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d5f0c08a88
No need to keep duplicate globals.
123 lines
3.6 KiB
C
123 lines
3.6 KiB
C
#include "bitcoin/block.h"
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#include "bitcoin/pullpush.h"
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#include "bitcoin/tx.h"
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#include <ccan/str/hex/hex.h>
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#include <common/type_to_string.h>
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/* Encoding is <blockhdr> <varint-num-txs> <tx>... */
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struct bitcoin_block *
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bitcoin_block_from_hex(const tal_t *ctx, const struct chainparams *chainparams,
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const char *hex, size_t hexlen)
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{
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struct bitcoin_block *b;
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u8 *linear_tx;
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const u8 *p;
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size_t len, i, num;
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if (hexlen && hex[hexlen-1] == '\n')
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hexlen--;
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/* Set up the block for success. */
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b = tal(ctx, struct bitcoin_block);
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/* De-hex the array. */
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len = hex_data_size(hexlen);
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p = linear_tx = tal_arr(ctx, u8, len);
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if (!hex_decode(hex, hexlen, linear_tx, len))
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return tal_free(b);
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b->hdr.version = pull_le32(&p, &len);
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pull(&p, &len, &b->hdr.prev_hash, sizeof(b->hdr.prev_hash));
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pull(&p, &len, &b->hdr.merkle_hash, sizeof(b->hdr.merkle_hash));
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b->hdr.timestamp = pull_le32(&p, &len);
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if (is_elements(chainparams)) {
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b->elements_hdr = tal(b, struct elements_block_hdr);
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b->elements_hdr->block_height = pull_le32(&p, &len);
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size_t challenge_len = pull_varint(&p, &len);
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b->elements_hdr->proof.challenge = tal_arr(b->elements_hdr, u8, challenge_len);
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pull(&p, &len, b->elements_hdr->proof.challenge, challenge_len);
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size_t solution_len = pull_varint(&p, &len);
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b->elements_hdr->proof.solution = tal_arr(b->elements_hdr, u8, solution_len);
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pull(&p, &len, b->elements_hdr->proof.solution, solution_len);
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} else {
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b->hdr.target = pull_le32(&p, &len);
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b->hdr.nonce = pull_le32(&p, &len);
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}
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num = pull_varint(&p, &len);
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b->tx = tal_arr(b, struct bitcoin_tx *, num);
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for (i = 0; i < num; i++) {
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b->tx[i] = pull_bitcoin_tx(b->tx, &p, &len);
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b->tx[i]->chainparams = chainparams;
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}
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/* We should end up not overrunning, nor have extra */
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if (!p || len)
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return tal_free(b);
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tal_free(linear_tx);
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return b;
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}
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void bitcoin_block_blkid(const struct bitcoin_block *b,
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struct bitcoin_blkid *out)
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{
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struct sha256_ctx shactx;
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u8 vt[VARINT_MAX_LEN];
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size_t vtlen;
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sha256_init(&shactx);
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sha256_le32(&shactx, b->hdr.version);
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sha256_update(&shactx, &b->hdr.prev_hash, sizeof(b->hdr.prev_hash));
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sha256_update(&shactx, &b->hdr.merkle_hash, sizeof(b->hdr.merkle_hash));
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sha256_le32(&shactx, b->hdr.timestamp);
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if (is_elements(chainparams)) {
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size_t clen = tal_bytelen(b->elements_hdr->proof.challenge);
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sha256_le32(&shactx, b->elements_hdr->block_height);
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vtlen = varint_put(vt, clen);
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sha256_update(&shactx, vt, vtlen);
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sha256_update(&shactx, b->elements_hdr->proof.challenge, clen);
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/* The solution is skipped, since that'd create a circular
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* dependency apparently */
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} else {
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sha256_le32(&shactx, b->hdr.target);
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sha256_le32(&shactx, b->hdr.nonce);
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}
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sha256_double_done(&shactx, &out->shad);
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}
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/* We do the same hex-reversing crud as txids. */
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bool bitcoin_blkid_from_hex(const char *hexstr, size_t hexstr_len,
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struct bitcoin_blkid *blockid)
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{
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struct bitcoin_txid fake_txid;
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if (!bitcoin_txid_from_hex(hexstr, hexstr_len, &fake_txid))
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return false;
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blockid->shad = fake_txid.shad;
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return true;
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}
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bool bitcoin_blkid_to_hex(const struct bitcoin_blkid *blockid,
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char *hexstr, size_t hexstr_len)
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{
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struct bitcoin_txid fake_txid;
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fake_txid.shad = blockid->shad;
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return bitcoin_txid_to_hex(&fake_txid, hexstr, hexstr_len);
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}
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static char *fmt_bitcoin_blkid(const tal_t *ctx,
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const struct bitcoin_blkid *blkid)
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{
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char *hexstr = tal_arr(ctx, char, hex_str_size(sizeof(*blkid)));
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bitcoin_blkid_to_hex(blkid, hexstr, hex_str_size(sizeof(*blkid)));
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return hexstr;
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}
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REGISTER_TYPE_TO_STRING(bitcoin_blkid, fmt_bitcoin_blkid);
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