
|
|
node_factory.join_nodes([l1, l2, l3, l4], wait_for_announce=True)
|
|
node_factory.join_nodes([l3, l5], wait_for_announce=True)
|
|
|
|
channel_id = first_channel_id(l2, l3)
|
|
|
|
# push some money so that 1 + 4 can both send htlcs
|
|
inv = l2.rpc.invoice(10**9 // 2, '1', 'balancer')
|
|
l1.rpc.pay(inv['bolt11'])
|
|
|
|
inv = l4.rpc.invoice(10**9 // 2, '1', 'balancer')
|
|
l2.rpc.pay(inv['bolt11'])
|
|
|
|
# now we send two 'sticky' htlcs, l1->l5 + l4->l1
|
|
amt = 10**8 // 2
|
|
sticky_inv_1 = l5.rpc.invoice(amt, '2', 'sticky')
|
|
route = l1.rpc.getroute(l5.info['id'], amt, 1)['route']
|
|
l1.rpc.sendpay(route, sticky_inv_1['payment_hash'], payment_secret=sticky_inv_1['payment_secret'])
|
|
l5.daemon.wait_for_log('dev_disconnect: -WIRE_UPDATE_FULFILL_HTLC')
|
|
|
|
sticky_inv_2 = l1.rpc.invoice(amt, '2', 'sticky')
|
|
route = l4.rpc.getroute(l1.info['id'], amt, 1)['route']
|
|
l4.rpc.sendpay(route, sticky_inv_2['payment_hash'], payment_secret=sticky_inv_2['payment_secret'])
|
|
l1.daemon.wait_for_log('dev_disconnect: -WIRE_UPDATE_FULFILL_HTLC')
|
|
|
|
wait_for(lambda: len(l2.rpc.listpeers(l3.info['id'])['peers'][0]['channels'][0]['htlcs']) == 2)
|
|
|
|
# make database snapshot of l2
|
|
l2.stop()
|
|
l2_db_path = os.path.join(l2.daemon.lightning_dir, chainparams['name'], 'lightningd.sqlite3')
|
|
l2_db_path_bak = os.path.join(l2.daemon.lightning_dir, chainparams['name'], 'lightningd.sqlite3.bak')
|
|
copyfile(l2_db_path, l2_db_path_bak)
|
|
l2.start()
|
|
sync_blockheight(bitcoind, [l2])
|
|
|
|
# push some money from l3->l2, so that the commit counter advances
|
|
l2.rpc.connect(l3.info['id'], 'localhost', l3.port)
|
|
|
|
inv = l3.rpc.invoice(10**4, '1', 'push')
|
|
# Make sure gossipd in l2 knows it's active
|
|
wait_for(lambda: [c['active'] for c in l2.rpc.listchannels(l2.get_channel_scid(l3))['channels']] == [True, True])
|
|
l2.rpc.pay(inv['bolt11'])
|
|
|
|
# stop both nodes, roll back l2's database
|
|
l2.stop()
|
|
l3.stop()
|
|
copyfile(l2_db_path_bak, l2_db_path)
|
|
|
|
# start l2, now back a bit. force close channel with l3 while l3 is still offline
|
|
l2.start()
|
|
sync_blockheight(bitcoind, [l2])
|
|
l2.rpc.close(l3.info['id'], 1)
|
|
l2.daemon.wait_for_log('sendrawtx exit 0')
|
|
|
|
# reconnect with l1, which will fulfill the payment
|
|
l2.rpc.connect(l1.info['id'], 'localhost', l1.port)
|
|
l2.daemon.wait_for_log('got commitsig .*: feerate 11000, blockheight: 0, 0 added, 1 fulfilled, 0 failed, 0 changed')
|
|
l2.daemon.wait_for_log('coins payment_hash: {}'.format(sticky_inv_2['payment_hash']))
|
|
|
|
# l2 moves on for closed l3
|
|
bitcoind.generate_block(1, wait_for_mempool=1)
|
|
l2.daemon.wait_for_log('to ONCHAIN')
|
|
l2.daemon.wait_for_logs(['Propose handling OUR_UNILATERAL/OUR_HTLC by OUR_HTLC_TIMEOUT_TX .* after 16 blocks',
|
|
'Propose handling OUR_UNILATERAL/DELAYED_OUTPUT_TO_US by OUR_DELAYED_RETURN_TO_WALLET .* after 5 blocks',
|
|
'Propose handling OUR_UNILATERAL/THEIR_HTLC by OUR_HTLC_SUCCESS_TX .* after 0 blocks'])
|
|
|
|
l2.wait_for_onchaind_broadcast('OUR_HTLC_SUCCESS_TX',
|
|
'OUR_UNILATERAL/THEIR_HTLC')
|
|
|
|
bitcoind.generate_block(1, wait_for_mempool=1)
|
|
l2.daemon.wait_for_log('Propose handling OUR_HTLC_SUCCESS_TX/DELAYED_OUTPUT_TO_US by OUR_DELAYED_RETURN_TO_WALLET .* after 5 blocks')
|
|
|
|
# after 5 blocks, l2 reclaims both their DELAYED_OUTPUT_TO_US and their delayed output
|
|
bitcoind.generate_block(5, wait_for_mempool=0)
|
|
sync_blockheight(bitcoind, [l2])
|
|
l2.daemon.wait_for_logs(['Broadcasting OUR_DELAYED_RETURN_TO_WALLET .* to resolve OUR_HTLC_SUCCESS_TX/DELAYED_OUTPUT_TO_US',
|
|
'Broadcasting OUR_DELAYED_RETURN_TO_WALLET .* to resolve OUR_UNILATERAL/DELAYED_OUTPUT_TO_US'])
|
|
|
|
bitcoind.generate_block(10, wait_for_mempool=2)
|
|
l2.wait_for_onchaind_broadcast('OUR_HTLC_TIMEOUT_TX',
|
|
'OUR_UNILATERAL/OUR_HTLC')
|
|
|
|
bitcoind.generate_block(1, wait_for_mempool=1)
|
|
l2.daemon.wait_for_log('Propose handling OUR_HTLC_TIMEOUT_TX/DELAYED_OUTPUT_TO_US by OUR_DELAYED_RETURN_TO_WALLET .* after 5 blocks')
|
|
|
|
# l3 comes back up, sees cheat, penalizes l2 (revokes the htlc they've offered;
|
|
# notes that they've successfully claimed to_local and the fulfilled htlc)
|
|
l3.start()
|
|
sync_blockheight(bitcoind, [l3])
|
|
l3.daemon.wait_for_logs(['Propose handling THEIR_REVOKED_UNILATERAL/OUR_HTLC by OUR_PENALTY_TX',
|
|
'Propose handling THEIR_REVOKED_UNILATERAL/THEIR_HTLC by OUR_PENALTY_TX',
|
|
'Propose handling THEIR_REVOKED_UNILATERAL/DELAYED_CHEAT_OUTPUT_TO_THEM '
|
|
'by OUR_PENALTY_TX',
|
|
'Resolved THEIR_REVOKED_UNILATERAL/OUR_HTLC by OUR_HTLC_FULFILL_TO_THEM',
|
|
'Propose handling OUR_HTLC_FULFILL_TO_THEM/DELAYED_CHEAT_OUTPUT_TO_THEM'
|
|
' by OUR_PENALTY_TX',
|
|
'Resolved OUR_HTLC_FULFILL_TO_THEM/DELAYED_CHEAT_OUTPUT_TO_THEM '
|
|
'by THEIR_DELAYED_CHEAT',
|
|
'Resolved THEIR_REVOKED_UNILATERAL/DELAYED_CHEAT_OUTPUT_TO_THEM '
|
|
'by THEIR_DELAYED_CHEAT',
|
|
'Resolved THEIR_REVOKED_UNILATERAL/THEIR_HTLC by THEIR_HTLC_TIMEOUT_TO_THEM',
|
|
'Propose handling THEIR_HTLC_TIMEOUT_TO_THEM/DELAYED_CHEAT_OUTPUT_TO_THEM by OUR_PENALTY_TX'])
|
|
|
|
# Make sure we've broadcast the tx we expect (other channels shutting down can create
|
|
# unrelated txs!)
|
|
|
|
# In theory this could have occurred before all the previous loglines appeared.
|
|
l3.daemon.logsearch_start = 0
|
|
line = l3.daemon.wait_for_log(r'Broadcasting OUR_PENALTY_TX \([0-9a-f]*\) to resolve THEIR_HTLC_TIMEOUT_TO_THEM/DELAYED_CHEAT_OUTPUT_TO_THEM')
|
|
tx = re.search(r'\(([0-9a-f]*)\)', line).group(1)
|
|
txid = bitcoind.rpc.decoderawtransaction(tx)['txid']
|
|
bitcoind.generate_block(1, wait_for_mempool=[txid])
|
|
l3.daemon.wait_for_log('Resolved THEIR_HTLC_TIMEOUT_TO_THEM/DELAYED_CHEAT_OUTPUT_TO_THEM '
|
|
'by our proposal OUR_PENALTY_TX')
|
|
l2.daemon.wait_for_log('Unknown spend of OUR_HTLC_TIMEOUT_TX/DELAYED_OUTPUT_TO_US')
|
|
|
|
# 100 blocks later, l3+l2 are both done
|
|
bitcoind.generate_block(100)
|
|
l3.daemon.wait_for_log('{}.*: onchaind complete, forgetting peer'.format(l2.info['id']))
|
|
l2.daemon.wait_for_log('{}.*: onchaind complete, forgetting peer'.format(l3.info['id']))
|
|
|
|
assert account_balance(l3, channel_id) == 0
|
|
assert account_balance(l2, channel_id) == 0
|
|
|
|
|
|
@pytest.mark.developer("uses dev_sign_last_tx")
|
|
def test_penalty_rbf_normal(node_factory, bitcoind, executor, chainparams):
|
|
'''
|
|
Test that penalty transactions are RBFed.
|
|
'''
|
|
to_self_delay = 10
|
|
# l1 is the thief, which causes our honest upstanding lightningd
|
|
# code to break, so l1 can fail.
|
|
# Initially, disconnect before the HTLC can be resolved.
|
|
l1 = node_factory.get_node(disconnect=['=WIRE_COMMITMENT_SIGNED-nocommit'],
|
|
may_fail=True, allow_broken_log=True)
|
|
l2 = node_factory.get_node(disconnect=['=WIRE_COMMITMENT_SIGNED-nocommit'],
|
|
options={'watchtime-blocks': to_self_delay})
|
|
|
|
l1.rpc.connect(l2.info['id'], 'localhost', l2.port)
|
|
l1.fundchannel(l2, 10**7)
|
|
|
|
# Trigger an HTLC being added.
|
|
t = executor.submit(l1.pay, l2, 1000000 * 1000)
|
|
|
|
# Make sure the channel is still alive.
|
|
assert len(l1.getactivechannels()) == 2
|
|
assert len(l2.getactivechannels()) == 2
|
|
|
|
# Wait for the disconnection.
|
|
l1.daemon.wait_for_log('=WIRE_COMMITMENT_SIGNED-nocommit')
|
|
l2.daemon.wait_for_log('=WIRE_COMMITMENT_SIGNED-nocommit')
|
|
# Make sure l1 gets the new HTLC.
|
|
l1.daemon.wait_for_log('got commitsig')
|
|
|
|
# l1 prepares a theft commitment transaction
|
|
theft_tx = l1.rpc.dev_sign_last_tx(l2.info['id'])['tx']
|
|
|
|
# Now continue processing until fulfilment.
|
|
l1.rpc.dev_reenable_commit(l2.info['id'])
|
|
l2.rpc.dev_reenable_commit(l1.info['id'])
|
|
|
|
# Wait for the fulfilment.
|
|
l1.daemon.wait_for_log('peer_in WIRE_UPDATE_FULFILL_HTLC')
|
|
l1.daemon.wait_for_log('peer_out WIRE_REVOKE_AND_ACK')
|
|
l2.daemon.wait_for_log('peer_out WIRE_UPDATE_FULFILL_HTLC')
|
|
l1.daemon.wait_for_log('peer_in WIRE_REVOKE_AND_ACK')
|
|
|
|
# Now payment should complete.
|
|
t.result(timeout=10)
|
|
|
|
# l1 goes offline and bribes the miners to censor transactions from l2.
|
|
l1.rpc.stop()
|
|
|
|
def censoring_sendrawtx(r):
|
|
return {'id': r['id'], 'result': {}}
|
|
|
|
l2.daemon.rpcproxy.mock_rpc('sendrawtransaction', censoring_sendrawtx)
|
|
|
|
# l1 now performs the theft attack!
|
|
bitcoind.rpc.sendrawtransaction(theft_tx)
|
|
bitcoind.generate_block(1)
|
|
|
|
# l2 notices.
|
|
l2.daemon.wait_for_log(' to ONCHAIN')
|
|
|
|
def get_rbf_tx(self, depth, name, resolve):
|
|
r = self.daemon.wait_for_log('Broadcasting RBF {} .* to resolve {} depth={}'
|
|
.format(name, resolve, depth))
|
|
return re.search(r'.* \(([0-9a-fA-F]*)\)', r).group(1)
|
|
|
|
rbf_txes = []
|
|
# Now the censoring miners generate some blocks.
|
|
for depth in range(2, 8):
|
|
bitcoind.generate_block(1)
|
|
sync_blockheight(bitcoind, [l2])
|
|
# l2 should RBF, twice even, one for the l1 main output,
|
|
# one for the l1 HTLC output.
|
|
rbf_txes.append(get_rbf_tx(l2, depth,
|
|
'OUR_PENALTY_TX',
|
|
'THEIR_REVOKED_UNILATERAL/THEIR_HTLC'))
|
|
rbf_txes.append(get_rbf_tx(l2, depth,
|
|
'OUR_PENALTY_TX',
|
|
'THEIR_REVOKED_UNILATERAL/DELAYED_CHEAT_OUTPUT_TO_THEM'))
|
|
|
|
# Now that the transactions have high fees, independent miners
|
|
# realize they can earn potentially more money by grabbing the
|
|
# high-fee censored transactions, and fresh, non-censoring
|
|
# hashpower arises, evicting the censor.
|
|
l2.daemon.rpcproxy.mock_rpc('sendrawtransaction', None)
|
|
|
|
# Check that the order in which l2 generated RBF transactions
|
|
# would be acceptable to Bitcoin.
|
|
for tx in rbf_txes:
|
|
# Use the bcli interface as well, so that we also check the
|
|
# bcli interface.
|
|
l2.rpc.call('sendrawtransaction', [tx, True])
|
|
|
|
# Now the non-censoring miners overpower the censoring miners.
|
|
bitcoind.generate_block(1)
|
|
sync_blockheight(bitcoind, [l2])
|
|
|
|
# And l2 should consider it resolved now.
|
|
l2.daemon.wait_for_log('Resolved THEIR_REVOKED_UNILATERAL/DELAYED_CHEAT_OUTPUT_TO_THEM by our proposal OUR_PENALTY_TX')
|
|
l2.daemon.wait_for_log('Resolved THEIR_REVOKED_UNILATERAL/THEIR_HTLC by our proposal OUR_PENALTY_TX')
|
|
|
|
# And l2 should consider it in its listfunds.
|
|
assert(len(l2.rpc.listfunds()['outputs']) >= 1)
|
|
|
|
|
|
@pytest.mark.developer("uses dev_sign_last_tx")
|
|
def test_penalty_rbf_burn(node_factory, bitcoind, executor, chainparams):
|
|
'''
|
|
Test that penalty transactions are RBFed and we are willing to burn
|
|
it all up to spite the thief.
|
|
'''
|
|
to_self_delay = 10
|
|
# l1 is the thief, which causes our honest upstanding lightningd
|
|
# code to break, so l1 can fail.
|
|
# Initially, disconnect before the HTLC can be resolved.
|
|
l1 = node_factory.get_node(disconnect=['=WIRE_COMMITMENT_SIGNED-nocommit'],
|
|
may_fail=True, allow_broken_log=True)
|
|
l2 = node_factory.get_node(disconnect=['=WIRE_COMMITMENT_SIGNED-nocommit'],
|
|
options={'watchtime-blocks': to_self_delay})
|
|
|
|
l1.rpc.connect(l2.info['id'], 'localhost', l2.port)
|
|
l1.fundchannel(l2, 10**7)
|
|
|
|
# Trigger an HTLC being added.
|
|
t = executor.submit(l1.pay, l2, 1000000 * 1000)
|
|
|
|
# Make sure the channel is still alive.
|
|
assert len(l1.getactivechannels()) == 2
|
|
assert len(l2.getactivechannels()) == 2
|
|
|
|
# Wait for the disconnection.
|
|
l1.daemon.wait_for_log('=WIRE_COMMITMENT_SIGNED-nocommit')
|
|
l2.daemon.wait_for_log('=WIRE_COMMITMENT_SIGNED-nocommit')
|
|
# Make sure l1 gets the new HTLC.
|
|
l1.daemon.wait_for_log('got commitsig')
|
|
|
|
# l1 prepares a theft commitment transaction
|
|
theft_tx = l1.rpc.dev_sign_last_tx(l2.info['id'])['tx']
|
|
|
|
# Now continue processing until fulfilment.
|
|
l1.rpc.dev_reenable_commit(l2.info['id'])
|
|
l2.rpc.dev_reenable_commit(l1.info['id'])
|
|
|
|
# Wait for the fulfilment.
|
|
l1.daemon.wait_for_log('peer_in WIRE_UPDATE_FULFILL_HTLC')
|
|
l1.daemon.wait_for_log('peer_out WIRE_REVOKE_AND_ACK')
|
|
l2.daemon.wait_for_log('peer_out WIRE_UPDATE_FULFILL_HTLC')
|
|
l1.daemon.wait_for_log('peer_in WIRE_REVOKE_AND_ACK')
|
|
|
|
# Now payment should complete.
|
|
t.result(timeout=10)
|
|
|
|
# l1 goes offline and bribes the miners to censor transactions from l2.
|
|
l1.rpc.stop()
|
|
|
|
def censoring_sendrawtx(r):
|
|
return {'id': r['id'], 'result': {}}
|
|
|
|
l2.daemon.rpcproxy.mock_rpc('sendrawtransaction', censoring_sendrawtx)
|
|
|
|
# l1 now performs the theft attack!
|
|
bitcoind.rpc.sendrawtransaction(theft_tx)
|
|
bitcoind.generate_block(1)
|
|
|
|
# l2 notices.
|
|
l2.daemon.wait_for_log(' to ONCHAIN')
|
|
|
|
def get_rbf_tx(self, depth, name, resolve):
|
|
r = self.daemon.wait_for_log('Broadcasting RBF {} .* to resolve {} depth={}'
|
|
.format(name, resolve, depth))
|
|
return re.search(r'.* \(([0-9a-fA-F]*)\)', r).group(1)
|
|
|
|
rbf_txes = []
|
|
# Now the censoring miners generate some blocks.
|
|
for depth in range(2, 10):
|
|
bitcoind.generate_block(1)
|
|
sync_blockheight(bitcoind, [l2])
|
|
# l2 should RBF, twice even, one for the l1 main output,
|
|
# one for the l1 HTLC output.
|
|
rbf_txes.append(get_rbf_tx(l2, depth,
|
|
'OUR_PENALTY_TX',
|
|
'THEIR_REVOKED_UNILATERAL/THEIR_HTLC'))
|
|
rbf_txes.append(get_rbf_tx(l2, depth,
|
|
'OUR_PENALTY_TX',
|
|
'THEIR_REVOKED_UNILATERAL/DELAYED_CHEAT_OUTPUT_TO_THEM'))
|
|
|
|
# Now that the transactions have high fees, independent miners
|
|
# realize they can earn potentially more money by grabbing the
|
|
# high-fee censored transactions, and fresh, non-censoring
|
|
# hashpower arises, evicting the censor.
|
|
l2.daemon.rpcproxy.mock_rpc('sendrawtransaction', None)
|
|
|
|
# Check that the last two txes can be broadcast.
|
|
# These should donate the total amount to miners.
|
|
rbf_txes = rbf_txes[-2:]
|
|
for tx in rbf_txes:
|
|
l2.rpc.call('sendrawtransaction', [tx, True])
|
|
|
|
# Now the non-censoring miners overpower the censoring miners.
|
|
bitcoind.generate_block(1)
|
|
sync_blockheight(bitcoind, [l2])
|
|
|
|
# And l2 should consider it resolved now.
|
|
l2.daemon.wait_for_log('Resolved THEIR_REVOKED_UNILATERAL/DELAYED_CHEAT_OUTPUT_TO_THEM by our proposal OUR_PENALTY_TX')
|
|
l2.daemon.wait_for_log('Resolved THEIR_REVOKED_UNILATERAL/THEIR_HTLC by our proposal OUR_PENALTY_TX')
|
|
|
|
# l2 donated it to the miners, so it owns nothing
|
|
assert(len(l2.rpc.listfunds()['outputs']) == 0)
|
|
|
|
|
|
@pytest.mark.developer("needs DEVELOPER=1")
|
|
def test_onchain_first_commit(node_factory, bitcoind):
|
|
"""Onchain handling where opener immediately drops to chain"""
|
|
|
|
# We track channel balances, to verify that accounting is ok.
|
|
coin_mvt_plugin = os.path.join(os.getcwd(), 'tests/plugins/coin_movements.py')
|
|
|
|
# HTLC 1->2, 1 fails just after funding.
|
|
disconnects = ['+WIRE_FUNDING_LOCKED', 'permfail']
|
|
# Make locktime different, as we once had them reversed!
|
|
l1, l2 = node_factory.line_graph(2, opts=[{'disconnect': disconnects,
|
|
'plugin': coin_mvt_plugin},
|
|
{'watchtime-blocks': 10,
|
|
'plugin': coin_mvt_plugin}],
|
|
fundchannel=False)
|
|
l1.fundwallet(10**7)
|
|
l1.rpc.fundchannel(l2.info['id'], 10**6)
|
|
l1.daemon.wait_for_log('sendrawtx exit 0')
|
|
|
|
bitcoind.generate_block(1)
|
|
|
|
# l1 will drop to chain.
|
|
l1.daemon.wait_for_log('permfail')
|
|
l1.daemon.wait_for_log('sendrawtx exit 0')
|
|
bitcoind.generate_block(1)
|
|
l1.daemon.wait_for_log(' to ONCHAIN')
|
|
l2.daemon.wait_for_log(' to ONCHAIN')
|
|
|
|
# 10 later, l1 should collect its to-self payment.
|
|
bitcoind.generate_block(10)
|
|
l1.wait_for_onchaind_broadcast('OUR_DELAYED_RETURN_TO_WALLET',
|
|
'OUR_UNILATERAL/DELAYED_OUTPUT_TO_US')
|
|
|
|
# 94 later, l2 is done.
|
|
bitcoind.generate_block(94)
|
|
l2.daemon.wait_for_log('onchaind complete, forgetting peer')
|
|
|
|
# Now, 100 blocks and l1 should be done.
|
|
bitcoind.generate_block(6)
|
|
l1.daemon.wait_for_log('onchaind complete, forgetting peer')
|
|
|
|
|
|
@pytest.mark.developer("needs DEVELOPER=1")
|
|
def test_onchain_unwatch(node_factory, bitcoind):
|
|
"""Onchaind should not watch random spends"""
|
|
# We track channel balances, to verify that accounting is ok.
|
|
coin_mvt_plugin = os.path.join(os.getcwd(), 'tests/plugins/coin_movements.py')
|
|
l1, l2 = node_factory.line_graph(2, opts={'plugin': coin_mvt_plugin})
|
|
channel_id = first_channel_id(l1, l2)
|
|
|
|
l1.pay(l2, 200000000)
|
|
|
|
l1.rpc.dev_fail(l2.info['id'])
|
|
l1.daemon.wait_for_log('Failing due to dev-fail command')
|
|
l1.wait_for_channel_onchain(l2.info['id'])
|
|
|
|
l1.bitcoin.generate_block(1)
|
|
l1.daemon.wait_for_log(' to ONCHAIN')
|
|
l2.daemon.wait_for_log(' to ONCHAIN')
|
|
|
|
# 10 later, l1 should collect its to-self payment.
|
|
bitcoind.generate_block(10)
|
|
l1.wait_for_onchaind_broadcast('OUR_DELAYED_RETURN_TO_WALLET',
|
|
'OUR_UNILATERAL/DELAYED_OUTPUT_TO_US')
|
|
|
|
# First time it sees it, onchaind cares.
|
|
bitcoind.generate_block(1)
|
|
l1.daemon.wait_for_log('Resolved OUR_UNILATERAL/DELAYED_OUTPUT_TO_US by our proposal '
|
|
'OUR_DELAYED_RETURN_TO_WALLET')
|
|
|
|
# Now test unrelated onchain churn.
|
|
# Daemon gets told about wallet; says it doesn't care.
|
|
l1.rpc.withdraw(l1.rpc.newaddr()['bech32'], 'all')
|
|
bitcoind.generate_block(1)
|
|
l1.daemon.wait_for_log("but we don't care")
|
|
|
|
# And lightningd should respect that!
|
|
assert not l1.daemon.is_in_log("Can't unwatch txid")
|
|
|
|
# So these should not generate further messages
|
|
for i in range(5):
|
|
l1.rpc.withdraw(l1.rpc.newaddr()['bech32'], 'all')
|
|
bitcoind.generate_block(1)
|
|
# Make sure it digests the block
|
|
sync_blockheight(bitcoind, [l1])
|
|
|
|
# We won't see this again.
|
|
assert not l1.daemon.is_in_log("but we don't care",
|
|
start=l1.daemon.logsearch_start)
|
|
|
|
assert account_balance(l1, channel_id) == 0
|
|
assert account_balance(l2, channel_id) == 0
|
|
# Note: for this test we leave onchaind running, so we can detect
|
|
# any leaks!
|
|
|
|
|
|
@pytest.mark.developer("needs DEVELOPER=1")
|
|
def test_onchaind_replay(node_factory, bitcoind):
|
|
disconnects = ['+WIRE_REVOKE_AND_ACK', 'permfail']
|
|
# Feerates identical so we don't get gratuitous commit to update them
|
|
l1, l2 = node_factory.line_graph(2, opts=[{'watchtime-blocks': 201, 'cltv-delta': 101,
|
|
'disconnect': disconnects,
|
|
'feerates': (7500, 7500, 7500, 7500)},
|
|
{'watchtime-blocks': 201, 'cltv-delta': 101}])
|
|
|
|
inv = l2.rpc.invoice(10**8, 'onchaind_replay', 'desc')
|
|
rhash = inv['payment_hash']
|
|
routestep = {
|
|
'msatoshi': 10**8 - 1,
|
|
'id': l2.info['id'],
|
|
'delay': 101,
|
|
'channel': '1x1x1'
|
|
}
|
|
l1.rpc.sendpay([routestep], rhash, payment_secret=inv['payment_secret'])
|
|
l1.daemon.wait_for_log('sendrawtx exit 0')
|
|
bitcoind.generate_block(1, wait_for_mempool=1)
|
|
|
|
# Wait for nodes to notice the failure, this seach needle is after the
|
|
# DB commit so we're sure the tx entries in onchaindtxs have been added
|
|
l1.daemon.wait_for_log("Deleting channel .* due to the funding outpoint being spent")
|
|
l2.daemon.wait_for_log("Deleting channel .* due to the funding outpoint being spent")
|
|
|
|
# We should at least have the init tx now
|
|
assert len(l1.db_query("SELECT * FROM channeltxs;")) > 0
|
|
assert len(l2.db_query("SELECT * FROM channeltxs;")) > 0
|
|
|
|
# Generate some blocks so we restart the onchaind from DB (we rescan
|
|
# last_height - 100)
|
|
bitcoind.generate_block(100)
|
|
sync_blockheight(bitcoind, [l1, l2])
|
|
|
|
# l1 should still have a running onchaind
|
|
assert len(l1.db_query("SELECT * FROM channeltxs;")) > 0
|
|
|
|
l2.rpc.stop()
|
|
l1.restart()
|
|
|
|
# Can't wait for it, it's after the "Server started" wait in restart()
|
|
assert l1.daemon.is_in_log(r'Restarting onchaind for channel')
|
|
|
|
# l1 should still notice that the funding was spent and that we should react to it
|
|
l1.daemon.wait_for_log("Propose handling OUR_UNILATERAL/DELAYED_OUTPUT_TO_US by OUR_DELAYED_RETURN_TO_WALLET")
|
|
sync_blockheight(bitcoind, [l1])
|
|
bitcoind.generate_block(10)
|
|
sync_blockheight(bitcoind, [l1])
|
|
|
|
|
|
@pytest.mark.developer("needs DEVELOPER=1")
|
|
def test_onchain_dust_out(node_factory, bitcoind, executor):
|
|
"""Onchain handling of outgoing dust htlcs (they should fail)"""
|
|
# We track channel balances, to verify that accounting is ok.
|
|
coin_mvt_plugin = os.path.join(os.getcwd(), 'tests/plugins/coin_movements.py')
|
|
|
|
# HTLC 1->2, 1 fails after it's irrevocably committed
|
|
disconnects = ['@WIRE_REVOKE_AND_ACK', 'permfail']
|
|
# Feerates identical so we don't get gratuitous commit to update them
|
|
l1, l2 = node_factory.line_graph(2,
|
|
opts=[{'disconnect': disconnects,
|
|
'feerates': (7500, 7500, 7500, 7500),
|
|
'plugin': coin_mvt_plugin},
|
|
{'plugin': coin_mvt_plugin}])
|
|
|
|
channel_id = first_channel_id(l1, l2)
|
|
|
|
# Must be dust!
|
|
inv = l2.rpc.invoice(1, 'onchain_dust_out', 'desc')
|
|
rhash = inv['payment_hash']
|
|
routestep = {
|
|
'msatoshi': 1,
|
|
'id': l2.info['id'],
|
|
'delay': 5,
|
|
'channel': '1x1x1'
|
|
}
|
|
|
|
l1.rpc.sendpay([routestep], rhash, payment_secret=inv['payment_secret'])
|
|
payfuture = executor.submit(l1.rpc.waitsendpay, rhash)
|
|
|
|
# l1 will drop to chain.
|
|
l1.daemon.wait_for_log('permfail')
|
|
l1.wait_for_channel_onchain(l2.info['id'])
|
|
l1.bitcoin.generate_block(1)
|
|
l1.daemon.wait_for_log(' to ONCHAIN')
|
|
l2.daemon.wait_for_log(' to ONCHAIN')
|
|
|
|
# We use 3 blocks for "reasonable depth"
|
|
bitcoind.generate_block(3)
|
|
|
|
# It should fail.
|
|
with pytest.raises(RpcError, match=r'WIRE_PERMANENT_CHANNEL_FAILURE: missing in commitment tx'):
|
|
payfuture.result(5)
|
|
|
|
# Retry payment, this should fail (and, as a side-effect, tickle a
|
|
# bug).
|
|
with pytest.raises(RpcError, match=r'WIRE_UNKNOWN_NEXT_PEER'):
|
|
l1.rpc.sendpay([routestep], rhash, payment_secret=inv['payment_secret'])
|
|
|
|
# 6 later, l1 should collect its to-self payment.
|
|
bitcoind.generate_block(6)
|
|
l1.wait_for_onchaind_broadcast('OUR_DELAYED_RETURN_TO_WALLET',
|
|
'OUR_UNILATERAL/DELAYED_OUTPUT_TO_US')
|
|
|
|
# 94 later, l2 is done.
|
|
bitcoind.generate_block(94)
|
|
l2.daemon.wait_for_log('onchaind complete, forgetting peer')
|
|
|
|
# Restart l1, it should not crash!
|
|
l1.restart()
|
|
|
|
# Now, 100 blocks and l1 should be done.
|
|
bitcoind.generate_block(6)
|
|
l1.daemon.wait_for_log('onchaind complete, forgetting peer')
|
|
|
|
# Payment failed, BTW
|
|
assert only_one(l2.rpc.listinvoices('onchain_dust_out')['invoices'])['status'] == 'unpaid'
|
|
|
|
assert account_balance(l1, channel_id) == 0
|
|
assert account_balance(l2, channel_id) == 0
|
|
|
|
|
|
@pytest.mark.developer("needs DEVELOPER=1")
|
|
def test_onchain_timeout(node_factory, bitcoind, executor):
|
|
"""Onchain handling of outgoing failed htlcs"""
|
|
# We track channel balances, to verify that accounting is ok.
|
|
coin_mvt_plugin = os.path.join(os.getcwd(), 'tests/plugins/coin_movements.py')
|
|
|
|
# HTLC 1->2, 1 fails just after it's irrevocably committed
|
|
disconnects = ['+WIRE_REVOKE_AND_ACK*3', 'permfail']
|
|
# Feerates identical so we don't get gratuitous commit to update them
|
|
l1, l2 = node_factory.line_graph(2,
|
|
opts=[{'disconnect': disconnects,
|
|
'feerates': (7500, 7500, 7500, 7500),
|
|
'plugin': coin_mvt_plugin},
|
|
{'plugin': coin_mvt_plugin}])
|
|
|
|
channel_id = first_channel_id(l1, l2)
|
|
|
|
inv = l2.rpc.invoice(10**8, 'onchain_timeout', 'desc')
|
|
rhash = inv['payment_hash']
|
|
# We underpay, so it fails.
|
|
routestep = {
|
|
'msatoshi': 10**8 - 1,
|
|
'id': l2.info['id'],
|
|
'delay': 5,
|
|
'channel': '1x1x1'
|
|
}
|
|
|
|
l1.rpc.sendpay([routestep], rhash, payment_secret=inv['payment_secret'])
|
|
with pytest.raises(RpcError):
|
|
l1.rpc.waitsendpay(rhash)
|
|
|
|
# Make sure CLTVs are different, in case it confuses onchaind.
|
|
bitcoind.generate_block(1)
|
|
sync_blockheight(bitcoind, [l1])
|
|
|
|
# Second one will cause drop to chain.
|
|
l1.rpc.sendpay([routestep], rhash, payment_secret=inv['payment_secret'])
|
|
payfuture = executor.submit(l1.rpc.waitsendpay, rhash)
|
|
|
|
# l1 will drop to chain.
|
|
l1.daemon.wait_for_log('permfail')
|
|
l1.wait_for_channel_onchain(l2.info['id'])
|
|
l1.bitcoin.generate_block(1)
|
|
l1.daemon.wait_for_log(' to ONCHAIN')
|
|
l2.daemon.wait_for_log(' to ONCHAIN')
|
|
|
|
# Wait for timeout.
|
|
l1.daemon.wait_for_logs(['Propose handling OUR_UNILATERAL/DELAYED_OUTPUT_TO_US by OUR_DELAYED_RETURN_TO_WALLET .* after 5 blocks',
|
|
'Propose handling OUR_UNILATERAL/OUR_HTLC by OUR_HTLC_TIMEOUT_TX .* after 6 blocks'])
|
|
bitcoind.generate_block(4)
|
|
|
|
l1.wait_for_onchaind_broadcast('OUR_DELAYED_RETURN_TO_WALLET',
|
|
'OUR_UNILATERAL/DELAYED_OUTPUT_TO_US')
|
|
|
|
bitcoind.generate_block(1)
|
|
l1.wait_for_onchaind_broadcast('OUR_HTLC_TIMEOUT_TX',
|
|
'OUR_UNILATERAL/OUR_HTLC')
|
|
|
|
# We use 3 blocks for "reasonable depth"
|
|
bitcoind.generate_block(3)
|
|
|
|
# It should fail.
|
|
with pytest.raises(RpcError, match=r'WIRE_PERMANENT_CHANNEL_FAILURE: timed out'):
|
|
payfuture.result(TIMEOUT)
|
|
|
|
# 2 later, l1 spends HTLC (5 blocks total).
|
|
bitcoind.generate_block(2)
|
|
l1.wait_for_onchaind_broadcast('OUR_DELAYED_RETURN_TO_WALLET',
|
|
'OUR_HTLC_TIMEOUT_TX/DELAYED_OUTPUT_TO_US')
|
|
|
|
# 89 later, l2 is done.
|
|
bitcoind.generate_block(89)
|
|
l2.daemon.wait_for_log('onchaind complete, forgetting peer')
|
|
|
|
# Now, 100 blocks and l1 should be done.
|
|
bitcoind.generate_block(10)
|
|
sync_blockheight(bitcoind, [l1])
|
|
assert not l1.daemon.is_in_log('onchaind complete, forgetting peer')
|
|
bitcoind.generate_block(1)
|
|
l1.daemon.wait_for_log('onchaind complete, forgetting peer')
|
|
|
|
# Payment failed, BTW
|
|
assert only_one(l2.rpc.listinvoices('onchain_timeout')['invoices'])['status'] == 'unpaid'
|
|
assert account_balance(l1, channel_id) == 0
|
|
assert account_balance(l2, channel_id) == 0
|
|
|
|
|
|
@pytest.mark.developer("needs DEVELOPER=1")
|
|
def test_onchain_middleman(node_factory, bitcoind):
|
|
# We track channel balances, to verify that accounting is ok.
|
|
coin_mvt_plugin = os.path.join(os.getcwd(), 'tests/plugins/coin_movements.py')
|
|
|
|
# HTLC 1->2->3, 1->2 goes down after 2 gets preimage from 3.
|
|
disconnects = ['-WIRE_UPDATE_FULFILL_HTLC', 'permfail']
|
|
l1, l2, l3 = node_factory.get_nodes(3, opts=[{'plugin': coin_mvt_plugin},
|
|
{'plugin': coin_mvt_plugin,
|
|
'disconnect': disconnects},
|
|
{}])
|
|
|
|
# l2 connects to both, so l1 can't reconnect and thus l2 drops to chain
|
|
l2.rpc.connect(l1.info['id'], 'localhost', l1.port)
|
|
l2.rpc.connect(l3.info['id'], 'localhost', l3.port)
|
|
l2.fundchannel(l1, 10**6)
|
|
c23, _ = l2.fundchannel(l3, 10**6)
|
|
channel_id = first_channel_id(l1, l2)
|
|
|
|
# Make sure routes finalized.
|
|
bitcoind.generate_block(5)
|
|
l1.wait_channel_active(c23)
|
|
|
|
# Give l1 some money to play with.
|
|
l2.pay(l1, 2 * 10**8)
|
|
|
|
# Must be bigger than dust!
|
|
inv = l3.rpc.invoice(10**8, 'middleman', 'desc')
|
|
rhash = inv['payment_hash']
|
|
|
|
route = l1.rpc.getroute(l3.info['id'], 10**8, 1)["route"]
|
|
assert len(route) == 2
|
|
|
|
q = queue.Queue()
|
|
|
|
def try_pay():
|
|
try:
|
|
l1.rpc.sendpay(route, rhash, payment_secret=inv['payment_secret'])
|
|
l1.rpc.waitsendpay(rhash)
|
|
q.put(None)
|
|
except Exception as err:
|
|
q.put(err)
|
|
|
|
t = threading.Thread(target=try_pay)
|
|
t.daemon = True
|
|
t.start()
|
|
|
|
# l2 will drop to chain.
|
|
l2.daemon.wait_for_log('sendrawtx exit 0')
|
|
l1.bitcoin.generate_block(1, wait_for_mempool=1)
|
|
l2.daemon.wait_for_log(' to ONCHAIN')
|
|
l1.daemon.wait_for_log(' to ONCHAIN')
|
|
l2.daemon.wait_for_log('OUR_UNILATERAL/THEIR_HTLC')
|
|
|
|
# l2 should fulfill HTLC onchain, and spend to-us (any order)
|
|
l2.wait_for_onchaind_broadcast('OUR_HTLC_SUCCESS_TX',
|
|
'OUR_UNILATERAL/THEIR_HTLC')
|
|
|
|
# Payment should succeed.
|
|
l1.bitcoin.generate_block(1)
|
|
l1.daemon.wait_for_log('THEIR_UNILATERAL/OUR_HTLC gave us preimage')
|
|
err = q.get(timeout=10)
|
|
if err:
|
|
print("Got err from sendpay thread")
|
|
raise err
|
|
t.join(timeout=1)
|
|
assert not t.is_alive()
|
|
|
|
# Three more, l2 can spend to-us.
|
|
bitcoind.generate_block(3)
|
|
l2.wait_for_onchaind_broadcast('OUR_DELAYED_RETURN_TO_WALLET',
|
|
'OUR_UNILATERAL/DELAYED_OUTPUT_TO_US')
|
|
|
|
# One more block, HTLC tx is now spendable.
|
|
l1.bitcoin.generate_block(1)
|
|
l2.wait_for_onchaind_broadcast('OUR_DELAYED_RETURN_TO_WALLET',
|
|
'OUR_HTLC_SUCCESS_TX/DELAYED_OUTPUT_TO_US')
|
|
|
|
# 100 blocks after last spend, l2 should be done.
|
|
l1.bitcoin.generate_block(100)
|
|
l2.daemon.wait_for_log('onchaind complete, forgetting peer')
|
|
|
|
# Verify accounting for l1 & l2
|
|
assert account_balance(l1, channel_id) == 0
|
|
assert account_balance(l2, channel_id) == 0
|
|
|
|
|
|
@pytest.mark.developer("needs DEVELOPER=1")
|
|
def test_onchain_middleman_their_unilateral_in(node_factory, bitcoind):
|
|
""" This is the same as test_onchain_middleman, except that
|
|
node l1 drops to chain, not l2, reversing the unilateral
|
|
handling logic """
|
|
# We track channel balances, to verify that accounting is ok.
|
|
coin_mvt_plugin = os.path.join(os.getcwd(), 'tests/plugins/coin_movements.py')
|
|
|
|
l1_disconnects = ['=WIRE_UPDATE_FULFILL_HTLC', 'permfail']
|
|
l2_disconnects = ['-WIRE_UPDATE_FULFILL_HTLC']
|
|
|
|
l1, l2, l3 = node_factory.get_nodes(3, opts=[{'plugin': coin_mvt_plugin,
|
|
'disconnect': l1_disconnects},
|
|
{'plugin': coin_mvt_plugin,
|
|
'disconnect': l2_disconnects},
|
|
{}])
|
|
l2.rpc.connect(l1.info['id'], 'localhost', l1.port)
|
|
l2.rpc.connect(l3.info['id'], 'localhost', l3.port)
|
|
|
|
c12, _ = l2.fundchannel(l1, 10**6)
|
|
c23, _ = l2.fundchannel(l3, 10**6)
|
|
channel_id = first_channel_id(l1, l2)
|
|
|
|
# Make sure routes finalized.
|
|
bitcoind.generate_block(5)
|
|
l1.wait_channel_active(c23)
|
|
|
|
# Make sure l3 sees gossip for channel now; it can get upset
|
|
# and give bad gossip msg if channel is closed before it sees
|
|
# node announcement.
|
|
wait_for(lambda: l3.rpc.listchannels(c12)['channels'] != [])
|
|
|
|
# Give l1 some money to play with.
|
|
l2.pay(l1, 2 * 10**8)
|
|
|
|
# Must be bigger than dust!
|
|
inv = l3.rpc.invoice(10**8, 'middleman', 'desc')
|
|
rhash = inv['payment_hash']
|
|
|
|
route = l1.rpc.getroute(l3.info['id'], 10**8, 1)["route"]
|
|
assert len(route) == 2
|
|
|
|
q = queue.Queue()
|
|
|
|
def try_pay():
|
|
try:
|
|
l1.rpc.sendpay(route, rhash, payment_secret=inv['payment_secret'])
|
|
l1.rpc.waitsendpay(rhash)
|
|
q.put(None)
|
|
except Exception as err:
|
|
q.put(err)
|
|
|
|
t = threading.Thread(target=try_pay)
|
|
t.daemon = True
|
|
t.start()
|
|
|
|
# l1 will drop to chain.
|
|
l1.daemon.wait_for_log(' to AWAITING_UNILATERAL')
|
|
l1.daemon.wait_for_log('sendrawtx exit 0')
|
|
l1.bitcoin.generate_block(1)
|
|
l2.daemon.wait_for_log(' to ONCHAIN')
|
|
l1.daemon.wait_for_log(' to ONCHAIN')
|
|
l2.daemon.wait_for_log('THEIR_UNILATERAL/THEIR_HTLC')
|
|
|
|
# l2 should fulfill HTLC onchain, immediately
|
|
l2.wait_for_onchaind_broadcast('THEIR_HTLC_FULFILL_TO_US',
|
|
'THEIR_UNILATERAL/THEIR_HTLC')
|
|
|
|
# Payment should succeed.
|
|
l1.bitcoin.generate_block(1)
|
|
l1.daemon.wait_for_log('OUR_UNILATERAL/OUR_HTLC gave us preimage')
|
|
err = q.get(timeout=10)
|
|
if err:
|
|
print("Got err from sendpay thread")
|
|
raise err
|
|
t.join(timeout=1)
|
|
assert not t.is_alive()
|
|
|
|
l1.bitcoin.generate_block(6)
|
|
l1.wait_for_onchaind_broadcast('OUR_DELAYED_RETURN_TO_WALLET',
|
|
'OUR_UNILATERAL/DELAYED_OUTPUT_TO_US')
|
|
|
|
# 100 blocks after last spend, l1 should be done.
|
|
l1.bitcoin.generate_block(100)
|
|
l2.daemon.wait_for_log('onchaind complete, forgetting peer')
|
|
l1.daemon.wait_for_log('onchaind complete, forgetting peer')
|
|
|
|
# Verify accounting for l1 & l2
|
|
assert account_balance(l1, channel_id) == 0
|
|
assert account_balance(l2, channel_id) == 0
|
|
|
|
|
|
@pytest.mark.developer("needs DEVELOPER=1")
|
|
def test_onchain_their_unilateral_out(node_factory, bitcoind):
|
|
""" Very similar to the test_onchain_middleman, except there's no
|
|
middleman, we simply want to check that our offered htlc
|
|
on their unilateral returns to us (and is accounted
|
|
for correctly) """
|
|
# We track channel balances, to verify that accounting is ok.
|
|
coin_mvt_plugin = os.path.join(os.getcwd(), 'tests/plugins/coin_movements.py')
|
|
|
|
disconnects = ['-WIRE_UPDATE_FAIL_HTLC', 'permfail']
|
|
|
|
l1, l2 = node_factory.line_graph(2, opts=[{'plugin': coin_mvt_plugin},
|
|
{'disconnect': disconnects,
|
|
'plugin': coin_mvt_plugin}])
|
|
channel_id = first_channel_id(l1, l2)
|
|
|
|
route = l1.rpc.getroute(l2.info['id'], 10**8, 1)["route"]
|
|
assert len(route) == 1
|
|
|
|
q = queue.Queue()
|
|
|
|
def try_pay():
|
|
try:
|
|
# rhash is fake (so is payment_secret)
|
|
rhash = 'B1' * 32
|
|
l1.rpc.sendpay(route, rhash, payment_secret=rhash)
|
|
q.put(None)
|
|
except Exception as err:
|
|
q.put(err)
|
|
|
|
t = threading.Thread(target=try_pay)
|
|
t.daemon = True
|
|
t.start()
|
|
|
|
# l2 will drop to chain.
|
|
l2.daemon.wait_for_log(' to AWAITING_UNILATERAL')
|
|
l2.daemon.wait_for_log('sendrawtx exit 0')
|
|
l2.bitcoin.generate_block(1)
|
|
l1.daemon.wait_for_log(' to ONCHAIN')
|
|
l2.daemon.wait_for_log(' to ONCHAIN')
|
|
l1.daemon.wait_for_log('THEIR_UNILATERAL/OUR_HTLC')
|
|
|
|
# l1 should wait til to_self_delay (10), then fulfill onchain
|
|
l2.bitcoin.generate_block(9)
|
|
l1.wait_for_onchaind_broadcast('OUR_HTLC_TIMEOUT_TO_US',
|
|
'THEIR_UNILATERAL/OUR_HTLC')
|
|
l2.daemon.wait_for_log('Ignoring output .*_UNILATERAL/THEIR_HTLC')
|
|
|
|
err = q.get(timeout=10)
|
|
if err:
|
|
print("Got err from sendpay thread")
|
|
raise err
|
|
t.join(timeout=1)
|
|
assert not t.is_alive()
|
|
|
|
# 100 blocks after last spend, l1+l2 should be done.
|
|
l2.bitcoin.generate_block(100)
|
|
l1.daemon.wait_for_log('onchaind complete, forgetting peer')
|
|
l2.daemon.wait_for_log('onchaind complete, forgetting peer')
|
|
|
|
# Verify accounting for l1 & l2
|
|
assert account_balance(l2, channel_id) == 0
|
|
assert account_balance(l1, channel_id) == 0
|
|
|
|
|
|
def test_listfunds_after_their_unilateral(node_factory, bitcoind):
|
|
"""We keep spending info around for their unilateral closes.
|
|
|
|
Make sure we show the address.
|
|
"""
|
|
coin_mvt_plugin = os.path.join(os.getcwd(), 'tests/plugins/coin_movements.py')
|
|
# FIXME: We can get warnings from unilteral changes, since we treat
|
|
# such errors a soft because LND.
|
|
l1, l2 = node_factory.line_graph(2, opts=[{'plugin': coin_mvt_plugin,
|
|
"allow_warning": True},
|
|
{'plugin': coin_mvt_plugin}])
|
|
channel_id = first_channel_id(l1, l2)
|
|
|
|
# listfunds will show 1 output change, and channels.
|
|
assert len([o for o in l1.rpc.listfunds()['outputs'] if not o['reserved']]) == 1
|
|
|
|
l1.stop()
|
|
l2.rpc.close(l1.info['id'], unilateraltimeout=1)
|
|
l2.wait_for_channel_onchain(l1.info['id'])
|
|
bitcoind.generate_block(100)
|
|
|
|
l1.start()
|
|
l2.daemon.wait_for_log('onchaind complete, forgetting peer')
|
|
l1.daemon.wait_for_log('onchaind complete, forgetting peer')
|
|
wait_for(lambda: len(l1.rpc.listfunds()['outputs']) == 2)
|
|
assert all(['address' in o for o in l1.rpc.listfunds()['outputs']])
|
|
|
|
# Verify accounting for l1 & l2
|
|
assert account_balance(l1, channel_id) == 0
|
|
assert account_balance(l2, channel_id) == 0
|
|
|
|
|
|
@pytest.mark.developer("needs DEVELOPER=1")
|
|
def test_onchain_feechange(node_factory, bitcoind, executor):
|
|
"""Onchain handling when we restart with different fees"""
|
|
# HTLC 1->2, 2 fails just after they're both irrevocably committed
|
|
# We need 2 to drop to chain, because then 1's HTLC timeout tx
|
|
# is generated on-the-fly, and is thus feerate sensitive.
|
|
disconnects = ['-WIRE_UPDATE_FAIL_HTLC', 'permfail']
|
|
l1, l2 = node_factory.line_graph(2, opts=[
|
|
{
|
|
'may_reconnect': True,
|
|
'allow_warning': True,
|
|
}, {
|
|
'may_reconnect': True,
|
|
'disconnect': disconnects,
|
|
}
|
|
])
|
|
|
|
inv = l2.rpc.invoice(10**8, 'onchain_timeout', 'desc')
|
|
rhash = inv['payment_hash']
|
|
# We underpay, so it fails.
|
|
routestep = {
|
|
'msatoshi': 10**8 - 1,
|
|
'id': l2.info['id'],
|
|
'delay': 5,
|
|
'channel': '1x1x1'
|
|
}
|
|
|
|
executor.submit(l1.rpc.sendpay, [routestep], rhash, payment_secret=inv['payment_secret'])
|
|
|
|
# l2 will drop to chain.
|
|
l2.daemon.wait_for_log('permfail')
|
|
l2.wait_for_channel_onchain(l1.info['id'])
|
|
bitcoind.generate_block(1)
|
|
l1.daemon.wait_for_log(' to ONCHAIN')
|
|
l2.daemon.wait_for_log(' to ONCHAIN')
|
|
|
|
# Wait for timeout.
|
|
l1.daemon.wait_for_log('Propose handling THEIR_UNILATERAL/OUR_HTLC by OUR_HTLC_TIMEOUT_TO_US .* after 6 blocks')
|
|
bitcoind.generate_block(6)
|
|
|
|
l1.wait_for_onchaind_broadcast('OUR_HTLC_TIMEOUT_TO_US',
|
|
'THEIR_UNILATERAL/OUR_HTLC')
|
|
|
|
# Make sure that gets included.
|
|
|
|
bitcoind.generate_block(1)
|
|
# Now we restart with different feerates.
|
|
l1.stop()
|
|
|
|
l1.daemon.cmd_line.append('--override-fee-rates=20000/9000/2000')
|
|
l1.start()
|
|
|
|
# We recognize different proposal as ours.
|
|
l1.daemon.wait_for_log('Resolved THEIR_UNILATERAL/OUR_HTLC by our proposal OUR_HTLC_TIMEOUT_TO_US')
|
|
|
|
# We use 3 blocks for "reasonable depth", so add two more
|
|
bitcoind.generate_block(2)
|
|
|
|
# Note that the very similar test_onchain_timeout looks for a
|
|
# different string: that's because it sees the JSONRPC response,
|
|
# and due to the l1 restart, there is none here.
|
|
l1.daemon.wait_for_log('WIRE_PERMANENT_CHANNEL_FAILURE')
|
|
|
|
# 90 later, l2 is done
|
|
bitcoind.generate_block(89)
|
|
sync_blockheight(bitcoind, [l2])
|
|
assert not l2.daemon.is_in_log('onchaind complete, forgetting peer')
|
|
bitcoind.generate_block(1)
|
|
l2.daemon.wait_for_log('onchaind complete, forgetting peer')
|
|
|
|
# Now, 7 blocks and l1 should be done.
|
|
bitcoind.generate_block(6)
|
|
sync_blockheight(bitcoind, [l1])
|
|
assert not l1.daemon.is_in_log('onchaind complete, forgetting peer')
|
|
bitcoind.generate_block(1)
|
|
l1.daemon.wait_for_log('onchaind complete, forgetting peer')
|
|
|
|
# Payment failed, BTW
|
|
assert only_one(l2.rpc.listinvoices('onchain_timeout')['invoices'])['status'] == 'unpaid'
|
|
|
|
|
|
@pytest.mark.developer("needs DEVELOPER=1 for dev-set-fees")
|
|
def test_onchain_all_dust(node_factory, bitcoind, executor):
|
|
"""Onchain handling when we reduce output to all dust"""
|
|
# We track channel balances, to verify that accounting is ok.
|
|
coin_mvt_plugin = os.path.join(os.getcwd(), 'tests/plugins/coin_movements.py')
|
|
|
|
# HTLC 1->2, 2 fails just after they're both irrevocably committed
|
|
# We need 2 to drop to chain, because then 1's HTLC timeout tx
|
|
# is generated on-the-fly, and is thus feerate sensitive.
|
|
disconnects = ['-WIRE_UPDATE_FAIL_HTLC', 'permfail']
|
|
# Feerates identical so we don't get gratuitous commit to update them
|
|
l1 = node_factory.get_node(options={'dev-no-reconnect': None,
|
|
'plugin': coin_mvt_plugin},
|
|
feerates=(7500, 7500, 7500, 7500))
|
|
l2 = node_factory.get_node(disconnect=disconnects, options={'plugin': coin_mvt_plugin})
|
|
|
|
l1.rpc.connect(l2.info['id'], 'localhost', l2.port)
|
|
l1.fundchannel(l2, 10**6)
|
|
channel_id = first_channel_id(l1, l2)
|
|
|
|
inv = l2.rpc.invoice(10**8, 'onchain_timeout', 'desc')
|
|
rhash = inv['payment_hash']
|
|
# We underpay, so it fails.
|
|
routestep = {
|
|
'msatoshi': 10**7 - 1,
|
|
'id': l2.info['id'],
|
|
'delay': 5,
|
|
'channel': '1x1x1'
|
|
}
|
|
|
|
executor.submit(l1.rpc.sendpay, [routestep], rhash, payment_secret=inv['payment_secret'])
|
|
|
|
# l2 will drop to chain.
|
|
l2.daemon.wait_for_log('permfail')
|
|
l2.wait_for_channel_onchain(l1.info['id'])
|
|
|
|
# Make l1's fees really high (and wait for it to exceed 50000)
|
|
l1.set_feerates((100000, 100000, 100000, 100000))
|
|
l1.daemon.wait_for_log('Feerate estimate for unilateral_close set to [56789][0-9]{4}')
|
|
|
|
bitcoind.generate_block(1)
|
|
l1.daemon.wait_for_log(' to ONCHAIN')
|
|
l2.daemon.wait_for_log(' to ONCHAIN')
|
|
|
|
# Wait for timeout.
|
|
l1.daemon.wait_for_log('Propose handling THEIR_UNILATERAL/OUR_HTLC by IGNORING_TINY_PAYMENT .* after 6 blocks')
|
|
bitcoind.generate_block(5)
|
|
|
|
l1.wait_for_onchaind_broadcast('IGNORING_TINY_PAYMENT',
|
|
'THEIR_UNILATERAL/OUR_HTLC')
|
|
l1.daemon.wait_for_log('Ignoring output .* of .*: THEIR_UNILATERAL/OUR_HTLC')
|
|
|
|
# 100 deep and l2 forgets.
|
|
bitcoind.generate_block(93)
|
|
sync_blockheight(bitcoind, [l1, l2])
|
|
assert not l2.daemon.is_in_log('onchaind complete, forgetting peer')
|
|
assert not l1.daemon.is_in_log('onchaind complete, forgetting peer')
|
|
bitcoind.generate_block(1)
|
|
l2.daemon.wait_for_log('onchaind complete, forgetting peer')
|
|
|
|
# l1 does not wait for ignored payment.
|
|
l1.daemon.wait_for_log('onchaind complete, forgetting peer')
|
|
|
|
assert account_balance(l1, channel_id) == 0
|
|
assert account_balance(l2, channel_id) == 0
|
|
|
|
|
|
@pytest.mark.developer("needs DEVELOPER=1 for dev_fail")
|
|
def test_onchain_different_fees(node_factory, bitcoind, executor):
|
|
"""Onchain handling when we've had a range of fees"""
|
|
l1, l2 = node_factory.line_graph(2, fundchannel=True, fundamount=10**7,
|
|
opts={'may_reconnect': True})
|
|
|
|
l2.rpc.dev_ignore_htlcs(id=l1.info['id'], ignore=True)
|
|
p1 = executor.submit(l1.pay, l2, 1000000000)
|
|
l2.daemon.wait_for_log('htlc 0: SENT_ADD_ACK_COMMIT->RCVD_ADD_ACK_REVOCATION')
|
|
|
|
l1.set_feerates((16000, 11000, 7500, 3750))
|
|
p2 = executor.submit(l1.pay, l2, 900000000)
|
|
l2.daemon.wait_for_log('htlc 1: SENT_ADD_ACK_COMMIT->RCVD_ADD_ACK_REVOCATION')
|
|
|
|
# Restart with different feerate for second HTLC.
|
|
l1.set_feerates((5000, 5000, 5000, 3750))
|
|
l1.restart()
|
|
l1.daemon.wait_for_log('peer_out WIRE_UPDATE_FEE')
|
|
|
|
p3 = executor.submit(l1.pay, l2, 800000000)
|
|
l2.daemon.wait_for_log('htlc 2: SENT_ADD_ACK_COMMIT->RCVD_ADD_ACK_REVOCATION')
|
|
|
|
# Drop to chain
|
|
l1.rpc.dev_fail(l2.info['id'])
|
|
l1.wait_for_channel_onchain(l2.info['id'])
|
|
|
|
bitcoind.generate_block(1)
|
|
l1.daemon.wait_for_log(' to ONCHAIN')
|
|
l2.daemon.wait_for_log(' to ONCHAIN')
|
|
|
|
# Both sides should have correct feerate
|
|
assert l1.db_query('SELECT min_possible_feerate, max_possible_feerate FROM channels;') == [{
|
|
'min_possible_feerate': 5000,
|
|
'max_possible_feerate': 11000
|
|
}]
|
|
assert l2.db_query('SELECT min_possible_feerate, max_possible_feerate FROM channels;') == [{
|
|
'min_possible_feerate': 5000,
|
|
'max_possible_feerate': 11000
|
|
}]
|
|
|
|
bitcoind.generate_block(5)
|
|
# Three HTLCs, and one for the to-us output.
|
|
l1.daemon.wait_for_logs(['sendrawtx exit 0'] * 4)
|
|
|
|
# We use 3 blocks for "reasonable depth"
|
|
bitcoind.generate_block(3)
|
|
|
|
with pytest.raises(Exception):
|
|
p1.result(10)
|
|
with pytest.raises(Exception):
|
|
p2.result(10)
|
|
with pytest.raises(Exception):
|
|
p3.result(10)
|
|
|
|
# Two more for HTLC timeout tx to be spent.
|
|
bitcoind.generate_block(2)
|
|
l1.daemon.wait_for_logs(['sendrawtx exit 0'] * 3)
|
|
|
|
# Now, 100 blocks it should be done.
|
|
bitcoind.generate_block(100)
|
|
wait_for(lambda: l1.rpc.listpeers()['peers'] == [])
|
|
wait_for(lambda: l2.rpc.listpeers()['peers'] == [])
|
|
|
|
|
|
@pytest.mark.developer("needs DEVELOPER=1")
|
|
def test_permfail_new_commit(node_factory, bitcoind, executor):
|
|
# Test case where we have two possible commits: it will use new one.
|
|
disconnects = ['-WIRE_REVOKE_AND_ACK', 'permfail']
|
|
# Feerates identical so we don't get gratuitous commit to update them
|
|
l1 = node_factory.get_node(options={'dev-no-reconnect': None},
|
|
feerates=(7500, 7500, 7500, 7500))
|
|
l2 = node_factory.get_node(disconnect=disconnects)
|
|
|
|
l1.rpc.connect(l2.info['id'], 'localhost', l2.port)
|
|
l1.fundchannel(l2, 10**6)
|
|
|
|
# This will fail at l2's end.
|
|
t = executor.submit(l1.pay, l2, 200000000)
|
|
|
|
l2.daemon.wait_for_log('dev_disconnect permfail')
|
|
l2.wait_for_channel_onchain(l1.info['id'])
|
|
bitcoind.generate_block(1)
|
|
l1.daemon.wait_for_log('Their unilateral tx, new commit point')
|
|
l1.daemon.wait_for_log(' to ONCHAIN')
|
|
l2.daemon.wait_for_log(' to ONCHAIN')
|
|
l2.daemon.wait_for_log('Propose handling OUR_UNILATERAL/THEIR_HTLC by THEIR_HTLC_TIMEOUT_TO_THEM \\(IGNORING\\) after 6 blocks')
|
|
l1.daemon.wait_for_log('Propose handling THEIR_UNILATERAL/OUR_HTLC by OUR_HTLC_TIMEOUT_TO_US (.*) after 6 blocks')
|
|
|
|
# OK, time out HTLC.
|
|
bitcoind.generate_block(5)
|
|
l1.wait_for_onchaind_broadcast('OUR_HTLC_TIMEOUT_TO_US',
|
|
'THEIR_UNILATERAL/OUR_HTLC')
|
|
|
|
bitcoind.generate_block(1)
|
|
l1.daemon.wait_for_log('Resolved THEIR_UNILATERAL/OUR_HTLC by our proposal OUR_HTLC_TIMEOUT_TO_US')
|
|
l2.daemon.wait_for_log('Ignoring output.*: OUR_UNILATERAL/THEIR_HTLC')
|
|
|
|
t.cancel()
|
|
|
|
# Now, 100 blocks it should be done.
|
|
bitcoind.generate_block(100)
|
|
wait_for(lambda: l1.rpc.listpeers()['peers'] == [])
|
|
wait_for(lambda: l2.rpc.listpeers()['peers'] == [])
|
|
|
|
|
|
def setup_multihtlc_test(node_factory, bitcoind):
|
|
# l1 -> l2 -> l3 -> l4 -> l5 -> l6 -> l7
|
|
# l1 and l7 ignore and HTLCs they're sent.
|
|
# For each direction, we create these HTLCs with same payment_hash:
|
|
# 1 failed (CLTV1)
|
|
# 1 failed (CLTV2)
|
|
# 2 live (CLTV2)
|
|
# 1 live (CLTV3)
|
|
nodes = node_factory.line_graph(7, wait_for_announce=True,
|
|
opts={'dev-no-reconnect': None,
|
|
'may_reconnect': True})
|
|
|
|
# Balance by pushing half the funds.
|
|
b11 = nodes[-1].rpc.invoice(10**9 // 2, '1', 'balancer')['bolt11']
|
|
nodes[0].rpc.pay(b11)
|
|
|
|
nodes[0].rpc.dev_ignore_htlcs(id=nodes[1].info['id'], ignore=True)
|
|
nodes[-1].rpc.dev_ignore_htlcs(id=nodes[-2].info['id'], ignore=True)
|
|
|
|
preimage = "0" * 64
|
|
inv = nodes[0].rpc.invoice(msatoshi=10**8, label='x', description='desc',
|
|
preimage=preimage)
|
|
h = inv['payment_hash']
|
|
nodes[-1].rpc.invoice(msatoshi=10**8, label='x', description='desc',
|
|
preimage=preimage)['payment_hash']
|
|
|
|
# First, the failed attempts (paying wrong node). CLTV1
|
|
r = nodes[0].rpc.getroute(nodes[-2].info['id'], 10**8, 1)["route"]
|
|
nodes[0].rpc.sendpay(r, h, payment_secret=inv['payment_secret'])
|
|
with pytest.raises(RpcError, match=r'INCORRECT_OR_UNKNOWN_PAYMENT_DETAILS'):
|
|
nodes[0].rpc.waitsendpay(h)
|
|
|
|
r = nodes[-1].rpc.getroute(nodes[1].info['id'], 10**8, 1)["route"]
|
|
nodes[-1].rpc.sendpay(r, h, payment_secret=inv['payment_secret'])
|
|
with pytest.raises(RpcError, match=r'INCORRECT_OR_UNKNOWN_PAYMENT_DETAILS'):
|
|
nodes[-1].rpc.waitsendpay(h)
|
|
|
|
# Now increment CLTV -> CLTV2
|
|
bitcoind.generate_block(1)
|
|
sync_blockheight(bitcoind, nodes)
|
|
|
|
# Now, the live attempts with CLTV2 (blackholed by end nodes)
|
|
r = nodes[0].rpc.getroute(nodes[-1].info['id'], 10**8, 1)["route"]
|
|
nodes[0].rpc.sendpay(r, h, payment_secret=inv['payment_secret'])
|
|
r = nodes[-1].rpc.getroute(nodes[0].info['id'], 10**8, 1)["route"]
|
|
nodes[-1].rpc.sendpay(r, h, payment_secret=inv['payment_secret'])
|
|
|
|
# We send second HTLC from different node, since they refuse to send
|
|
# multiple with same hash.
|
|
r = nodes[1].rpc.getroute(nodes[-1].info['id'], 10**8, 1)["route"]
|
|
nodes[1].rpc.sendpay(r, h, payment_secret=inv['payment_secret'])
|
|
r = nodes[-2].rpc.getroute(nodes[0].info['id'], 10**8, 1)["route"]
|
|
nodes[-2].rpc.sendpay(r, h, payment_secret=inv['payment_secret'])
|
|
|
|
# Now increment CLTV -> CLTV3.
|
|
bitcoind.generate_block(1)
|
|
sync_blockheight(bitcoind, nodes)
|
|
|
|
r = nodes[2].rpc.getroute(nodes[-1].info['id'], 10**8, 1)["route"]
|
|
nodes[2].rpc.sendpay(r, h, payment_secret=inv['payment_secret'])
|
|
r = nodes[-3].rpc.getroute(nodes[0].info['id'], 10**8, 1)["route"]
|
|
nodes[-3].rpc.sendpay(r, h, payment_secret=inv['payment_secret'])
|
|
|
|
# Make sure HTLCs have reached the end.
|
|
nodes[0].daemon.wait_for_logs(['peer_in WIRE_UPDATE_ADD_HTLC'] * 3)
|
|
nodes[-1].daemon.wait_for_logs(['peer_in WIRE_UPDATE_ADD_HTLC'] * 3)
|
|
|
|
return h, nodes
|
|
|
|
|
|
@pytest.mark.developer("needs DEVELOPER=1 for dev_ignore_htlcs")
|
|
@pytest.mark.slow_test
|
|
def test_onchain_multihtlc_our_unilateral(node_factory, bitcoind):
|
|
"""Node pushes a channel onchain with multiple HTLCs with same payment_hash """
|
|
h, nodes = setup_multihtlc_test(node_factory, bitcoind)
|
|
|
|
mid = len(nodes) // 2
|
|
|
|
for i in range(len(nodes) - 1):
|
|
assert only_one(nodes[i].rpc.listpeers(nodes[i + 1].info['id'])['peers'])['connected']
|
|
|
|
# Now midnode goes onchain with n+1 channel.
|
|
nodes[mid].rpc.dev_fail(nodes[mid + 1].info['id'])
|
|
nodes[mid].wait_for_channel_onchain(nodes[mid + 1].info['id'])
|
|
|
|
bitcoind.generate_block(1)
|
|
nodes[mid].daemon.wait_for_log(' to ONCHAIN')
|
|
nodes[mid + 1].daemon.wait_for_log(' to ONCHAIN')
|
|
|
|
# Now, restart and manually reconnect end nodes (so they don't ignore HTLCs)
|
|
# In fact, they'll fail them with WIRE_TEMPORARY_NODE_FAILURE.
|
|
# TODO Remove our reliance on HTLCs failing on startup and the need for
|
|
# this plugin
|
|
nodes[0].daemon.opts['plugin'] = os.path.join(os.getcwd(), 'tests/plugins/fail_htlcs.py')
|
|
nodes[-1].daemon.opts['plugin'] = os.path.join(os.getcwd(), 'tests/plugins/fail_htlcs.py')
|
|
nodes[0].restart()
|
|
nodes[-1].restart()
|
|
|
|
# We disabled auto-reconnect so we'd detect breakage, so manually reconnect.
|
|
nodes[0].rpc.connect(nodes[1].info['id'], 'localhost', nodes[1].port)
|
|
nodes[-1].rpc.connect(nodes[-2].info['id'], 'localhost', nodes[-2].port)
|
|
|
|
# Wait for HTLCs to stabilize.
|
|
nodes[0].daemon.wait_for_logs(['peer_out WIRE_UPDATE_FAIL_HTLC'] * 3)
|
|
nodes[0].daemon.wait_for_log('peer_out WIRE_COMMITMENT_SIGNED')
|
|
nodes[0].daemon.wait_for_log('peer_out WIRE_REVOKE_AND_ACK')
|
|
nodes[-1].daemon.wait_for_logs(['peer_out WIRE_UPDATE_FAIL_HTLC'] * 3)
|
|
nodes[-1].daemon.wait_for_log('peer_out WIRE_COMMITMENT_SIGNED')
|
|
nodes[-1].daemon.wait_for_log('peer_out WIRE_REVOKE_AND_ACK')
|
|
|
|
# After at depth 5, midnode will spend its own to-self output.
|
|
bitcoind.generate_block(4)
|
|
nodes[mid].wait_for_onchaind_broadcast('OUR_DELAYED_RETURN_TO_WALLET',
|
|
'OUR_UNILATERAL/DELAYED_OUTPUT_TO_US')
|
|
|
|
# The three outgoing HTLCs time out at 21, 21 and 22 blocks.
|
|
bitcoind.generate_block(16)
|
|
nodes[mid].wait_for_onchaind_broadcast('OUR_HTLC_TIMEOUT_TX',
|
|
'OUR_UNILATERAL/OUR_HTLC')
|
|
nodes[mid].wait_for_onchaind_broadcast('OUR_HTLC_TIMEOUT_TX',
|
|
'OUR_UNILATERAL/OUR_HTLC')
|
|
bitcoind.generate_block(1)
|
|
nodes[mid].wait_for_onchaind_broadcast('OUR_HTLC_TIMEOUT_TX',
|
|
'OUR_UNILATERAL/OUR_HTLC')
|
|
|
|
# And three more for us to consider them all settled.
|
|
bitcoind.generate_block(3)
|
|
|
|
# Now, those nodes should have correctly failed the HTLCs
|
|
for n in nodes[:mid - 1]:
|
|
with pytest.raises(RpcError, match=r'WIRE_PERMANENT_CHANNEL_FAILURE'):
|
|
n.rpc.waitsendpay(h, TIMEOUT)
|
|
|
|
# Other timeouts are 27,27,28 blocks.
|
|
bitcoind.generate_block(2)
|
|
nodes[mid].daemon.wait_for_logs(['Ignoring output.*: OUR_UNILATERAL/THEIR_HTLC'] * 2)
|
|
for _ in range(2):
|
|
nodes[mid + 1].wait_for_onchaind_broadcast('OUR_HTLC_TIMEOUT_TO_US',
|
|
'THEIR_UNILATERAL/OUR_HTLC')
|
|
bitcoind.generate_block(1)
|
|
nodes[mid].daemon.wait_for_log('Ignoring output.*: OUR_UNILATERAL/THEIR_HTLC')
|
|
nodes[mid + 1].wait_for_onchaind_broadcast('OUR_HTLC_TIMEOUT_TO_US',
|
|
'THEIR_UNILATERAL/OUR_HTLC')
|
|
|
|
# Depth 3 to consider it settled.
|
|
bitcoind.generate_block(3)
|
|
|
|
for n in nodes[mid + 1:]:
|
|
with pytest.raises(RpcError, match=r'WIRE_PERMANENT_CHANNEL_FAILURE'):
|
|
n.rpc.waitsendpay(h, TIMEOUT)
|
|
|
|
# At depth 100 it's all done (we didn't bother waiting for mid+1's
|
|
# spends, so that might still be going)
|
|
bitcoind.generate_block(97)
|
|
nodes[mid].daemon.wait_for_logs(['onchaind complete, forgetting peer'])
|
|
|
|
# No other channels should have failed.
|
|
for i in range(len(nodes) - 1):
|
|
if i != mid:
|
|
assert only_one(nodes[i].rpc.listpeers(nodes[i + 1].info['id'])['peers'])['connected']
|
|
|
|
|
|
@pytest.mark.developer("needs DEVELOPER=1 for dev_ignore_htlcs")
|
|
@pytest.mark.slow_test
|
|
def test_onchain_multihtlc_their_unilateral(node_factory, bitcoind):
|
|
"""Node pushes a channel onchain with multiple HTLCs with same payment_hash """
|
|
h, nodes = setup_multihtlc_test(node_factory, bitcoind)
|
|
|
|
mid = len(nodes) // 2
|
|
|
|
for i in range(len(nodes) - 1):
|
|
assert only_one(nodes[i].rpc.listpeers(nodes[i + 1].info['id'])['peers'])['connected']
|
|
|
|
# Now midnode+1 goes onchain with midnode channel.
|
|
nodes[mid + 1].rpc.dev_fail(nodes[mid].info['id'])
|
|
nodes[mid + 1].wait_for_channel_onchain(nodes[mid].info['id'])
|
|
|
|
bitcoind.generate_block(1)
|
|
nodes[mid].daemon.wait_for_log(' to ONCHAIN')
|
|
nodes[mid + 1].daemon.wait_for_log(' to ONCHAIN')
|
|
|
|
# Now, restart and manually reconnect end nodes (so they don't ignore HTLCs)
|
|
# In fact, they'll fail them with WIRE_TEMPORARY_NODE_FAILURE.
|
|
# TODO Remove our reliance on HTLCs failing on startup and the need for
|
|
# this plugin
|
|
nodes[0].daemon.opts['plugin'] = os.path.join(os.getcwd(), 'tests/plugins/fail_htlcs.py')
|
|
nodes[-1].daemon.opts['plugin'] = os.path.join(os.getcwd(), 'tests/plugins/fail_htlcs.py')
|
|
nodes[0].restart()
|
|
nodes[-1].restart()
|
|
|
|
# We disabled auto-reconnect so we'd detect breakage, so manually reconnect.
|
|
nodes[0].rpc.connect(nodes[1].info['id'], 'localhost', nodes[1].port)
|
|
nodes[-1].rpc.connect(nodes[-2].info['id'], 'localhost', nodes[-2].port)
|
|
|
|
# Wait for HTLCs to stabilize.
|
|
nodes[0].daemon.wait_for_logs(['peer_out WIRE_UPDATE_FAIL_HTLC'] * 3)
|
|
nodes[0].daemon.wait_for_log('peer_out WIRE_COMMITMENT_SIGNED')
|
|
nodes[0].daemon.wait_for_log('peer_out WIRE_REVOKE_AND_ACK')
|
|
nodes[-1].daemon.wait_for_logs(['peer_out WIRE_UPDATE_FAIL_HTLC'] * 3)
|
|
nodes[-1].daemon.wait_for_log('peer_out WIRE_COMMITMENT_SIGNED')
|
|
nodes[-1].daemon.wait_for_log('peer_out WIRE_REVOKE_AND_ACK')
|
|
|
|
# At depth 5, midnode+1 will spend its own to-self output.
|
|
bitcoind.generate_block(4)
|
|
nodes[mid + 1].wait_for_onchaind_broadcast('OUR_DELAYED_RETURN_TO_WALLET')
|
|
|
|
# The three outgoing HTLCs time out at depth 21, 21 and 22 blocks.
|
|
bitcoind.generate_block(16)
|
|
nodes[mid].wait_for_onchaind_broadcast('OUR_HTLC_TIMEOUT_TO_US',
|
|
'THEIR_UNILATERAL/OUR_HTLC')
|
|
nodes[mid].wait_for_onchaind_broadcast('OUR_HTLC_TIMEOUT_TO_US',
|
|
'THEIR_UNILATERAL/OUR_HTLC')
|
|
bitcoind.generate_block(1)
|
|
nodes[mid].wait_for_onchaind_broadcast('OUR_HTLC_TIMEOUT_TO_US',
|
|
'THEIR_UNILATERAL/OUR_HTLC')
|
|
|
|
# At depth 3 we consider them all settled.
|
|
bitcoind.generate_block(3)
|
|
|
|
# Now, those nodes should have correctly failed the HTLCs
|
|
for n in nodes[:mid - 1]:
|
|
with pytest.raises(RpcError, match=r'WIRE_PERMANENT_CHANNEL_FAILURE'):
|
|
n.rpc.waitsendpay(h, TIMEOUT)
|
|
|
|
# Other timeouts are at depths 27,27,28 blocks.
|
|
bitcoind.generate_block(2)
|
|
nodes[mid].daemon.wait_for_logs(['Ignoring output.*: THEIR_UNILATERAL/THEIR_HTLC'] * 2)
|
|
for _ in range(2):
|
|
nodes[mid + 1].wait_for_onchaind_broadcast('OUR_HTLC_TIMEOUT_TX',
|
|
'OUR_UNILATERAL/OUR_HTLC')
|
|
bitcoind.generate_block(1)
|
|
nodes[mid].daemon.wait_for_log('Ignoring output.*: THEIR_UNILATERAL/THEIR_HTLC')
|
|
nodes[mid + 1].wait_for_onchaind_broadcast('OUR_HTLC_TIMEOUT_TX',
|
|
'OUR_UNILATERAL/OUR_HTLC')
|
|
|
|
# At depth 3 we consider them all settled.
|
|
bitcoind.generate_block(3)
|
|
|
|
for n in nodes[mid + 1:]:
|
|
with pytest.raises(RpcError, match=r'WIRE_PERMANENT_CHANNEL_FAILURE'):
|
|
n.rpc.waitsendpay(h, TIMEOUT)
|
|
|
|
# At depth 5, mid+1 can spend HTLC_TIMEOUT_TX output.
|
|
bitcoind.generate_block(1)
|
|
for _ in range(2):
|
|
nodes[mid + 1].wait_for_onchaind_broadcast('OUR_DELAYED_RETURN_TO_WALLET',
|
|
'OUR_HTLC_TIMEOUT_TX/DELAYED_OUTPUT_TO_US')
|
|
bitcoind.generate_block(1)
|
|
nodes[mid + 1].wait_for_onchaind_broadcast('OUR_DELAYED_RETURN_TO_WALLET',
|
|
'OUR_HTLC_TIMEOUT_TX/DELAYED_OUTPUT_TO_US')
|
|
|
|
# At depth 100 they're all done.
|
|
bitcoind.generate_block(100)
|
|
nodes[mid].daemon.wait_for_logs(['onchaind complete, forgetting peer'])
|
|
nodes[mid + 1].daemon.wait_for_logs(['onchaind complete, forgetting peer'])
|
|
|
|
# No other channels should have failed.
|
|
for i in range(len(nodes) - 1):
|
|
if i != mid:
|
|
assert only_one(nodes[i].rpc.listpeers(nodes[i + 1].info['id'])['peers'])['connected']
|
|
|
|
|
|
@pytest.mark.developer("needs DEVELOPER=1")
|
|
def test_permfail_htlc_in(node_factory, bitcoind, executor):
|
|
# Test case where we fail with unsettled incoming HTLC.
|
|
disconnects = ['-WIRE_UPDATE_FULFILL_HTLC', 'permfail']
|
|
# Feerates identical so we don't get gratuitous commit to update them
|
|
l1 = node_factory.get_node(options={'dev-no-reconnect': None},
|
|
feerates=(7500, 7500, 7500, 7500))
|
|
l2 = node_factory.get_node(disconnect=disconnects)
|
|
|
|
l1.rpc.connect(l2.info['id'], 'localhost', l2.port)
|
|
l1.fundchannel(l2, 10**6)
|
|
|
|
# This will fail at l2's end.
|
|
t = executor.submit(l1.pay, l2, 200000000)
|
|
|
|
l2.daemon.wait_for_log('dev_disconnect permfail')
|
|
l2.wait_for_channel_onchain(l1.info['id'])
|
|
bitcoind.generate_block(1)
|
|
l1.daemon.wait_for_log('Their unilateral tx, old commit point')
|
|
l1.daemon.wait_for_log(' to ONCHAIN')
|
|
l2.daemon.wait_for_log(' to ONCHAIN')
|
|
l2.daemon.wait_for_log('Propose handling OUR_UNILATERAL/THEIR_HTLC by THEIR_HTLC_TIMEOUT_TO_THEM \\(IGNORING\\) after 6 blocks')
|
|
l1.daemon.wait_for_log('Propose handling THEIR_UNILATERAL/OUR_HTLC by OUR_HTLC_TIMEOUT_TO_US (.*) after 6 blocks')
|
|
# l2 then gets preimage, uses it instead of ignoring
|
|
l2.wait_for_onchaind_broadcast('OUR_HTLC_SUCCESS_TX',
|
|
'OUR_UNILATERAL/THEIR_HTLC')
|
|
bitcoind.generate_block(1)
|
|
|
|
# OK, l1 sees l2 fulfill htlc.
|
|
l1.daemon.wait_for_log('THEIR_UNILATERAL/OUR_HTLC gave us preimage')
|
|
l2.daemon.wait_for_log('Propose handling OUR_HTLC_SUCCESS_TX/DELAYED_OUTPUT_TO_US by OUR_DELAYED_RETURN_TO_WALLET .* after 5 blocks')
|
|
bitcoind.generate_block(5)
|
|
|
|
l2.wait_for_onchaind_broadcast('OUR_DELAYED_RETURN_TO_WALLET',
|
|
'OUR_HTLC_SUCCESS_TX/DELAYED_OUTPUT_TO_US')
|
|
|
|
t.cancel()
|
|
|
|
# Now, 100 blocks it should be done.
|
|
bitcoind.generate_block(95)
|
|
l1.daemon.wait_for_log('onchaind complete, forgetting peer')
|
|
assert not l2.daemon.is_in_log('onchaind complete, forgetting peer')
|
|
bitcoind.generate_block(5)
|
|
l2.daemon.wait_for_log('onchaind complete, forgetting peer')
|
|
|
|
|
|
@pytest.mark.developer("needs DEVELOPER=1")
|
|
def test_permfail_htlc_out(node_factory, bitcoind, executor):
|
|
# Test case where we fail with unsettled outgoing HTLC.
|
|
disconnects = ['+WIRE_REVOKE_AND_ACK', 'permfail']
|
|
l1 = node_factory.get_node(options={'dev-no-reconnect': None})
|
|
# Feerates identical so we don't get gratuitous commit to update them
|
|
l2 = node_factory.get_node(disconnect=disconnects,
|
|
feerates=(7500, 7500, 7500, 7500))
|
|
|
|
l1.rpc.connect(l2.info['id'], 'localhost', l2.port)
|
|
l2.daemon.wait_for_log('Handed peer, entering loop')
|
|
l2.fundchannel(l1, 10**6)
|
|
|
|
# This will fail at l2's end.
|
|
t = executor.submit(l2.pay, l1, 200000000)
|
|
|
|
l2.daemon.wait_for_log('dev_disconnect permfail')
|
|
l2.wait_for_channel_onchain(l1.info['id'])
|
|
bitcoind.generate_block(1)
|
|
l1.daemon.wait_for_log('Their unilateral tx, old commit point')
|
|
l1.daemon.wait_for_log(' to ONCHAIN')
|
|
l2.daemon.wait_for_log(' to ONCHAIN')
|
|
l2.daemon.wait_for_logs([
|
|
'Propose handling OUR_UNILATERAL/OUR_HTLC by OUR_HTLC_TIMEOUT_TX \\(.*\\) after 6 blocks',
|
|
'Propose handling OUR_UNILATERAL/DELAYED_OUTPUT_TO_US by OUR_DELAYED_RETURN_TO_WALLET .* after 5 blocks'
|
|
])
|
|
|
|
l1.daemon.wait_for_log('Propose handling THEIR_UNILATERAL/THEIR_HTLC by THEIR_HTLC_TIMEOUT_TO_THEM \\(IGNORING\\) after 6 blocks')
|
|
# l1 then gets preimage, uses it instead of ignoring
|
|
l1.wait_for_onchaind_broadcast('THEIR_HTLC_FULFILL_TO_US',
|
|
'THEIR_UNILATERAL/THEIR_HTLC')
|
|
|
|
# l2 sees l1 fulfill tx.
|
|
bitcoind.generate_block(1)
|
|
|
|
l2.daemon.wait_for_log('OUR_UNILATERAL/OUR_HTLC gave us preimage')
|
|
t.cancel()
|
|
|
|
# l2 can send OUR_DELAYED_RETURN_TO_WALLET after 3 more blocks.
|
|
bitcoind.generate_block(3)
|
|
l2.wait_for_onchaind_broadcast('OUR_DELAYED_RETURN_TO_WALLET',
|
|
'OUR_UNILATERAL/DELAYED_OUTPUT_TO_US')
|
|
|
|
# Now, 100 blocks they should be done.
|
|
bitcoind.generate_block(95)
|
|
sync_blockheight(bitcoind, [l1, l2])
|
|
assert not l1.daemon.is_in_log('onchaind complete, forgetting peer')
|
|
assert not l2.daemon.is_in_log('onchaind complete, forgetting peer')
|
|
bitcoind.generate_block(1)
|
|
l1.daemon.wait_for_log('onchaind complete, forgetting peer')
|
|
sync_blockheight(bitcoind, [l2])
|
|
assert not l2.daemon.is_in_log('onchaind complete, forgetting peer')
|
|
bitcoind.generate_block(3)
|
|
sync_blockheight(bitcoind, [l2])
|
|
assert not l2.daemon.is_in_log('onchaind complete, forgetting peer')
|
|
bitcoind.generate_block(1)
|
|
wait_for(lambda: l2.rpc.listpeers()['peers'] == [])
|
|
|
|
|
|
@pytest.mark.developer("needs DEVELOPER=1")
|
|
def test_permfail(node_factory, bitcoind):
|
|
l1, l2 = node_factory.line_graph(2)
|
|
|
|
# The funding change should be confirmed and our only output
|
|
assert [o['status'] for o in l1.rpc.listfunds()['outputs']] == ['confirmed']
|
|
l1.pay(l2, 200000000)
|
|
|
|
# Make sure l2 has received sig with 0 htlcs!
|
|
l2.daemon.wait_for_log('Received commit_sig with 1 htlc sigs')
|
|
l2.daemon.wait_for_log('Received commit_sig with 0 htlc sigs')
|
|
|
|
# Make sure l1 has final revocation.
|
|
l1.daemon.wait_for_log('Sending commit_sig with 1 htlc sigs')
|
|
l1.daemon.wait_for_log('Sending commit_sig with 0 htlc sigs')
|
|
l1.daemon.wait_for_log('peer_in WIRE_REVOKE_AND_ACK')
|
|
|
|
# We fail l2, so l1 will reconnect to it.
|
|
l2.rpc.dev_fail(l1.info['id'])
|
|
l2.daemon.wait_for_log('Failing due to dev-fail command')
|
|
l2.wait_for_channel_onchain(l1.info['id'])
|
|
|
|
assert l1.bitcoin.rpc.getmempoolinfo()['size'] == 1
|
|
|
|
# Now grab the close transaction
|
|
closetxid = only_one(l1.bitcoin.rpc.getrawmempool(False))
|
|
|
|
# l2 will send out tx (l1 considers it a transient error)
|
|
bitcoind.generate_block(1)
|
|
|
|
l1.daemon.wait_for_log('Their unilateral tx, old commit point')
|
|
l1.daemon.wait_for_log(' to ONCHAIN')
|
|
l2.daemon.wait_for_log(' to ONCHAIN')
|
|
l2.daemon.wait_for_log('Propose handling OUR_UNILATERAL/DELAYED_OUTPUT_TO_US by OUR_DELAYED_RETURN_TO_WALLET (.*) after 5 blocks')
|
|
|
|
wait_for(lambda: only_one(l1.rpc.listpeers(l2.info['id'])['peers'][0]['channels'])['status']
|
|
== ['ONCHAIN:Tracking their unilateral close',
|
|
'ONCHAIN:All outputs resolved: waiting 99 more blocks before forgetting channel'])
|
|
|
|
def check_billboard():
|
|
billboard = only_one(l2.rpc.listpeers(l1.info['id'])['peers'][0]['channels'])['status']
|
|
return (
|
|
len(billboard) == 2
|
|
and billboard[0] == 'ONCHAIN:Tracking our own unilateral close'
|
|
and re.fullmatch(r'ONCHAIN:.* outputs unresolved: in 4 blocks will spend DELAYED_OUTPUT_TO_US \(.*:.*\) using OUR_DELAYED_RETURN_TO_WALLET', billboard[1])
|
|
)
|
|
wait_for(check_billboard)
|
|
|
|
# Now, mine 4 blocks so it sends out the spending tx.
|
|
bitcoind.generate_block(4)
|
|
|
|
# onchaind notes to-local payment immediately.
|
|
assert (closetxid, "confirmed") in set([(o['txid'], o['status']) for o in l1.rpc.listfunds()['outputs']])
|
|
|
|
# Restart, should still be confirmed (fails: unwinding blocks erases
|
|
# the confirmation, and we don't re-make it).
|
|
l1.restart()
|
|
wait_for(lambda: (closetxid, "confirmed") in set([(o['txid'], o['status']) for o in l1.rpc.listfunds()['outputs']]))
|
|
|
|
# It should send the to-wallet tx.
|
|
l2.wait_for_onchaind_broadcast('OUR_DELAYED_RETURN_TO_WALLET',
|
|
'OUR_UNILATERAL/DELAYED_OUTPUT_TO_US')
|
|
|
|
# 100 after l1 sees tx, it should be done.
|
|
bitcoind.generate_block(95)
|
|
wait_for(lambda: l1.rpc.listpeers()['peers'] == [])
|
|
|
|
wait_for(lambda: only_one(l2.rpc.listpeers(l1.info['id'])['peers'][0]['channels'])['status'] == [
|
|
'ONCHAIN:Tracking our own unilateral close',
|
|
'ONCHAIN:All outputs resolved: waiting 5 more blocks before forgetting channel'
|
|
])
|
|
|
|
# Now, 100 blocks l2 should be done.
|
|
bitcoind.generate_block(5)
|
|
wait_for(lambda: l2.rpc.listpeers()['peers'] == [])
|
|
|
|
# Only l1 has a direct output since all of l2's outputs are respent (it
|
|
# failed). Also the output should now be listed as confirmed since we
|
|
# generated some more blocks.
|
|
assert (closetxid, "confirmed") in set([(o['txid'], o['status']) for o in l1.rpc.listfunds()['outputs']])
|
|
|
|
# Check that the all the addresses match what we generated ourselves:
|
|
for o in l1.rpc.listfunds()['outputs']:
|
|
txout = bitcoind.rpc.gettxout(o['txid'], o['output'])
|
|
addr = scriptpubkey_addr(txout['scriptPubKey'])
|
|
assert(addr == o['address'])
|
|
|
|
addr = l1.bitcoin.getnewaddress()
|
|
l1.rpc.withdraw(addr, "all")
|
|
|
|
|
|
@pytest.mark.developer("needs DEVELOPER=1")
|
|
def test_shutdown(node_factory):
|
|
# Fail, in that it will exit before cleanup.
|
|
l1 = node_factory.get_node(may_fail=True)
|
|
if not node_factory.valgrind:
|
|
leaks = l1.rpc.dev_memleak()['leaks']
|
|
if len(leaks):
|
|
raise Exception("Node {} has memory leaks: {}"
|
|
.format(l1.daemon.lightning_dir, leaks))
|
|
l1.rpc.stop()
|
|
|
|
|
|
@flaky
|
|
@pytest.mark.developer("needs to set upfront_shutdown_script")
|
|
def test_option_upfront_shutdown_script(node_factory, bitcoind, executor):
|
|
# There's a workaround in channeld, that it treats incoming errors
|
|
# before both sides are locked in as warnings; this happens in
|
|
# this test, so l1 reports the error as a warning!
|
|
l1 = node_factory.get_node(start=False, allow_warning=True)
|
|
# Insist on upfront script we're not going to match.
|
|
l1.daemon.env["DEV_OPENINGD_UPFRONT_SHUTDOWN_SCRIPT"] = "76a91404b61f7dc1ea0dc99424464cc4064dc564d91e8988ac"
|
|
l1.start()
|
|
|
|
l2 = node_factory.get_node()
|
|
l1.rpc.connect(l2.info['id'], 'localhost', l2.port)
|
|
l1.fundchannel(l2, 1000000, False)
|
|
|
|
# This will block, as l12 will send an error but l2 will retry.
|
|
fut = executor.submit(l1.rpc.close, l2.info['id'])
|
|
|
|
# l2 will close unilaterally when it dislikes shutdown script.
|
|
l1.daemon.wait_for_log(r'scriptpubkey .* is not as agreed upfront \(76a91404b61f7dc1ea0dc99424464cc4064dc564d91e8988ac\)')
|
|
|
|
# Clear channel.
|
|
wait_for(lambda: len(bitcoind.rpc.getrawmempool()) != 0)
|
|
bitcoind.generate_block(1)
|
|
fut.result(TIMEOUT)
|
|
wait_for(lambda: [c['state'] for c in only_one(l1.rpc.listpeers()['peers'])['channels']] == ['ONCHAIN'])
|
|
wait_for(lambda: [c['state'] for c in only_one(l2.rpc.listpeers()['peers'])['channels']] == ['ONCHAIN'])
|
|
|
|
# Works when l2 closes channel, too.
|
|
l1.rpc.connect(l2.info['id'], 'localhost', l2.port)
|
|
l1.fundchannel(l2, 1000000, False)
|
|
|
|
l2.rpc.close(l1.info['id'])
|
|
|
|
# l2 will close unilaterally when it dislikes shutdown script.
|
|
l1.daemon.wait_for_log(r'scriptpubkey .* is not as agreed upfront \(76a91404b61f7dc1ea0dc99424464cc4064dc564d91e8988ac\)')
|
|
|
|
# Clear channel.
|
|
wait_for(lambda: len(bitcoind.rpc.getrawmempool()) != 0)
|
|
bitcoind.generate_block(1)
|
|
wait_for(lambda: [c['state'] for c in only_one(l1.rpc.listpeers()['peers'])['channels']] == ['ONCHAIN', 'ONCHAIN'])
|
|
wait_for(lambda: [c['state'] for c in only_one(l2.rpc.listpeers()['peers'])['channels']] == ['ONCHAIN', 'ONCHAIN'])
|
|
|
|
# Figure out what address it will try to use.
|
|
keyidx = int(l1.db_query("SELECT intval FROM vars WHERE name='bip32_max_index';")[0]['intval'])
|
|
|
|
# Expect 1 for change address, plus 1 for the funding address of the actual
|
|
# funding tx.
|
|
addr = l1.rpc.call('dev-listaddrs', [keyidx + 2])['addresses'][-1]
|
|
# the above used to be keyidx + 3, but that was when `fundchannel`
|
|
# used the `txprepare`-`txdiscard`-`txprepare` trick, which skipped
|
|
# one address in the discarded tx.
|
|
# Now we use PSBTs, which means we never discard and skip an address.
|
|
|
|
# Now, if we specify upfront and it's OK, all good.
|
|
l1.stop()
|
|
# We need to prepend the segwit version (0) and push opcode (14).
|
|
l1.daemon.env["DEV_OPENINGD_UPFRONT_SHUTDOWN_SCRIPT"] = '0014' + addr['bech32_redeemscript']
|
|
l1.start()
|
|
|
|
l1.rpc.connect(l2.info['id'], 'localhost', l2.port)
|
|
l1.rpc.fundchannel(l2.info['id'], 1000000)
|
|
l1.rpc.close(l2.info['id'])
|
|
wait_for(lambda: sorted([c['state'] for c in only_one(l1.rpc.listpeers()['peers'])['channels']]) == ['CLOSINGD_COMPLETE', 'ONCHAIN', 'ONCHAIN'])
|
|
|
|
|
|
@pytest.mark.developer("needs to set upfront_shutdown_script")
|
|
def test_invalid_upfront_shutdown_script(node_factory, bitcoind, executor):
|
|
l1, l2 = node_factory.line_graph(2, fundchannel=False)
|
|
|
|
l1 = node_factory.get_node(start=False, allow_warning=True)
|
|
# Insist on upfront script we're not going to match.
|
|
l1.daemon.env["DEV_OPENINGD_UPFRONT_SHUTDOWN_SCRIPT"] = "76a91404b61f7dc1ea0dc99424464cc4064dc564d91e8988ac00"
|
|
l1.start()
|
|
|
|
l2 = node_factory.get_node()
|
|
l1.rpc.connect(l2.info['id'], 'localhost', l2.port)
|
|
with pytest.raises(RpcError, match=r'Unacceptable upfront_shutdown_script'):
|
|
l1.fundchannel(l2, 1000000, False)
|
|
|
|
|
|
@pytest.mark.developer("needs to set upfront_shutdown_script")
|
|
@pytest.mark.slow_test
|
|
def test_segwit_shutdown_script(node_factory, bitcoind, executor):
|
|
"""
|
|
Try a range of future segwit versions as shutdown scripts. We create many nodes, so this is quite slow under valgrind
|
|
"""
|
|
l1 = node_factory.get_node(allow_warning=True)
|
|
|
|
# BOLT #2:
|
|
# 5. if (and only if) `option_shutdown_anysegwit` is negotiated:
|
|
# * `OP_1` through `OP_16` inclusive, followed by a single push of 2 to 40 bytes
|
|
# (witness program versions 1 through 16)
|
|
edge_valid = ['51020000', '5128' + '00' * 0x28,
|
|
'60020000', '6028' + '00' * 0x28]
|
|
other_valid = ['52020000', '5228' + '00' * 0x28,
|
|
'53020000', '5328' + '00' * 0x28,
|
|
'54020000', '5428' + '00' * 0x28,
|
|
'55020000', '5528' + '00' * 0x28,
|
|
'56020000', '5628' + '00' * 0x28,
|
|
'57020000', '5728' + '00' * 0x28,
|
|
'58020000', '5828' + '00' * 0x28,
|
|
'59020000', '5928' + '00' * 0x28,
|
|
'5A020000', '5A28' + '00' * 0x28,
|
|
'5B020000', '5B28' + '00' * 0x28,
|
|
'5C020000', '5C28' + '00' * 0x28,
|
|
'5D020000', '5D28' + '00' * 0x28,
|
|
'5E020000', '5E28' + '00' * 0x28,
|
|
'5F020000', '5F28' + '00' * 0x28]
|
|
|
|
invalid = ['50020000', # Not OP_1-OP_16
|
|
'61020000', # Not OP_1-OP_16
|
|
'5102000000', # Extra bytes
|
|
'510100', # Too short
|
|
'5129' + '00' * 0x29] # Too long
|
|
|
|
# Don't stress CI; just test edge cases
|
|
if SLOW_MACHINE:
|
|
valid = edge_valid
|
|
else:
|
|
valid = edge_valid + other_valid
|
|
|
|
# More efficient to create them all up-front.
|
|
nodes = node_factory.get_nodes(len(valid) + len(invalid))
|
|
|
|
# Give it one UTXO to spend for each node.
|
|
addresses = {}
|
|
for n in nodes:
|
|
addresses[l1.rpc.newaddr()['bech32']] = (10**6 + 100000) / 10**8
|
|
bitcoind.rpc.sendmany("", addresses)
|
|
bitcoind.generate_block(1)
|
|
wait_for(lambda: len(l1.rpc.listfunds()['outputs']) == len(addresses))
|
|
|
|
# FIXME: Since we don't support other non-v0 encodings, we need a protocol
|
|
# test for this (we're actually testing our upfront check, not the real
|
|
# shutdown one!),
|
|
for script in valid:
|
|
# Insist on upfront script we're not going to match.
|
|
l1.stop()
|
|
l1.daemon.env["DEV_OPENINGD_UPFRONT_SHUTDOWN_SCRIPT"] = script
|
|
l1.start()
|
|
|
|
l2 = nodes.pop()
|
|
l1.rpc.connect(l2.info['id'], 'localhost', l2.port)
|
|
l1.rpc.fundchannel(l2.info['id'], 10**6)
|
|
|
|
for script in invalid:
|
|
# Insist on upfront script we're not going to match.
|
|
l1.stop()
|
|
l1.daemon.env["DEV_OPENINGD_UPFRONT_SHUTDOWN_SCRIPT"] = script
|
|
l1.start()
|
|
|
|
l2 = nodes.pop()
|
|
l1.rpc.connect(l2.info['id'], 'localhost', l2.port)
|
|
with pytest.raises(RpcError, match=r'Unacceptable upfront_shutdown_script'):
|
|
l1.rpc.fundchannel(l2.info['id'], 10**6)
|
|
|
|
|
|
@pytest.mark.openchannel('v1')
|
|
def test_shutdown_alternate_txid(node_factory, bitcoind):
|
|
l1, l2 = node_factory.line_graph(2, fundchannel=False,
|
|
opts={'experimental-shutdown-wrong-funding': None,
|
|
'allow-deprecated-apis': True})
|
|
|
|
amount = 1000000
|
|
amount_msat = Millisatoshi(amount * 1000)
|
|
|
|
# Let's make a classic fundchannel mistake (wrong txid!)
|
|
addr = l1.rpc.fundchannel_start(l2.info['id'], amount_msat)['funding_address']
|
|
txid = bitcoind.rpc.sendtoaddress(addr, amount / 10**8)
|
|
|
|
# Gotta figure out which output manually :(
|
|
tx = bitcoind.rpc.getrawtransaction(txid, 1)
|
|
for n, out in enumerate(tx['vout']):
|
|
if scriptpubkey_addr(out['scriptPubKey']) == addr:
|
|
txout = n
|
|
|
|
bitcoind.generate_block(1, wait_for_mempool=1)
|
|
|
|
# Wrong txid, wrong txout!
|
|
wrong_txid = txid[16:] + txid[:16]
|
|
wrong_txout = txout ^ 1
|
|
l1.rpc.fundchannel_complete(l2.info['id'], wrong_txid, wrong_txout)
|
|
|
|
wait_for(lambda: only_one(l2.rpc.listpeers()['peers'])['channels'] != [])
|
|
wait_for(lambda: only_one(l2.rpc.listpeers()['peers'])['channels'][0]['state'] == 'CHANNELD_AWAITING_LOCKIN')
|
|
|
|
closeaddr = l1.rpc.newaddr()['bech32']
|
|
|
|
# Oops, try rescuing it!
|
|
l1.rpc.call('close', {'id': l2.info['id'], 'destination': closeaddr, 'wrong_funding': txid + ':' + str(txout)})
|
|
|
|
# Just make sure node has no funds.
|
|
assert l1.rpc.listfunds()['outputs'] == []
|
|
|
|
bitcoind.generate_block(100, wait_for_mempool=1)
|
|
sync_blockheight(bitcoind, [l1, l2])
|
|
|
|
# We will see our funds return.
|
|
assert len(l1.rpc.listfunds()['outputs']) == 1
|
|
|
|
wait_for(lambda: l2.rpc.listpeers()['peers'] == [])
|
|
wait_for(lambda: l1.rpc.listpeers()['peers'] == [])
|
|
|
|
|
|
@pytest.mark.developer("needs dev_disconnect")
|
|
def test_htlc_rexmit_while_closing(node_factory, executor):
|
|
"""Retranmitting an HTLC revocation while shutting down should work"""
|
|
# l1 disconnects after sending second COMMITMENT_SIGNED.
|
|
# Then it stops receiving after sending WIRE_SHUTDOWN (which is before it
|
|
# reads the revoke_and_ack).
|
|
disconnects = ['+WIRE_COMMITMENT_SIGNED*2',
|
|
'xWIRE_SHUTDOWN']
|
|
|
|
l1, l2 = node_factory.line_graph(2, opts=[{'may_reconnect': True,
|
|
'dev-no-reconnect': None,
|
|
'disconnect': disconnects},
|
|
{'may_reconnect': True,
|
|
'dev-no-reconnect': None}])
|
|
|
|
# Start payment, will disconnect
|
|
l1.pay(l2, 200000)
|
|
wait_for(lambda: only_one(l1.rpc.listpeers()['peers'])['connected'] is False)
|
|
|
|
# Tell it to close (will block)
|
|
fut = executor.submit(l1.rpc.close, l2.info['id'])
|
|
|
|
# Original problem was with multiple disconnects, but to simplify we make
|
|
# l2 send shutdown too.
|
|
fut2 = executor.submit(l2.rpc.close, l1.info['id'])
|
|
|
|
# Reconnect, shutdown will continue disconnect again
|
|
l1.rpc.connect(l2.info['id'], 'localhost', l2.port)
|
|
|
|
# Now l2 should be in CLOSINGD_SIGEXCHANGE, l1 still waiting on
|
|
# WIRE_REVOKE_AND_ACK.
|
|
wait_for(lambda: only_one(only_one(l2.rpc.listpeers()['peers'])['channels'])['state'] == 'CLOSINGD_SIGEXCHANGE')
|
|
assert only_one(only_one(l1.rpc.listpeers()['peers'])['channels'])['state'] == 'CHANNELD_SHUTTING_DOWN'
|
|
|
|
# They don't realize they're not talking, so disconnect and reconnect.
|
|
l1.rpc.disconnect(l2.info['id'], force=True)
|
|
|
|
# Now it hangs, since l1 is expecting rexmit of revoke-and-ack.
|
|
l1.rpc.connect(l2.info['id'], 'localhost', l2.port)
|
|
|
|
fut.result(TIMEOUT)
|
|
fut2.result(TIMEOUT)
|
|
|
|
|
|
@pytest.mark.openchannel('v1')
|
|
@pytest.mark.developer("needs dev_disconnect")
|
|
def test_you_forgot_closed_channel(node_factory, executor):
|
|
"""Ideally you'd keep talking to us about closed channels: simple"""
|
|
disconnects = ['@WIRE_CLOSING_SIGNED']
|
|
|
|
l1, l2 = node_factory.line_graph(2, opts=[{'may_reconnect': True,
|
|
'dev-no-reconnect': None},
|
|
{'may_reconnect': True,
|
|
'dev-no-reconnect': None,
|
|
'disconnect': disconnects}])
|
|
|
|
l1.pay(l2, 200000)
|
|
|
|
fut = executor.submit(l1.rpc.close, l2.info['id'])
|
|
|
|
# l2 considers the closing done, l1 does not
|
|
wait_for(lambda: only_one(only_one(l2.rpc.listpeers()['peers'])['channels'])['state'] == 'CLOSINGD_COMPLETE')
|
|
assert only_one(only_one(l1.rpc.listpeers()['peers'])['channels'])['state'] == 'CLOSINGD_SIGEXCHANGE'
|
|
|
|
# l1 reconnects, it should succeed.
|
|
l1.rpc.connect(l2.info['id'], 'localhost', l2.port)
|
|
fut.result(TIMEOUT)
|
|
|
|
|
|
@pytest.mark.developer("needs dev_disconnect")
|
|
def test_you_forgot_closed_channel_onchain(node_factory, bitcoind, executor):
|
|
"""Ideally you'd keep talking to us about closed channels: even if close is mined"""
|
|
disconnects = ['@WIRE_CLOSING_SIGNED']
|
|
|
|
l1, l2 = node_factory.line_graph(2, opts=[{'may_reconnect': True,
|
|
'dev-no-reconnect': None},
|
|
{'may_reconnect': True,
|
|
'dev-no-reconnect': None,
|
|
'disconnect': disconnects}])
|
|
|
|
l1.pay(l2, 200000)
|
|
|
|
fut = executor.submit(l1.rpc.close, l2.info['id'])
|
|
|
|
# l2 considers the closing done, l1 does not
|
|
wait_for(lambda: only_one(only_one(l2.rpc.listpeers()['peers'])['channels'])['state'] == 'CLOSINGD_COMPLETE')
|
|
assert only_one(only_one(l1.rpc.listpeers()['peers'])['channels'])['state'] == 'CLOSINGD_SIGEXCHANGE'
|
|
|
|
# l1 does not see any new blocks.
|
|
def no_new_blocks(req):
|
|
return {"result": {"blockhash": None, "block": None}}
|
|
|
|
l1.daemon.rpcproxy.mock_rpc('getrawblockbyheight', no_new_blocks)
|
|
|
|
# Close transaction mined
|
|
bitcoind.generate_block(1, wait_for_mempool=1)
|
|
|
|
wait_for(lambda: only_one(only_one(l2.rpc.listpeers()['peers'])['channels'])['state'] == 'ONCHAIN')
|
|
|
|
# l1 reconnects, it should succeed.
|
|
l1.rpc.connect(l2.info['id'], 'localhost', l2.port)
|
|
fut.result(TIMEOUT)
|
|
|
|
|
|
@unittest.skipIf(TEST_NETWORK == 'liquid-regtest', "Uses regtest addresses")
|
|
@pytest.mark.developer("too slow without fast polling for blocks")
|
|
def test_segwit_anyshutdown(node_factory, bitcoind, executor):
|
|
"""Try a range of future segwit versions for shutdown"""
|
|
l1, l2 = node_factory.line_graph(2, fundchannel=False)
|
|
|
|
l1.fundwallet(10**7)
|
|
|
|
# Based on BIP-320, but all changed to regtest.
|
|
addrs = ("BCRT1QW508D6QEJXTDG4Y5R3ZARVARY0C5XW7KYGT080",
|
|
"bcrt1qrp33g0q5c5txsp9arysrx4k6zdkfs4nce4xj0gdcccefvpysxf3qzf4jry",
|
|
"bcrt1pw508d6qejxtdg4y5r3zarvary0c5xw7kw508d6qejxtdg4y5r3zarvary0c5xw7k0ylj56",
|
|
"BCRT1SW50QT2UWHA",
|
|
"bcrt1zw508d6qejxtdg4y5r3zarvaryv2wuatf",
|
|
"bcrt1qqqqqp399et2xygdj5xreqhjjvcmzhxw4aywxecjdzew6hylgvseswlauz7",
|
|
"bcrt1pqqqqp399et2xygdj5xreqhjjvcmzhxw4aywxecjdzew6hylgvsesyga46z",
|
|
"bcrt1p0xlxvlhemja6c4dqv22uapctqupfhlxm9h8z3k2e72q4k9hcz7vqc8gma6")
|
|
|
|
for addr in addrs:
|
|
l1.rpc.connect(l2.info['id'], 'localhost', l2.port)
|
|
l1.rpc.fundchannel(l2.info['id'], 10**6)
|
|
# If we don't actually make a payment, two of the above cases fail
|
|
# because the resulting tx is too small! Balance channel so close
|
|
# has two outputs.
|
|
bitcoind.generate_block(1, wait_for_mempool=1)
|
|
wait_for(lambda: any([c['state'] == 'CHANNELD_NORMAL' for c in only_one(l1.rpc.listpeers()['peers'])['channels']]))
|
|
l1.pay(l2, 10**9 // 2)
|
|
l1.rpc.close(l2.info['id'], destination=addr)
|
|
bitcoind.generate_block(1, wait_for_mempool=1)
|
|
wait_for(lambda: all([c['state'] == 'ONCHAIN' for c in only_one(l1.rpc.listpeers()['peers'])['channels']]))
|
|
|
|
|
|
@pytest.mark.developer("needs to manipulate features")
|
|
@unittest.skipIf(TEST_NETWORK == 'liquid-regtest', "Uses regtest addresses")
|
|
def test_anysegwit_close_needs_feature(node_factory, bitcoind):
|
|
"""Rather than have peer reject our shutdown, we should refuse to shutdown toa v1+ address if they don't support it"""
|
|
# L2 says "no option_shutdown_anysegwit"
|
|
l1, l2 = node_factory.line_graph(2, opts=[{'may_reconnect': True},
|
|
{'may_reconnect': True,
|
|
'dev-force-features': -27}])
|
|
|
|
with pytest.raises(RpcError, match=r'Peer does not allow v1\+ shutdown addresses'):
|
|
l1.rpc.close(l2.info['id'], destination='bcrt1pw508d6qejxtdg4y5r3zarvary0c5xw7kw508d6qejxtdg4y5r3zarvary0c5xw7k0ylj56')
|
|
|
|
# From TFM: "Tell your friends to upgrade!"
|
|
l2.stop()
|
|
del l2.daemon.opts['dev-force-features']
|
|
l2.start()
|
|
|
|
# Now it will work!
|
|
l1.rpc.connect(l2.info['id'], 'localhost', l2.port)
|
|
l1.rpc.close(l2.info['id'], destination='bcrt1pw508d6qejxtdg4y5r3zarvary0c5xw7kw508d6qejxtdg4y5r3zarvary0c5xw7k0ylj56')
|
|
wait_for(lambda: only_one(only_one(l1.rpc.listpeers()['peers'])['channels'])['state'] == 'CLOSINGD_COMPLETE')
|
|
bitcoind.generate_block(1, wait_for_mempool=1)
|