from collections import namedtuple from decimal import Decimal from fixtures import * # noqa: F401,F403 from fixtures import TEST_NETWORK from flaky import flaky # noqa: F401 from pyln.client import RpcError, Millisatoshi from utils import ( DEVELOPER, only_one, wait_for, sync_blockheight, VALGRIND, TIMEOUT, SLOW_MACHINE, expected_peer_features, expected_node_features, check_coin_moves, first_channel_id, account_balance ) from bitcoin.core import CMutableTransaction, CMutableTxOut import binascii import os import pytest import random import re import shutil import time import unittest def test_connect(node_factory): l1, l2 = node_factory.line_graph(2, fundchannel=False) # These should be in openingd. assert l1.rpc.getpeer(l2.info['id'])['connected'] assert l2.rpc.getpeer(l1.info['id'])['connected'] assert len(l1.rpc.getpeer(l2.info['id'])['channels']) == 0 assert len(l2.rpc.getpeer(l1.info['id'])['channels']) == 0 # Reconnect should be a noop ret = l1.rpc.connect(l2.info['id'], 'localhost', port=l2.port) assert ret['id'] == l2.info['id'] ret = l2.rpc.connect(l1.info['id'], host='localhost', port=l1.port) assert ret['id'] == l1.info['id'] # Should still only have one peer! assert len(l1.rpc.listpeers()) == 1 assert len(l2.rpc.listpeers()) == 1 # Should get reasonable error if unknown addr for peer. with pytest.raises(RpcError, match=r'Unable to connect, no address known'): l1.rpc.connect('032cf15d1ad9c4a08d26eab1918f732d8ef8fdc6abb9640bf3db174372c491304e') # Should get reasonable error if connection refuse. with pytest.raises(RpcError, match=r'Connection establishment: Connection refused'): l1.rpc.connect('032cf15d1ad9c4a08d26eab1918f732d8ef8fdc6abb9640bf3db174372c491304e', 'localhost', 1) # Should get reasonable error if wrong key for peer. with pytest.raises(RpcError, match=r'Cryptographic handshake: peer closed connection \(wrong key\?\)'): l1.rpc.connect('032cf15d1ad9c4a08d26eab1918f732d8ef8fdc6abb9640bf3db174372c491304e', 'localhost', l2.port) def test_connect_standard_addr(node_factory): """Test standard node@host:port address """ l1, l2, l3 = node_factory.get_nodes(3) # node@host ret = l1.rpc.connect("{}@{}".format(l2.info['id'], 'localhost'), port=l2.port) assert ret['id'] == l2.info['id'] # node@host:port ret = l1.rpc.connect("{}@localhost:{}".format(l3.info['id'], l3.port)) assert ret['id'] == l3.info['id'] # node@[ipv6]:port --- not supported by our CI # ret = l1.rpc.connect("{}@[::1]:{}".format(l3.info['id'], l3.port)) # assert ret['id'] == l3.info['id'] def test_reconnect_channel_peers(node_factory, executor): l1 = node_factory.get_node(may_reconnect=True) l2 = node_factory.get_node(may_reconnect=True) l1.rpc.connect(l2.info['id'], 'localhost', l2.port) l1.fund_channel(l2, 10**6) l2.restart() # Should reconnect. wait_for(lambda: only_one(l1.rpc.listpeers(l2.info['id'])['peers'])['connected']) wait_for(lambda: only_one(l2.rpc.listpeers(l1.info['id'])['peers'])['connected']) # Connect command should succeed. l1.rpc.connect(l2.info['id'], 'localhost', l2.port) # Stop l2 and wait for l1 to notice. l2.stop() wait_for(lambda: not only_one(l1.rpc.listpeers(l2.info['id'])['peers'])['connected']) # Now should fail. with pytest.raises(RpcError, match=r'Connection refused'): l1.rpc.connect(l2.info['id'], 'localhost', l2.port) # Wait for exponential backoff to give us a 2 second window. l1.daemon.wait_for_log('Will try reconnect in 2 seconds') # It should now succeed when it restarts. l2.start() # Multiples should be fine! fut1 = executor.submit(l1.rpc.connect, l2.info['id'], 'localhost', l2.port) fut2 = executor.submit(l1.rpc.connect, l2.info['id'], 'localhost', l2.port) fut3 = executor.submit(l1.rpc.connect, l2.info['id'], 'localhost', l2.port) fut1.result(10) fut2.result(10) fut3.result(10) def test_balance(node_factory): l1, l2 = node_factory.line_graph(2, fundchannel=True) p1 = only_one(l1.rpc.getpeer(peer_id=l2.info['id'], level='info')['channels']) p2 = only_one(l2.rpc.getpeer(l1.info['id'], 'info')['channels']) assert p1['msatoshi_to_us'] == 10**6 * 1000 assert p1['msatoshi_total'] == 10**6 * 1000 assert p2['msatoshi_to_us'] == 0 assert p2['msatoshi_total'] == 10**6 * 1000 def test_bad_opening(node_factory): # l1 asks for a too-long locktime l1 = node_factory.get_node(options={'watchtime-blocks': 100}) l2 = node_factory.get_node(options={'max-locktime-blocks': 99}) ret = l1.rpc.connect(l2.info['id'], 'localhost', l2.port) assert ret['id'] == l2.info['id'] l1.daemon.wait_for_log('openingd-.*: Handed peer, entering loop') l2.daemon.wait_for_log('openingd-.*: Handed peer, entering loop') l1.fundwallet(10**6 + 1000000) with pytest.raises(RpcError): l1.rpc.fundchannel(l2.info['id'], 10**6) l2.daemon.wait_for_log('to_self_delay 100 larger than 99') @unittest.skipIf(not DEVELOPER, "gossip without DEVELOPER=1 is slow") @unittest.skipIf(TEST_NETWORK != 'regtest', "Fee computation and limits are network specific") def test_opening_tiny_channel(node_factory): # Test custom min-capacity-sat parameters # # o---> [l2] (1000) - old default (too little for reserves) # / # [l1]-----> [l3] (~6000) - technical minimal value that wont be rejected # \ # o---> [l4] (~10000) - the current default # \ # o-> [l5] (20000) - a node with a higher minimal value # # For each: # 1. Try to establish channel 1sat smaller than min_capacity_sat # 2. Try to establish channel exact min_capacity_sat # # BOLT2 # The receiving node MAY fail the channel if: # - funding_satoshis is too small # - it considers `feerate_per_kw` too small for timely processing or unreasonably large. # dustlimit = 546 reserves = 2 * dustlimit min_commit_tx_fees = 5430 min_for_opener = min_commit_tx_fees + dustlimit + 1 l1_min_capacity = 1000 # 1k old default, too small but used at l1 to allow small incoming channels l2_min_capacity = reserves # just enough to get past capacity filter l3_min_capacity = min_for_opener # the absolute technical minimum l4_min_capacity = 10000 # the current default l5_min_capacity = 20000 # a server with more than default minimum l1 = node_factory.get_node(options={'min-capacity-sat': l1_min_capacity}) l2 = node_factory.get_node(options={'min-capacity-sat': l2_min_capacity}) l3 = node_factory.get_node(options={'min-capacity-sat': l3_min_capacity}) l4 = node_factory.get_node(options={'min-capacity-sat': l4_min_capacity}) l5 = node_factory.get_node(options={'min-capacity-sat': l5_min_capacity}) l1.rpc.connect(l2.info['id'], 'localhost', l2.port) l1.rpc.connect(l3.info['id'], 'localhost', l3.port) l1.rpc.connect(l4.info['id'], 'localhost', l4.port) l1.rpc.connect(l5.info['id'], 'localhost', l5.port) # Open channel with one less than reserves should be rejected at l2 with pytest.raises(RpcError, match=r'channel_reserve_satoshis .*sat and .*sat too large for funding .*sat'): l1.fund_channel(l2, l2_min_capacity - 1) # Open a channel with exactly the minimal amount for the fundee, # This will raise an exception at l1, as the opener cannot afford fees for initial_commit_tx. # Note: The old default of 1k sat is below the technical minimum when accounting for dust reserves and fees # This is why this must fail, for this reason the default will be raised to 10k sat. with pytest.raises(RpcError, match=r'Funder cannot afford fee on initial commitment transaction'): l1.fund_channel(l2, l2_min_capacity) # Open channel with one less than technical minimum should be rejected at l3 with pytest.raises(RpcError, match=r'channel capacity is .*sat, which is below .*sat'): l1.fund_channel(l3, l3_min_capacity - 1) # When amount technical minimum matches exactly, own initial_commit_tx fees can now be covered l1.fund_channel(l3, l3_min_capacity) # Open channel with one less than default 10k sats should be rejected at l4 with pytest.raises(RpcError, match=r'channel capacity is .*, which is below .*msat'): l1.fund_channel(l4, l4_min_capacity - 1) # This must be possible with enough capacity l1.fund_channel(l4, l4_min_capacity) # Open channel with less than minimum should be rejected at l5 with pytest.raises(RpcError, match=r'channel capacity is .*, which is below .*msat'): l1.fund_channel(l5, l5_min_capacity - 1) # bigger channels must not be affected l1.fund_channel(l5, l5_min_capacity * 10) def test_second_channel(node_factory): l1 = node_factory.get_node() l2 = node_factory.get_node() l3 = node_factory.get_node() l1.rpc.connect(l2.info['id'], 'localhost', l2.port) l1.rpc.connect(l3.info['id'], 'localhost', l3.port) l1.fund_channel(l2, 10**6) l1.fund_channel(l3, 10**6) @unittest.skipIf(not DEVELOPER, "needs DEVELOPER=1") def test_disconnect(node_factory): # These should all make us fail disconnects = ['-WIRE_INIT', '@WIRE_INIT', '+WIRE_INIT'] l1 = node_factory.get_node(disconnect=disconnects) l2 = node_factory.get_node() with pytest.raises(RpcError): l1.rpc.connect(l2.info['id'], 'localhost', l2.port) with pytest.raises(RpcError): l1.rpc.connect(l2.info['id'], 'localhost', l2.port) with pytest.raises(RpcError): l1.rpc.connect(l2.info['id'], 'localhost', l2.port) # Should have 3 connect fails. for d in disconnects: l1.daemon.wait_for_log('{}-.*Failed connected out' .format(l2.info['id'])) # Should still only have one peer! assert len(l1.rpc.listpeers()) == 1 assert len(l2.rpc.listpeers()) == 1 @unittest.skipIf(not DEVELOPER, "needs DEVELOPER=1") def test_disconnect_opener(node_factory): # Now error on opener side during channel open. disconnects = ['-WIRE_OPEN_CHANNEL', '@WIRE_OPEN_CHANNEL', '+WIRE_OPEN_CHANNEL', '-WIRE_FUNDING_CREATED', '@WIRE_FUNDING_CREATED'] l1 = node_factory.get_node(disconnect=disconnects) l2 = node_factory.get_node() l1.fundwallet(2000000) for d in disconnects: l1.rpc.connect(l2.info['id'], 'localhost', l2.port) with pytest.raises(RpcError): l1.rpc.fundchannel(l2.info['id'], 20000) assert l1.rpc.getpeer(l2.info['id']) is None # This one will succeed. l1.rpc.connect(l2.info['id'], 'localhost', l2.port) l1.rpc.fundchannel(l2.info['id'], 20000) # Should still only have one peer! assert len(l1.rpc.listpeers()) == 1 assert len(l2.rpc.listpeers()) == 1 @unittest.skipIf(not DEVELOPER, "needs DEVELOPER=1") def test_disconnect_fundee(node_factory): # Now error on fundee side during channel open. disconnects = ['-WIRE_ACCEPT_CHANNEL', '@WIRE_ACCEPT_CHANNEL', '+WIRE_ACCEPT_CHANNEL'] l1 = node_factory.get_node() l2 = node_factory.get_node(disconnect=disconnects) l1.fundwallet(2000000) for d in disconnects: l1.rpc.connect(l2.info['id'], 'localhost', l2.port) with pytest.raises(RpcError): l1.rpc.fundchannel(l2.info['id'], 20000) assert l1.rpc.getpeer(l2.info['id']) is None # This one will succeed. l1.rpc.connect(l2.info['id'], 'localhost', l2.port) l1.rpc.fundchannel(l2.info['id'], 20000) # Should still only have one peer! assert len(l1.rpc.listpeers()) == 1 assert len(l2.rpc.listpeers()) == 1 @unittest.skipIf(not DEVELOPER, "needs DEVELOPER=1") def test_disconnect_half_signed(node_factory): # Now, these are the corner cases. Fundee sends funding_signed, # but opener doesn't receive it. disconnects = ['@WIRE_FUNDING_SIGNED'] l1 = node_factory.get_node() l2 = node_factory.get_node(disconnect=disconnects) l1.fundwallet(2000000) l1.rpc.connect(l2.info['id'], 'localhost', l2.port) with pytest.raises(RpcError): l1.rpc.fundchannel(l2.info['id'], 20000) # Peer remembers, opener doesn't. assert l1.rpc.getpeer(l2.info['id']) is None assert l2.rpc.getpeer(l1.info['id'])['id'] == l1.info['id'] @unittest.skipIf(not DEVELOPER, "needs DEVELOPER=1") def test_reconnect_signed(node_factory): # This will fail *after* both sides consider channel opening. disconnects = ['+WIRE_FUNDING_SIGNED'] l1 = node_factory.get_node(may_reconnect=True) l2 = node_factory.get_node(disconnect=disconnects, may_reconnect=True) l1.fundwallet(2000000) l1.rpc.connect(l2.info['id'], 'localhost', l2.port) l1.rpc.fundchannel(l2.info['id'], 20000) # They haven't forgotten each other. assert l1.rpc.getpeer(l2.info['id'])['id'] == l2.info['id'] assert l2.rpc.getpeer(l1.info['id'])['id'] == l1.info['id'] # Technically, this is async to fundchannel (and could reconnect first) l1.daemon.wait_for_logs(['sendrawtx exit 0', 'Peer has reconnected, state CHANNELD_AWAITING_LOCKIN']) l1.bitcoin.generate_block(6) l1.daemon.wait_for_log(' to CHANNELD_NORMAL') l2.daemon.wait_for_log(' to CHANNELD_NORMAL') @unittest.skipIf(not DEVELOPER, "needs DEVELOPER=1") def test_reconnect_openingd(node_factory): # Openingd thinks we're still opening; opener reconnects.. disconnects = ['0WIRE_ACCEPT_CHANNEL'] l1 = node_factory.get_node(may_reconnect=True) l2 = node_factory.get_node(disconnect=disconnects, may_reconnect=True) l1.rpc.connect(l2.info['id'], 'localhost', l2.port) l1.fundwallet(2000000) # l2 closes on l1, l1 forgets. with pytest.raises(RpcError): l1.rpc.fundchannel(l2.info['id'], 20000) assert l1.rpc.getpeer(l2.info['id']) is None # Reconnect. l1.rpc.connect(l2.info['id'], 'localhost', l2.port) # We should get a message about reconnecting. l2.daemon.wait_for_log('Killing openingd: Reconnected') l2.daemon.wait_for_log('openingd.*Handed peer, entering loop') # Should work fine. l1.rpc.fundchannel(l2.info['id'], 20000) l1.daemon.wait_for_log('sendrawtx exit 0') l1.bitcoin.generate_block(3) # Just to be sure, second openingd hand over to channeld. This log line is about channeld being started l2.daemon.wait_for_log(r'channeld-chan#[0-9]: pid [0-9]+, msgfd [0-9]+') @unittest.skipIf(not DEVELOPER, "needs DEVELOPER=1") def test_reconnect_gossiping(node_factory): # connectd thinks we're still gossiping; peer reconnects. disconnects = ['0WIRE_PING'] l1 = node_factory.get_node(may_reconnect=True) l2 = node_factory.get_node(disconnect=disconnects, may_reconnect=True) l1.rpc.connect(l2.info['id'], 'localhost', l2.port) # Make sure l2 knows about l1 wait_for(lambda: l2.rpc.listpeers(l1.info['id'])['peers'] != []) l2.rpc.ping(l1.info['id'], 1, 65532) wait_for(lambda: l1.rpc.listpeers(l2.info['id'])['peers'] == []) l1.rpc.connect(l2.info['id'], 'localhost', l2.port) l2.daemon.wait_for_log('processing now old peer gone') @unittest.skipIf(not DEVELOPER, "needs dev-disconnect") def test_reconnect_no_update(node_factory, executor): """ This tests if the `funding_locked` is sent if we receive a `channel_reestablish` message with `next_commitment_number` == 1 and our `next_commitment_number` == 1. """ disconnects = ["@WIRE_FUNDING_LOCKED", "@WIRE_SHUTDOWN"] # Allow bad gossip because it might receive WIRE_CHANNEL_UPDATE before # announcement before of the disconnection l1 = node_factory.get_node(may_reconnect=True, allow_bad_gossip=True) l2 = node_factory.get_node(disconnect=disconnects, may_reconnect=True) # For channeld reconnection l1.rpc.connect(l2.info["id"], "localhost", l2.port) fundchannel_exec = executor.submit(l1.fund_channel, l2, 10**6, False) l1.daemon.wait_for_log(r"channeld.* Retransmitting funding_locked for channel") l1.stop() # For closingd reconnection scid = fundchannel_exec.result() l1.daemon.start() executor.submit(l1.rpc.close, scid, 0) l2.daemon.wait_for_log(r"closingd.* Retransmitting funding_locked for channel") l1.daemon.wait_for_log(r"CLOSINGD_COMPLETE") def test_connect_stresstest(node_factory, executor): # This test is unreliable, but it's better than nothing. l1 = node_factory.get_node(may_reconnect=True) l2 = node_factory.get_node(may_reconnect=True) l3 = node_factory.get_node(may_reconnect=True) # Hack l3 into a clone of l2, to stress reconnect code. l3.stop() shutil.copyfile(os.path.join(l2.daemon.lightning_dir, TEST_NETWORK, 'hsm_secret'), os.path.join(l3.daemon.lightning_dir, TEST_NETWORK, 'hsm_secret')) l3.start() l3.info = l3.rpc.getinfo() assert l3.info['id'] == l2.info['id'] # We fire off random connect/disconnect commands. actions = [ (l2.rpc.connect, l1.info['id'], 'localhost', l1.port), (l3.rpc.connect, l1.info['id'], 'localhost', l3.port), (l1.rpc.connect, l2.info['id'], 'localhost', l2.port), (l1.rpc.connect, l3.info['id'], 'localhost', l3.port), (l1.rpc.disconnect, l2.info['id']) ] args = [random.choice(actions) for _ in range(1000)] # We get them all to connect to each other. futs = [] for a in args: futs.append(executor.submit(*a)) # We don't actually care if they fail, since some will. successes = 0 failures = 0 for f in futs: if f.exception(): failures += 1 else: f.result() successes += 1 assert successes > failures @unittest.skipIf(not DEVELOPER, "needs DEVELOPER=1") def test_reconnect_normal(node_factory): # Should reconnect fine even if locked message gets lost. disconnects = ['-WIRE_FUNDING_LOCKED', '@WIRE_FUNDING_LOCKED', '+WIRE_FUNDING_LOCKED'] l1 = node_factory.get_node(disconnect=disconnects, may_reconnect=True) l2 = node_factory.get_node(may_reconnect=True) l1.rpc.connect(l2.info['id'], 'localhost', l2.port) l1.fund_channel(l2, 10**6) @unittest.skipIf(not DEVELOPER, "needs DEVELOPER=1") def test_reconnect_sender_add1(node_factory): # Fail after add is OK, will cause payment failure though. disconnects = ['-WIRE_UPDATE_ADD_HTLC-nocommit', '+WIRE_UPDATE_ADD_HTLC-nocommit', '@WIRE_UPDATE_ADD_HTLC-nocommit'] # Feerates identical so we don't get gratuitous commit to update them l1 = node_factory.get_node(disconnect=disconnects, may_reconnect=True, feerates=(7500, 7500, 7500, 7500)) l2 = node_factory.get_node(may_reconnect=True) l1.rpc.connect(l2.info['id'], 'localhost', l2.port) l1.fund_channel(l2, 10**6) amt = 200000000 rhash = l2.rpc.invoice(amt, 'test_reconnect_sender_add1', 'desc')['payment_hash'] assert only_one(l2.rpc.listinvoices('test_reconnect_sender_add1')['invoices'])['status'] == 'unpaid' route = [{'msatoshi': amt, 'id': l2.info['id'], 'delay': 5, 'channel': '1x1x1'}] for i in range(0, len(disconnects)): l1.rpc.sendpay(route, rhash) with pytest.raises(RpcError): l1.rpc.waitsendpay(rhash) # Wait for reconnection. l1.daemon.wait_for_log('Already have funding locked in') # This will send commit, so will reconnect as required. l1.rpc.sendpay(route, rhash) @unittest.skipIf(not DEVELOPER, "needs DEVELOPER=1") def test_reconnect_sender_add(node_factory): disconnects = ['-WIRE_COMMITMENT_SIGNED', '@WIRE_COMMITMENT_SIGNED', '+WIRE_COMMITMENT_SIGNED', '-WIRE_REVOKE_AND_ACK', '@WIRE_REVOKE_AND_ACK', '+WIRE_REVOKE_AND_ACK'] # Feerates identical so we don't get gratuitous commit to update them l1 = node_factory.get_node(disconnect=disconnects, may_reconnect=True, feerates=(7500, 7500, 7500, 7500)) l2 = node_factory.get_node(may_reconnect=True) l1.rpc.connect(l2.info['id'], 'localhost', l2.port) l1.fund_channel(l2, 10**6) amt = 200000000 rhash = l2.rpc.invoice(amt, 'testpayment', 'desc')['payment_hash'] assert only_one(l2.rpc.listinvoices('testpayment')['invoices'])['status'] == 'unpaid' route = [{'msatoshi': amt, 'id': l2.info['id'], 'delay': 5, 'channel': '1x1x1'}] # This will send commit, so will reconnect as required. l1.rpc.sendpay(route, rhash) # Should have printed this for every reconnect. for i in range(0, len(disconnects)): l1.daemon.wait_for_log('Already have funding locked in') @unittest.skipIf(not DEVELOPER, "needs DEVELOPER=1") def test_reconnect_receiver_add(node_factory): disconnects = ['-WIRE_COMMITMENT_SIGNED', '@WIRE_COMMITMENT_SIGNED', '+WIRE_COMMITMENT_SIGNED', '-WIRE_REVOKE_AND_ACK', '@WIRE_REVOKE_AND_ACK', '+WIRE_REVOKE_AND_ACK'] # Feerates identical so we don't get gratuitous commit to update them l1 = node_factory.get_node(may_reconnect=True, feerates=(7500, 7500, 7500, 7500)) l2 = node_factory.get_node(disconnect=disconnects, may_reconnect=True) l1.rpc.connect(l2.info['id'], 'localhost', l2.port) l1.fund_channel(l2, 10**6) amt = 200000000 rhash = l2.rpc.invoice(amt, 'testpayment2', 'desc')['payment_hash'] assert only_one(l2.rpc.listinvoices('testpayment2')['invoices'])['status'] == 'unpaid' route = [{'msatoshi': amt, 'id': l2.info['id'], 'delay': 5, 'channel': '1x1x1'}] l1.rpc.sendpay(route, rhash) for i in range(len(disconnects)): l1.daemon.wait_for_log('Already have funding locked in') assert only_one(l2.rpc.listinvoices('testpayment2')['invoices'])['status'] == 'paid' @unittest.skipIf(not DEVELOPER, "needs DEVELOPER=1") def test_reconnect_receiver_fulfill(node_factory): # Ordering matters: after +WIRE_UPDATE_FULFILL_HTLC, channeld # will continue and try to send WIRE_COMMITMENT_SIGNED: if # that's the next failure, it will do two in one run. disconnects = ['@WIRE_UPDATE_FULFILL_HTLC', '+WIRE_UPDATE_FULFILL_HTLC', '-WIRE_UPDATE_FULFILL_HTLC', '-WIRE_COMMITMENT_SIGNED', '@WIRE_COMMITMENT_SIGNED', '+WIRE_COMMITMENT_SIGNED', '-WIRE_REVOKE_AND_ACK', '@WIRE_REVOKE_AND_ACK', '+WIRE_REVOKE_AND_ACK'] l1 = node_factory.get_node(may_reconnect=True) l2 = node_factory.get_node(disconnect=disconnects, may_reconnect=True) l1.rpc.connect(l2.info['id'], 'localhost', l2.port) l1.fund_channel(l2, 10**6) amt = 200000000 rhash = l2.rpc.invoice(amt, 'testpayment2', 'desc')['payment_hash'] assert only_one(l2.rpc.listinvoices('testpayment2')['invoices'])['status'] == 'unpaid' route = [{'msatoshi': amt, 'id': l2.info['id'], 'delay': 5, 'channel': '1x1x1'}] l1.rpc.sendpay(route, rhash) for i in range(len(disconnects)): l1.daemon.wait_for_log('Already have funding locked in') assert only_one(l2.rpc.listinvoices('testpayment2')['invoices'])['status'] == 'paid' @flaky @unittest.skipIf(not DEVELOPER, "needs DEVELOPER=1") def test_shutdown_reconnect(node_factory): disconnects = ['-WIRE_SHUTDOWN', '@WIRE_SHUTDOWN', '+WIRE_SHUTDOWN'] l1 = node_factory.get_node(disconnect=disconnects, may_reconnect=True) l2 = node_factory.get_node(may_reconnect=True) l1.rpc.connect(l2.info['id'], 'localhost', l2.port) chan = l1.fund_channel(l2, 10**6) l1.pay(l2, 200000000) assert l1.bitcoin.rpc.getmempoolinfo()['size'] == 0 # This should wait until we're closed. l1.rpc.close(chan) l1.daemon.wait_for_log(' to CHANNELD_SHUTTING_DOWN') l2.daemon.wait_for_log(' to CHANNELD_SHUTTING_DOWN') l1.daemon.wait_for_log(' to CLOSINGD_SIGEXCHANGE') l2.daemon.wait_for_log(' to CLOSINGD_SIGEXCHANGE') # And should put closing into mempool (happens async, so # CLOSINGD_COMPLETE may come first). l1.daemon.wait_for_logs(['sendrawtx exit 0', ' to CLOSINGD_COMPLETE']) l2.daemon.wait_for_logs(['sendrawtx exit 0', ' to CLOSINGD_COMPLETE']) assert l1.bitcoin.rpc.getmempoolinfo()['size'] == 1 @flaky @unittest.skipIf(not DEVELOPER, "needs DEVELOPER=1") def test_reconnect_remote_sends_no_sigs(node_factory): """We re-announce, even when remote node doesn't send its announcement_signatures on reconnect. """ l1, l2 = node_factory.line_graph(2, wait_for_announce=True, opts={'may_reconnect': True}) # When l1 restarts (with rescan=1), make it think it hasn't # reached announce_depth, so it wont re-send announcement_signatures def no_blocks_above(req): if req['params'][0] > 107: return {"result": None, "error": {"code": -8, "message": "Block height out of range"}, "id": req['id']} else: return {'result': l1.bitcoin.rpc.getblockhash(req['params'][0]), "error": None, 'id': req['id']} l1.daemon.rpcproxy.mock_rpc('getblockhash', no_blocks_above) l1.restart() # l2 will now uses (REMOTE's) announcement_signatures it has stored wait_for(lambda: only_one(l2.rpc.listpeers()['peers'][0]['channels'])['status'] == [ 'CHANNELD_NORMAL:Reconnected, and reestablished.', 'CHANNELD_NORMAL:Funding transaction locked. Channel announced.']) # But l2 still sends its own sigs on reconnect l2.daemon.wait_for_logs([r'peer_out WIRE_ANNOUNCEMENT_SIGNATURES', r'peer_out WIRE_ANNOUNCEMENT_SIGNATURES']) # l1 only did send them the first time assert(''.join(l1.daemon.logs).count(r'peer_out WIRE_ANNOUNCEMENT_SIGNATURES') == 1) def test_shutdown_awaiting_lockin(node_factory, bitcoind): l1 = node_factory.get_node() l2 = node_factory.get_node(options={'funding-confirms': 3}) l1.rpc.connect(l2.info['id'], 'localhost', l2.port) l1.fundwallet(10**6 + 1000000) chanid = l1.rpc.fundchannel(l2.info['id'], 10**6)['channel_id'] # Technically, this is async to fundchannel. l1.daemon.wait_for_log('sendrawtx exit 0') bitcoind.generate_block(1) l1.rpc.close(chanid) l1.daemon.wait_for_log('CHANNELD_AWAITING_LOCKIN to CHANNELD_SHUTTING_DOWN') l2.daemon.wait_for_log('CHANNELD_AWAITING_LOCKIN to CHANNELD_SHUTTING_DOWN') l1.daemon.wait_for_log('CHANNELD_SHUTTING_DOWN to CLOSINGD_SIGEXCHANGE') l2.daemon.wait_for_log('CHANNELD_SHUTTING_DOWN to CLOSINGD_SIGEXCHANGE') # And should put closing into mempool (happens async, so # CLOSINGD_COMPLETE may come first). l1.daemon.wait_for_logs(['sendrawtx exit 0', ' to CLOSINGD_COMPLETE']) l2.daemon.wait_for_logs(['sendrawtx exit 0', ' to CLOSINGD_COMPLETE']) assert bitcoind.rpc.getmempoolinfo()['size'] == 1 bitcoind.generate_block(1) l1.daemon.wait_for_log(' to ONCHAIN') l2.daemon.wait_for_log(' to ONCHAIN') bitcoind.generate_block(100) wait_for(lambda: l1.rpc.listpeers()['peers'] == []) wait_for(lambda: l2.rpc.listpeers()['peers'] == []) def test_funding_change(node_factory, bitcoind): """Add some funds, fund a channel, and make sure we remember the change """ l1, l2 = node_factory.line_graph(2, fundchannel=False) l1.fundwallet(10000000) bitcoind.generate_block(1) sync_blockheight(bitcoind, [l1]) outputs = l1.db_query('SELECT value FROM outputs WHERE status=0;') assert only_one(outputs)['value'] == 10000000 l1.rpc.fundchannel(l2.info['id'], 1000000) outputs = {r['status']: r['value'] for r in l1.db_query( 'SELECT status, SUM(value) AS value FROM outputs GROUP BY status;')} # The 10m out is spent and we have a change output of 9m-fee assert outputs[0] > 8990000 assert outputs[2] == 10000000 def test_funding_all(node_factory, bitcoind): """Add some funds, fund a channel using all funds, make sure no funds remain """ l1, l2 = node_factory.line_graph(2, fundchannel=False) l1.fundwallet(0.1 * 10**8) bitcoind.generate_block(1) sync_blockheight(bitcoind, [l1]) outputs = l1.db_query('SELECT value FROM outputs WHERE status=0;') assert only_one(outputs)['value'] == 10000000 l1.rpc.fundchannel(l2.info['id'], "all") outputs = l1.db_query('SELECT value FROM outputs WHERE status=0;') assert len(outputs) == 0 def test_funding_all_too_much(node_factory): """Add more than max possible funds, fund a channel using all funds we can. """ l1, l2 = node_factory.line_graph(2, fundchannel=False) l1.fundwallet(2**24 + 10000) l1.rpc.fundchannel(l2.info['id'], "all") assert only_one(l1.rpc.listfunds()['outputs'])['status'] == 'unconfirmed' assert only_one(l1.rpc.listfunds()['channels'])['channel_total_sat'] == 2**24 - 1 def test_funding_fail(node_factory, bitcoind): """Add some funds, fund a channel without enough funds""" # Previous runs with same bitcoind can leave funds! max_locktime = 5 * 6 * 24 l1 = node_factory.get_node(random_hsm=True, options={'max-locktime-blocks': max_locktime}) l2 = node_factory.get_node(options={'watchtime-blocks': max_locktime + 1}) l1.rpc.connect(l2.info['id'], 'localhost', l2.port) funds = 1000000 addr = l1.rpc.newaddr()['bech32'] l1.bitcoin.rpc.sendtoaddress(addr, funds / 10**8) bitcoind.generate_block(1) # Wait for it to arrive. wait_for(lambda: len(l1.rpc.listfunds()['outputs']) > 0) # Fail because l1 dislikes l2's huge locktime. with pytest.raises(RpcError, match=r'to_self_delay \d+ larger than \d+'): l1.rpc.fundchannel(l2.info['id'], int(funds / 10)) assert only_one(l1.rpc.listpeers()['peers'])['connected'] assert only_one(l2.rpc.listpeers()['peers'])['connected'] # Restart l2 without ridiculous locktime. del l2.daemon.opts['watchtime-blocks'] l2.restart() l1.rpc.connect(l2.info['id'], 'localhost', l2.port) # We don't have enough left to cover fees if we try to spend it all. with pytest.raises(RpcError, match=r'Cannot afford transaction'): l1.rpc.fundchannel(l2.info['id'], funds) # Should still be connected. assert only_one(l1.rpc.listpeers()['peers'])['connected'] l2.daemon.wait_for_log('openingd-.*: Handed peer, entering loop') assert only_one(l2.rpc.listpeers()['peers'])['connected'] # This works. l1.rpc.fundchannel(l2.info['id'], int(funds / 10)) def test_funding_toolarge(node_factory, bitcoind): """Try to create a giant channel""" l1 = node_factory.get_node() l2 = node_factory.get_node() l1.rpc.connect(l2.info['id'], 'localhost', l2.port) # Send funds. amount = 2**24 bitcoind.rpc.sendtoaddress(l1.rpc.newaddr()['bech32'], amount / 10**8 + 0.01) bitcoind.generate_block(1) # Wait for it to arrive. wait_for(lambda: len(l1.rpc.listfunds()['outputs']) > 0) # Fail to open (too large) with pytest.raises(RpcError, match=r'Amount exceeded 16777215'): l1.rpc.fundchannel(l2.info['id'], amount) # This should work. amount = amount - 1 l1.rpc.fundchannel(l2.info['id'], amount) def test_funding_push(node_factory, bitcoind): """ Try to push peer some sats """ # We track balances, to verify that accounting is ok. coin_mvt_plugin = os.path.join(os.getcwd(), 'tests/plugins/coin_movements.py') l1 = node_factory.get_node(options={'plugin': coin_mvt_plugin}) l2 = node_factory.get_node() l1.rpc.connect(l2.info['id'], 'localhost', l2.port) # Send funds. amount = 2**24 push_sat = 20000 bitcoind.rpc.sendtoaddress(l1.rpc.newaddr()['bech32'], amount / 10**8 + 0.01) bitcoind.generate_block(1) # Wait for it to arrive. wait_for(lambda: len(l1.rpc.listfunds()['outputs']) > 0) # Fail to open (try to push too much) with pytest.raises(RpcError, match=r'Requested to push_msat of 20000000msat is greater than available funding amount 10000sat'): l1.rpc.fundchannel(l2.info['id'], 10000, push_msat=push_sat * 1000) # This should work. amount = amount - 1 l1.rpc.fundchannel(l2.info['id'], amount, push_msat=push_sat * 1000) bitcoind.generate_block(1) sync_blockheight(bitcoind, [l1]) funds = only_one(l1.rpc.listfunds()['channels']) assert funds['channel_sat'] + push_sat == funds['channel_total_sat'] chanid = first_channel_id(l2, l1) l1.daemon.wait_for_log('coins account: {}'.format(chanid)) # give the file write a second time.sleep(1) channel_mvts = [ {'type': 'chain_mvt', 'credit': 0, 'debit': 20000000, 'tag': 'pushed'}, {'type': 'chain_mvt', 'credit': 16777215000, 'debit': 0, 'tag': 'deposit'}, ] check_coin_moves(l1, chanid, channel_mvts) assert account_balance(l1, chanid) == (amount - push_sat) * 1000 def test_funding_by_utxos(node_factory, bitcoind): """Fund a channel with specific utxos""" l1, l2, l3 = node_factory.line_graph(3, fundchannel=False) # Get 3 differents utxo l1.fundwallet(0.01 * 10**8) l1.fundwallet(0.01 * 10**8) l1.fundwallet(0.01 * 10**8) wait_for(lambda: len(l1.rpc.listfunds()["outputs"]) == 3) utxos = [utxo["txid"] + ":" + str(utxo["output"]) for utxo in l1.rpc.listfunds()["outputs"]] # Fund with utxos we don't own with pytest.raises(RpcError, match=r"No matching utxo was found from the wallet"): l3.rpc.fundchannel(l2.info["id"], int(0.01 * 10**8), utxos=utxos) # Fund with an empty array with pytest.raises(RpcError, match=r"Please specify an array of \\'txid:output_index\\', not \"*\""): l1.rpc.fundchannel(l2.info["id"], int(0.01 * 10**8), utxos=[]) # Fund a channel from some of the utxos, without change l1.rpc.fundchannel(l2.info["id"], "all", utxos=utxos[0:2]) # Fund a channel from the rest of utxos, with change l1.rpc.connect(l3.info["id"], "localhost", l3.port) l1.rpc.fundchannel(l3.info["id"], int(0.007 * 10**8), utxos=[utxos[2]]) # Fund another channel with already spent utxos with pytest.raises(RpcError, match=r"No matching utxo was found from the wallet"): l1.rpc.fundchannel(l3.info["id"], int(0.01 * 10**8), utxos=utxos) @unittest.skipIf(not DEVELOPER, "needs dev_forget_channel") def test_funding_external_wallet_corners(node_factory, bitcoind): l1 = node_factory.get_node(may_reconnect=True) l2 = node_factory.get_node(may_reconnect=True) amount = 2**24 l1.fundwallet(amount + 10000000) amount = amount - 1 fake_txid = '929764844a8f9938b669a60a1d51a11c9e2613c7eb4776e4126f1f20c0a685c3' fake_txout = 0 with pytest.raises(RpcError, match=r'Unknown peer'): l1.rpc.fundchannel_start(l2.info['id'], amount) with pytest.raises(RpcError, match=r'Unknown peer'): l1.rpc.fundchannel_complete(l2.info['id'], fake_txid, fake_txout) # Should not be able to continue without being in progress. l1.rpc.connect(l2.info['id'], 'localhost', l2.port) with pytest.raises(RpcError, match=r'No channel funding in progress.'): l1.rpc.fundchannel_complete(l2.info['id'], fake_txid, fake_txout) # Fail to open (too large) with pytest.raises(RpcError, match=r'Amount exceeded 16777215'): l1.rpc.fundchannel_start(l2.info['id'], amount + 1) l1.rpc.fundchannel_start(l2.info['id'], amount) with pytest.raises(RpcError, match=r'Already funding channel'): l1.rpc.fundchannel(l2.info['id'], amount) l1.rpc.fundchannel_cancel(l2.info['id']) # Should be able to 'restart' after canceling amount2 = 1000000 funding_addr = l1.rpc.fundchannel_start(l2.info['id'], amount2)['funding_address'] addr = l1.rpc.newaddr()['bech32'] l1.bitcoin.rpc.sendtoaddress(addr, 0.1) bitcoind.generate_block(1) wait_for(lambda: len(l1.rpc.listfunds()['outputs']) == 1) # Create the funding transaction prep = l1.rpc.txprepare([{funding_addr: amount2}]) decode = bitcoind.rpc.decoderawtransaction(prep['unsigned_tx']) assert decode['txid'] == prep['txid'] # One output will be correct. if decode['vout'][0]['value'] == Decimal('0.01000000'): txout = 0 elif decode['vout'][1]['value'] == Decimal('0.01000000'): txout = 1 else: assert False # Be sure fundchannel_complete is successful assert l1.rpc.fundchannel_complete(l2.info['id'], prep['txid'], txout)['commitments_secured'] # Peer shouldn't be able to cancel channel with pytest.raises(RpcError, match=r'Cannot cancel channel that was initiated by peer'): l2.rpc.fundchannel_cancel(l1.info['id']) # We can cancel channel after fundchannel_complete assert l1.rpc.fundchannel_cancel(l2.info['id'])['cancelled'] l1.rpc.connect(l2.info['id'], 'localhost', l2.port) l1.rpc.fundchannel_start(l2.info['id'], amount)['funding_address'] assert l1.rpc.fundchannel_complete(l2.info['id'], prep['txid'], txout)['commitments_secured'] # Check that can still cancel when peer is disconnected l1.rpc.disconnect(l2.info['id'], force=True) wait_for(lambda: not only_one(l1.rpc.listpeers()['peers'])['connected']) assert l1.rpc.fundchannel_cancel(l2.info['id'])['cancelled'] assert len(l1.rpc.listpeers()['peers']) == 0 # l2 still has the channel open/waiting wait_for(lambda: only_one(only_one(l2.rpc.listpeers()['peers'])['channels'])['state'] == 'CHANNELD_AWAITING_LOCKIN') # on reconnect, channel should get destroyed l1.rpc.connect(l2.info['id'], 'localhost', l2.port) l1.daemon.wait_for_log('Rejecting WIRE_CHANNEL_REESTABLISH for unknown channel_id') wait_for(lambda: len(l1.rpc.listpeers()['peers']) == 0) wait_for(lambda: len(l2.rpc.listpeers()['peers']) == 0) # we have to connect again, because we got disconnected when everything errored l1.rpc.connect(l2.info['id'], 'localhost', l2.port) l1.rpc.fundchannel_start(l2.info['id'], amount)['funding_address'] # A successful funding_complete will always have a commitments_secured that is true, # otherwise it would have failed assert l1.rpc.fundchannel_complete(l2.info['id'], prep['txid'], txout)['commitments_secured'] l1.rpc.txsend(prep['txid']) with pytest.raises(RpcError, match=r'.* been broadcast.*'): l1.rpc.fundchannel_cancel(l2.info['id']) l1.rpc.close(l2.info['id']) def test_funding_cancel_race(node_factory, bitcoind, executor): l1 = node_factory.get_node() if VALGRIND or SLOW_MACHINE: num = 5 else: num = 100 nodes = node_factory.get_nodes(num) # Speed up cleanup by not cleaning our test nodes: on my laptop, this goes # from 214 to 15 seconds node_factory.nodes = [l1] num_complete = 0 num_cancel = 0 for count, n in enumerate(nodes): l1.rpc.connect(n.info['id'], 'localhost', n.port) l1.rpc.fundchannel_start(n.info['id'], "100000sat") # We simply make up txids. And submit two of each at once. completes = [] cancels = [] # Switch order around. for i in range(4): if (i + count) % 2 == 0: completes.append(executor.submit(l1.rpc.fundchannel_complete, n.info['id'], "9f1844419d2f41532a57fb5ef038cacb602000f7f37b3dae68dc2d047c89048f", 0)) else: cancels.append(executor.submit(l1.rpc.fundchannel_cancel, n.info['id'])) # Only one should succeed. success = False for c in completes: try: c.result(TIMEOUT) num_complete += 1 assert not success success = True except RpcError: pass # These may both succeed, iff the above didn't. cancelled = False for c in cancels: try: c.result(TIMEOUT) cancelled = True assert not success except RpcError: pass if cancelled: num_cancel += 1 else: assert success print("Cancelled {} complete {}".format(num_cancel, num_complete)) assert num_cancel + num_complete == len(nodes) # We should have raced at least once! if not VALGRIND: assert num_cancel > 0 assert num_complete > 0 @unittest.skipIf(TEST_NETWORK != 'regtest', "External wallet support doesn't work with elements yet.") def test_funding_close_upfront(node_factory, bitcoind): l1 = node_factory.get_node() opts = {'plugin': os.path.join(os.getcwd(), 'tests/plugins/accepter_close_to.py')} l2 = node_factory.get_node(options=opts) # The 'accepter_close_to' plugin uses the channel funding amount to determine # whether or not to include a 'close_to' address amt_normal = 100007 # continues without returning a close_to amt_addr = 100001 # returns valid regtest address remote_valid_addr = 'bcrt1q7gtnxmlaly9vklvmfj06amfdef3rtnrdazdsvw' def _fundchannel(l1, l2, amount, close_to): l1.rpc.connect(l2.info['id'], 'localhost', l2.port) assert(l1.rpc.listpeers()['peers'][0]['id'] == l2.info['id']) resp = l1.rpc.fundchannel_start(l2.info['id'], amount, close_to=close_to) address = resp['funding_address'] if close_to: assert resp['close_to'] else: assert 'close_to' not in resp peer = l1.rpc.listpeers()['peers'][0] # Peer should still be connected and in state waiting for funding_txid assert peer['id'] == l2.info['id'] r = re.compile('Funding channel start: awaiting funding_txid with output to .*') assert any(r.match(line) for line in peer['channels'][0]['status']) assert 'OPENINGD' in peer['channels'][0]['state'] # 'Externally' fund the address from fundchannel_start addr_scriptpubkey = bitcoind.rpc.getaddressinfo(address)['scriptPubKey'] txout = CMutableTxOut(amount, bytearray.fromhex(addr_scriptpubkey)) unfunded_tx = CMutableTransaction([], [txout]) hextx = binascii.hexlify(unfunded_tx.serialize()).decode('utf8') funded_tx_obj = bitcoind.rpc.fundrawtransaction(hextx) raw_funded_tx = funded_tx_obj['hex'] txid = bitcoind.rpc.decoderawtransaction(raw_funded_tx)['txid'] txout = 1 if funded_tx_obj['changepos'] == 0 else 0 assert l1.rpc.fundchannel_complete(l2.info['id'], txid, txout)['commitments_secured'] # Broadcast the transaction manually and confirm that channel locks in signed_tx = bitcoind.rpc.signrawtransactionwithwallet(raw_funded_tx)['hex'] assert txid == bitcoind.rpc.decoderawtransaction(signed_tx)['txid'] bitcoind.rpc.sendrawtransaction(signed_tx) bitcoind.generate_block(1) for node in [l1, l2]: node.daemon.wait_for_log(r'State changed from CHANNELD_AWAITING_LOCKIN to CHANNELD_NORMAL') channel = node.rpc.listpeers()['peers'][0]['channels'][-1] assert amount * 1000 == channel['msatoshi_total'] # check that normal peer close works _fundchannel(l1, l2, amt_normal, None) assert l1.rpc.close(l2.info['id'])['type'] == 'mutual' # check that you can provide a closing address upfront addr = l1.rpc.newaddr()['bech32'] _fundchannel(l1, l2, amt_normal, addr) # confirm that it appears in listpeers assert addr == only_one(l1.rpc.listpeers()['peers'])['channels'][1]['close_to_addr'] resp = l1.rpc.close(l2.info['id']) assert resp['type'] == 'mutual' assert only_one(only_one(bitcoind.rpc.decoderawtransaction(resp['tx'])['vout'])['scriptPubKey']['addresses']) == addr # check that passing in the same addr to close works addr = bitcoind.rpc.getnewaddress() _fundchannel(l1, l2, amt_normal, addr) assert addr == only_one(l1.rpc.listpeers()['peers'])['channels'][2]['close_to_addr'] resp = l1.rpc.close(l2.info['id'], destination=addr) assert resp['type'] == 'mutual' assert only_one(only_one(bitcoind.rpc.decoderawtransaction(resp['tx'])['vout'])['scriptPubKey']['addresses']) == addr # check that remote peer closing works as expected (and that remote's close_to works) _fundchannel(l1, l2, amt_addr, addr) # send some money to remote so that they have a closeout l1.rpc.pay(l2.rpc.invoice((amt_addr // 2) * 1000, 'test_remote_close_to', 'desc')['bolt11']) assert only_one(l2.rpc.listpeers()['peers'])['channels'][-1]['close_to_addr'] == remote_valid_addr resp = l2.rpc.close(l1.info['id']) assert resp['type'] == 'mutual' vouts = bitcoind.rpc.decoderawtransaction(resp['tx'])['vout'] assert len(vouts) == 2 for vout in vouts: assert only_one(vout['scriptPubKey']['addresses']) in [addr, remote_valid_addr] # check that passing in a different addr to close causes an RPC error addr2 = l1.rpc.newaddr()['bech32'] _fundchannel(l1, l2, amt_normal, addr) with pytest.raises(RpcError, match=r'does not match previous shutdown script'): l1.rpc.close(l2.info['id'], destination=addr2) @unittest.skipIf(TEST_NETWORK != 'regtest', "External wallet support doesn't work with elements yet.") def test_funding_external_wallet(node_factory, bitcoind): l1 = node_factory.get_node() l2 = node_factory.get_node() l3 = node_factory.get_node() l1.rpc.connect(l2.info['id'], 'localhost', l2.port) assert(l1.rpc.listpeers()['peers'][0]['id'] == l2.info['id']) amount = 2**24 - 1 address = l1.rpc.fundchannel_start(l2.info['id'], amount)['funding_address'] assert len(address) > 0 peer = l1.rpc.listpeers()['peers'][0] # Peer should still be connected and in state waiting for funding_txid assert peer['id'] == l2.info['id'] r = re.compile('Funding channel start: awaiting funding_txid with output to .*') assert any(r.match(line) for line in peer['channels'][0]['status']) assert 'OPENINGD' in peer['channels'][0]['state'] # Trying to start a second funding should not work, it's in progress. with pytest.raises(RpcError, match=r'Already funding channel'): l1.rpc.fundchannel_start(l2.info['id'], amount) # 'Externally' fund the address from fundchannel_start addr_scriptpubkey = bitcoind.rpc.getaddressinfo(address)['scriptPubKey'] txout = CMutableTxOut(amount, bytearray.fromhex(addr_scriptpubkey)) unfunded_tx = CMutableTransaction([], [txout]) hextx = binascii.hexlify(unfunded_tx.serialize()).decode('utf8') funded_tx_obj = bitcoind.rpc.fundrawtransaction(hextx) raw_funded_tx = funded_tx_obj['hex'] txid = bitcoind.rpc.decoderawtransaction(raw_funded_tx)['txid'] txout = 1 if funded_tx_obj['changepos'] == 0 else 0 assert l1.rpc.fundchannel_complete(l2.info['id'], txid, txout)['commitments_secured'] # Broadcast the transaction manually and confirm that channel locks in signed_tx = bitcoind.rpc.signrawtransactionwithwallet(raw_funded_tx)['hex'] assert txid == bitcoind.rpc.decoderawtransaction(signed_tx)['txid'] bitcoind.rpc.sendrawtransaction(signed_tx) bitcoind.generate_block(1) l1.daemon.wait_for_log(r'Funding tx {} depth 1 of 1'.format(txid)) # Check that tx is broadcast by a third party can be catched. # Only when the transaction (broadcast by a third pary) is onchain, we can catch it. with pytest.raises(RpcError, match=r'.* been broadcast.*'): l1.rpc.fundchannel_cancel(l2.info['id']) for node in [l1, l2]: node.daemon.wait_for_log(r'State changed from CHANNELD_AWAITING_LOCKIN to CHANNELD_NORMAL') channel = node.rpc.listpeers()['peers'][0]['channels'][0] assert amount * 1000 == channel['msatoshi_total'] # Test that we don't crash if peer disconnects after fundchannel_start l2.connect(l3) l2.rpc.fundchannel_start(l3.info["id"], amount) l3.rpc.close(l2.info["id"]) def test_lockin_between_restart(node_factory, bitcoind): l1 = node_factory.get_node(may_reconnect=True) l2 = node_factory.get_node(options={'funding-confirms': 3}, may_reconnect=True) l1.rpc.connect(l2.info['id'], 'localhost', l2.port) l1.fundwallet(10**6 + 1000000) l1.rpc.fundchannel(l2.info['id'], 10**6)['tx'] # l1 goes down. l1.stop() # Now 120 blocks go by... bitcoind.generate_block(120) # Restart l1.start() # All should be good. l1.daemon.wait_for_log(' to CHANNELD_NORMAL') l2.daemon.wait_for_log(' to CHANNELD_NORMAL') def test_funding_while_offline(node_factory, bitcoind): l1 = node_factory.get_node() addr = l1.rpc.newaddr()['bech32'] sync_blockheight(bitcoind, [l1]) # l1 goes down. l1.stop() # We send funds bitcoind.rpc.sendtoaddress(addr, (10**6 + 1000000) / 10**8) # Now 120 blocks go by... bitcoind.generate_block(120) # Restart l1.start() sync_blockheight(bitcoind, [l1]) assert len(l1.rpc.listfunds()['outputs']) == 1 @unittest.skipIf(not DEVELOPER, "needs DEVELOPER=1") def test_channel_persistence(node_factory, bitcoind, executor): # Start two nodes and open a channel (to remember). l2 will # mysteriously die while committing the first HTLC so we can # check that HTLCs reloaded from the DB work. # Feerates identical so we don't get gratuitous commit to update them l1 = node_factory.get_node(may_reconnect=True, feerates=(7500, 7500, 7500, 7500)) l2 = node_factory.get_node(disconnect=['=WIRE_COMMITMENT_SIGNED-nocommit'], may_reconnect=True) l1.rpc.connect(l2.info['id'], 'localhost', l2.port) # Neither node should have a channel open, they are just connected for n in (l1, l2): assert(n.db_query('SELECT COUNT(id) as count FROM channels;')[0]['count'] == 0) l1.fund_channel(l2, 100000) peers = l1.rpc.listpeers()['peers'] assert(only_one(peers[0]['channels'])['state'] == 'CHANNELD_NORMAL') # Both nodes should now have exactly one channel in the database for n in (l1, l2): assert(n.db_query('SELECT COUNT(id) as count FROM channels;')[0]['count'] == 1) # Fire off a sendpay request, it'll get interrupted by a restart executor.submit(l1.pay, l2, 10000) # Wait for it to be committed to, i.e., stored in the DB l1.daemon.wait_for_log('peer_in WIRE_COMMITMENT_SIGNED') # Stop l2, l1 will reattempt to connect print("Killing l2 in mid HTLC") l2.daemon.kill() # Clear the disconnect and timer stop so we can proceed normally del l2.daemon.opts['dev-disconnect'] # Wait for l1 to notice wait_for(lambda: 'connected' not in only_one(l1.rpc.listpeers()['peers'][0]['channels'])) # Now restart l2 and it should reload peers/channels from the DB l2.start() wait_for(lambda: len(l2.rpc.listpeers()['peers']) == 1) # Wait for the restored HTLC to finish wait_for(lambda: only_one(l1.rpc.listpeers()['peers'][0]['channels'])['msatoshi_to_us'] == 99990000) wait_for(lambda: len([p for p in l1.rpc.listpeers()['peers'] if p['connected']])) wait_for(lambda: len([p for p in l2.rpc.listpeers()['peers'] if p['connected']])) # Now make sure this is really functional by sending a payment l1.pay(l2, 10000) # L1 doesn't actually update msatoshi_to_us until it receives # revoke_and_ack from L2, which can take a little bit. wait_for(lambda: only_one(l1.rpc.listpeers()['peers'][0]['channels'])['msatoshi_to_us'] == 99980000) assert only_one(l2.rpc.listpeers()['peers'][0]['channels'])['msatoshi_to_us'] == 20000 # Finally restart l1, and make sure it remembers l1.restart() assert only_one(l1.rpc.listpeers()['peers'][0]['channels'])['msatoshi_to_us'] == 99980000 # Now make sure l1 is watching for unilateral closes l2.rpc.dev_fail(l1.info['id']) l2.daemon.wait_for_log('Failing due to dev-fail command') l2.wait_for_channel_onchain(l1.info['id']) bitcoind.generate_block(1) # L1 must notice. l1.daemon.wait_for_log(' to ONCHAIN') @unittest.skipIf(not DEVELOPER, "gossip without DEVELOPER=1 is slow") def test_private_channel(node_factory): l1, l2 = node_factory.line_graph(2, announce_channels=False, wait_for_announce=False) l3, l4 = node_factory.line_graph(2, announce_channels=True, wait_for_announce=True) assert l1.daemon.is_in_log('Will open private channel with node {}'.format(l2.info['id'])) assert not l2.daemon.is_in_log('Will open private channel with node {}'.format(l1.info['id'])) assert not l3.daemon.is_in_log('Will open private channel with node {}'.format(l4.info['id'])) l3.daemon.wait_for_log('Received node_announcement for node {}'.format(l4.info['id'])) l4.daemon.wait_for_log('Received node_announcement for node {}'.format(l3.info['id'])) assert not l1.daemon.is_in_log('Received node_announcement for node {}'.format(l2.info['id'])) assert not l2.daemon.is_in_log('Received node_announcement for node {}'.format(l1.info['id'])) # test for 'private' flag in rpc output assert only_one(only_one(l1.rpc.listpeers(l2.info['id'])['peers'])['channels'])['private'] # check non-private channel assert not only_one(only_one(l4.rpc.listpeers(l3.info['id'])['peers'])['channels'])['private'] @unittest.skipIf(not DEVELOPER, "Too slow without --dev-fast-gossip") def test_channel_reenable(node_factory): l1, l2 = node_factory.line_graph(2, opts={'may_reconnect': True}, fundchannel=True, wait_for_announce=True) l1.daemon.wait_for_log('Received node_announcement for node {}'.format(l2.info['id'])) l2.daemon.wait_for_log('Received node_announcement for node {}'.format(l1.info['id'])) # Both directions should be active before the restart wait_for(lambda: [c['active'] for c in l1.rpc.listchannels()['channels']] == [True, True]) # Restart l2, will cause l1 to reconnect l2.stop() wait_for(lambda: [c['active'] for c in l1.rpc.listchannels()['channels']] == [False, False]) l2.start() # Updates may be suppressed if redundant; just test results. wait_for(lambda: [c['active'] for c in l1.rpc.listchannels()['channels']] == [True, True]) wait_for(lambda: [c['active'] for c in l2.rpc.listchannels()['channels']] == [True, True]) @unittest.skipIf(not DEVELOPER, "needs DEVELOPER=1") def test_update_fee(node_factory, bitcoind): l1, l2 = node_factory.line_graph(2, fundchannel=True) chanid = l1.get_channel_scid(l2) # Make l1 send out feechange. l1.set_feerates((14000, 11000, 7500, 3750)) # Now make sure an HTLC works. # (First wait for route propagation.) l1.wait_channel_active(chanid) sync_blockheight(bitcoind, [l1, l2]) # Make payments. l1.pay(l2, 200000000) # First payment causes fee update. l2.daemon.wait_for_log('peer updated fee to 14000') l2.pay(l1, 100000000) # Now shutdown cleanly. l1.rpc.close(chanid) l1.daemon.wait_for_log(' to CLOSINGD_COMPLETE') l2.daemon.wait_for_log(' to CLOSINGD_COMPLETE') # And should put closing into mempool. l1.wait_for_channel_onchain(l2.info['id']) l2.wait_for_channel_onchain(l1.info['id']) bitcoind.generate_block(1) l1.daemon.wait_for_log(' to ONCHAIN') l2.daemon.wait_for_log(' to ONCHAIN') bitcoind.generate_block(99) l1.daemon.wait_for_log('onchaind complete, forgetting peer') l2.daemon.wait_for_log('onchaind complete, forgetting peer') @unittest.skipIf(not DEVELOPER, "needs DEVELOPER=1") def test_fee_limits(node_factory, bitcoind): l1, l2 = node_factory.line_graph(2, opts={'dev-max-fee-multiplier': 5, 'may_reconnect': True}, fundchannel=True) # Kick off fee adjustment using HTLC. l1.pay(l2, 1000) # L1 asks for stupid low fee (will actually hit the floor of 253) l1.stop() l1.set_feerates((15, 15, 15, 15), False) l1.start() l1.daemon.wait_for_log('Peer transient failure in CHANNELD_NORMAL: channeld: .*: update_fee 253 outside range 1875-75000') # Make sure the resolution of this one doesn't interfere with the next! # Note: may succeed, may fail with insufficient fee, depending on how # bitcoind feels! l2.daemon.wait_for_log('sendrawtx exit') bitcoind.generate_block(1) sync_blockheight(bitcoind, [l1, l2]) # Trying to open a channel with too low a fee-rate is denied l4 = node_factory.get_node() l1.rpc.connect(l4.info['id'], 'localhost', l4.port) with pytest.raises(RpcError, match='They sent error .* feerate_per_kw 253 below minimum'): l1.fund_channel(l4, 10**6) # Restore to normal. l1.stop() l1.set_feerates((15000, 11000, 7500, 3750), False) l1.start() # Try with node which sets --ignore-fee-limits l3 = node_factory.get_node(options={'ignore-fee-limits': 'true'}, may_reconnect=True) l1.rpc.connect(l3.info['id'], 'localhost', l3.port) chan = l1.fund_channel(l3, 10**6) # Kick off fee adjustment using HTLC. l1.pay(l3, 1000) # Try stupid high fees l1.stop() l1.set_feerates((15000 * 10, 11000, 7500, 3750), False) l1.start() l3.daemon.wait_for_log('peer_in WIRE_UPDATE_FEE') l3.daemon.wait_for_log('peer_in WIRE_COMMITMENT_SIGNED') # We need to wait until both have committed and revoked the # old state, otherwise we'll still try to commit with the old # 15sat/byte fee l1.daemon.wait_for_log('peer_out WIRE_REVOKE_AND_ACK') # This should wait for close to complete l1.rpc.close(chan) @unittest.skipIf(not DEVELOPER, "needs DEVELOPER=1") def test_update_fee_reconnect(node_factory, bitcoind): # Disconnect after commitsig for fee update. disconnects = ['+WIRE_COMMITMENT_SIGNED*3'] # Feerates identical so we don't get gratuitous commit to update them l1 = node_factory.get_node(disconnect=disconnects, may_reconnect=True, feerates=(15000, 15000, 15000, 3750)) # We match l2's later feerate, so we agree on same closing tx for simplicity. l2 = node_factory.get_node(may_reconnect=True, feerates=(14000, 15000, 14000, 3750)) l1.rpc.connect(l2.info['id'], 'localhost', l2.port) chan = l1.fund_channel(l2, 10**6) # Make an HTLC just to get us to do feechanges. l1.pay(l2, 1000) # Make l1 send out feechange; triggers disconnect/reconnect. # (Note: < 10% change, so no smoothing here!) l1.set_feerates((14000, 14000, 14000, 3750)) l1.daemon.wait_for_log('Setting REMOTE feerate to 14000') l2.daemon.wait_for_log('Setting LOCAL feerate to 14000') l1.daemon.wait_for_log(r'dev_disconnect: \+WIRE_COMMITMENT_SIGNED') # Wait for reconnect.... l1.daemon.wait_for_log('Feerate:.*LOCAL now 14000') l1.pay(l2, 200000000) l2.pay(l1, 100000000) # They should both have gotten commits with correct feerate. assert l1.daemon.is_in_log('got commitsig [0-9]*: feerate 14000') assert l2.daemon.is_in_log('got commitsig [0-9]*: feerate 14000') # Now shutdown cleanly. l1.rpc.close(chan) # And should put closing into mempool. l1.wait_for_channel_onchain(l2.info['id']) l2.wait_for_channel_onchain(l1.info['id']) bitcoind.generate_block(1) l1.daemon.wait_for_log(' to ONCHAIN') l2.daemon.wait_for_log(' to ONCHAIN') bitcoind.generate_block(99) l1.daemon.wait_for_log('onchaind complete, forgetting peer') l2.daemon.wait_for_log('onchaind complete, forgetting peer') @unittest.skipIf(not DEVELOPER, "Too slow without --dev-bitcoind-poll") def test_multiple_channels(node_factory): l1 = node_factory.get_node() l2 = node_factory.get_node() for i in range(3): # FIXME: we shouldn't disconnect on close? ret = l1.rpc.connect(l2.info['id'], 'localhost', l2.port) assert ret['id'] == l2.info['id'] l1.daemon.wait_for_log('openingd-.*: Handed peer, entering loop') l2.daemon.wait_for_log('openingd-.*: Handed peer, entering loop') chan = l1.fund_channel(l2, 10**6) l1.rpc.close(chan) channels = only_one(l1.rpc.listpeers()['peers'])['channels'] assert len(channels) == 3 # Most in state ONCHAIN, last is CLOSINGD_COMPLETE for i in range(len(channels) - 1): assert channels[i]['state'] == 'ONCHAIN' assert channels[-1]['state'] == 'CLOSINGD_COMPLETE' @unittest.skipIf(not DEVELOPER, "needs DEVELOPER=1") def test_forget_channel(node_factory): l1 = node_factory.get_node() l2 = node_factory.get_node() l1.fundwallet(10**6) l1.rpc.connect(l2.info['id'], 'localhost', l2.port) l1.rpc.fundchannel(l2.info['id'], 10**5) assert len(l1.rpc.listpeers()['peers']) == 1 # This should fail, the funding tx is in the mempool and may confirm with pytest.raises(RpcError, match=r'Cowardly refusing to forget channel'): l1.rpc.dev_forget_channel(l2.info['id']) assert len(l1.rpc.listpeers()['peers']) == 1 # Forcing should work l1.rpc.dev_forget_channel(l2.info['id'], True) assert len(l1.rpc.listpeers()['peers']) == 0 # And restarting should keep that peer forgotten l1.restart() assert len(l1.rpc.listpeers()['peers']) == 0 # The entry in the channels table should still be there assert l1.db_query("SELECT count(*) as c FROM channels;")[0]['c'] == 1 assert l2.db_query("SELECT count(*) as c FROM channels;")[0]['c'] == 1 def test_peerinfo(node_factory, bitcoind): l1, l2 = node_factory.line_graph(2, fundchannel=False, opts={'may_reconnect': True}) lfeatures = expected_peer_features() nfeatures = expected_node_features() # Gossiping but no node announcement yet assert l1.rpc.getpeer(l2.info['id'])['connected'] assert len(l1.rpc.getpeer(l2.info['id'])['channels']) == 0 assert l1.rpc.getpeer(l2.info['id'])['features'] == lfeatures # Fund a channel to force a node announcement chan = l1.fund_channel(l2, 10**6) # Now proceed to funding-depth and do a full gossip round bitcoind.generate_block(5) l1.daemon.wait_for_logs(['Received node_announcement for node ' + l2.info['id']]) l2.daemon.wait_for_logs(['Received node_announcement for node ' + l1.info['id']]) # Should have announced the same features as told to peer. nodes1 = l1.rpc.listnodes(l2.info['id'])['nodes'] nodes2 = l2.rpc.listnodes(l2.info['id'])['nodes'] peer1 = l1.rpc.getpeer(l2.info['id']) peer2 = l2.rpc.getpeer(l1.info['id']) # peer features != to node features now because of keysend, which adds a node feature assert only_one(nodes1)['features'] == nfeatures assert only_one(nodes2)['features'] == nfeatures assert peer1['features'] == lfeatures assert peer2['features'] == lfeatures # If it reconnects after db load, it should know features. l1.restart() wait_for(lambda: l1.rpc.getpeer(l2.info['id'])['connected']) wait_for(lambda: l2.rpc.getpeer(l1.info['id'])['connected']) assert l1.rpc.getpeer(l2.info['id'])['features'] == lfeatures assert l2.rpc.getpeer(l1.info['id'])['features'] == lfeatures # Close the channel to forget the peer l1.rpc.close(chan) wait_for(lambda: not only_one(l1.rpc.listpeers(l2.info['id'])['peers'])['connected']) wait_for(lambda: not only_one(l2.rpc.listpeers(l1.info['id'])['peers'])['connected']) # Make sure close tx hits mempool before we mine blocks. bitcoind.generate_block(100, wait_for_mempool=1) l1.daemon.wait_for_log('onchaind complete, forgetting peer') l2.daemon.wait_for_log('onchaind complete, forgetting peer') # The only channel was closed, everybody should have forgotten the nodes assert l1.rpc.listnodes()['nodes'] == [] assert l2.rpc.listnodes()['nodes'] == [] def test_disconnectpeer(node_factory, bitcoind): l1, l2, l3 = node_factory.get_nodes(3, opts={'may_reconnect': False}) l1.rpc.connect(l2.info['id'], 'localhost', l2.port) l1.rpc.connect(l3.info['id'], 'localhost', l3.port) # Gossiping assert l1.rpc.getpeer(l2.info['id'])['connected'] assert len(l1.rpc.getpeer(l2.info['id'])['channels']) == 0 assert l1.rpc.getpeer(l3.info['id'])['connected'] assert len(l1.rpc.getpeer(l3.info['id'])['channels']) == 0 wait_for(lambda: l2.rpc.getpeer(l1.info['id']) is not None) # Disconnect l2 from l1 l1.rpc.disconnect(l2.info['id']) # Make sure listpeers no longer returns the disconnected node assert l1.rpc.getpeer(l2.info['id']) is None wait_for(lambda: l2.rpc.getpeer(l1.info['id']) is None) # Make sure you cannot disconnect after disconnecting with pytest.raises(RpcError, match=r'Peer not connected'): l1.rpc.disconnect(l2.info['id']) with pytest.raises(RpcError, match=r'Peer not connected'): l2.rpc.disconnect(l1.info['id']) # Fund channel l1 -> l3 l1.fund_channel(l3, 10**6) bitcoind.generate_block(5) # disconnecting a non gossiping peer results in error with pytest.raises(RpcError, match=r'Peer is in state CHANNELD_NORMAL'): l1.rpc.disconnect(l3.info['id']) @unittest.skipIf(not DEVELOPER, "needs --dev-max-funding-unconfirmed-blocks") def test_fundee_forget_funding_tx_unconfirmed(node_factory, bitcoind): """Test that fundee will forget the channel if the funding tx has been unconfirmed for too long. """ # Keep this low (default is 2016), since everything # is much slower in VALGRIND mode and wait_for_log # could time out before lightningd processes all the # blocks. blocks = 200 # opener l1 = node_factory.get_node() # peer l2 = node_factory.get_node(options={"dev-max-funding-unconfirmed-blocks": blocks}) l1.rpc.connect(l2.info['id'], 'localhost', l2.port) # Give opener some funds. l1.fundwallet(10**7) # Let blocks settle. time.sleep(1) def mock_sendrawtransaction(r): return {'id': r['id'], 'error': {'code': 100, 'message': 'sendrawtransaction disabled'}} # Prevent opener from broadcasting funding tx (any tx really). l1.daemon.rpcproxy.mock_rpc('sendrawtransaction', mock_sendrawtransaction) # Fund the channel. # The process will complete, but opener will be unable # to broadcast and confirm funding tx. with pytest.raises(RpcError, match=r'sendrawtransaction disabled'): l1.rpc.fundchannel(l2.info['id'], 10**6) # Generate blocks until unconfirmed. bitcoind.generate_block(blocks) # fundee will forget channel! l2.daemon.wait_for_log('Forgetting channel: It has been {} blocks'.format(blocks)) # fundee will also forget and disconnect from peer. assert len(l2.rpc.listpeers(l1.info['id'])['peers']) == 0 @unittest.skipIf(not DEVELOPER, "needs dev_fail") def test_no_fee_estimate(node_factory, bitcoind, executor): l1 = node_factory.get_node(start=False) # Fail any fee estimation requests until we allow them further down l1.daemon.rpcproxy.mock_rpc('estimatesmartfee', { 'error': {"errors": ["Insufficient data or no feerate found"], "blocks": 0} }) l1.start() l2 = node_factory.get_node() l1.rpc.connect(l2.info['id'], 'localhost', l2.port) # Can't fund a channel. l1.fundwallet(10**7) with pytest.raises(RpcError, match=r'Cannot estimate fees'): l1.rpc.fundchannel(l2.info['id'], 10**6) # Can't withdraw either. with pytest.raises(RpcError, match=r'Cannot estimate fees'): l1.rpc.withdraw(l2.rpc.newaddr()['bech32'], 'all') # Can't use feerate names, either. with pytest.raises(RpcError, match=r'Cannot estimate fees'): l1.rpc.withdraw(l2.rpc.newaddr()['bech32'], 'all', 'urgent') l1.rpc.withdraw(l2.rpc.newaddr()['bech32'], 'all', 'normal') l1.rpc.withdraw(l2.rpc.newaddr()['bech32'], 'all', 'slow') with pytest.raises(RpcError, match=r'Cannot estimate fees'): l1.rpc.fundchannel(l2.info['id'], 10**6, 'urgent') l1.rpc.fundchannel(l2.info['id'], 10**6, 'normal') l1.rpc.fundchannel(l2.info['id'], 10**6, 'slow') # Can with manual feerate. l1.rpc.withdraw(l2.rpc.newaddr()['bech32'], 10000, '1500perkb') l1.rpc.fundchannel(l2.info['id'], 10**6, '2000perkw', minconf=0) # Make sure we clean up cahnnel for later attempt. l1.daemon.wait_for_log('sendrawtx exit 0') l1.rpc.dev_fail(l2.info['id']) l1.daemon.wait_for_log('Failing due to dev-fail command') l1.wait_for_channel_onchain(l2.info['id']) bitcoind.generate_block(6) wait_for(lambda: only_one(l1.rpc.getpeer(l2.info['id'])['channels'])['state'] == 'ONCHAIN') wait_for(lambda: only_one(l2.rpc.getpeer(l1.info['id'])['channels'])['state'] == 'ONCHAIN') # But can accept incoming connections. l1.rpc.connect(l2.info['id'], 'localhost', l2.port) l2.fund_channel(l1, 10**6) # Can do HTLCs. l2.pay(l1, 10**5) # Can do mutual close. l1.rpc.close(l2.info['id']) wait_for(lambda: len(bitcoind.rpc.getrawmempool()) > 0) bitcoind.generate_block(100) # Can do unilateral close. l2.rpc.connect(l1.info['id'], 'localhost', l1.port) l2.fund_channel(l1, 10**6) l2.pay(l1, 10**9 // 2) l1.rpc.dev_fail(l2.info['id']) l1.daemon.wait_for_log('Failing due to dev-fail command') l1.wait_for_channel_onchain(l2.info['id']) bitcoind.generate_block(5) wait_for(lambda: len(bitcoind.rpc.getrawmempool()) > 0) bitcoind.generate_block(100) # Start estimatesmartfee. l1.set_feerates((15000, 11000, 7500, 3750), True) # Can now fund a channel (as a test, use slow feerate). l1.rpc.connect(l2.info['id'], 'localhost', l2.port) l1.rpc.fundchannel(l2.info['id'], 10**6, 'slow') # Can withdraw (use urgent feerate). `minconf` may be needed depending on # the previous `fundchannel` selecting all confirmed outputs. l1.rpc.withdraw(l2.rpc.newaddr()['bech32'], 'all', 'urgent', minconf=0) @unittest.skipIf(not DEVELOPER, "needs --dev-disconnect") def test_opener_feerate_reconnect(node_factory, bitcoind): # l1 updates fees, then reconnect so l2 retransmits commitment_signed. disconnects = ['-WIRE_COMMITMENT_SIGNED*3'] l1 = node_factory.get_node(may_reconnect=True, feerates=(7500, 7500, 7500, 7500)) l2 = node_factory.get_node(disconnect=disconnects, may_reconnect=True) l1.rpc.connect(l2.info['id'], 'localhost', l2.port) l1.fund_channel(l2, 10**6) # Need a payment otherwise it won't update fee. l1.pay(l2, 10**9 // 2) # create fee update, causing disconnect. l1.set_feerates((15000, 11000, 7500, 3750)) l2.daemon.wait_for_log(r'dev_disconnect: \-WIRE_COMMITMENT_SIGNED') # Wait until they reconnect. l1.daemon.wait_for_log('Peer transient failure in CHANNELD_NORMAL') wait_for(lambda: l1.rpc.getpeer(l2.info['id'])['connected']) # Should work normally. l1.pay(l2, 200000000) def test_opener_simple_reconnect(node_factory, bitcoind): """Sanity check that reconnection works with completely unused channels""" # Set fees even so it doesn't send any commitments. l1 = node_factory.get_node(may_reconnect=True, feerates=(7500, 7500, 7500, 7500)) l2 = node_factory.get_node(may_reconnect=True) l1.rpc.connect(l2.info['id'], 'localhost', l2.port) l1.fund_channel(l2, 10**6) l1.rpc.disconnect(l2.info['id'], True) # Wait until they reconnect. wait_for(lambda: l1.rpc.getpeer(l2.info['id'])['connected']) # Should work normally. l1.pay(l2, 200000000) @unittest.skipIf(os.getenv('TEST_DB_PROVIDER', 'sqlite3') != 'sqlite3', "sqlite3-specific DB rollback") @unittest.skipIf(not DEVELOPER, "needs LIGHTNINGD_DEV_LOG_IO") def test_dataloss_protection(node_factory, bitcoind): l1 = node_factory.get_node(may_reconnect=True, options={'log-level': 'io'}, feerates=(7500, 7500, 7500, 7500)) l2 = node_factory.get_node(may_reconnect=True, options={'log-level': 'io'}, feerates=(7500, 7500, 7500, 7500), allow_broken_log=True) lf = expected_peer_features() l1.rpc.connect(l2.info['id'], 'localhost', l2.port) # l1 should send out WIRE_INIT (0010) l1.daemon.wait_for_log(r"\[OUT\] 0010.*" # lflen + format(len(lf) // 2, '04x') + lf) l1.fund_channel(l2, 10**6) l2.stop() # Save copy of the db. dbpath = os.path.join(l2.daemon.lightning_dir, TEST_NETWORK, "lightningd.sqlite3") orig_db = open(dbpath, "rb").read() l2.start() # l1 should have sent WIRE_CHANNEL_REESTABLISH with extra fields. l1.daemon.wait_for_log(r"\[OUT\] 0088" # channel_id "[0-9a-f]{64}" # next_local_commitment_number "0000000000000001" # next_remote_revocation_number "0000000000000000" # your_last_per_commitment_secret (funding_depth may # trigger a fee-update and commit, hence this may not # be zero) "[0-9a-f]{64}" # my_current_per_commitment_point "0[23][0-9a-f]{64}'$") # After an htlc, we should get different results (two more commits) l1.pay(l2, 200000000) # Make sure both sides consider it completely settled (has received both # REVOKE_AND_ACK) l1.daemon.wait_for_logs([r"\[IN\] 0085"] * 2) l2.daemon.wait_for_logs([r"\[IN\] 0085"] * 2) l2.restart() # l1 should have sent WIRE_CHANNEL_REESTABLISH with extra fields. l1.daemon.wait_for_log(r"\[OUT\] 0088" # channel_id "[0-9a-f]{64}" # next_local_commitment_number "000000000000000[1-9]" # next_remote_revocation_number "000000000000000[1-9]" # your_last_per_commitment_secret "[0-9a-f]{64}" # my_current_per_commitment_point "0[23][0-9a-f]{64}'$") # Now, move l2 back in time. l2.stop() # Overwrite with OLD db. open(dbpath, "wb").write(orig_db) l2.start() # l2 should freak out! l2.daemon.wait_for_log("Peer permanent failure in CHANNELD_NORMAL: Awaiting unilateral close") # l1 should drop to chain. l1.wait_for_channel_onchain(l2.info['id']) # l2 must NOT drop to chain. l2.daemon.wait_for_log("Cannot broadcast our commitment tx: they have a future one") assert not l2.daemon.is_in_log('sendrawtx exit 0') closetxid = only_one(bitcoind.rpc.getrawmempool(False)) # l2 should still recover something! bitcoind.generate_block(1) l2.daemon.wait_for_log("ERROR: Unknown commitment #[0-9], recovering our funds!") # Restarting l2, and it should remember from db. l2.restart() l2.daemon.wait_for_log("ERROR: Unknown commitment #[0-9], recovering our funds!") bitcoind.generate_block(100) l2.daemon.wait_for_log('onchaind complete, forgetting peer') # l2 should have it in wallet. assert (closetxid, "confirmed") in set([(o['txid'], o['status']) for o in l2.rpc.listfunds()['outputs']]) @unittest.skipIf(not DEVELOPER, "needs dev_disconnect") def test_restart_multi_htlc_rexmit(node_factory, bitcoind, executor): # l1 disables commit timer once we send first htlc, dies on commit disconnects = ['=WIRE_UPDATE_ADD_HTLC-nocommit', '-WIRE_COMMITMENT_SIGNED'] l1, l2 = node_factory.line_graph(2, opts=[{'disconnect': disconnects, 'may_reconnect': True}, {'may_reconnect': True}]) executor.submit(l1.pay, l2, 20000) executor.submit(l1.pay, l2, 30000) l1.daemon.wait_for_logs(['peer_out WIRE_UPDATE_ADD_HTLC'] * 2) l1.rpc.dev_reenable_commit(l2.info['id']) l1.daemon.wait_for_log('dev_disconnect: -WIRE_COMMITMENT_SIGNED') # This will make it reconnect l1.stop() # Clear the disconnect so we can proceed normally del l1.daemon.opts['dev-disconnect'] l1.start() # Payments will fail due to restart, but we can see results in listsendpays. print(l1.rpc.listsendpays()) wait_for(lambda: [p['status'] for p in l1.rpc.listsendpays()['payments']] == ['complete', 'complete']) @unittest.skipIf(not DEVELOPER, "needs dev-disconnect") def test_fulfill_incoming_first(node_factory, bitcoind): """Test that we handle the case where we completely resolve incoming htlc before fulfilled outgoing htlc""" # We agree on fee change first, then add HTLC, then remove; stop after remove. disconnects = ['+WIRE_COMMITMENT_SIGNED*3'] # We manually reconnect l2 & l3, after 100 blocks; hence allowing manual # reconnect, but disabling auto connect, and massive cltv so 2/3 doesn't # time out. l1, l2, l3 = node_factory.line_graph(3, opts=[{}, {'may_reconnect': True, 'dev-no-reconnect': None}, {'may_reconnect': True, 'dev-no-reconnect': None, 'disconnect': disconnects, 'cltv-final': 200}], wait_for_announce=True) # This succeeds. l1.rpc.pay(l3.rpc.invoice(200000000, 'test_fulfill_incoming_first', 'desc')['bolt11']) # l1 can shutdown, fine. l1.rpc.close(l2.info['id']) l1.wait_for_channel_onchain(l2.info['id']) bitcoind.generate_block(100) l2.daemon.wait_for_log('onchaind complete, forgetting peer') # Now, l2 should restore from DB fine, even though outgoing HTLC no longer # has an incoming. l2.restart() # Manually reconnect l2->l3. l2.rpc.connect(l3.info['id'], 'localhost', l3.port) # Fulfill should be retransmitted OK (ignored result). l2.rpc.close(l3.info['id']) l2.wait_for_channel_onchain(l3.info['id']) bitcoind.generate_block(100) l2.daemon.wait_for_log('onchaind complete, forgetting peer') l3.daemon.wait_for_log('onchaind complete, forgetting peer') @unittest.skipIf(not DEVELOPER, "gossip without DEVELOPER=1 is slow") def test_restart_many_payments(node_factory, bitcoind): l1 = node_factory.get_node(may_reconnect=True) # On my laptop, these take 74 seconds and 44 seconds (with restart commented out) if VALGRIND: num = 2 else: num = 5 # Nodes with channels into the main node innodes = node_factory.get_nodes(num, opts={'may_reconnect': True}) inchans = [] for n in innodes: n.rpc.connect(l1.info['id'], 'localhost', l1.port) inchans.append(n.fund_channel(l1, 10**6, False)) # Nodes with channels out of the main node outnodes = node_factory.get_nodes(len(innodes), opts={'may_reconnect': True}) outchans = [] for n in outnodes: n.rpc.connect(l1.info['id'], 'localhost', l1.port) outchans.append(l1.fund_channel(n, 10**6, False)) # Make sure they're all announced. bitcoind.generate_block(5) # We wait for each node to see each dir active, and its own # channel CHANNELD_NORMAL logs = ([r'update for channel {}/0 now ACTIVE'.format(scid) for scid in inchans + outchans] + [r'update for channel {}/1 now ACTIVE'.format(scid) for scid in inchans + outchans] + ['to CHANNELD_NORMAL']) # Now do all the waiting at once: if !DEVELOPER, this can be *very* slow! for n in innodes + outnodes: n.daemon.wait_for_logs(logs) # Manually create routes, get invoices Payment = namedtuple('Payment', ['innode', 'route', 'payment_hash']) to_pay = [] for i in range(len(innodes)): # This one will cause WIRE_INCORRECT_CLTV_EXPIRY from l1. route = [{'msatoshi': 100001001, 'id': l1.info['id'], 'delay': 10, 'channel': inchans[i]}, {'msatoshi': 100000000, 'id': outnodes[i].info['id'], 'delay': 5, 'channel': outchans[i]}] payment_hash = outnodes[i].rpc.invoice(100000000, "invoice", "invoice")['payment_hash'] to_pay.append(Payment(innodes[i], route, payment_hash)) # This one should be routed through to the outnode. route = [{'msatoshi': 100001001, 'id': l1.info['id'], 'delay': 11, 'channel': inchans[i]}, {'msatoshi': 100000000, 'id': outnodes[i].info['id'], 'delay': 5, 'channel': outchans[i]}] payment_hash = outnodes[i].rpc.invoice(100000000, "invoice2", "invoice2")['payment_hash'] to_pay.append(Payment(innodes[i], route, payment_hash)) # sendpay is async. for p in to_pay: p.innode.rpc.sendpay(p.route, p.payment_hash) # Now restart l1 while traffic is flowing... l1.restart() # Wait for them to finish. for n in innodes: wait_for(lambda: 'pending' not in [p['status'] for p in n.rpc.listsendpays()['payments']]) @unittest.skipIf(not DEVELOPER, "need dev-disconnect") def test_fail_unconfirmed(node_factory, bitcoind, executor): """Test that if we crash with an unconfirmed connection to a known peer, we don't have a dangling peer in db""" # = is a NOOP disconnect, but sets up file. l1 = node_factory.get_node(disconnect=['=WIRE_OPEN_CHANNEL']) l2 = node_factory.get_node() # First one, we close by mutual agreement. l1.rpc.connect(l2.info['id'], 'localhost', l2.port) l1.fund_channel(l2, 200000, wait_for_active=True) l1.rpc.close(l2.info['id']) # Make sure it's closed l1.wait_for_channel_onchain(l2.info['id']) bitcoind.generate_block(1) l1.daemon.wait_for_log('State changed from CLOSINGD_COMPLETE to FUNDING_SPEND_SEEN') l1.stop() # Mangle disconnect file so this time it blackholes.... with open(l1.daemon.disconnect_file, "w") as f: f.write("0WIRE_OPEN_CHANNEL\n") l1.start() # Now we establish a new channel, which gets stuck. l1.rpc.connect(l2.info['id'], 'localhost', l2.port) l1.fundwallet(10**7) executor.submit(l1.rpc.fundchannel, l2.info['id'], 100000) l1.daemon.wait_for_log("dev_disconnect") # Now complete old channel. bitcoind.generate_block(100) l1.daemon.wait_for_log('onchaind complete, forgetting peer') # And crash l1, which is stuck. l1.daemon.kill() # Now, restart and see if it can connect OK. del l1.daemon.opts['dev-disconnect'] l1.start() l1.rpc.connect(l2.info['id'], 'localhost', l2.port) l1.fund_channel(l2, 200000, wait_for_active=True) def test_change_chaining(node_factory, bitcoind): """Test change chaining of unconfirmed fundings Change chaining is the case where one transaction is broadcast but not confirmed yet and we already build a followup on top of the change. If the first transaction doesn't confirm we may end up creating a series of unconfirmable transactions. This is why we generally disallow chaining. """ l1, l2, l3 = node_factory.get_nodes(3) l1.fundwallet(10**8) # This will create an output with 1 confirmation # Now fund a channel from l1 to l2, that should succeed, with minconf=1 but not before l1.connect(l2) with pytest.raises(RpcError): l1.rpc.fundchannel(l2.info['id'], 10**7, minconf=2) l1.rpc.fundchannel(l2.info['id'], 10**7) # Defaults to minconf=1 # We don't have confirmed outputs anymore, so this should fail without minconf=0 l1.connect(l3) with pytest.raises(RpcError): l1.rpc.fundchannel(l3.info['id'], 10**7) # Defaults to minconf=1 l1.rpc.fundchannel(l3.info['id'], 10**7, minconf=0) def test_feerate_spam(node_factory, chainparams): l1, l2 = node_factory.line_graph(2) # We constrain the value the opener has at its disposal so we get the # REMOTE feerate we are looking for below. This may be fragile and depends # on the transactions we generate. slack = 45000000 if not chainparams['elements'] else 68000000 # Pay almost everything to l2. l1.pay(l2, 10**9 - slack) # It will send this once (may have happened before line_graph's wait) wait_for(lambda: l1.daemon.is_in_log('Setting REMOTE feerate to 15000')) wait_for(lambda: l1.daemon.is_in_log('peer_out WIRE_UPDATE_FEE')) # Now change feerates to something l1 can't afford. l1.set_feerates((100000, 100000, 100000, 100000)) # It will raise as far as it can (48000) l1.daemon.wait_for_log('Setting REMOTE feerate to 48000') l1.daemon.wait_for_log('peer_out WIRE_UPDATE_FEE') # But it won't do it again once it's at max. with pytest.raises(TimeoutError): l1.daemon.wait_for_log('peer_out WIRE_UPDATE_FEE', timeout=5) @unittest.skipIf(not DEVELOPER, "need dev-feerate") def test_feerate_stress(node_factory, executor): # Third node makes HTLC traffic less predictable. l1, l2, l3 = node_factory.line_graph(3, opts={'commit-time': 100, 'may_reconnect': True}) l1.pay(l2, 10**9 // 2) scid12 = l1.get_channel_scid(l2) scid23 = l2.get_channel_scid(l3) routel1l3 = [{'msatoshi': '10002msat', 'id': l2.info['id'], 'delay': 11, 'channel': scid12}, {'msatoshi': '10000msat', 'id': l3.info['id'], 'delay': 5, 'channel': scid23}] routel2l1 = [{'msatoshi': '10000msat', 'id': l1.info['id'], 'delay': 5, 'channel': scid12}] rate = 1875 NUM_ATTEMPTS = 25 l1done = 0 l2done = 0 prev_log = 0 while l1done < NUM_ATTEMPTS and l2done < NUM_ATTEMPTS: try: r = random.randrange(6) if r == 5: l1.rpc.sendpay(routel1l3, "{:064x}".format(l1done)) l1done += 1 elif r == 4: l2.rpc.sendpay(routel2l1, "{:064x}".format(l2done)) l2done += 1 elif r > 0: l1.rpc.call('dev-feerate', [l2.info['id'], rate]) rate += 5 else: l2.rpc.disconnect(l1.info['id'], True) time.sleep(1) except RpcError: time.sleep(0.01) assert not l1.daemon.is_in_log('Bad.*signature', start=prev_log) prev_log = len(l1.daemon.logs) # Make sure it's reconnected, and wait for last payment. wait_for(lambda: l1.rpc.getpeer(l2.info['id'])['connected']) # We can get TEMPORARY_CHANNEL_FAILURE due to disconnect, too. with pytest.raises(RpcError, match='WIRE_INCORRECT_OR_UNKNOWN_PAYMENT_DETAILS|WIRE_TEMPORARY_CHANNEL_FAILURE'): l1.rpc.waitsendpay("{:064x}".format(l1done - 1)) with pytest.raises(RpcError, match='WIRE_INCORRECT_OR_UNKNOWN_PAYMENT_DETAILS|WIRE_TEMPORARY_CHANNEL_FAILURE'): l2.rpc.waitsendpay("{:064x}".format(l2done - 1)) l1.rpc.call('dev-feerate', [l2.info['id'], rate - 5]) assert not l1.daemon.is_in_log('Bad.*signature') assert not l2.daemon.is_in_log('Bad.*signature') @unittest.skipIf(not DEVELOPER, "need dev_disconnect") def test_pay_disconnect_stress(node_factory, executor): """Expose race in htlc restoration in channeld: 50% chance of failure""" if SLOW_MACHINE and VALGRIND: NUM_RUNS = 2 else: NUM_RUNS = 5 for i in range(NUM_RUNS): l1, l2 = node_factory.line_graph(2, opts=[{'may_reconnect': True}, {'may_reconnect': True, 'disconnect': ['=WIRE_UPDATE_ADD_HTLC', '-WIRE_COMMITMENT_SIGNED']}]) scid12 = l1.get_channel_scid(l2) routel2l1 = [{'msatoshi': '10000msat', 'id': l1.info['id'], 'delay': 5, 'channel': scid12}] # Get invoice from l1 to pay. payhash1 = l1.rpc.invoice(10000, "invoice", "invoice")['payment_hash'] # Start balancing payment. fut = executor.submit(l1.pay, l2, 10**9 // 2) # As soon as reverse payment is accepted, reconnect. while True: l2.rpc.sendpay(routel2l1, payhash1) try: # This will usually fail with Capacity exceeded l2.rpc.waitsendpay(payhash1, timeout=TIMEOUT) break except RpcError: pass fut.result() def test_wumbo_channels(node_factory, bitcoind): f = bytes.fromhex(expected_peer_features()) # OPT_LARGE_CHANNELS = 18 (19 for us). 0x080000 f = (f[:-3] + bytes([f[-3] | 0x08]) + f[-2:]).hex() l1, l2, l3 = node_factory.get_nodes(3, opts=[{'large-channels': None}, {'large-channels': None}, {}]) conn = l1.rpc.connect(l2.info['id'], 'localhost', port=l2.port) assert conn['features'] == f assert only_one(l1.rpc.listpeers(l2.info['id'])['peers'])['features'] == f # Now, can we open a giant channel? l1.fundwallet(1 << 26) l1.rpc.fundchannel(l2.info['id'], 1 << 24) # Get that mined, and announced. bitcoind.generate_block(6, wait_for_mempool=1) # Connect l3, get gossip. l3.rpc.connect(l1.info['id'], 'localhost', port=l1.port) wait_for(lambda: len(l3.rpc.listnodes(l1.info['id'])['nodes']) == 1) wait_for(lambda: 'features' in only_one(l3.rpc.listnodes(l1.info['id'])['nodes'])) # Make sure channel capacity is what we expected. assert ([c['amount_msat'] for c in l3.rpc.listchannels()['channels']] == [Millisatoshi(str(1 << 24) + "sat")] * 2) # Make sure we can't open a wumbo channel if we don't agree. with pytest.raises(RpcError, match='Amount exceeded'): l1.rpc.fundchannel(l3.info['id'], 1 << 24) # But we can open and announce a normal one. l1.rpc.fundchannel(l3.info['id'], 'all') bitcoind.generate_block(6, wait_for_mempool=1) wait_for(lambda: l1.channel_state(l3) == 'CHANNELD_NORMAL') # Make sure l2 sees correct size. wait_for(lambda: [c['amount_msat'] for c in l2.rpc.listchannels(l1.get_channel_scid(l3))['channels']] == [Millisatoshi(str((1 << 24) - 1) + "sat")] * 2) # Make sure 'all' works with wumbo peers. l1.rpc.close(l2.info['id']) bitcoind.generate_block(1, wait_for_mempool=1) wait_for(lambda: l1.channel_state(l2) == 'ONCHAIN') l1.rpc.connect(l2.info['id'], 'localhost', port=l2.port) l1.rpc.fundchannel(l2.info['id'], 'all') bitcoind.generate_block(1, wait_for_mempool=1) wait_for(lambda: 'CHANNELD_NORMAL' in [c['state'] for c in only_one(l1.rpc.listpeers(l2.info['id'])['peers'])['channels']]) # Exact amount depends on fees, but it will be wumbo! amount = [c['funding_msat'][l1.info['id']] for c in only_one(l1.rpc.listpeers(l2.info['id'])['peers'])['channels'] if c['state'] == 'CHANNELD_NORMAL'][0] assert Millisatoshi(amount) > Millisatoshi(str((1 << 24) - 1) + "sat")