from binascii import hexlify, unhexlify from concurrent import futures from decimal import Decimal from hashlib import sha256 from lightning import LightningRpc import copy import json import logging import queue import os import random import re import sqlite3 import string import sys import tempfile import threading import time import unittest import utils bitcoind = None TEST_DIR = tempfile.mkdtemp(prefix='lightning-') VALGRIND = os.getenv("NO_VALGRIND", "0") == "0" DEVELOPER = os.getenv("DEVELOPER", "0") == "1" TEST_DEBUG = os.getenv("TEST_DEBUG", "0") == "1" print("Testing results are in {}".format(TEST_DIR)) if TEST_DEBUG: logging.basicConfig(level=logging.DEBUG, stream=sys.stdout) logging.info("Tests running in '%s'", TEST_DIR) def to_json(arg): return json.loads(json.dumps(arg)) def setupBitcoind(directory): global bitcoind bitcoind = utils.BitcoinD(bitcoin_dir=directory, rpcport=28332) bitcoind.start() info = bitcoind.rpc.getblockchaininfo() # Make sure we have segwit and some funds if info['blocks'] < 432: logging.debug("SegWit not active, generating some more blocks") bitcoind.generate_block(432 - info['blocks']) elif bitcoind.rpc.getwalletinfo()['balance'] < 1: logging.debug("Insufficient balance, generating 1 block") bitcoind.generate_block(1) def wait_for(success, timeout=30, interval=0.1): start_time = time.time() while not success() and time.time() < start_time + timeout: time.sleep(interval) if time.time() > start_time + timeout: raise ValueError("Error waiting for {}", success) def sync_blockheight(nodes): target = bitcoind.rpc.getblockcount() for n in nodes: wait_for(lambda: n.rpc.getinfo()['blockheight'] == target) def tearDownBitcoind(): global bitcoind try: bitcoind.rpc.stop() except: bitcoind.proc.kill() bitcoind.proc.wait() class NodeFactory(object): """A factory to setup and start `lightningd` daemons. """ def __init__(self, testname, bitcoind, executor): self.testname = testname self.next_id = 1 self.nodes = [] self.executor = executor self.bitcoind = bitcoind def get_node(self, disconnect=None, options=None, may_fail=False, random_hsm=False): node_id = self.next_id self.next_id += 1 lightning_dir = os.path.join( TEST_DIR, self.testname, "lightning-{}/".format(node_id)) socket_path = os.path.join(lightning_dir, "lightning-rpc").format(node_id) port = 16330+node_id daemon = utils.LightningD(lightning_dir, self.bitcoind.bitcoin_dir, port=port, random_hsm=random_hsm) # If we have a disconnect string, dump it to a file for daemon. if disconnect: with open(os.path.join(lightning_dir, "dev_disconnect"), "w") as f: f.write("\n".join(disconnect)) daemon.cmd_line.append("--dev-disconnect=dev_disconnect") if DEVELOPER: daemon.cmd_line.append("--dev-fail-on-subdaemon-fail") daemon.env["LIGHTNINGD_DEV_MEMLEAK"] = "1" if VALGRIND: daemon.env["LIGHTNINGD_DEV_NO_BACKTRACE"] = "1" opts = [] if options is None else options for opt in opts: daemon.cmd_line.append(opt) rpc = LightningRpc(socket_path, self.executor) node = utils.LightningNode(daemon, rpc, self.bitcoind, self.executor, may_fail=may_fail) self.nodes.append(node) if VALGRIND: node.daemon.cmd_line = [ 'valgrind', '-q', '--trace-children=yes', '--trace-children-skip=*bitcoin-cli*', '--error-exitcode=7', '--log-file={}/valgrind-errors.%p'.format(node.daemon.lightning_dir) ] + node.daemon.cmd_line node.daemon.start() # Cache `getinfo`, we'll be using it a lot node.info = node.rpc.getinfo() return node def killall(self, expected_successes): """Returns true if every node we expected to succeed actually succeeded""" unexpected_fail = False for i in range(len(self.nodes)): leaks = None # leak detection upsets VALGRIND by reading uninitialized mem. # If it's dead, we'll catch it below. if not VALGRIND: try: # This also puts leaks in log. leaks = self.nodes[i].rpc.dev_memleak()['leaks'] except: pass try: self.nodes[i].stop() except: if expected_successes[i]: unexpected_fail = True if leaks is not None and len(leaks) != 0: raise Exception("Node {} has memory leaks: {}" .format(self.nodes[i].daemon.lightning_dir, leaks)) return not unexpected_fail class BaseLightningDTests(unittest.TestCase): def setUp(self): bitcoin_dir = os.path.join(TEST_DIR, self._testMethodName, "bitcoind") setupBitcoind(bitcoin_dir) # Most of the executor threads will be waiting for IO, so # let's have a few of them self.executor = futures.ThreadPoolExecutor(max_workers=20) self.node_factory = NodeFactory(self._testMethodName, bitcoind, self.executor) def getValgrindErrors(self, node): for error_file in os.listdir(node.daemon.lightning_dir): if not re.fullmatch("valgrind-errors.\d+", error_file): continue with open(os.path.join(node.daemon.lightning_dir, error_file), 'r') as f: errors = f.read().strip() if errors: return errors, error_file return None, None def printValgrindErrors(self, node): errors, fname = self.getValgrindErrors(node) if errors: print("-"*31, "Valgrind errors", "-"*32) print("Valgrind error file:", fname) print(errors) print("-"*80) return 1 if errors else 0 def getCrashLog(self, node): if node.may_fail: return None, None try: crashlog = os.path.join(node.daemon.lightning_dir, 'crash.log') with open(crashlog, 'r') as f: return f.readlines(), crashlog except: return None, None def printCrashLog(self, node): errors, fname = self.getCrashLog(node) if errors: print("-"*10, "{} (last 50 lines)".format(fname), "-"*10) for l in errors[-50:]: print(l, end='') print("-"*80) return 1 if errors else 0 def tearDown(self): ok = self.node_factory.killall([not n.may_fail for n in self.node_factory.nodes]) self.executor.shutdown(wait=False) tearDownBitcoind() err_count = 0 # Do not check for valgrind error files if it is disabled if VALGRIND: for node in self.node_factory.nodes: err_count += self.printValgrindErrors(node) if err_count: raise ValueError("{} nodes reported valgrind errors".format(err_count)) for node in self.node_factory.nodes: err_count += self.printCrashLog(node) if err_count: raise ValueError("{} nodes had crash.log files".format(err_count)) if not ok: raise Exception("At least one lightning exited with unexpected non-zero return code") class LightningDTests(BaseLightningDTests): def connect(self): l1 = self.node_factory.get_node() l2 = self.node_factory.get_node() ret = l1.rpc.connect(l2.info['id'], 'localhost', l2.info['port']) assert ret['id'] == l2.info['id'] l1.daemon.wait_for_log('WIRE_GOSSIPCTL_HAND_BACK_PEER') l2.daemon.wait_for_log('WIRE_GOSSIPCTL_HAND_BACK_PEER') return l1,l2 # Returns the short channel-id: :: def fund_channel(self, l1, l2, amount): addr = l1.rpc.newaddr()['address'] txid = l1.bitcoin.rpc.sendtoaddress(addr, amount / 10**8 + 0.01) tx = l1.bitcoin.rpc.getrawtransaction(txid) l1.rpc.addfunds(tx) # Generate a block, so we know next tx will be first in block. l1.bitcoin.generate_block(1) tx = l1.rpc.fundchannel(l2.info['id'], amount)['tx'] # Technically, this is async to fundchannel. l1.daemon.wait_for_log('sendrawtx exit 0') l1.bitcoin.generate_block(1) l1.daemon.wait_for_log('-> CHANNELD_NORMAL') l2.daemon.wait_for_log('-> CHANNELD_NORMAL') # Hacky way to find our output. decoded=bitcoind.rpc.decoderawtransaction(tx) for out in decoded['vout']: # Sometimes a float? Sometimes a decimal? WTF Python?! if out['scriptPubKey']['type'] == 'witness_v0_scripthash': if out['value'] == Decimal(amount) / 10**8 or out['value'] * 10**8 == amount: return "{}:1:{}".format(bitcoind.rpc.getblockcount(), out['n']) # Intermittent decoding failure. See if it decodes badly twice? decoded2=bitcoind.rpc.decoderawtransaction(tx) raise ValueError("Can't find {} payment in {} (1={} 2={})".format(amount, tx, decoded, decoded2)) def line_graph(self, n=2): """Build a line graph of the specified length and fund it. """ nodes = [self.node_factory.get_node() for _ in range(n)] for i in range(len(nodes)-1): nodes[i].rpc.connect( nodes[i+1].info['id'], 'localhost', nodes[i+1].info['port'] ) self.fund_channel(nodes[i], nodes[i+1], 10**6) return nodes def pay(self, lsrc, ldst, amt, label=None, async=False): if not label: label = ''.join(random.choice(string.ascii_letters + string.digits) for _ in range(20)) rhash = ldst.rpc.invoice(amt, label, label)['payment_hash'] assert ldst.rpc.listinvoice(label)[0]['complete'] == False routestep = { 'msatoshi' : amt, 'id' : ldst.info['id'], 'delay' : 5, 'channel': '1:1:1' } def wait_pay(): # Up to 10 seconds for payment to succeed. start_time = time.time() while not ldst.rpc.listinvoice(label)[0]['complete']: if time.time() > start_time + 10: raise TimeoutError('Payment timed out') time.sleep(0.1) if async: self.executor.submit(lsrc.rpc.sendpay, to_json([routestep]), rhash, async=False) return self.executor.submit(wait_pay) else: lsrc.rpc.sendpay(to_json([routestep]), rhash, async=False) # This waits until gossipd sees channel_update in both directions # (or for local channels, at least a local announcment) def wait_for_routes(self, l1, channel_ids): bitcoind.generate_block(5) # Could happen in any order... l1.daemon.wait_for_logs(['Channel {}\\(0\\) was updated'.format(c) for c in channel_ids] + ['Channel {}\\(1\\) was updated'.format(c) for c in channel_ids]) @unittest.skipIf(not DEVELOPER, "needs DEVELOPER=1") def test_shutdown(self): # Fail, in that it will exit before cleanup. l1 = self.node_factory.get_node(may_fail=True) if not VALGRIND: leaks = l1.rpc.dev_memleak()['leaks'] if len(leaks): raise Exception("Node {} has memory leaks: {}" .format(l1.daemon.lightning_dir, leaks)) l1.rpc.stop() def test_invoice(self): l1 = self.node_factory.get_node() before = int(time.time()) inv = l1.rpc.invoice(123000, 'label', 'description') after = int(time.time()) b11 = l1.rpc.decodepay(inv['bolt11']) assert b11['currency'] == 'tb' assert b11['timestamp'] >= before assert b11['timestamp'] <= after assert b11['payment_hash'] == inv['payment_hash'] assert b11['description'] == 'description' assert b11['expiry'] == 3600 assert b11['payee'] == l1.info['id'] # Check pay_index is null outputs = l1.db_query('SELECT pay_index IS NULL AS q FROM invoices WHERE label="label";') assert len(outputs) == 1 and outputs[0]['q'] != 0 # Check any-amount invoice inv = l1.rpc.invoice("any", 'label2', 'description2'); b11 = inv['bolt11'] # Amount usually comes after currency (tb in our case), # but an any-amount invoices will have no amount assert b11.startswith("lntb1") # By bech32 rules, the last '1' digit is the separator # between the human-readable and data parts. We want # to match the "lntb1" above with the '1' digit as the # separator, and not for example "lntb1m1....". assert b11.count('1') == 1 def test_invoice_expiry(self): l1,l2 = self.connect() chanid = self.fund_channel(l1, l2, 10**6) # Wait for route propagation. self.wait_for_routes(l1, [chanid]) inv = l2.rpc.invoice(123000, 'test_pay', 'description', 1)['bolt11'] time.sleep(2) self.assertRaises(ValueError, l1.rpc.pay, inv) assert l2.rpc.listinvoice('test_pay')[0]['complete'] == False assert l2.rpc.listinvoice('test_pay')[0]['expiry_time'] < time.time() def test_connect(self): l1,l2 = self.connect() # These should be in gossipd. assert l1.rpc.getpeer(l2.info['id'])['state'] == 'GOSSIPING' assert l2.rpc.getpeer(l1.info['id'])['state'] == 'GOSSIPING' # Both gossipds will have them as new peers once handed back. l1.daemon.wait_for_log('hand_back_peer {}: now local again'.format(l2.info['id'])) l2.daemon.wait_for_log('hand_back_peer {}: now local again'.format(l1.info['id'])) # Reconnect should be a noop ret = l1.rpc.connect(l2.info['id'], 'localhost', l2.info['port']) assert ret['id'] == l2.info['id'] ret = l2.rpc.connect(l1.info['id'], 'localhost', l1.info['port']) assert ret['id'] == l1.info['id'] # Should still only have one peer! assert len(l1.rpc.getpeers()) == 1 assert len(l2.rpc.getpeers()) == 1 def test_balance(self): l1,l2 = self.connect() self.fund_channel(l1, l2, 10**6) p1 = l1.rpc.getpeer(l2.info['id'], 'info') p2 = l2.rpc.getpeer(l1.info['id'], 'info') assert p1['msatoshi_to_us'] == 10**6 * 1000 assert p1['msatoshi_total'] == 10**6 * 1000 assert p2['msatoshi_to_us'] == 0 assert p2['msatoshi_total'] == 10**6 * 1000 def test_decodepay(self): l1 = self.node_factory.get_node() # BOLT #11: # > ### Please make a donation of any amount using payment_hash 0001020304050607080900010203040506070809000102030405060708090102 to me @03e7156ae33b0a208d0744199163177e909e80176e55d97a2f221ede0f934dd9ad # > lnbc1pvjluezpp5qqqsyqcyq5rqwzqfqqqsyqcyq5rqwzqfqqqsyqcyq5rqwzqfqypqdpl2pkx2ctnv5sxxmmwwd5kgetjypeh2ursdae8g6twvus8g6rfwvs8qun0dfjkxaq8rkx3yf5tcsyz3d73gafnh3cax9rn449d9p5uxz9ezhhypd0elx87sjle52x86fux2ypatgddc6k63n7erqz25le42c4u4ecky03ylcqca784w # # Breakdown: # # * `lnbc`: prefix, lightning on bitcoin mainnet # * `1`: Bech32 separator # * `pvjluez`: timestamp (1496314658) # * `p`: payment hash # * `p5`: `data_length` (`p` = 1, `5` = 20. 1 * 32 + 20 == 52) # * `qqqsyqcyq5rqwzqfqqqsyqcyq5rqwzqfqqqsyqcyq5rqwzqfqypq`: payment hash 0001020304050607080900010203040506070809000102030405060708090102 # * `d`: short description # * `pl`: `data_length` (`p` = 1, `l` = 31. 1 * 32 + 31 == 63) # * `2pkx2ctnv5sxxmmwwd5kgetjypeh2ursdae8g6twvus8g6rfwvs8qun0dfjkxaq`: 'Please consider supporting this project' # * `32vjcgqxyuj7nqphl3xmmhls2rkl3t97uan4j0xa87gj5779czc8p0z58zf5wpt9ggem6adl64cvawcxlef9djqwp2jzzfvs272504sp`: signature # * `0lkg3c`: Bech32 checksum b11 = l1.rpc.decodepay('lnbc1pvjluezpp5qqqsyqcyq5rqwzqfqqqsyqcyq5rqwzqfqqqsyqcyq5rqwzqfqypqdpl2pkx2ctnv5sxxmmwwd5kgetjypeh2ursdae8g6twvus8g6rfwvs8qun0dfjkxaq8rkx3yf5tcsyz3d73gafnh3cax9rn449d9p5uxz9ezhhypd0elx87sjle52x86fux2ypatgddc6k63n7erqz25le42c4u4ecky03ylcqca784w') assert b11['currency'] == 'bc' assert b11['timestamp'] == 1496314658 assert b11['payment_hash'] == '0001020304050607080900010203040506070809000102030405060708090102' assert b11['description'] == 'Please consider supporting this project' assert b11['expiry'] == 3600 assert b11['payee'] == '03e7156ae33b0a208d0744199163177e909e80176e55d97a2f221ede0f934dd9ad' # BOLT #11: # > ### Please send $3 for a cup of coffee to the same peer, within 1 minute # > lnbc2500u1pvjluezpp5qqqsyqcyq5rqwzqfqqqsyqcyq5rqwzqfqqqsyqcyq5rqwzqfqypqdq5xysxxatsyp3k7enxv4jsxqzpuaztrnwngzn3kdzw5hydlzf03qdgm2hdq27cqv3agm2awhz5se903vruatfhq77w3ls4evs3ch9zw97j25emudupq63nyw24cg27h2rspfj9srp # # Breakdown: # # * `lnbc`: prefix, lightning on bitcoin mainnet # * `2500u`: amount (2500 micro-bitcoin) # * `1`: Bech32 separator # * `pvjluez`: timestamp (1496314658) # * `p`: payment hash... # * `d`: short description # * `q5`: `data_length` (`q` = 0, `5` = 20. 0 * 32 + 20 == 20) # * `xysxxatsyp3k7enxv4js`: '1 cup coffee' # * `x`: expiry time # * `qz`: `data_length` (`q` = 0, `z` = 2. 0 * 32 + 2 == 2) # * `pu`: 60 seconds (`p` = 1, `u` = 28. 1 * 32 + 28 == 60) # * `azh8qt5w7qeewkmxtv55khqxvdfs9zzradsvj7rcej9knpzdwjykcq8gv4v2dl705pjadhpsc967zhzdpuwn5qzjm0s4hqm2u0vuhhqq`: signature # * `7vc09u`: Bech32 checksum b11 = l1.rpc.decodepay('lnbc2500u1pvjluezpp5qqqsyqcyq5rqwzqfqqqsyqcyq5rqwzqfqqqsyqcyq5rqwzqfqypqdq5xysxxatsyp3k7enxv4jsxqzpuaztrnwngzn3kdzw5hydlzf03qdgm2hdq27cqv3agm2awhz5se903vruatfhq77w3ls4evs3ch9zw97j25emudupq63nyw24cg27h2rspfj9srp') assert b11['currency'] == 'bc' assert b11['msatoshi'] == 2500 * 10**11 // 1000000 assert b11['timestamp'] == 1496314658 assert b11['payment_hash'] == '0001020304050607080900010203040506070809000102030405060708090102' assert b11['description'] == '1 cup coffee' assert b11['expiry'] == 60 assert b11['payee'] == '03e7156ae33b0a208d0744199163177e909e80176e55d97a2f221ede0f934dd9ad' # BOLT #11: # > ### Now send $24 for an entire list of things (hashed) # > lnbc20m1pvjluezpp5qqqsyqcyq5rqwzqfqqqsyqcyq5rqwzqfqqqsyqcyq5rqwzqfqypqhp58yjmdan79s6qqdhdzgynm4zwqd5d7xmw5fk98klysy043l2ahrqscc6gd6ql3jrc5yzme8v4ntcewwz5cnw92tz0pc8qcuufvq7khhr8wpald05e92xw006sq94mg8v2ndf4sefvf9sygkshp5zfem29trqq2yxxz7 # # Breakdown: # # * `lnbc`: prefix, lightning on bitcoin mainnet # * `20m`: amount (20 milli-bitcoin) # * `1`: Bech32 separator # * `pvjluez`: timestamp (1496314658) # * `p`: payment hash... # * `h`: tagged field: hash of description # * `p5`: `data_length` (`p` = 1, `5` = 20. 1 * 32 + 20 == 52) # * `8yjmdan79s6qqdhdzgynm4zwqd5d7xmw5fk98klysy043l2ahrqs`: SHA256 of 'One piece of chocolate cake, one icecream cone, one pickle, one slice of swiss cheese, one slice of salami, one lollypop, one piece of cherry pie, one sausage, one cupcake, and one slice of watermelon' # * `vjfls3ljx9e93jkw0kw40yxn4pevgzflf83qh2852esjddv4xk4z70nehrdcxa4fk0t6hlcc6vrxywke6njenk7yzkzw0quqcwxphkcp`: signature # * `vam37w`: Bech32 checksum b11 = l1.rpc.decodepay('lnbc20m1pvjluezpp5qqqsyqcyq5rqwzqfqqqsyqcyq5rqwzqfqqqsyqcyq5rqwzqfqypqhp58yjmdan79s6qqdhdzgynm4zwqd5d7xmw5fk98klysy043l2ahrqscc6gd6ql3jrc5yzme8v4ntcewwz5cnw92tz0pc8qcuufvq7khhr8wpald05e92xw006sq94mg8v2ndf4sefvf9sygkshp5zfem29trqq2yxxz7', 'One piece of chocolate cake, one icecream cone, one pickle, one slice of swiss cheese, one slice of salami, one lollypop, one piece of cherry pie, one sausage, one cupcake, and one slice of watermelon') assert b11['currency'] == 'bc' assert b11['msatoshi'] == 20 * 10**11 // 1000 assert b11['timestamp'] == 1496314658 assert b11['payment_hash'] == '0001020304050607080900010203040506070809000102030405060708090102' assert b11['expiry'] == 3600 assert b11['payee'] == '03e7156ae33b0a208d0744199163177e909e80176e55d97a2f221ede0f934dd9ad' # > ### The same, on testnet, with a fallback address mk2QpYatsKicvFVuTAQLBryyccRXMUaGHP # > lntb20m1pvjluezhp58yjmdan79s6qqdhdzgynm4zwqd5d7xmw5fk98klysy043l2ahrqspp5qqqsyqcyq5rqwzqfqqqsyqcyq5rqwzqfqqqsyqcyq5rqwzqfqypqfpp3x9et2e20v6pu37c5d9vax37wxq72un98kmzzhznpurw9sgl2v0nklu2g4d0keph5t7tj9tcqd8rexnd07ux4uv2cjvcqwaxgj7v4uwn5wmypjd5n69z2xm3xgksg28nwht7f6zspwp3f9t # # Breakdown: # # * `lntb`: prefix, lightning on bitcoin testnet # * `20m`: amount (20 milli-bitcoin) # * `1`: Bech32 separator # * `pvjluez`: timestamp (1496314658) # * `p`: payment hash... # * `f`: tagged field: fallback address # * `pp`: `data_length` (`p` = 1. 1 * 32 + 1 == 33) # * `3x9et2e20v6pu37c5d9vax37wxq72un98`: `3` = 17, so P2PKH address # * `h`: tagged field: hash of description... # * `qh84fmvn2klvglsjxfy0vq2mz6t9kjfzlxfwgljj35w2kwa60qv49k7jlsgx43yhs9nuutllkhhnt090mmenuhp8ue33pv4klmrzlcqp`: signature # * `us2s2r`: Bech32 checksum b11 = l1.rpc.decodepay('lntb20m1pvjluezhp58yjmdan79s6qqdhdzgynm4zwqd5d7xmw5fk98klysy043l2ahrqspp5qqqsyqcyq5rqwzqfqqqsyqcyq5rqwzqfqqqsyqcyq5rqwzqfqypqfpp3x9et2e20v6pu37c5d9vax37wxq72un98kmzzhznpurw9sgl2v0nklu2g4d0keph5t7tj9tcqd8rexnd07ux4uv2cjvcqwaxgj7v4uwn5wmypjd5n69z2xm3xgksg28nwht7f6zspwp3f9t', 'One piece of chocolate cake, one icecream cone, one pickle, one slice of swiss cheese, one slice of salami, one lollypop, one piece of cherry pie, one sausage, one cupcake, and one slice of watermelon') assert b11['currency'] == 'tb' assert b11['msatoshi'] == 20 * 10**11 // 1000 assert b11['timestamp'] == 1496314658 assert b11['payment_hash'] == '0001020304050607080900010203040506070809000102030405060708090102' assert b11['expiry'] == 3600 assert b11['payee'] == '03e7156ae33b0a208d0744199163177e909e80176e55d97a2f221ede0f934dd9ad' assert b11['fallback']['type'] == 'P2PKH' assert b11['fallback']['addr'] == 'mk2QpYatsKicvFVuTAQLBryyccRXMUaGHP' # > ### On mainnet, with fallback address 1RustyRX2oai4EYYDpQGWvEL62BBGqN9T with extra routing info to go via nodes 029e03a901b85534ff1e92c43c74431f7ce72046060fcf7a95c37e148f78c77255 then 039e03a901b85534ff1e92c43c74431f7ce72046060fcf7a95c37e148f78c77255 # > lnbc20m1pvjluezpp5qqqsyqcyq5rqwzqfqqqsyqcyq5rqwzqfqqqsyqcyq5rqwzqfqypqhp58yjmdan79s6qqdhdzgynm4zwqd5d7xmw5fk98klysy043l2ahrqsfpp3qjmp7lwpagxun9pygexvgpjdc4jdj85fr9yq20q82gphp2nflc7jtzrcazrra7wwgzxqc8u7754cdlpfrmccae92qgzqvzq2ps8pqqqqqqpqqqqq9qqqvpeuqafqxu92d8lr6fvg0r5gv0heeeqgcrqlnm6jhphu9y00rrhy4grqszsvpcgpy9qqqqqqgqqqqq7qqzqj9n4evl6mr5aj9f58zp6fyjzup6ywn3x6sk8akg5v4tgn2q8g4fhx05wf6juaxu9760yp46454gpg5mtzgerlzezqcqvjnhjh8z3g2qqdhhwkj # # Breakdown: # # * `lnbc`: prefix, lightning on bitcoin mainnet # * `20m`: amount (20 milli-bitcoin) # * `1`: Bech32 separator # * `pvjluez`: timestamp (1496314658) # * `p`: payment hash... # * `h`: tagged field: hash of description... # * `f`: tagged field: fallback address # * `pp`: `data_length` (`p` = 1. 1 * 32 + 1 == 33) # * `3` = 17, so P2PKH address # * `qjmp7lwpagxun9pygexvgpjdc4jdj85f`: 160 bit P2PKH address # * `r`: tagged field: route information # * `9y`: `data_length` (`9` = 5, `y` = 4. 5 * 32 + 4 = 164) # `q20q82gphp2nflc7jtzrcazrra7wwgzxqc8u7754cdlpfrmccae92qgzqvzq2ps8pqqqqqqqqqqqq9qqqvpeuqafqxu92d8lr6fvg0r5gv0heeeqgcrqlnm6jhphu9y00rrhy4grqszsvpcgpy9qqqqqqqqqqqq7qqzq`: pubkey `029e03a901b85534ff1e92c43c74431f7ce72046060fcf7a95c37e148f78c77255`, `short_channel_id` 0102030405060708, `fee_base_msat` 1 millisatoshi, `fee_proportional_millionths` 20, `cltv_expiry_delta` 3. pubkey `039e03a901b85534ff1e92c43c74431f7ce72046060fcf7a95c37e148f78c77255`, `short_channel_id` 030405060708090a, `fee_base_msat` 2 millisatoshi, `fee_proportional_millionths` 30, `cltv_expiry_delta` 4. # * `j9n4evl6mr5aj9f58zp6fyjzup6ywn3x6sk8akg5v4tgn2q8g4fhx05wf6juaxu9760yp46454gpg5mtzgerlzezqcqvjnhjh8z3g2qq`: signature # * `dhhwkj`: Bech32 checksum b11 = l1.rpc.decodepay('lnbc20m1pvjluezpp5qqqsyqcyq5rqwzqfqqqsyqcyq5rqwzqfqqqsyqcyq5rqwzqfqypqhp58yjmdan79s6qqdhdzgynm4zwqd5d7xmw5fk98klysy043l2ahrqsfpp3qjmp7lwpagxun9pygexvgpjdc4jdj85fr9yq20q82gphp2nflc7jtzrcazrra7wwgzxqc8u7754cdlpfrmccae92qgzqvzq2ps8pqqqqqqpqqqqq9qqqvpeuqafqxu92d8lr6fvg0r5gv0heeeqgcrqlnm6jhphu9y00rrhy4grqszsvpcgpy9qqqqqqgqqqqq7qqzqj9n4evl6mr5aj9f58zp6fyjzup6ywn3x6sk8akg5v4tgn2q8g4fhx05wf6juaxu9760yp46454gpg5mtzgerlzezqcqvjnhjh8z3g2qqdhhwkj', 'One piece of chocolate cake, one icecream cone, one pickle, one slice of swiss cheese, one slice of salami, one lollypop, one piece of cherry pie, one sausage, one cupcake, and one slice of watermelon') assert b11['currency'] == 'bc' assert b11['msatoshi'] == 20 * 10**11 // 1000 assert b11['timestamp'] == 1496314658 assert b11['payment_hash'] == '0001020304050607080900010203040506070809000102030405060708090102' assert b11['expiry'] == 3600 assert b11['payee'] == '03e7156ae33b0a208d0744199163177e909e80176e55d97a2f221ede0f934dd9ad' assert b11['fallback']['type'] == 'P2PKH' assert b11['fallback']['addr'] == '1RustyRX2oai4EYYDpQGWvEL62BBGqN9T' assert len(b11['routes']) == 1 assert len(b11['routes'][0]) == 2 assert b11['routes'][0][0]['pubkey'] == '029e03a901b85534ff1e92c43c74431f7ce72046060fcf7a95c37e148f78c77255' # 0x010203:0x040506:0x0708 assert b11['routes'][0][0]['short_channel_id'] == '66051:263430:1800' assert b11['routes'][0][0]['fee_base_msat'] == 1 assert b11['routes'][0][0]['fee_proportional_millionths'] == 20 assert b11['routes'][0][0]['cltv_expiry_delta'] == 3 assert b11['routes'][0][1]['pubkey'] == '039e03a901b85534ff1e92c43c74431f7ce72046060fcf7a95c37e148f78c77255' # 0x030405:0x060708:0x090a assert b11['routes'][0][1]['short_channel_id'] == '197637:395016:2314' assert b11['routes'][0][1]['fee_base_msat'] == 2 assert b11['routes'][0][1]['fee_proportional_millionths'] == 30 assert b11['routes'][0][1]['cltv_expiry_delta'] == 4 # > ### On mainnet, with fallback (P2SH) address 3EktnHQD7RiAE6uzMj2ZifT9YgRrkSgzQX # > lnbc20m1pvjluezhp58yjmdan79s6qqdhdzgynm4zwqd5d7xmw5fk98klysy043l2ahrqspp5qqqsyqcyq5rqwzqfqqqsyqcyq5rqwzqfqqqsyqcyq5rqwzqfqypqfppj3a24vwu6r8ejrss3axul8rxldph2q7z9kmrgvr7xlaqm47apw3d48zm203kzcq357a4ls9al2ea73r8jcceyjtya6fu5wzzpe50zrge6ulk4nvjcpxlekvmxl6qcs9j3tz0469gq5g658y # # Breakdown: # # * `lnbc`: prefix, lightning on bitcoin mainnet # * `20m`: amount (20 milli-bitcoin) # * `1`: Bech32 separator # * `pvjluez`: timestamp (1496314658) # * `p`: payment hash... # * `f`: tagged field: fallback address. # * `pp`: `data_length` (`p` = 1. 1 * 32 + 1 == 33) # * `j3a24vwu6r8ejrss3axul8rxldph2q7z9`: `j` = 18, so P2SH address # * `h`: tagged field: hash of description... # * `2jhz8j78lv2jynuzmz6g8ve53he7pheeype33zlja5azae957585uu7x59w0f2l3rugyva6zpu394y4rh093j6wxze0ldsvk757a9msq`: signature # * `mf9swh`: Bech32 checksum b11 = l1.rpc.decodepay('lnbc20m1pvjluezhp58yjmdan79s6qqdhdzgynm4zwqd5d7xmw5fk98klysy043l2ahrqspp5qqqsyqcyq5rqwzqfqqqsyqcyq5rqwzqfqqqsyqcyq5rqwzqfqypqfppj3a24vwu6r8ejrss3axul8rxldph2q7z9kmrgvr7xlaqm47apw3d48zm203kzcq357a4ls9al2ea73r8jcceyjtya6fu5wzzpe50zrge6ulk4nvjcpxlekvmxl6qcs9j3tz0469gq5g658y', 'One piece of chocolate cake, one icecream cone, one pickle, one slice of swiss cheese, one slice of salami, one lollypop, one piece of cherry pie, one sausage, one cupcake, and one slice of watermelon') assert b11['currency'] == 'bc' assert b11['msatoshi'] == 20 * 10**11 // 1000 assert b11['timestamp'] == 1496314658 assert b11['payment_hash'] == '0001020304050607080900010203040506070809000102030405060708090102' assert b11['expiry'] == 3600 assert b11['payee'] == '03e7156ae33b0a208d0744199163177e909e80176e55d97a2f221ede0f934dd9ad' assert b11['fallback']['type'] == 'P2SH' assert b11['fallback']['addr'] == '3EktnHQD7RiAE6uzMj2ZifT9YgRrkSgzQX' # > ### On mainnet, with fallback (P2WPKH) address bc1qw508d6qejxtdg4y5r3zarvary0c5xw7kv8f3t4 # > lnbc20m1pvjluezhp58yjmdan79s6qqdhdzgynm4zwqd5d7xmw5fk98klysy043l2ahrqspp5qqqsyqcyq5rqwzqfqqqsyqcyq5rqwzqfqqqsyqcyq5rqwzqfqypqfppqw508d6qejxtdg4y5r3zarvary0c5xw7kepvrhrm9s57hejg0p662ur5j5cr03890fa7k2pypgttmh4897d3raaq85a293e9jpuqwl0rnfuwzam7yr8e690nd2ypcq9hlkdwdvycqa0qza8 # # * `lnbc`: prefix, lightning on bitcoin mainnet # * `20m`: amount (20 milli-bitcoin) # * `1`: Bech32 separator # * `pvjluez`: timestamp (1496314658) # * `p`: payment hash... # * `f`: tagged field: fallback address. # * `pp`: `data_length` (`p` = 1. 1 * 32 + 1 == 33) # * `q`: 0, so witness version 0. # * `qw508d6qejxtdg4y5r3zarvary0c5xw7k`: 160 bits = P2WPKH. # * `h`: tagged field: hash of description... # * `gw6tk8z0p0qdy9ulggx65lvfsg3nxxhqjxuf2fvmkhl9f4jc74gy44d5ua9us509prqz3e7vjxrftn3jnk7nrglvahxf7arye5llphgq`: signature # * `qdtpa4`: Bech32 checksum b11 = l1.rpc.decodepay('lnbc20m1pvjluezhp58yjmdan79s6qqdhdzgynm4zwqd5d7xmw5fk98klysy043l2ahrqspp5qqqsyqcyq5rqwzqfqqqsyqcyq5rqwzqfqqqsyqcyq5rqwzqfqypqfppqw508d6qejxtdg4y5r3zarvary0c5xw7kepvrhrm9s57hejg0p662ur5j5cr03890fa7k2pypgttmh4897d3raaq85a293e9jpuqwl0rnfuwzam7yr8e690nd2ypcq9hlkdwdvycqa0qza8', 'One piece of chocolate cake, one icecream cone, one pickle, one slice of swiss cheese, one slice of salami, one lollypop, one piece of cherry pie, one sausage, one cupcake, and one slice of watermelon') assert b11['currency'] == 'bc' assert b11['msatoshi'] == 20 * 10**11 // 1000 assert b11['timestamp'] == 1496314658 assert b11['payment_hash'] == '0001020304050607080900010203040506070809000102030405060708090102' assert b11['expiry'] == 3600 assert b11['payee'] == '03e7156ae33b0a208d0744199163177e909e80176e55d97a2f221ede0f934dd9ad' assert b11['fallback']['type'] == 'P2WPKH' assert b11['fallback']['addr'] == 'bc1qw508d6qejxtdg4y5r3zarvary0c5xw7kv8f3t4' # > ### On mainnet, with fallback (P2WSH) address bc1qrp33g0q5c5txsp9arysrx4k6zdkfs4nce4xj0gdcccefvpysxf3qccfmv3 # > lnbc20m1pvjluezhp58yjmdan79s6qqdhdzgynm4zwqd5d7xmw5fk98klysy043l2ahrqspp5qqqsyqcyq5rqwzqfqqqsyqcyq5rqwzqfqqqsyqcyq5rqwzqfqypqfp4qrp33g0q5c5txsp9arysrx4k6zdkfs4nce4xj0gdcccefvpysxf3q28j0v3rwgy9pvjnd48ee2pl8xrpxysd5g44td63g6xcjcu003j3qe8878hluqlvl3km8rm92f5stamd3jw763n3hck0ct7p8wwj463cql26ava # # * `lnbc`: prefix, lightning on bitcoin mainnet # * `20m`: amount (20 milli-bitcoin) # * `1`: Bech32 separator # * `pvjluez`: timestamp (1496314658) # * `p`: payment hash... # * `f`: tagged field: fallback address. # * `p4`: `data_length` (`p` = 1, `4` = 21. 1 * 32 + 21 == 53) # * `q`: 0, so witness version 0. # * `rp33g0q5c5txsp9arysrx4k6zdkfs4nce4xj0gdcccefvpysxf3q`: 260 bits = P2WSH. # * `h`: tagged field: hash of description... # * `5yps56lmsvgcrf476flet6js02m93kgasews8q3jhtp7d6cqckmh70650maq4u65tk53ypszy77v9ng9h2z3q3eqhtc3ewgmmv2grasp`: signature # * `akvd7y`: Bech32 checksum b11 = l1.rpc.decodepay('lnbc20m1pvjluezhp58yjmdan79s6qqdhdzgynm4zwqd5d7xmw5fk98klysy043l2ahrqspp5qqqsyqcyq5rqwzqfqqqsyqcyq5rqwzqfqqqsyqcyq5rqwzqfqypqfp4qrp33g0q5c5txsp9arysrx4k6zdkfs4nce4xj0gdcccefvpysxf3q28j0v3rwgy9pvjnd48ee2pl8xrpxysd5g44td63g6xcjcu003j3qe8878hluqlvl3km8rm92f5stamd3jw763n3hck0ct7p8wwj463cql26ava', 'One piece of chocolate cake, one icecream cone, one pickle, one slice of swiss cheese, one slice of salami, one lollypop, one piece of cherry pie, one sausage, one cupcake, and one slice of watermelon') assert b11['currency'] == 'bc' assert b11['msatoshi'] == 20 * 10**11 // 1000 assert b11['timestamp'] == 1496314658 assert b11['payment_hash'] == '0001020304050607080900010203040506070809000102030405060708090102' assert b11['expiry'] == 3600 assert b11['payee'] == '03e7156ae33b0a208d0744199163177e909e80176e55d97a2f221ede0f934dd9ad' assert b11['fallback']['type'] == 'P2WSH' assert b11['fallback']['addr'] == 'bc1qrp33g0q5c5txsp9arysrx4k6zdkfs4nce4xj0gdcccefvpysxf3qccfmv3' def test_sendpay(self): l1,l2 = self.connect() self.fund_channel(l1, l2, 10**6) amt = 200000000 rhash = l2.rpc.invoice(amt, 'testpayment2', 'desc')['payment_hash'] assert l2.rpc.listinvoice('testpayment2')[0]['complete'] == False routestep = { 'msatoshi' : amt, 'id' : l2.info['id'], 'delay' : 5, 'channel': '1:1:1' } # Insufficient funds. rs = copy.deepcopy(routestep) rs['msatoshi'] = rs['msatoshi'] - 1 self.assertRaises(ValueError, l1.rpc.sendpay, to_json([rs]), rhash) assert l2.rpc.listinvoice('testpayment2')[0]['complete'] == False # Gross overpayment (more than factor of 2) rs = copy.deepcopy(routestep) rs['msatoshi'] = rs['msatoshi'] * 2 + 1 self.assertRaises(ValueError, l1.rpc.sendpay, to_json([rs]), rhash) assert l2.rpc.listinvoice('testpayment2')[0]['complete'] == False # Insufficient delay. rs = copy.deepcopy(routestep) rs['delay'] = rs['delay'] - 2 self.assertRaises(ValueError, l1.rpc.sendpay, to_json([rs]), rhash) assert l2.rpc.listinvoice('testpayment2')[0]['complete'] == False # Bad ID. rs = copy.deepcopy(routestep) rs['id'] = '00000000000000000000000000000000' self.assertRaises(ValueError, l1.rpc.sendpay, to_json([rs]), rhash) assert l2.rpc.listinvoice('testpayment2')[0]['complete'] == False # FIXME: test paying via another node, should fail to pay twice. p1 = l1.rpc.getpeer(l2.info['id'], 'info') p2 = l2.rpc.getpeer(l1.info['id'], 'info') assert p1['msatoshi_to_us'] == 10**6 * 1000 assert p1['msatoshi_total'] == 10**6 * 1000 assert p2['msatoshi_to_us'] == 0 assert p2['msatoshi_total'] == 10**6 * 1000 # This works. l1.rpc.sendpay(to_json([routestep]), rhash) assert l2.rpc.listinvoice('testpayment2')[0]['complete'] == True assert l2.rpc.listinvoice('testpayment2')[0]['pay_index'] == 1 assert l2.rpc.listinvoice('testpayment2')[0]['msatoshi_received'] == rs['msatoshi'] # Balances should reflect it. time.sleep(1) p1 = l1.rpc.getpeer(l2.info['id'], 'info') p2 = l2.rpc.getpeer(l1.info['id'], 'info') assert p1['msatoshi_to_us'] == 10**6 * 1000 - amt assert p1['msatoshi_total'] == 10**6 * 1000 assert p2['msatoshi_to_us'] == amt assert p2['msatoshi_total'] == 10**6 * 1000 # Repeat will "succeed", but won't actually send anything (duplicate) assert not l1.daemon.is_in_log('... succeeded') l1.rpc.sendpay(to_json([routestep]), rhash) l1.daemon.wait_for_log('... succeeded') assert l2.rpc.listinvoice('testpayment2')[0]['complete'] == True assert l2.rpc.listinvoice('testpayment2')[0]['msatoshi_received'] == rs['msatoshi'] # Overpaying by "only" a factor of 2 succeeds. rhash = l2.rpc.invoice(amt, 'testpayment3', 'desc')['payment_hash'] assert l2.rpc.listinvoice('testpayment3')[0]['complete'] == False routestep = { 'msatoshi' : amt * 2, 'id' : l2.info['id'], 'delay' : 5, 'channel': '1:1:1'} l1.rpc.sendpay(to_json([routestep]), rhash) assert l2.rpc.listinvoice('testpayment3')[0]['complete'] == True assert l2.rpc.listinvoice('testpayment3')[0]['msatoshi_received'] == amt*2 def test_sendpay_cant_afford(self): l1,l2 = self.connect() # Note, this is in SATOSHI, rest are in MILLISATOSHI! self.fund_channel(l1, l2, 10**6) # Can't pay more than channel capacity. self.assertRaises(ValueError, self.pay, l1, l2, 10**9 + 1) # This is the fee, which needs to be taken into account for l1. available = 10**9 - 6720 # Reserve is 1%. reserve = 10**7 # Can't pay past reserve. self.assertRaises(ValueError, self.pay, l1, l2, available) self.assertRaises(ValueError, self.pay, l1, l2, available - reserve + 1) # Can pay up to reserve (1%) self.pay(l1, l2, available - reserve) # And now it can't pay back, due to its own reserve. self.assertRaises(ValueError, self.pay, l2, l1, available - reserve) # But this should work. self.pay(l2, l1, available - reserve*2) def test_pay(self): l1,l2 = self.connect() chanid = self.fund_channel(l1, l2, 10**6) # Wait for route propagation. self.wait_for_routes(l1, [chanid]) inv = l2.rpc.invoice(123000, 'test_pay', 'description')['bolt11'] l1.rpc.pay(inv) assert l2.rpc.listinvoice('test_pay')[0]['complete'] == True # Repeat payments are NOPs (if valid): we can hand null. l1.rpc.pay(inv, None) # This won't work: can't provide an amount (even if correct!) self.assertRaises(ValueError, l1.rpc.pay, inv, 123000) self.assertRaises(ValueError, l1.rpc.pay, inv, 122000) # Check pay_index is not null outputs = l2.db_query('SELECT pay_index IS NOT NULL AS q FROM invoices WHERE label="label";') assert len(outputs) == 1 and outputs[0]['q'] != 0 # Check payment of any-amount invoice. for i in range(5): label = "any{}".format(i) inv = l2.rpc.invoice("any", label, 'description')['bolt11'] # Must provide an amount! self.assertRaises(ValueError, l1.rpc.pay, inv) self.assertRaises(ValueError, l1.rpc.pay, inv, None) l1.rpc.pay(inv, random.randint(1000, 999999)) def test_bad_opening(self): # l1 asks for a too-long locktime l1 = self.node_factory.get_node(options=['--locktime-blocks=100']) l2 = self.node_factory.get_node(options=['--max-locktime-blocks=99']) ret = l1.rpc.connect(l2.info['id'], 'localhost', l2.info['port']) assert ret['id'] == l2.info['id'] l1.daemon.wait_for_log('WIRE_GOSSIPCTL_HAND_BACK_PEER') l2.daemon.wait_for_log('WIRE_GOSSIPCTL_HAND_BACK_PEER') addr = l1.rpc.newaddr()['address'] txid = l1.bitcoin.rpc.sendtoaddress(addr, 10**6 / 10**8 + 0.01) tx = l1.bitcoin.rpc.getrawtransaction(txid) l1.rpc.addfunds(tx) self.assertRaises(ValueError, l1.rpc.fundchannel, l2.info['id'], 10**6) l2.daemon.wait_for_log('to_self_delay 100 larger than 99') def test_closing(self): l1,l2 = self.connect() self.fund_channel(l1, l2, 10**6) self.pay(l1, l2, 200000000) assert l1.bitcoin.rpc.getmempoolinfo()['size'] == 0 # This should return, then close. l1.rpc.close(l2.info['id']) l1.daemon.wait_for_log('-> CHANNELD_SHUTTING_DOWN') l2.daemon.wait_for_log('-> CHANNELD_SHUTTING_DOWN') l1.daemon.wait_for_log('-> CLOSINGD_SIGEXCHANGE') l2.daemon.wait_for_log('-> CLOSINGD_SIGEXCHANGE') # And should put closing into mempool. l1.daemon.wait_for_log('sendrawtx exit 0') l2.daemon.wait_for_log('sendrawtx exit 0') assert l1.bitcoin.rpc.getmempoolinfo()['size'] == 1 # Now grab the close transaction closetxid = l1.bitcoin.rpc.getrawmempool(False)[0] l1.bitcoin.rpc.generate(10) l1.daemon.wait_for_log(r'Owning output .* txid %s' % closetxid) l2.daemon.wait_for_log(r'Owning output .* txid %s' % closetxid) # Make sure both nodes have grabbed their close tx funds assert closetxid in set([o['txid'] for o in l1.rpc.listfunds()['outputs']]) assert closetxid in set([o['txid'] for o in l2.rpc.listfunds()['outputs']]) @unittest.skipIf(not DEVELOPER, "needs DEVELOPER=1") def test_permfail(self): l1,l2 = self.connect() self.fund_channel(l1, l2, 10**6) self.pay(l1,l2,200000000) # Make sure l2 has received sig with 0 htlcs! l2.daemon.wait_for_log('Received commit_sig with 0 htlc sigs') # Make sure l1 has final revocation. l1.daemon.wait_for_log('Sending commit_sig with 0 htlc sigs') l1.daemon.wait_for_log('peer_in WIRE_REVOKE_AND_ACK') # We fail l2, so l1 will reconnect to it. l2.rpc.dev_fail(l1.info['id']) l2.daemon.wait_for_log('Failing due to dev-fail command') l2.daemon.wait_for_log('sendrawtx exit 0') assert l1.bitcoin.rpc.getmempoolinfo()['size'] == 1 # Now grab the close transaction closetxid = l1.bitcoin.rpc.getrawmempool(False)[0] # "Internal error" in hex l1.daemon.wait_for_log('WIRE_ERROR.*496e7465726e616c206572726f72') # l2 will send out tx (l1 considers it a transient error) bitcoind.generate_block(1) l1.daemon.wait_for_log('Their unilateral tx, old commit point') l1.daemon.wait_for_log('-> ONCHAIND_THEIR_UNILATERAL') l2.daemon.wait_for_log('-> ONCHAIND_OUR_UNILATERAL') l2.daemon.wait_for_log('Propose handling OUR_UNILATERAL/DELAYED_OUTPUT_TO_US by OUR_DELAYED_RETURN_TO_WALLET (.*) in 5 blocks') # Now, mine 5 blocks so it sends out the spending tx. bitcoind.generate_block(5) # It should send the to-wallet tx. l2.daemon.wait_for_log('Broadcasting OUR_DELAYED_RETURN_TO_WALLET') l2.daemon.wait_for_log('sendrawtx exit 0') # 100 after l1 sees tx, it should be done. bitcoind.generate_block(95) l1.daemon.wait_for_log('onchaind complete, forgetting peer') # Now, 100 blocks l2 should be done. bitcoind.generate_block(5) l2.daemon.wait_for_log('onchaind complete, forgetting peer') # Only l1 has a direct output since all of l2's outputs are respent (it failed) assert closetxid in set([o['txid'] for o in l1.rpc.listfunds()['outputs']]) #import pdb; pdb.set_trace() addr = l1.bitcoin.rpc.getnewaddress() print(addr) l1.rpc.withdraw(addr, "all") @unittest.skipIf(not DEVELOPER, "needs DEVELOPER=1") def test_onchain_first_commit(self): """Onchain handling where funder immediately drops to chain""" # HTLC 1->2, 1 fails just after funding. disconnects = ['+WIRE_FUNDING_LOCKED', 'permfail'] l1 = self.node_factory.get_node(disconnect=disconnects) # Make locktime different, as we once had them reversed! l2 = self.node_factory.get_node(options=['--locktime-blocks=10']) l1.rpc.connect(l2.info['id'], 'localhost', l2.info['port']) # Like fundchannel, but we'll probably fail before CHANNELD_NORMAL. addr = l1.rpc.newaddr()['address'] txid = l1.bitcoin.rpc.sendtoaddress(addr, 10**6 / 10**8 + 0.01) tx = l1.bitcoin.rpc.getrawtransaction(txid) l1.rpc.addfunds(tx) l1.rpc.fundchannel(l2.info['id'], 10**6) l1.daemon.wait_for_log('sendrawtx exit 0') l1.bitcoin.generate_block(1) # l1 will drop to chain. l1.daemon.wait_for_log('permfail') l1.daemon.wait_for_log('sendrawtx exit 0') l1.bitcoin.generate_block(1) l1.daemon.wait_for_log('-> ONCHAIND_OUR_UNILATERAL') l2.daemon.wait_for_log('-> ONCHAIND_THEIR_UNILATERAL') # 10 later, l1 should collect its to-self payment. bitcoind.generate_block(10) l1.daemon.wait_for_log('Broadcasting OUR_DELAYED_RETURN_TO_WALLET .* to resolve OUR_UNILATERAL/DELAYED_OUTPUT_TO_US') l1.daemon.wait_for_log('sendrawtx exit 0') # 94 later, l2 is done. bitcoind.generate_block(94) l2.daemon.wait_for_log('onchaind complete, forgetting peer') # Now, 100 blocks and l1 should be done. bitcoind.generate_block(6) l1.daemon.wait_for_log('onchaind complete, forgetting peer') @unittest.skipIf(not DEVELOPER, "needs DEVELOPER=1") def test_onchain_dust_out(self): """Onchain handling of outgoing dust htlcs (they should fail)""" # HTLC 1->2, 1 fails after it's irrevocably committed disconnects = ['@WIRE_REVOKE_AND_ACK', 'permfail'] l1 = self.node_factory.get_node(disconnect=disconnects) l2 = self.node_factory.get_node() l1.rpc.connect(l2.info['id'], 'localhost', l2.info['port']) self.fund_channel(l1, l2, 10**6) # Must be dust! rhash = l2.rpc.invoice(1, 'onchain_dust_out', 'desc')['payment_hash'] routestep = { 'msatoshi' : 1, 'id' : l2.info['id'], 'delay' : 5, 'channel': '1:1:1' } payfuture = self.executor.submit(l1.rpc.sendpay, to_json([routestep]), rhash) # l1 will drop to chain. l1.daemon.wait_for_log('permfail') l1.daemon.wait_for_log('sendrawtx exit 0') l1.bitcoin.generate_block(1) l1.daemon.wait_for_log('-> ONCHAIND_OUR_UNILATERAL') l2.daemon.wait_for_log('-> ONCHAIND_THEIR_UNILATERAL') # We use 3 blocks for "reasonable depth" bitcoind.generate_block(3) # It should fail. self.assertRaises(ValueError, payfuture.result, 5) l1.daemon.wait_for_log('WIRE_PERMANENT_CHANNEL_FAILURE: missing in commitment tx') # 6 later, l1 should collect its to-self payment. bitcoind.generate_block(6) l1.daemon.wait_for_log('Broadcasting OUR_DELAYED_RETURN_TO_WALLET .* to resolve OUR_UNILATERAL/DELAYED_OUTPUT_TO_US') l1.daemon.wait_for_log('sendrawtx exit 0') # 94 later, l2 is done. bitcoind.generate_block(94) l2.daemon.wait_for_log('onchaind complete, forgetting peer') # Now, 100 blocks and l1 should be done. bitcoind.generate_block(6) l1.daemon.wait_for_log('onchaind complete, forgetting peer') # Payment failed, BTW assert l2.rpc.listinvoice('onchain_dust_out')[0]['complete'] == False @unittest.skipIf(not DEVELOPER, "needs DEVELOPER=1") def test_onchain_timeout(self): """Onchain handling of outgoing failed htlcs""" # HTLC 1->2, 1 fails just after it's irrevocably committed disconnects = ['+WIRE_REVOKE_AND_ACK', 'permfail'] l1 = self.node_factory.get_node(disconnect=disconnects) l2 = self.node_factory.get_node() l1.rpc.connect(l2.info['id'], 'localhost', l2.info['port']) self.fund_channel(l1, l2, 10**6) rhash = l2.rpc.invoice(10**8, 'onchain_timeout', 'desc')['payment_hash'] # We underpay, so it fails. routestep = { 'msatoshi' : 10**8 - 1, 'id' : l2.info['id'], 'delay' : 5, 'channel': '1:1:1' } payfuture = self.executor.submit(l1.rpc.sendpay, to_json([routestep]), rhash) # l1 will drop to chain. l1.daemon.wait_for_log('permfail') l1.daemon.wait_for_log('sendrawtx exit 0') l1.bitcoin.generate_block(1) l1.daemon.wait_for_log('-> ONCHAIND_OUR_UNILATERAL') l2.daemon.wait_for_log('-> ONCHAIND_THEIR_UNILATERAL') # Wait for timeout. l1.daemon.wait_for_log('Propose handling OUR_UNILATERAL/DELAYED_OUTPUT_TO_US by OUR_DELAYED_RETURN_TO_WALLET .* in 5 blocks') bitcoind.generate_block(5) # (l1 will also collect its to-self payment.) l1.daemon.wait_for_log('sendrawtx exit 0') l1.daemon.wait_for_log('sendrawtx exit 0') # We use 3 blocks for "reasonable depth" bitcoind.generate_block(3) # It should fail. self.assertRaises(ValueError, payfuture.result, 5) l1.daemon.wait_for_log('WIRE_PERMANENT_CHANNEL_FAILURE: timed out') # 2 later, l1 spends HTLC (5 blocks total). bitcoind.generate_block(2) l1.daemon.wait_for_log('Broadcasting OUR_DELAYED_RETURN_TO_WALLET .* to resolve OUR_HTLC_TIMEOUT_TX/DELAYED_OUTPUT_TO_US') l1.daemon.wait_for_log('sendrawtx exit 0') # 89 later, l2 is done. bitcoind.generate_block(89) l2.daemon.wait_for_log('onchaind complete, forgetting peer') # Now, 100 blocks and l1 should be done. bitcoind.generate_block(10) assert not l1.daemon.is_in_log('onchaind complete, forgetting peer') bitcoind.generate_block(1) l1.daemon.wait_for_log('onchaind complete, forgetting peer') # Payment failed, BTW assert l2.rpc.listinvoice('onchain_timeout')[0]['complete'] == False @unittest.skipIf(not DEVELOPER, "needs DEVELOPER=1") def test_onchain_middleman(self): # HTLC 1->2->3, 1->2 goes down after 2 gets preimage from 3. disconnects = ['-WIRE_UPDATE_FULFILL_HTLC', 'permfail'] l1 = self.node_factory.get_node() l2 = self.node_factory.get_node(disconnect=disconnects) l3 = self.node_factory.get_node() # l2 connects to both, so l1 can't reconnect and thus l2 drops to chain l2.rpc.connect(l1.info['id'], 'localhost', l1.info['port']) l2.rpc.connect(l3.info['id'], 'localhost', l3.info['port']) c12 = self.fund_channel(l2, l1, 10**6) c23 = self.fund_channel(l2, l3, 10**6) # Make sure routes finalized. self.wait_for_routes(l1, [c23]) # Give l1 some money to play with. self.pay(l2, l1, 2 * 10**8) # Must be bigger than dust! rhash = l3.rpc.invoice(10**8, 'middleman', 'desc')['payment_hash'] route = l1.rpc.getroute(l3.info['id'], 10**8, 1)["route"] assert len(route) == 2 q = queue.Queue() def try_pay(): try: l1.rpc.sendpay(to_json(route), rhash, async=False) q.put(None) except Exception as err: q.put(err) t = threading.Thread(target=try_pay) t.daemon = True t.start() # l2 will drop to chain. l2.daemon.wait_for_log('sendrawtx exit 0') l1.bitcoin.generate_block(1) l2.daemon.wait_for_log('-> ONCHAIND_OUR_UNILATERAL') l1.daemon.wait_for_log('-> ONCHAIND_THEIR_UNILATERAL') l2.daemon.wait_for_log('OUR_UNILATERAL/THEIR_HTLC') # l2 should fulfill HTLC onchain, and spend to-us (any order) l2.daemon.wait_for_log('Propose handling OUR_UNILATERAL/THEIR_HTLC by OUR_HTLC_SUCCESS_TX .* in 0 blocks') l2.daemon.wait_for_log('sendrawtx exit 0') # Payment should succeed. l1.bitcoin.generate_block(1) l1.daemon.wait_for_log('THEIR_UNILATERAL/OUR_HTLC gave us preimage') err = q.get(timeout = 10) if err: print("Got err from sendpay thread") raise err t.join(timeout=1) assert not t.isAlive() # Three more, l2 can spend to-us. bitcoind.generate_block(3) l2.daemon.wait_for_log('Broadcasting OUR_DELAYED_RETURN_TO_WALLET .* to resolve OUR_UNILATERAL/DELAYED_OUTPUT_TO_US') l2.daemon.wait_for_log('sendrawtx exit 0') # One more block, HTLC tx is now spendable. l1.bitcoin.generate_block(1) l2.daemon.wait_for_log('Broadcasting OUR_DELAYED_RETURN_TO_WALLET .* to resolve OUR_HTLC_SUCCESS_TX/DELAYED_OUTPUT_TO_US') l2.daemon.wait_for_log('sendrawtx exit 0') # 100 blocks after last spend, l2 should be done. l1.bitcoin.generate_block(100) l2.daemon.wait_for_log('onchaind complete, forgetting peer') @unittest.skipIf(not DEVELOPER, "needs DEVELOPER=1") def test_penalty_inhtlc(self): """Test penalty transaction with an incoming HTLC""" # We suppress each one after first commit; HTLC gets added not fulfilled. l1 = self.node_factory.get_node(disconnect=['=WIRE_COMMITMENT_SIGNED-nocommit'], may_fail=True) l2 = self.node_factory.get_node(disconnect=['=WIRE_COMMITMENT_SIGNED-nocommit']) l1.rpc.connect(l2.info['id'], 'localhost', l2.info['port']) self.fund_channel(l1, l2, 10**6) # Now, this will get stuck due to l1 commit being disabled.. t = self.pay(l1,l2,100000000,async=True) # They should both have commitments blocked now. l1.daemon.wait_for_log('=WIRE_COMMITMENT_SIGNED-nocommit') l2.daemon.wait_for_log('=WIRE_COMMITMENT_SIGNED-nocommit') # Make sure l1 got l2's commitment to the HTLC, and sent to master. l1.daemon.wait_for_log('UPDATE WIRE_CHANNEL_GOT_COMMITSIG') # Take our snapshot. tx = l1.rpc.dev_sign_last_tx(l2.info['id'])['tx'] # Let them continue l1.rpc.dev_reenable_commit(l2.info['id']) l2.rpc.dev_reenable_commit(l1.info['id']) # Should fulfill. l1.daemon.wait_for_log('peer_in WIRE_UPDATE_FULFILL_HTLC') l1.daemon.wait_for_log('peer_out WIRE_REVOKE_AND_ACK') l2.daemon.wait_for_log('peer_out WIRE_UPDATE_FULFILL_HTLC') l1.daemon.wait_for_log('peer_in WIRE_REVOKE_AND_ACK') # Payment should now complete. t.result(timeout=10) # Now we really mess things up! bitcoind.rpc.sendrawtransaction(tx) bitcoind.generate_block(1) l2.daemon.wait_for_log('-> ONCHAIND_CHEATED') # FIXME: l1 should try to stumble along! # l2 should spend all of the outputs (except to-us). # Could happen in any order, depending on commitment tx. l2.daemon.wait_for_logs(['Propose handling THEIR_REVOKED_UNILATERAL/DELAYED_OUTPUT_TO_THEM by OUR_PENALTY_TX .* in 0 blocks', 'sendrawtx exit 0', 'Propose handling THEIR_REVOKED_UNILATERAL/THEIR_HTLC by OUR_PENALTY_TX .* in 0 blocks', 'sendrawtx exit 0']) # FIXME: test HTLC tx race! # 100 blocks later, all resolved. bitcoind.generate_block(100) # FIXME: Test wallet balance... l2.daemon.wait_for_log('onchaind complete, forgetting peer') @unittest.skip("flaky test causing CI fails too often") def test_penalty_outhtlc(self): """Test penalty transaction with an outgoing HTLC""" # First we need to get funds to l2, so suppress after second. l1 = self.node_factory.get_node(disconnect=['=WIRE_COMMITMENT_SIGNED*3-nocommit'], may_fail=True) l2 = self.node_factory.get_node(disconnect=['=WIRE_COMMITMENT_SIGNED*3-nocommit']) l1.rpc.connect(l2.info['id'], 'localhost', l2.info['port']) self.fund_channel(l1, l2, 10**6) # Move some across to l2. self.pay(l1,l2,200000000) assert not l1.daemon.is_in_log('=WIRE_COMMITMENT_SIGNED') assert not l2.daemon.is_in_log('=WIRE_COMMITMENT_SIGNED') # Now, this will get stuck due to l1 commit being disabled.. t = self.pay(l2,l1,100000000,async=True) # Make sure we get signature from them. l1.daemon.wait_for_log('peer_in WIRE_UPDATE_ADD_HTLC') l1.daemon.wait_for_log('peer_in WIRE_COMMITMENT_SIGNED') # They should both have commitments blocked now. l1.daemon.wait_for_log('dev_disconnect: =WIRE_COMMITMENT_SIGNED') l2.daemon.wait_for_log('dev_disconnect: =WIRE_COMMITMENT_SIGNED') # Take our snapshot. tx = l1.rpc.dev_sign_last_tx(l2.info['id'])['tx'] # Let the continue l1.rpc.dev_reenable_commit(l2.info['id']) l2.rpc.dev_reenable_commit(l1.info['id']) # Thread should complete. t.result(timeout=10) # Make sure both sides got revoke_and_ack for final. l1.daemon.wait_for_log('peer_in WIRE_REVOKE_AND_ACK') l2.daemon.wait_for_log('peer_in WIRE_REVOKE_AND_ACK') # Now we really mess things up! bitcoind.rpc.sendrawtransaction(tx) bitcoind.generate_block(1) l2.daemon.wait_for_log('-> ONCHAIND_CHEATED') # FIXME: l1 should try to stumble along! # l2 should spend all of the outputs (except to-us). # Could happen in any order, depending on commitment tx. l2.daemon.wait_for_logs(['Ignoring output.*: THEIR_REVOKED_UNILATERAL/OUTPUT_TO_US', 'Propose handling THEIR_REVOKED_UNILATERAL/DELAYED_OUTPUT_TO_THEM by OUR_PENALTY_TX .* in 0 blocks', 'sendrawtx exit 0', 'Propose handling THEIR_REVOKED_UNILATERAL/OUR_HTLC by OUR_PENALTY_TX .* in 0 blocks', 'sendrawtx exit 0']) # FIXME: test HTLC tx race! # 100 blocks later, all resolved. bitcoind.generate_block(100) # FIXME: Test wallet balance... l2.daemon.wait_for_log('onchaind complete, forgetting peer') @unittest.skipIf(not DEVELOPER, "needs DEVELOPER=1") def test_permfail_new_commit(self): # Test case where we have two possible commits: it will use new one. disconnects = ['-WIRE_REVOKE_AND_ACK', 'permfail'] l1 = self.node_factory.get_node() l2 = self.node_factory.get_node(disconnect=disconnects) l1.rpc.connect(l2.info['id'], 'localhost', l2.info['port']) self.fund_channel(l1, l2, 10**6) # This will fail at l2's end. t=self.pay(l1,l2,200000000,async=True) l2.daemon.wait_for_log('dev_disconnect permfail') l2.daemon.wait_for_log('sendrawtx exit 0') bitcoind.generate_block(1) l1.daemon.wait_for_log('Their unilateral tx, new commit point') l1.daemon.wait_for_log('-> ONCHAIND_THEIR_UNILATERAL') l2.daemon.wait_for_log('-> ONCHAIND_OUR_UNILATERAL') l2.daemon.wait_for_log('Propose handling OUR_UNILATERAL/THEIR_HTLC by THEIR_HTLC_TIMEOUT_TO_THEM \\(IGNORING\\) in 5 blocks') l1.daemon.wait_for_log('Propose handling THEIR_UNILATERAL/OUR_HTLC by OUR_HTLC_TIMEOUT_TO_US (.*) in 5 blocks') # OK, time out HTLC. bitcoind.generate_block(5) l1.daemon.wait_for_log('sendrawtx exit 0') bitcoind.generate_block(1) l1.daemon.wait_for_log('Resolved THEIR_UNILATERAL/OUR_HTLC by our proposal OUR_HTLC_TIMEOUT_TO_US') l2.daemon.wait_for_log('Ignoring output.*: OUR_UNILATERAL/THEIR_HTLC') t.cancel() # Now, 100 blocks it should be done. bitcoind.generate_block(100) l1.daemon.wait_for_log('onchaind complete, forgetting peer') l2.daemon.wait_for_log('onchaind complete, forgetting peer') @unittest.skipIf(not DEVELOPER, "needs DEVELOPER=1") def test_permfail_htlc_in(self): # Test case where we fail with unsettled incoming HTLC. disconnects = ['-WIRE_UPDATE_FULFILL_HTLC', 'permfail'] l1 = self.node_factory.get_node() l2 = self.node_factory.get_node(disconnect=disconnects) l1.rpc.connect(l2.info['id'], 'localhost', l2.info['port']) self.fund_channel(l1, l2, 10**6) # This will fail at l2's end. t=self.pay(l1, l2, 200000000, async=True) l2.daemon.wait_for_log('dev_disconnect permfail') l2.daemon.wait_for_log('sendrawtx exit 0') bitcoind.generate_block(1) l1.daemon.wait_for_log('Their unilateral tx, old commit point') l1.daemon.wait_for_log('-> ONCHAIND_THEIR_UNILATERAL') l2.daemon.wait_for_log('-> ONCHAIND_OUR_UNILATERAL') l2.daemon.wait_for_log('Propose handling OUR_UNILATERAL/THEIR_HTLC by THEIR_HTLC_TIMEOUT_TO_THEM \\(IGNORING\\) in 5 blocks') l1.daemon.wait_for_log('Propose handling THEIR_UNILATERAL/OUR_HTLC by OUR_HTLC_TIMEOUT_TO_US (.*) in 5 blocks') # l2 then gets preimage, uses it instead of ignoring l2.daemon.wait_for_log('Propose handling OUR_UNILATERAL/THEIR_HTLC by OUR_HTLC_SUCCESS_TX .* in 0 blocks') l2.daemon.wait_for_log('sendrawtx exit 0') bitcoind.generate_block(1) # OK, l1 sees l2 fulfill htlc. l1.daemon.wait_for_log('THEIR_UNILATERAL/OUR_HTLC gave us preimage') l2.daemon.wait_for_log('Propose handling OUR_HTLC_SUCCESS_TX/DELAYED_OUTPUT_TO_US by OUR_DELAYED_RETURN_TO_WALLET .* in 5 blocks') bitcoind.generate_block(5) l2.daemon.wait_for_log('sendrawtx exit 0') t.cancel() # Now, 100 blocks it should be done. bitcoind.generate_block(95) l1.daemon.wait_for_log('onchaind complete, forgetting peer') assert not l2.daemon.is_in_log('onchaind complete, forgetting peer') bitcoind.generate_block(5) l2.daemon.wait_for_log('onchaind complete, forgetting peer') @unittest.skipIf(not DEVELOPER, "needs DEVELOPER=1") def test_permfail_htlc_out(self): # Test case where we fail with unsettled outgoing HTLC. disconnects = ['+WIRE_REVOKE_AND_ACK', 'permfail'] l1 = self.node_factory.get_node() l2 = self.node_factory.get_node(disconnect=disconnects) l1.rpc.connect(l2.info['id'], 'localhost', l2.info['port']) self.fund_channel(l2, l1, 10**6) # This will fail at l2's end. t=self.pay(l2,l1,200000000,async=True) l2.daemon.wait_for_log('dev_disconnect permfail') l2.daemon.wait_for_log('sendrawtx exit 0') bitcoind.generate_block(1) l1.daemon.wait_for_log('Their unilateral tx, old commit point') l1.daemon.wait_for_log('-> ONCHAIND_THEIR_UNILATERAL') l2.daemon.wait_for_log('-> ONCHAIND_OUR_UNILATERAL') l2.daemon.wait_for_logs(['Propose handling OUR_UNILATERAL/OUR_HTLC by OUR_HTLC_TIMEOUT_TX \\(.*\\) in 5 blocks', 'Propose handling OUR_UNILATERAL/DELAYED_OUTPUT_TO_US by OUR_DELAYED_RETURN_TO_WALLET .* in 5 blocks']) l1.daemon.wait_for_log('Propose handling THEIR_UNILATERAL/THEIR_HTLC by THEIR_HTLC_TIMEOUT_TO_THEM \\(IGNORING\\) in 5 blocks') # l1 then gets preimage, uses it instead of ignoring l1.daemon.wait_for_log('Propose handling THEIR_UNILATERAL/THEIR_HTLC by THEIR_HTLC_FULFILL_TO_US .* in 0 blocks') l1.daemon.wait_for_log('sendrawtx exit 0') # l2 sees l1 fulfill tx. bitcoind.generate_block(1) l2.daemon.wait_for_log('OUR_UNILATERAL/OUR_HTLC gave us preimage') t.cancel() # l2 can send OUR_DELAYED_RETURN_TO_WALLET after 4 more blocks. bitcoind.generate_block(4) l2.daemon.wait_for_log('Broadcasting OUR_DELAYED_RETURN_TO_WALLET .* to resolve OUR_UNILATERAL/DELAYED_OUTPUT_TO_US') l2.daemon.wait_for_log('sendrawtx exit 0') # Now, 100 blocks they should be done. bitcoind.generate_block(94) assert not l1.daemon.is_in_log('onchaind complete, forgetting peer') assert not l2.daemon.is_in_log('onchaind complete, forgetting peer') bitcoind.generate_block(1) l1.daemon.wait_for_log('onchaind complete, forgetting peer') assert not l2.daemon.is_in_log('onchaind complete, forgetting peer') bitcoind.generate_block(5) assert not l2.daemon.is_in_log('onchaind complete, forgetting peer') bitcoind.generate_block(1) l2.daemon.wait_for_log('onchaind complete, forgetting peer') def test_gossip_jsonrpc(self): l1, l2 = self.line_graph(n=2) # Shouldn't send announce signatures until 6 deep. assert not l1.daemon.is_in_log('peer_out WIRE_ANNOUNCEMENT_SIGNATURES') # Channels should be activated locally wait_for(lambda: [c['active'] for c in l1.rpc.getchannels()['channels']] == [True]) # Make sure we can route through the channel, will raise on failure l1.rpc.getroute(l2.info['id'], 100, 1) # Outgoing should be active, but not public. channels = l1.rpc.getchannels()['channels'] assert len(channels) == 1 assert channels[0]['active'] == True assert channels[0]['public'] == False channels = l2.rpc.getchannels()['channels'] assert len(channels) == 1 assert channels[0]['active'] == True assert channels[0]['public'] == False # Now proceed to funding-depth and do a full gossip round l1.bitcoin.generate_block(5) # Could happen in either order. l1.daemon.wait_for_logs(['peer_out WIRE_ANNOUNCEMENT_SIGNATURES', 'peer_in WIRE_ANNOUNCEMENT_SIGNATURES']) channel_id = channels[0]['short_channel_id'] # Could happen in any order. l1.daemon.wait_for_logs(['peer_out WIRE_CHANNEL_ANNOUNCEMENT', 'peer_in WIRE_CHANNEL_ANNOUNCEMENT', 'Channel {}\\(0\\) was updated.' .format(channel_id), 'Channel {}\\(1\\) was updated.' .format(channel_id)]) l2.daemon.wait_for_logs(['peer_out WIRE_CHANNEL_ANNOUNCEMENT', 'peer_in WIRE_CHANNEL_ANNOUNCEMENT', 'Channel {}\\(0\\) was updated.' .format(channel_id), 'Channel {}\\(1\\) was updated.' .format(channel_id)]) nodes = l1.rpc.getnodes()['nodes'] assert set([n['nodeid'] for n in nodes]) == set([l1.info['id'], l2.info['id']]) assert [c['active'] for c in l1.rpc.getchannels()['channels']] == [True, True] assert [c['public'] for c in l1.rpc.getchannels()['channels']] == [True, True] assert [c['active'] for c in l2.rpc.getchannels()['channels']] == [True, True] assert [c['public'] for c in l2.rpc.getchannels()['channels']] == [True, True] def ping_tests(self, l1, l2): # 0-byte pong gives just type + length field. ret = l1.rpc.dev_ping(l2.info['id'], 0, 0) assert ret['totlen'] == 4 # 1000-byte ping, 0-byte pong. ret = l1.rpc.dev_ping(l2.info['id'], 1000, 0) assert ret['totlen'] == 4 # 1000 byte pong. ret = l1.rpc.dev_ping(l2.info['id'], 1000, 1000) assert ret['totlen'] == 1004 # Maximum length pong. ret = l1.rpc.dev_ping(l2.info['id'], 1000, 65531) assert ret['totlen'] == 65535 # Overlength -> no reply. for s in range(65532, 65536): ret = l1.rpc.dev_ping(l2.info['id'], 1000, s) assert ret['totlen'] == 0 @unittest.skipIf(not DEVELOPER, "needs DEVELOPER=1") def test_ping(self): l1,l2 = self.connect() # Test gossip pinging. self.ping_tests(l1, l2) self.fund_channel(l1, l2, 10**5) # channeld pinging self.ping_tests(l1, l2) @unittest.skipIf(not DEVELOPER, "needs DEVELOPER=1") def test_routing_gossip_reconnect(self): # Connect two peers, reconnect and then see if we resume the # gossip. disconnects = ['-WIRE_CHANNEL_ANNOUNCEMENT'] l1 = self.node_factory.get_node(disconnect=disconnects) l2 = self.node_factory.get_node() l3 = self.node_factory.get_node() l1.rpc.connect(l2.info['id'], 'localhost', l2.info['port']) l1.openchannel(l2, 20000) # Now open new channels and everybody should sync l2.rpc.connect(l3.info['id'], 'localhost', l3.info['port']) l2.openchannel(l3, 20000) # Settle the gossip for n in [l1, l2, l3]: wait_for(lambda: len(n.rpc.getchannels()['channels']) == 4) def test_second_channel(self): l1 = self.node_factory.get_node() l2 = self.node_factory.get_node() l3 = self.node_factory.get_node() l1.rpc.connect(l2.info['id'], 'localhost', l2.info['port']) l1.rpc.connect(l3.info['id'], 'localhost', l3.info['port']) self.fund_channel(l1, l2, 10**6) self.fund_channel(l1, l3, 10**6) @unittest.skipIf(not DEVELOPER, "needs DEVELOPER=1 for --dev-broadcast-interval") def test_routing_gossip(self): nodes = [self.node_factory.get_node() for _ in range(5)] l1 = nodes[0] l5 = nodes[4] for i in range(len(nodes)-1): src, dst = nodes[i], nodes[i+1] src.rpc.connect(dst.info['id'], 'localhost', dst.info['port']) src.openchannel(dst, 20000) # Allow announce messages. l1.bitcoin.generate_block(5) def settle_gossip(n): """Wait for gossip to settle at the node """ expected_connections = 2*(len(nodes) - 1) start_time = time.time() # Wait at most 10 seconds, broadcast interval is 1 second while time.time() - start_time < 10: channels = n.rpc.getchannels()['channels'] if len(channels) == expected_connections: break else: time.sleep(0.1) for n in nodes: settle_gossip(n) # Deep check that all channels are in there comb = [] for i in range(len(nodes) - 1): comb.append((nodes[i].info['id'], nodes[i+1].info['id'])) comb.append((nodes[i+1].info['id'], nodes[i].info['id'])) for n in nodes: seen = [] channels = n.rpc.getchannels()['channels'] for c in channels: seen.append((c['source'],c['destination'])) assert set(seen) == set(comb) def test_forward(self): # Connect 1 -> 2 -> 3. l1,l2 = self.connect() l3 = self.node_factory.get_node() ret = l2.rpc.connect(l3.info['id'], 'localhost', l3.info['port']) assert ret['id'] == l3.info['id'] l3.daemon.wait_for_log('WIRE_GOSSIPCTL_HAND_BACK_PEER') self.fund_channel(l1, l2, 10**6) self.fund_channel(l2, l3, 10**6) # Allow announce messages. l1.bitcoin.generate_block(5) # If they're at different block heights we can get spurious errors. sync_blockheight([l1, l2, l3]) chanid1 = l1.rpc.getpeer(l2.info['id'])['channel'] chanid2 = l2.rpc.getpeer(l3.info['id'])['channel'] assert l2.rpc.getpeer(l1.info['id'])['channel'] == chanid1 assert l3.rpc.getpeer(l2.info['id'])['channel'] == chanid2 rhash = l3.rpc.invoice(100000000, 'testpayment1', 'desc')['payment_hash'] assert l3.rpc.listinvoice('testpayment1')[0]['complete'] == False # Fee for node2 is 10 millionths, plus 1. amt = 100000000 fee = amt * 10 // 1000000 + 1 baseroute = [ { 'msatoshi' : amt + fee, 'id' : l2.info['id'], 'delay' : 12, 'channel' : chanid1 }, { 'msatoshi' : amt, 'id' : l3.info['id'], 'delay' : 6, 'channel' : chanid2 } ] # Unknown other peer route = copy.deepcopy(baseroute) route[1]['id'] = '031a8dc444e41bb989653a4501e11175a488a57439b0c4947704fd6e3de5dca607' self.assertRaises(ValueError, l1.rpc.sendpay, to_json(route), rhash) # Delay too short (we always add one internally anyway, so subtract 2 here). route = copy.deepcopy(baseroute) route[0]['delay'] = 8 self.assertRaises(ValueError, l1.rpc.sendpay, to_json(route), rhash) # Final delay too short route = copy.deepcopy(baseroute) route[1]['delay'] = 3 self.assertRaises(ValueError, l1.rpc.sendpay, to_json(route), rhash) # This one works route = copy.deepcopy(baseroute) l1.rpc.sendpay(to_json(route), rhash) @unittest.skipIf(not DEVELOPER, "needs DEVELOPER=1 for --dev-broadcast-interval") def test_forward_different_fees_and_cltv(self): # FIXME: Check BOLT quotes here too # BOLT #7: # ``` # B # / \ # / \ # A C # \ / # \ / # D # ``` # # Each advertises the following `cltv_expiry_delta` on its end of every # channel: # # 1. A: 10 blocks # 2. B: 20 blocks # 3. C: 30 blocks # 4. D: 40 blocks # # C also uses a minimum `cltv_expiry` of 9 (the default) when requesting # payments. # # Also, each node has the same fee scheme which it uses for each of its # channels: # # 1. A: 100 base + 1000 millionths # 1. B: 200 base + 2000 millionths # 1. C: 300 base + 3000 millionths # 1. D: 400 base + 4000 millionths # We don't do D yet. l1 = self.node_factory.get_node(options=['--cltv-delta=10', '--fee-base=100', '--fee-per-satoshi=1000']) l2 = self.node_factory.get_node(options=['--cltv-delta=20', '--fee-base=200', '--fee-per-satoshi=2000']) l3 = self.node_factory.get_node(options=['--cltv-delta=30', '--cltv-final=9', '--fee-base=300', '--fee-per-satoshi=3000']) ret = l1.rpc.connect(l2.info['id'], 'localhost', l2.info['port']) assert ret['id'] == l2.info['id'] l1.daemon.wait_for_log('WIRE_GOSSIPCTL_HAND_BACK_PEER') l2.daemon.wait_for_log('WIRE_GOSSIPCTL_HAND_BACK_PEER') ret = l2.rpc.connect(l3.info['id'], 'localhost', l3.info['port']) assert ret['id'] == l3.info['id'] l2.daemon.wait_for_log('WIRE_GOSSIPCTL_HAND_BACK_PEER') l3.daemon.wait_for_log('WIRE_GOSSIPCTL_HAND_BACK_PEER') c1 = self.fund_channel(l1, l2, 10**6) c2 = self.fund_channel(l2, l3, 10**6) # Make sure l1 has seen announce for all channels. self.wait_for_routes(l1, [c1, c2]) # BOLT #7: # # If B were to send 4,999,999 millisatoshi directly to C, it wouldn't # charge itself a fee nor add its own `cltv_expiry_delta`, so it would # use C's requested `cltv_expiry` of 9. We also assume it adds a # "shadow route" to give an extra CLTV of 42. It could also add extra # cltv deltas at other hops, as these values are a minimum, but we don't # here for simplicity: # FIXME: Add shadow route shadow_route=0 route = l2.rpc.getroute(l3.info['id'], 4999999, 1)["route"] assert len(route) == 1 # BOLT #7: # # * `amount_msat`: 4999999 # * `cltv_expiry`: current-block-height + 9 + 42 # * `onion_routing_packet`: # * `amt_to_forward` = 4999999 # * `outgoing_cltv_value` = current-block-height + 9 + 42 # assert route[0]['msatoshi'] == 4999999 assert route[0]['delay'] == 9 + shadow_route # BOLT #7: # If A were to send an 4,999,999 millisatoshi to C via B, it needs to # pay B the fee it specified in the B->C `channel_update`, calculated as # per [HTLC Fees](#htlc_fees): # # 200 + 4999999 * 2000 / 1000000 = 10199 # # Similarly, it would need to add the `cltv_expiry` from B->C's # `channel_update` (20), plus C's requested minimum (9), plus 42 for the # "shadow route". Thus the `update_add_htlc` message from A to B would # be: # # * `amount_msat`: 5010198 # * `cltv_expiry`: current-block-height + 20 + 9 + 42 # * `onion_routing_packet`: # * `amt_to_forward` = 4999999 # * `outgoing_cltv_value` = current-block-height + 9 + 42 route = l1.rpc.getroute(l3.info['id'], 4999999, 1)["route"] assert len(route) == 2 assert route[0]['msatoshi'] == 5010198 assert route[0]['delay'] == 20 + 9 + shadow_route assert route[1]['msatoshi'] == 4999999 assert route[1]['delay'] == 9 + shadow_route rhash = l3.rpc.invoice(4999999, 'test_forward_different_fees_and_cltv', 'desc')['payment_hash'] assert l3.rpc.listinvoice('test_forward_different_fees_and_cltv')[0]['complete'] == False # This should work. l1.rpc.sendpay(to_json(route), rhash) # We add one to the blockcount for a bit of fuzz (FIXME: Shadowroute would fix this!) shadow_route = 1 l1.daemon.wait_for_log("Adding HTLC 0 msat=5010198 cltv={} gave 0" .format(bitcoind.rpc.getblockcount() + 20 + 9 + shadow_route)) l2.daemon.wait_for_log("Adding HTLC 0 msat=4999999 cltv={} gave 0" .format(bitcoind.rpc.getblockcount() + 9 + shadow_route)) l3.daemon.wait_for_log("test_forward_different_fees_and_cltv: Actual amount 4999999msat, HTLC expiry {}" .format(bitcoind.rpc.getblockcount() + 9 + shadow_route)) assert l3.rpc.listinvoice('test_forward_different_fees_and_cltv')[0]['complete'] == True @unittest.skipIf(not DEVELOPER, "needs DEVELOPER=1 for --dev-broadcast-interval") def test_forward_pad_fees_and_cltv(self): """Test that we are allowed extra locktime delta, and fees""" l1 = self.node_factory.get_node(options=['--cltv-delta=10', '--fee-base=100', '--fee-per-satoshi=1000']) l2 = self.node_factory.get_node(options=['--cltv-delta=20', '--fee-base=200', '--fee-per-satoshi=2000']) l3 = self.node_factory.get_node(options=['--cltv-delta=30', '--cltv-final=9', '--fee-base=300', '--fee-per-satoshi=3000']) ret = l1.rpc.connect(l2.info['id'], 'localhost', l2.info['port']) assert ret['id'] == l2.info['id'] l1.daemon.wait_for_log('WIRE_GOSSIPCTL_HAND_BACK_PEER') l2.daemon.wait_for_log('WIRE_GOSSIPCTL_HAND_BACK_PEER') ret = l2.rpc.connect(l3.info['id'], 'localhost', l3.info['port']) assert ret['id'] == l3.info['id'] l2.daemon.wait_for_log('WIRE_GOSSIPCTL_HAND_BACK_PEER') l3.daemon.wait_for_log('WIRE_GOSSIPCTL_HAND_BACK_PEER') c1 = self.fund_channel(l1, l2, 10**6) c2 = self.fund_channel(l2, l3, 10**6) # Make sure l1 has seen announce for all channels. self.wait_for_routes(l1, [c1, c2]) route = l1.rpc.getroute(l3.info['id'], 4999999, 1)["route"] assert len(route) == 2 assert route[0]['msatoshi'] == 5010198 assert route[0]['delay'] == 20 + 9 assert route[1]['msatoshi'] == 4999999 assert route[1]['delay'] == 9 # Modify so we overpay, overdo the cltv. route[0]['msatoshi'] += 2000 route[0]['delay'] += 20 route[1]['msatoshi'] += 1000 route[1]['delay'] += 10 # This should work. rhash = l3.rpc.invoice(4999999, 'test_forward_pad_fees_and_cltv', 'desc')['payment_hash'] l1.rpc.sendpay(to_json(route), rhash) assert l3.rpc.listinvoice('test_forward_pad_fees_and_cltv')[0]['complete'] == True @unittest.skipIf(not DEVELOPER, "needs DEVELOPER=1") def test_htlc_out_timeout(self): """Test that we drop onchain if the peer doesn't time out HTLC""" # HTLC 1->2, 1 fails after it's irrevocably committed, can't reconnect disconnects = ['@WIRE_REVOKE_AND_ACK'] l1 = self.node_factory.get_node(disconnect=disconnects, options=['--no-reconnect']) l2 = self.node_factory.get_node() l1.rpc.connect(l2.info['id'], 'localhost', l2.info['port']) chanid = self.fund_channel(l1, l2, 10**6) # Wait for route propagation. self.wait_for_routes(l1, [chanid]) amt = 200000000 inv = l2.rpc.invoice(amt, 'test_htlc_out_timeout', 'desc')['bolt11'] assert l2.rpc.listinvoice('test_htlc_out_timeout')[0]['complete'] == False payfuture = self.executor.submit(l1.rpc.pay, inv) # l1 will disconnect, and not reconnect. l1.daemon.wait_for_log('dev_disconnect: @WIRE_REVOKE_AND_ACK') # Takes 6 blocks to timeout (cltv-final + 1), but we also give grace period of 1 block. bitcoind.generate_block(5 + 1) assert not l1.daemon.is_in_log('hit deadline') bitcoind.generate_block(1) l1.daemon.wait_for_log('Offered HTLC 0 SENT_ADD_ACK_REVOCATION cltv .* hit deadline') l1.daemon.wait_for_log('sendrawtx exit 0') l1.bitcoin.generate_block(1) l1.daemon.wait_for_log('-> ONCHAIND_OUR_UNILATERAL') l2.daemon.wait_for_log('-> ONCHAIND_THEIR_UNILATERAL') # L1 will timeout HTLC immediately l1.daemon.wait_for_logs(['Propose handling OUR_UNILATERAL/OUR_HTLC by OUR_HTLC_TIMEOUT_TX .* in 0 blocks', 'Propose handling OUR_UNILATERAL/DELAYED_OUTPUT_TO_US by OUR_DELAYED_RETURN_TO_WALLET .* in 5 blocks']) l1.daemon.wait_for_log('sendrawtx exit 0') bitcoind.generate_block(1) l1.daemon.wait_for_log('Propose handling OUR_HTLC_TIMEOUT_TX/DELAYED_OUTPUT_TO_US by OUR_DELAYED_RETURN_TO_WALLET .* in 5 blocks') bitcoind.generate_block(5) # It should now claim both the to-local and htlc-timeout-tx outputs. l1.daemon.wait_for_logs(['Broadcasting OUR_DELAYED_RETURN_TO_WALLET', 'Broadcasting OUR_DELAYED_RETURN_TO_WALLET', 'sendrawtx exit 0', 'sendrawtx exit 0']) # Now, 100 blocks it should be done. bitcoind.generate_block(100) l1.daemon.wait_for_log('onchaind complete, forgetting peer') l2.daemon.wait_for_log('onchaind complete, forgetting peer') @unittest.skipIf(not DEVELOPER, "needs DEVELOPER=1") def test_htlc_in_timeout(self): """Test that we drop onchain if the peer doesn't accept fulfilled HTLC""" # HTLC 1->2, 1 fails after 2 has sent committed the fulfill disconnects = ['-WIRE_REVOKE_AND_ACK*2'] l1 = self.node_factory.get_node(disconnect=disconnects, options=['--no-reconnect']) l2 = self.node_factory.get_node() l1.rpc.connect(l2.info['id'], 'localhost', l2.info['port']) chanid = self.fund_channel(l1, l2, 10**6) self.wait_for_routes(l1, [chanid]) amt = 200000000 inv = l2.rpc.invoice(amt, 'test_htlc_in_timeout', 'desc')['bolt11'] assert l2.rpc.listinvoice('test_htlc_in_timeout')[0]['complete'] == False payfuture = self.executor.submit(l1.rpc.pay, inv) # l1 will disconnect and not reconnect. l1.daemon.wait_for_log('dev_disconnect: -WIRE_REVOKE_AND_ACK') # Deadline HTLC expiry minus 1/2 cltv-expiry delta (rounded up) (== cltv - 3). ctlv is 5+1. bitcoind.generate_block(2) assert not l2.daemon.is_in_log('hit deadline') bitcoind.generate_block(1) l2.daemon.wait_for_log('Fulfilled HTLC 0 SENT_REMOVE_COMMIT cltv .* hit deadline') l2.daemon.wait_for_log('sendrawtx exit 0') l2.bitcoin.generate_block(1) l2.daemon.wait_for_log('-> ONCHAIND_OUR_UNILATERAL') l1.daemon.wait_for_log('-> ONCHAIND_THEIR_UNILATERAL') # L2 will collect HTLC l2.daemon.wait_for_log('Propose handling OUR_UNILATERAL/THEIR_HTLC by OUR_HTLC_SUCCESS_TX .* in 0 blocks') l2.daemon.wait_for_log('sendrawtx exit 0') bitcoind.generate_block(1) l2.daemon.wait_for_log('Propose handling OUR_HTLC_SUCCESS_TX/DELAYED_OUTPUT_TO_US by OUR_DELAYED_RETURN_TO_WALLET .* in 5 blocks') bitcoind.generate_block(5) l2.daemon.wait_for_log('Broadcasting OUR_DELAYED_RETURN_TO_WALLET') l2.daemon.wait_for_log('sendrawtx exit 0') # Now, 100 blocks it should be both done. bitcoind.generate_block(100) l1.daemon.wait_for_log('onchaind complete, forgetting peer') l2.daemon.wait_for_log('onchaind complete, forgetting peer') @unittest.skipIf(not DEVELOPER, "needs DEVELOPER=1") def test_disconnect(self): # These should all make us fail, and retry. # FIXME: Configure short timeout for reconnect! disconnects = ['-WIRE_INIT', '@WIRE_INIT', '+WIRE_INIT'] l1 = self.node_factory.get_node(disconnect=disconnects) l2 = self.node_factory.get_node() l1.rpc.connect(l2.info['id'], 'localhost', l2.info['port']) # Should have 3 connect fails. for d in disconnects: l1.daemon.wait_for_log('Failed connected out for {}, will try again' .format(l2.info['id'])) # Should still only have one peer! assert len(l1.rpc.getpeers()) == 1 assert len(l2.rpc.getpeers()) == 1 @unittest.skipIf(not DEVELOPER, "needs DEVELOPER=1") def test_disconnect_funder(self): # Now error on funder side duringchannel open. disconnects = ['-WIRE_OPEN_CHANNEL', '@WIRE_OPEN_CHANNEL', '+WIRE_OPEN_CHANNEL', '-WIRE_FUNDING_CREATED', '@WIRE_FUNDING_CREATED'] l1 = self.node_factory.get_node(disconnect=disconnects) l2 = self.node_factory.get_node() addr = l1.rpc.newaddr()['address'] txid = l1.bitcoin.rpc.sendtoaddress(addr, 20000 / 10**6) tx = l1.bitcoin.rpc.getrawtransaction(txid) l1.rpc.addfunds(tx) for d in disconnects: l1.rpc.connect(l2.info['id'], 'localhost', l2.info['port']) self.assertRaises(ValueError, l1.rpc.fundchannel, l2.info['id'], 20000) assert l1.rpc.getpeer(l2.info['id']) == None # This one will succeed. l1.rpc.connect(l2.info['id'], 'localhost', l2.info['port']) l1.rpc.fundchannel(l2.info['id'], 20000) # Should still only have one peer! assert len(l1.rpc.getpeers()) == 1 assert len(l2.rpc.getpeers()) == 1 @unittest.skipIf(not DEVELOPER, "needs DEVELOPER=1") def test_disconnect_fundee(self): # Now error on fundee side during channel open. disconnects = ['-WIRE_ACCEPT_CHANNEL', '@WIRE_ACCEPT_CHANNEL', '+WIRE_ACCEPT_CHANNEL'] l1 = self.node_factory.get_node() l2 = self.node_factory.get_node(disconnect=disconnects) addr = l1.rpc.newaddr()['address'] txid = l1.bitcoin.rpc.sendtoaddress(addr, 20000 / 10**6) tx = l1.bitcoin.rpc.getrawtransaction(txid) l1.rpc.addfunds(tx) for d in disconnects: l1.rpc.connect(l2.info['id'], 'localhost', l2.info['port']) self.assertRaises(ValueError, l1.rpc.fundchannel, l2.info['id'], 20000) assert l1.rpc.getpeer(l2.info['id']) == None # This one will succeed. l1.rpc.connect(l2.info['id'], 'localhost', l2.info['port']) l1.rpc.fundchannel(l2.info['id'], 20000) # Should still only have one peer! assert len(l1.rpc.getpeers()) == 1 assert len(l2.rpc.getpeers()) == 1 @unittest.skipIf(not DEVELOPER, "needs DEVELOPER=1") def test_disconnect_half_signed(self): # Now, these are the corner cases. Fundee sends funding_signed, # but funder doesn't receive it. disconnects = ['@WIRE_FUNDING_SIGNED'] l1 = self.node_factory.get_node() l2 = self.node_factory.get_node(disconnect=disconnects) addr = l1.rpc.newaddr()['address'] txid = l1.bitcoin.rpc.sendtoaddress(addr, 20000 / 10**6) tx = l1.bitcoin.rpc.getrawtransaction(txid) l1.rpc.addfunds(tx) l1.rpc.connect(l2.info['id'], 'localhost', l2.info['port']) self.assertRaises(ValueError, l1.rpc.fundchannel, l2.info['id'], 20000) # Fundee remembers, funder doesn't. assert l1.rpc.getpeer(l2.info['id']) == None assert l2.rpc.getpeer(l1.info['id'])['peerid'] == l1.info['id'] @unittest.skipIf(not DEVELOPER, "needs DEVELOPER=1") def test_reconnect_signed(self): # This will fail *after* both sides consider channel opening. disconnects = ['+WIRE_FUNDING_SIGNED'] l1 = self.node_factory.get_node() l2 = self.node_factory.get_node(disconnect=disconnects) addr = l1.rpc.newaddr()['address'] txid = l1.bitcoin.rpc.sendtoaddress(addr, 20000 / 10**6) tx = l1.bitcoin.rpc.getrawtransaction(txid) l1.rpc.addfunds(tx) l1.rpc.connect(l2.info['id'], 'localhost', l2.info['port']) l1.rpc.fundchannel(l2.info['id'], 20000) # They haven't forgotten each other. assert l1.rpc.getpeer(l2.info['id'])['peerid'] == l2.info['id'] assert l2.rpc.getpeer(l1.info['id'])['peerid'] == l1.info['id'] # Technically, this is async to fundchannel (and could reconnect first) l1.daemon.wait_for_logs(['sendrawtx exit 0', 'Peer has reconnected, state CHANNELD_AWAITING_LOCKIN']) l1.bitcoin.generate_block(6) l1.daemon.wait_for_log('-> CHANNELD_NORMAL') l2.daemon.wait_for_log('-> CHANNELD_NORMAL') @unittest.skipIf(not DEVELOPER, "needs DEVELOPER=1") def test_reconnect_openingd(self): # Openingd thinks we're still opening; funder reconnects.. disconnects = ['0WIRE_ACCEPT_CHANNEL'] l1 = self.node_factory.get_node() l2 = self.node_factory.get_node(disconnect=disconnects) l1.rpc.connect(l2.info['id'], 'localhost', l2.info['port']) addr = l1.rpc.newaddr()['address'] txid = l1.bitcoin.rpc.sendtoaddress(addr, 20000 / 10**6) tx = l1.bitcoin.rpc.getrawtransaction(txid) l1.rpc.addfunds(tx) # l2 closes on l1, l1 forgets. self.assertRaises(ValueError, l1.rpc.fundchannel, l2.info['id'], 20000) assert l1.rpc.getpeer(l2.info['id']) == None # Reconnect. l1.rpc.connect(l2.info['id'], 'localhost', l2.info['port']) # We should get a message about reconnecting. l2.daemon.wait_for_log('Peer has reconnected, state OPENINGD') # Should work fine. l1.rpc.fundchannel(l2.info['id'], 20000) l1.daemon.wait_for_log('sendrawtx exit 0') # Just to be sure, second openingd hand over to channeld. l2.daemon.wait_for_log('lightning_openingd.*REPLY WIRE_OPENING_FUNDEE_REPLY with 2 fds') @unittest.skip("temporarily disabled due to flaky behavior, issue #468") @unittest.skipIf(not DEVELOPER, "needs DEVELOPER=1") def test_reconnect_normal(self): # Should reconnect fine even if locked message gets lost. disconnects = ['-WIRE_FUNDING_LOCKED', '@WIRE_FUNDING_LOCKED', '+WIRE_FUNDING_LOCKED'] l1 = self.node_factory.get_node(disconnect=disconnects) l2 = self.node_factory.get_node() ret = l1.rpc.connect(l2.info['id'], 'localhost', l2.info['port']) self.fund_channel(l1, l2, 10**6) @unittest.skipIf(not DEVELOPER, "needs DEVELOPER=1") def test_reconnect_sender_add1(self): # Fail after add is OK, will cause payment failure though. disconnects = ['-WIRE_UPDATE_ADD_HTLC-nocommit', '+WIRE_UPDATE_ADD_HTLC-nocommit', '@WIRE_UPDATE_ADD_HTLC-nocommit'] l1 = self.node_factory.get_node(disconnect=disconnects) l2 = self.node_factory.get_node() ret = l1.rpc.connect(l2.info['id'], 'localhost', l2.info['port']) self.fund_channel(l1, l2, 10**6) amt = 200000000 rhash = l2.rpc.invoice(amt, 'test_reconnect_sender_add1', 'desc')['payment_hash'] assert l2.rpc.listinvoice('test_reconnect_sender_add1')[0]['complete'] == False route = [ { 'msatoshi' : amt, 'id' : l2.info['id'], 'delay' : 5, 'channel': '1:1:1'} ] for i in range(0,len(disconnects)): self.assertRaises(ValueError, l1.rpc.sendpay, to_json(route), rhash) # Wait for reconnection. l1.daemon.wait_for_log('Already have funding locked in') # This will send commit, so will reconnect as required. l1.rpc.sendpay(to_json(route), rhash) @unittest.skipIf(not DEVELOPER, "needs DEVELOPER=1") def test_reconnect_sender_add(self): disconnects = ['-WIRE_COMMITMENT_SIGNED', '@WIRE_COMMITMENT_SIGNED', '+WIRE_COMMITMENT_SIGNED', '-WIRE_REVOKE_AND_ACK', '@WIRE_REVOKE_AND_ACK', '+WIRE_REVOKE_AND_ACK'] l1 = self.node_factory.get_node(disconnect=disconnects) l2 = self.node_factory.get_node() ret = l1.rpc.connect(l2.info['id'], 'localhost', l2.info['port']) self.fund_channel(l1, l2, 10**6) amt = 200000000 rhash = l2.rpc.invoice(amt, 'testpayment', 'desc')['payment_hash'] assert l2.rpc.listinvoice('testpayment')[0]['complete'] == False route = [ { 'msatoshi' : amt, 'id' : l2.info['id'], 'delay' : 5, 'channel': '1:1:1'} ] # This will send commit, so will reconnect as required. l1.rpc.sendpay(to_json(route), rhash) # Should have printed this for every reconnect. for i in range(0,len(disconnects)): l1.daemon.wait_for_log('Already have funding locked in') @unittest.skipIf(not DEVELOPER, "needs DEVELOPER=1") def test_reconnect_receiver_add(self): disconnects = ['-WIRE_COMMITMENT_SIGNED', '@WIRE_COMMITMENT_SIGNED', '+WIRE_COMMITMENT_SIGNED', '-WIRE_REVOKE_AND_ACK', '@WIRE_REVOKE_AND_ACK', '+WIRE_REVOKE_AND_ACK'] l1 = self.node_factory.get_node() l2 = self.node_factory.get_node(disconnect=disconnects) ret = l1.rpc.connect(l2.info['id'], 'localhost', l2.info['port']) self.fund_channel(l1, l2, 10**6) amt = 200000000 rhash = l2.rpc.invoice(amt, 'testpayment2', 'desc')['payment_hash'] assert l2.rpc.listinvoice('testpayment2')[0]['complete'] == False route = [ { 'msatoshi' : amt, 'id' : l2.info['id'], 'delay' : 5, 'channel': '1:1:1'} ] l1.rpc.sendpay(to_json(route), rhash) for i in range(len(disconnects)): l1.daemon.wait_for_log('Already have funding locked in') assert l2.rpc.listinvoice('testpayment2')[0]['complete'] == True @unittest.skipIf(not DEVELOPER, "needs DEVELOPER=1") def test_reconnect_receiver_fulfill(self): # Ordering matters: after +WIRE_UPDATE_FULFILL_HTLC, channeld # will continue and try to send WIRE_COMMITMENT_SIGNED: if # that's the next failure, it will do two in one run. disconnects = ['@WIRE_UPDATE_FULFILL_HTLC', '+WIRE_UPDATE_FULFILL_HTLC', '-WIRE_UPDATE_FULFILL_HTLC', '-WIRE_COMMITMENT_SIGNED', '@WIRE_COMMITMENT_SIGNED', '+WIRE_COMMITMENT_SIGNED', '-WIRE_REVOKE_AND_ACK', '@WIRE_REVOKE_AND_ACK', '+WIRE_REVOKE_AND_ACK'] l1 = self.node_factory.get_node() l2 = self.node_factory.get_node(disconnect=disconnects) ret = l1.rpc.connect(l2.info['id'], 'localhost', l2.info['port']) self.fund_channel(l1, l2, 10**6) amt = 200000000 rhash = l2.rpc.invoice(amt, 'testpayment2', 'desc')['payment_hash'] assert l2.rpc.listinvoice('testpayment2')[0]['complete'] == False route = [ { 'msatoshi' : amt, 'id' : l2.info['id'], 'delay' : 5, 'channel': '1:1:1'} ] l1.rpc.sendpay(to_json(route), rhash) for i in range(len(disconnects)): l1.daemon.wait_for_log('Already have funding locked in') assert l2.rpc.listinvoice('testpayment2')[0]['complete'] == True @unittest.skipIf(not DEVELOPER, "needs DEVELOPER=1") def test_shutdown_reconnect(self): disconnects = ['-WIRE_SHUTDOWN', '@WIRE_SHUTDOWN', '+WIRE_SHUTDOWN'] l1 = self.node_factory.get_node(disconnect=disconnects) l2 = self.node_factory.get_node() l1.rpc.connect(l2.info['id'], 'localhost', l2.info['port']) self.fund_channel(l1, l2, 10**6) self.pay(l1,l2,200000000) assert l1.bitcoin.rpc.getmempoolinfo()['size'] == 0 # This should return, then close. l1.rpc.close(l2.info['id']) l1.daemon.wait_for_log('-> CHANNELD_SHUTTING_DOWN') l2.daemon.wait_for_log('-> CHANNELD_SHUTTING_DOWN') l1.daemon.wait_for_log('-> CLOSINGD_SIGEXCHANGE') l2.daemon.wait_for_log('-> CLOSINGD_SIGEXCHANGE') # And should put closing into mempool (happens async, so # CLOSINGD_COMPLETE may come first). l1.daemon.wait_for_logs(['sendrawtx exit 0', '-> CLOSINGD_COMPLETE']) l2.daemon.wait_for_logs(['sendrawtx exit 0', '-> CLOSINGD_COMPLETE']) assert l1.bitcoin.rpc.getmempoolinfo()['size'] == 1 @unittest.skipIf(not DEVELOPER, "needs DEVELOPER=1") def test_closing_negotiation_reconnect(self): disconnects = ['-WIRE_CLOSING_SIGNED', '@WIRE_CLOSING_SIGNED', '+WIRE_CLOSING_SIGNED'] l1 = self.node_factory.get_node(disconnect=disconnects) l2 = self.node_factory.get_node() l1.rpc.connect(l2.info['id'], 'localhost', l2.info['port']) self.fund_channel(l1, l2, 10**6) self.pay(l1,l2,200000000) assert l1.bitcoin.rpc.getmempoolinfo()['size'] == 0 # This should return, then close. l1.rpc.close(l2.info['id']) l1.daemon.wait_for_log('-> CHANNELD_SHUTTING_DOWN') l2.daemon.wait_for_log('-> CHANNELD_SHUTTING_DOWN') l1.daemon.wait_for_log('-> CLOSINGD_SIGEXCHANGE') l2.daemon.wait_for_log('-> CLOSINGD_SIGEXCHANGE') # And should put closing into mempool (happens async, so # CLOSINGD_COMPLETE may come first). l1.daemon.wait_for_logs(['sendrawtx exit 0', '-> CLOSINGD_COMPLETE']) l2.daemon.wait_for_logs(['sendrawtx exit 0', '-> CLOSINGD_COMPLETE']) assert l1.bitcoin.rpc.getmempoolinfo()['size'] == 1 def test_json_addfunds(self): sat = 10**6 l1 = self.node_factory.get_node() addr = l1.rpc.newaddr()['address'] txid = l1.bitcoin.rpc.sendtoaddress(addr, 0.01) tx = l1.bitcoin.rpc.getrawtransaction(txid) # The first time should succeed assert l1.rpc.addfunds(tx) == { "outputs" : 1, "satoshis" : sat } # Second time should fail, we already have those funds self.assertRaises(ValueError, l1.rpc.addfunds, tx) def test_withdraw(self): amount = 1000000 # Don't get any funds from previous runs. l1 = self.node_factory.get_node(random_hsm=True) l2 = self.node_factory.get_node(random_hsm=True) addr = l1.rpc.newaddr()['address'] # Add some funds to withdraw later for i in range(10): txid = l1.bitcoin.rpc.sendtoaddress(addr, amount / 10**8 + 0.01) tx = l1.bitcoin.rpc.getrawtransaction(txid) l1.rpc.addfunds(tx) # Reach around into the db to check that outputs were added db = sqlite3.connect(os.path.join(l1.daemon.lightning_dir, "lightningd.sqlite3")) c = db.cursor() c.execute('SELECT COUNT(*) FROM outputs WHERE status=0') assert(c.fetchone()[0] == 10) waddr = l1.bitcoin.rpc.getnewaddress() # Now attempt to withdraw some (making sure we collect multiple inputs) self.assertRaises(ValueError, l1.rpc.withdraw, 'not an address', amount) self.assertRaises(ValueError, l1.rpc.withdraw, waddr, 'not an amount') self.assertRaises(ValueError, l1.rpc.withdraw, waddr, -amount) out = l1.rpc.withdraw(waddr, 2*amount) # Make sure bitcoind received the withdrawal unspent = l1.bitcoin.rpc.listunspent(0) withdrawal = [u for u in unspent if u['txid'] == out['txid']] assert(len(withdrawal) == 1) assert(withdrawal[0]['amount'] == Decimal('0.02')) # Now make sure two of them were marked as spent c = db.cursor() c.execute('SELECT COUNT(*) FROM outputs WHERE status=2') assert(c.fetchone()[0] == 2) # Now send some money to l2. # lightningd uses P2SH-P2WPKH waddr = l2.rpc.newaddr()['address'] out = l1.rpc.withdraw(waddr, 2*amount) l1.bitcoin.rpc.generate(1) # Make sure l2 received the withdrawal. wait_for(lambda: len(l2.rpc.listfunds()['outputs']) == 1) outputs = l2.db_query('SELECT value FROM outputs WHERE status=0;') assert len(outputs) == 1 and outputs[0]['value'] == 2*amount # Now make sure an additional two of them were marked as spent c = db.cursor() c.execute('SELECT COUNT(*) FROM outputs WHERE status=2') assert(c.fetchone()[0] == 4) # Simple test for withdrawal to P2WPKH # Address from: https://bc-2.jp/tools/bech32demo/index.html waddr = 'tb1qw508d6qejxtdg4y5r3zarvary0c5xw7kxpjzsx' self.assertRaises(ValueError, l1.rpc.withdraw, 'xx1qw508d6qejxtdg4y5r3zarvary0c5xw7kxpjzsx', 2*amount) self.assertRaises(ValueError, l1.rpc.withdraw, 'tb1pw508d6qejxtdg4y5r3zarvary0c5xw7kdl9fad', 2*amount) self.assertRaises(ValueError, l1.rpc.withdraw, 'tb1qw508d6qejxtdg4y5r3zarvary0c5xw7kxxxxxx', 2*amount) out = l1.rpc.withdraw(waddr, 2*amount) l1.bitcoin.rpc.generate(1) # Now make sure additional two of them were marked as spent c = db.cursor() c.execute('SELECT COUNT(*) FROM outputs WHERE status=2') assert(c.fetchone()[0] == 6) # Simple test for withdrawal to P2WSH # Address from: https://bc-2.jp/tools/bech32demo/index.html waddr = 'tb1qrp33g0q5c5txsp9arysrx4k6zdkfs4nce4xj0gdcccefvpysxf3q0sl5k7' self.assertRaises(ValueError, l1.rpc.withdraw, 'xx1qrp33g0q5c5txsp9arysrx4k6zdkfs4nce4xj0gdcccefvpysxf3q0sl5k7', 2*amount) self.assertRaises(ValueError, l1.rpc.withdraw, 'tb1prp33g0q5c5txsp9arysrx4k6zdkfs4nce4xj0gdcccefvpysxf3qsm03tq', 2*amount) self.assertRaises(ValueError, l1.rpc.withdraw, 'tb1qrp33g0q5c5txsp9arysrx4k6zdkfs4nce4xj0gdcccefvpysxf3qxxxxxx', 2*amount) out = l1.rpc.withdraw(waddr, 2*amount) l1.bitcoin.rpc.generate(1) # Now make sure additional two of them were marked as spent c = db.cursor() c.execute('SELECT COUNT(*) FROM outputs WHERE status=2') assert(c.fetchone()[0] == 8) # failure testing for invalid SegWit addresses, from BIP173 # HRP character out of range self.assertRaises(ValueError, l1.rpc.withdraw, ' 1nwldj5', 2*amount) # overall max length exceeded self.assertRaises(ValueError, l1.rpc.withdraw, 'an84characterslonghumanreadablepartthatcontainsthenumber1andtheexcludedcharactersbio1569pvx', 2*amount) # No separator character self.assertRaises(ValueError, l1.rpc.withdraw, 'pzry9x0s0muk', 2*amount) # Empty HRP self.assertRaises(ValueError, l1.rpc.withdraw, '1pzry9x0s0muk', 2*amount) # Invalid witness version self.assertRaises(ValueError, l1.rpc.withdraw, 'BC13W508D6QEJXTDG4Y5R3ZARVARY0C5XW7KN40WF2', 2*amount) # Invalid program length for witness version 0 (per BIP141) self.assertRaises(ValueError, l1.rpc.withdraw, 'BC1QR508D6QEJXTDG4Y5R3ZARVARYV98GJ9P', 2*amount) # Mixed case self.assertRaises(ValueError, l1.rpc.withdraw, 'tb1qrp33g0q5c5txsp9arysrx4k6zdkfs4nce4xj0gdcccefvpysxf3q0sL5k7', 2*amount) # Non-zero padding in 8-to-5 conversion self.assertRaises(ValueError, l1.rpc.withdraw, 'tb1qrp33g0q5c5txsp9arysrx4k6zdkfs4nce4xj0gdcccefvpysxf3pjxtptv', 2*amount) # Should have 6 outputs available. c = db.cursor() c.execute('SELECT COUNT(*) FROM outputs WHERE status=0') assert(c.fetchone()[0] == 6) out = l1.rpc.withdraw(waddr, 'all') c = db.cursor() c.execute('SELECT COUNT(*) FROM outputs WHERE status=0') assert(c.fetchone()[0] == 0) # This should fail, can't even afford fee. self.assertRaises(ValueError, l1.rpc.withdraw, waddr, 'all') l1.daemon.wait_for_log('Cannot afford fee') def test_funding_change(self): """Add some funds, fund a channel, and make sure we remember the change """ l1, l2 = self.connect() addr = l1.rpc.newaddr()['address'] txid = l1.bitcoin.rpc.sendtoaddress(addr, 0.1) tx = l1.bitcoin.rpc.getrawtransaction(txid) l1.rpc.addfunds(tx) outputs = l1.db_query('SELECT value FROM outputs WHERE status=0;') assert len(outputs) == 1 and outputs[0]['value'] == 10000000 l1.rpc.fundchannel(l2.info['id'], 1000000) outputs = {r['status']: r['value'] for r in l1.db_query( 'SELECT status, SUM(value) AS value FROM outputs GROUP BY status;')} # The 10m out is spent and we have a change output of 9m-fee assert outputs[0] > 8990000 assert outputs[2] == 10000000 def test_funding_fail(self): """Add some funds, fund a channel without enough funds""" # Previous runs with same bitcoind can leave funds! l1 = self.node_factory.get_node(random_hsm=True) max_locktime = 3 * 6 * 24 l2 = self.node_factory.get_node(options=['--locktime-blocks={}'.format(max_locktime + 1)]) l1.rpc.connect(l2.info['id'], 'localhost', l2.info['port']) funds = 1000000 addr = l1.rpc.newaddr()['address'] txid = l1.bitcoin.rpc.sendtoaddress(addr, funds / 10**8) bitcoind.generate_block(1) # Wait for it to arrive. wait_for(lambda: len(l1.rpc.listfunds()['outputs']) > 0) # Fail because l1 dislikes l2's huge locktime. self.assertRaisesRegex(ValueError, r'to_self_delay \d+ larger than \d+', l1.rpc.fundchannel, l2.info['id'], int(funds/10)) assert l1.rpc.getpeers()['peers'][0]['connected'] assert l2.rpc.getpeers()['peers'][0]['connected'] # Restart l2 without ridiculous locktime. l2.daemon.cmd_line.remove('--locktime-blocks={}'.format(max_locktime + 1)) l2.restart() l1.rpc.connect(l2.info['id'], 'localhost', l2.info['port']) # We don't have enough left to cover fees if we try to spend it all. self.assertRaisesRegex(ValueError, r'Cannot afford funding transaction', l1.rpc.fundchannel, l2.info['id'], funds) # Should still be connected. assert l1.rpc.getpeers()['peers'][0]['connected'] assert l2.rpc.getpeers()['peers'][0]['connected'] # This works. l1.rpc.fundchannel(l2.info['id'], int(funds/10)) def test_addfunds_from_block(self): """Send funds to the daemon without telling it explicitly """ # Previous runs with same bitcoind can leave funds! l1 = self.node_factory.get_node(random_hsm=True) addr = l1.rpc.newaddr()['address'] txid = l1.bitcoin.rpc.sendtoaddress(addr, 0.1) l1.bitcoin.rpc.generate(1) wait_for(lambda: len(l1.rpc.listfunds()['outputs']) == 1) outputs = l1.db_query('SELECT value FROM outputs WHERE status=0;') assert len(outputs) == 1 and outputs[0]['value'] == 10000000 # Now the same, but create a conflict between addfunds and from block txid = l1.bitcoin.rpc.sendtoaddress(addr, 0.1) tx = l1.bitcoin.rpc.getrawtransaction(txid) l1.rpc.addfunds(tx) l1.bitcoin.rpc.generate(1) time.sleep(5) @unittest.skipIf(not DEVELOPER, "needs DEVELOPER=1") def test_channel_persistence(self): # Start two nodes and open a channel (to remember). l2 will # mysteriously die while committing the first HTLC so we can # check that HTLCs reloaded from the DB work. l1 = self.node_factory.get_node() l2 = self.node_factory.get_node(disconnect=['=WIRE_COMMITMENT_SIGNED-nocommit']) l1.rpc.connect(l2.info['id'], 'localhost', l2.info['port']) # Neither node should have a channel open, they are just connected for n in (l1, l2): assert(n.db_query('SELECT COUNT(id) as count FROM channels;')[0]['count'] == 0) self.fund_channel(l1, l2, 100000) peers = l1.rpc.getpeers()['peers'] assert(len(peers) == 1 and peers[0]['state'] == 'CHANNELD_NORMAL') # Both nodes should now have exactly one channel in the database for n in (l1, l2): assert(n.db_query('SELECT COUNT(id) as count FROM channels;')[0]['count'] == 1) # Fire off a sendpay request, it'll get interrupted by a restart fut = self.executor.submit(self.pay, l1, l2, 10000) # Wait for it to be committed to, i.e., stored in the DB l1.daemon.wait_for_log('peer_in WIRE_COMMITMENT_SIGNED') # Stop l2, l1 will reattempt to connect print("Killing l2 in mid HTLC") l2.daemon.proc.terminate() # Clear the disconnect and timer stop so we can proceed normally l2.daemon.cmd_line = [e for e in l2.daemon.cmd_line if 'disconnect' not in e] print(" ".join(l2.daemon.cmd_line + ['--dev-debugger=channeld'])) # Wait for l1 to notice wait_for(lambda: not l1.rpc.getpeers()['peers'][0]['connected']) # Now restart l1 and it should reload peers/channels from the DB l2.daemon.start() wait_for(lambda: len(l2.rpc.getpeers()['peers']) == 1) # Wait for the restored HTLC to finish wait_for(lambda: l1.rpc.getpeers()['peers'][0]['msatoshi_to_us'] == 99990000, interval=1) wait_for(lambda: len([p for p in l1.rpc.getpeers()['peers'] if p['connected']]), interval=1) wait_for(lambda: len([p for p in l2.rpc.getpeers()['peers'] if p['connected']]), interval=1) # Now make sure this is really functional by sending a payment self.pay(l1, l2, 10000) time.sleep(1) assert l1.rpc.getpeers()['peers'][0]['msatoshi_to_us'] == 99980000 assert l2.rpc.getpeers()['peers'][0]['msatoshi_to_us'] == 20000 # Finally restart l1, and make sure it remembers l1.stop() l1.daemon.start() assert l1.rpc.getpeers()['peers'][0]['msatoshi_to_us'] == 99980000 # Now make sure l1 is watching for unilateral closes l2.rpc.dev_fail(l1.info['id']); l2.daemon.wait_for_log('Failing due to dev-fail command') l2.daemon.wait_for_log('sendrawtx exit 0') bitcoind.generate_block(1) # L1 must notice. l1.daemon.wait_for_log('-> ONCHAIND_THEIR_UNILATERAL') @unittest.skipIf(not DEVELOPER, "needs DEVELOPER=1 for --dev-broadcast-interval") def test_gossip_badsig(self): l1 = self.node_factory.get_node() l2 = self.node_factory.get_node() l3 = self.node_factory.get_node() # l2 connects to both, so l1 can't reconnect and thus l2 drops to chain l2.rpc.connect(l1.info['id'], 'localhost', l1.info['port']) l2.rpc.connect(l3.info['id'], 'localhost', l3.info['port']) self.fund_channel(l2, l1, 10**6) self.fund_channel(l2, l3, 10**6) # Wait for route propagation. l1.bitcoin.generate_block(5) l1.daemon.wait_for_log('Received node_announcement for node {}' .format(l3.info['id'])) assert not l1.daemon.is_in_log('signature verification failed') assert not l2.daemon.is_in_log('signature verification failed') assert not l3.daemon.is_in_log('signature verification failed') def test_waitinvoice(self): """Test waiting for one invoice will not return if another invoice is paid. """ # Setup l1, l2 = self.connect() self.fund_channel(l1, l2, 10**6) l1.bitcoin.generate_block(6) l1.daemon.wait_for_log('Received node_announcement for node {}'.format(l2.info['id'])) # Create invoices inv1 = l2.rpc.invoice(1000, 'inv1', 'inv1') inv2 = l2.rpc.invoice(1000, 'inv2', 'inv2') # Start waiting on invoice 1, should block f = self.executor.submit(l2.rpc.waitinvoice, 'inv1') time.sleep(1) assert not f.done() # Pay invoice 2 l1.rpc.pay(inv2['bolt11']) # Waiter should stil be blocked time.sleep(1) assert not f.done() # Pay invoice 1 l1.rpc.pay(inv1['bolt11']) # Waiter should now finish r = f.result(timeout=5) assert r['label'] == 'inv1' def test_waitanyinvoice(self): """Test various variants of waiting for the next invoice to complete. """ l1, l2 = self.connect() inv1 = l2.rpc.invoice(1000, 'inv1', 'inv1') inv2 = l2.rpc.invoice(1000, 'inv2', 'inv2') inv3 = l2.rpc.invoice(1000, 'inv3', 'inv3') self.fund_channel(l1, l2, 10**6) l1.bitcoin.generate_block(6) l1.daemon.wait_for_log('Received node_announcement for node {}'.format(l2.info['id'])) # Attempt to wait for the first invoice f = self.executor.submit(l2.rpc.waitanyinvoice) time.sleep(1) # The call to waitanyinvoice should not have returned just yet assert not f.done() # Now pay the first two invoices and make sure we notice l1.rpc.pay(inv1['bolt11']) l1.rpc.pay(inv2['bolt11']) r = f.result(timeout=5) assert r['label'] == 'inv1' pay_index = r['pay_index'] # This one should return immediately with inv2 r = self.executor.submit(l2.rpc.waitanyinvoice, pay_index).result(timeout=5) assert r['label'] == 'inv2' pay_index = r['pay_index'] # Now spawn the next waiter f = self.executor.submit(l2.rpc.waitanyinvoice, pay_index) time.sleep(1) assert not f.done() l1.rpc.pay(inv3['bolt11']) r = f.result(timeout=5) assert r['label'] == 'inv3' self.assertRaises(ValueError, l2.rpc.waitanyinvoice, 'non-number') def test_waitanyinvoice_reversed(self): """Test waiting for invoices, where they are paid in reverse order to when they are created. """ # Setup l1, l2 = self.connect() self.fund_channel(l1, l2, 10**6) l1.bitcoin.generate_block(6) l1.daemon.wait_for_log('Received node_announcement for node {}'.format(l2.info['id'])) # Create invoices inv1 = l2.rpc.invoice(1000, 'inv1', 'inv1') inv2 = l2.rpc.invoice(1000, 'inv2', 'inv2') # Pay inv2, wait, pay inv1, wait # Pay inv2 l1.rpc.pay(inv2['bolt11']) # Wait - should not block, should return inv2 r = self.executor.submit(l2.rpc.waitanyinvoice).result(timeout=5) assert r['label'] == 'inv2' pay_index = r['pay_index'] # Pay inv1 l1.rpc.pay(inv1['bolt11']) # Wait inv2 - should not block, should return inv1 r = self.executor.submit(l2.rpc.waitanyinvoice, pay_index).result(timeout=5) assert r['label'] == 'inv1' @unittest.skipIf(not DEVELOPER, "needs DEVELOPER=1 for --dev-broadcast-interval") def test_channel_reenable(self): l1, l2 = self.line_graph(n=2) l1.bitcoin.generate_block(6) l1.daemon.wait_for_log('Received node_announcement for node {}'.format(l2.info['id'])) l2.daemon.wait_for_log('Received node_announcement for node {}'.format(l1.info['id'])) # Both directions should be active before the restart wait_for(lambda: [c['active'] for c in l1.rpc.getchannels()['channels']] == [True, True]) # Restart l2, will cause l1 to reconnect l2.stop() l2.daemon.start() # Now they should sync and re-establish again l1.daemon.wait_for_log('Received node_announcement for node {}'.format(l2.info['id'])) l2.daemon.wait_for_log('Received node_announcement for node {}'.format(l1.info['id'])) wait_for(lambda: [c['active'] for c in l1.rpc.getchannels()['channels']] == [True, True]) @unittest.skipIf(not DEVELOPER, "needs DEVELOPER=1") def test_update_fee(self): l1, l2 = self.connect() chanid = self.fund_channel(l1, l2, 10**6) # Make l1 send out feechange. l1.rpc.dev_setfees('14000') l2.daemon.wait_for_log('peer updated fee to 14000') # Now make sure an HTLC works. # (First wait for route propagation.) self.wait_for_routes(l1, [chanid]) # Make payments. self.pay(l1,l2,200000000) self.pay(l2,l1,100000000) # Now shutdown cleanly. l1.rpc.close(l2.info['id']) l1.daemon.wait_for_log('-> CLOSINGD_COMPLETE') l2.daemon.wait_for_log('-> CLOSINGD_COMPLETE') # And should put closing into mempool. l1.daemon.wait_for_log('sendrawtx exit 0') l2.daemon.wait_for_log('sendrawtx exit 0') bitcoind.generate_block(1) l1.daemon.wait_for_log('-> ONCHAIND_MUTUAL') l2.daemon.wait_for_log('-> ONCHAIND_MUTUAL') bitcoind.generate_block(99) l1.daemon.wait_for_log('onchaind complete, forgetting peer') l2.daemon.wait_for_log('onchaind complete, forgetting peer') @unittest.skipIf(not DEVELOPER, "needs DEVELOPER=1") def test_update_fee_reconnect(self): # Disconnect after first commitsig. disconnects = ['+WIRE_COMMITMENT_SIGNED'] l1 = self.node_factory.get_node(disconnect=disconnects) l2 = self.node_factory.get_node() l1.rpc.connect(l2.info['id'], 'localhost', l2.info['port']) self.fund_channel(l1, l2, 10**6) # Make l1 send out feechange; triggers disconnect/reconnect. l1.rpc.dev_setfees('14000') l1.daemon.wait_for_log('Setting REMOTE feerate to 14000') l2.daemon.wait_for_log('Setting LOCAL feerate to 14000') l1.daemon.wait_for_log('dev_disconnect: \+WIRE_COMMITMENT_SIGNED') # Wait for reconnect.... l1.daemon.wait_for_log('Applying feerate 14000 to LOCAL') self.pay(l1,l2,200000000) self.pay(l2,l1,100000000) # They should both have gotten commits with correct feerate. assert l1.daemon.is_in_log('got commitsig [0-9]*: feerate 14000') assert l2.daemon.is_in_log('got commitsig [0-9]*: feerate 14000') # Now shutdown cleanly. l1.rpc.close(l2.info['id']) l1.daemon.wait_for_log('-> CLOSINGD_COMPLETE') l2.daemon.wait_for_log('-> CLOSINGD_COMPLETE') # And should put closing into mempool. l1.daemon.wait_for_log('sendrawtx exit 0') l2.daemon.wait_for_log('sendrawtx exit 0') bitcoind.generate_block(1) l1.daemon.wait_for_log('-> ONCHAIND_MUTUAL') l2.daemon.wait_for_log('-> ONCHAIND_MUTUAL') bitcoind.generate_block(99) l1.daemon.wait_for_log('onchaind complete, forgetting peer') l2.daemon.wait_for_log('onchaind complete, forgetting peer') @unittest.skipIf(not DEVELOPER, "needs DEVELOPER=1") def test_pay_disconnect(self): """If the remote node has disconnected, we fail payment, but can try again when it reconnects""" l1,l2 = self.connect() chanid = self.fund_channel(l1, l2, 10**6) # Wait for route propagation. self.wait_for_routes(l1, [chanid]) inv = l2.rpc.invoice(123000, 'test_pay_disconnect', 'description')['bolt11'] # Make l2 upset by asking for crazy fee. l1.rpc.dev_setfees('150000') # Wait for l1 notice l1.daemon.wait_for_log('STATUS_FAIL_PEER_BAD') # Can't pay while its offline. self.assertRaises(ValueError, l1.rpc.pay, inv) l1.daemon.wait_for_log('Failing: first peer not ready: WIRE_TEMPORARY_CHANNEL_FAILURE') # Should fail due to temporary channel fail self.assertRaises(ValueError, l1.rpc.pay, inv) l1.daemon.wait_for_log('Failing: first peer not ready: WIRE_TEMPORARY_CHANNEL_FAILURE') assert not l1.daemon.is_in_log('... still in progress') # After it sees block, someone should close channel. bitcoind.generate_block(1) l1.daemon.wait_for_log('ONCHAIND_.*_UNILATERAL') self.assertRaises(ValueError, l1.rpc.pay, inv) # Could fail with almost anything, but should fail with WIRE_PERMANENT_CHANNEL_FAILURE or unknown route. FIXME #l1.daemon.wait_for_log('Could not find a route') if __name__ == '__main__': unittest.main(verbosity=2)