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6 commits

Author SHA1 Message Date
Rusty Russell
32aa79a1e2 askrene: debug and check we actually reduce fees when mu increase.
Even after the previous fix, we still occasionally increase fees when my increases.

This is due to the difference between MCF's linear fees, and actual fees, and
is unavoidable, but add a check if it somehow happens.

Signed-off-by: Rusty Russell <rusty@rustcorp.com.au>
2024-10-15 09:58:04 +10:30
Rusty Russell
08df93cb25 askrene: fix base fee.
I noticed this in the logs:

	plugin-cln-askrene: notify msg unusual: The flows had a fee of 151950msat, greater than max of 53697msat, retrying with mu of 10%...
	plugin-cln-askrene: notify msg unusual: The flows had a fee of 220126msat, greater than max of 53697msat, retrying with mu of 20%...

We would expect increasing mu to *reduce* the fee!

Turns out that our linear fee is a bad terrible approximation, because I
was using base_fee_penalty of 10.0.

 |
 |          /   __ <- real fee, with base: fee = base + propfee * amount.
 |         / __/
 |       _//
 |    __/
 | __/_/
 |/  _/
 | _/ <- linearized fee: fee = linear * amount
 |/
 +-----------------------------------

These cross over where linear = propfee + base / amount.  Assume we split the
payment into 10 parts, this implies that the base_fee_penalty should be 10 / amount
(this gives a slight penalty to the normal case, but that's ok).

This gives better results, too: we get down to 650099 sats in fees, vs 801613
before.

Signed-off-by: Rusty Russell <rusty@rustcorp.com.au>
2024-10-15 09:58:04 +10:30
Rusty Russell
6273adbe47 askrene: calculate prob_cost_factor using ratio of typical mainnet channel.
During "test_real_data", then only successes with reduced fees were 92 on "mu=10", and only
1 on "mu=30": the rest went to mu=100 and failed.

I tried numerous approaches, and in the end, opted for the simplest:

The typical range of probability costs looks likes:
	min = 0, max = 924196240, mean = 10509.4, stddev = 1.9e+06

The typical range of linear fee costs looks like:
	min = 0, max = 101000000, mean = 81894.6, stddev = 2.6e+06

This implies a k factor of 8 makes the two comparable.

This makes the two numbers comparable, and thus makes "mu" much more
effective.  Here are the number of different mu values we succeeded at:

     87  mu=0
     90  mu=10
     42  mu=20
     24  mu=30
     17  mu=40
     19  mu=50
     19  mu=60
     11  mu=70
     95  mu=80
     19  mu=90

Signed-off-by: Rusty Russell <rusty@rustcorp.com.au>
2024-10-15 09:58:04 +10:30
Rusty Russell
b1817b6c52 askrene: include the mcf and flow routines.
This make the code use askrene's "struct route_query".

Signed-off-by: Rusty Russell <rusty@rustcorp.com.au>
2024-08-07 20:35:30 +09:30
Rusty Russell
d109fcb568 askrene: simplify minflow()
We let the caller choose mu, and iterate if necessary: it can also
check its limits for fees, etc.  Rationalize it to 0-100 inclusive for
human consumption.

This means we don't loop internally, and in fact there's only one
failure mode: we cannot find enough capacity.

Signed-off-by: Rusty Russell <rusty@rustcorp.com.au>
2024-08-07 20:35:30 +09:30
Rusty Russell
5999467dce askrene: copy mcf.[ch] from renepay with minimal modifications.
Signed-off-by: Rusty Russell <rusty@rustcorp.com.au>
2024-08-07 20:35:30 +09:30