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pytest: Stabilize test_penalty_htlc_tx_timeout
We weren't waiting for the transactions to enter the mempool which could cause all of our fine-tuned block counts to be off. Now just waiting for the expected number of txs.
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@ -984,12 +984,12 @@ def test_penalty_htlc_tx_timeout(node_factory, bitcoind, chainparams):
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l2.daemon.wait_for_log('Propose handling OUR_HTLC_SUCCESS_TX/DELAYED_OUTPUT_TO_US by OUR_DELAYED_RETURN_TO_WALLET .* after 5 blocks')
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# after 5 blocks, l2 reclaims both their DELAYED_OUTPUT_TO_US and their delayed output
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bitcoind.generate_block(5)
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bitcoind.generate_block(5, wait_for_mempool=0)
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sync_blockheight(bitcoind, [l2])
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l2.daemon.wait_for_logs(['Broadcasting OUR_DELAYED_RETURN_TO_WALLET .* to resolve OUR_HTLC_SUCCESS_TX/DELAYED_OUTPUT_TO_US',
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'Broadcasting OUR_DELAYED_RETURN_TO_WALLET .* to resolve OUR_UNILATERAL/DELAYED_OUTPUT_TO_US'])
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bitcoind.generate_block(10)
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bitcoind.generate_block(10, wait_for_mempool=2)
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l2.wait_for_onchaind_broadcast('OUR_HTLC_TIMEOUT_TX',
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'OUR_UNILATERAL/OUR_HTLC')
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@ -1013,7 +1013,7 @@ def test_penalty_htlc_tx_timeout(node_factory, bitcoind, chainparams):
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'by THEIR_DELAYED_CHEAT',
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'Resolved THEIR_REVOKED_UNILATERAL/THEIR_HTLC by THEIR_HTLC_TIMEOUT_TO_THEM',
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'Propose handling THEIR_HTLC_TIMEOUT_TO_THEM/DELAYED_CHEAT_OUTPUT_TO_THEM by OUR_PENALTY_TX'])
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bitcoind.generate_block(1)
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bitcoind.generate_block(1, wait_for_mempool=2) # OUR_PENALTY_TX + OUR_HTLC_TIMEOUT_TO_US
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l3.daemon.wait_for_log('Resolved THEIR_HTLC_TIMEOUT_TO_THEM/DELAYED_CHEAT_OUTPUT_TO_THEM '
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'by our proposal OUR_PENALTY_TX')
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l2.daemon.wait_for_log('Unknown spend of OUR_HTLC_TIMEOUT_TX/DELAYED_OUTPUT_TO_US')
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