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pytest: fix flake in test_sendpay_grouping
Now pay learns, it sometimes learns not to try again: ``` > assert(len(l1.rpc.listpays()['pays']) == 2) E AssertionError: assert 1 == 2 E + where 1 = len([{'amount_sent_msat': 0, 'bolt11': 'lnbcrt1pnjj7mysp5tfx8n6nyx7ehszgqn7gqm2r6n079p22u2yddtg797ka3pa9557tspp5f89z6genjqrl3knymvav9ajwcxrm5w7arxux06rrhjux88derjyqdq8v3jhxccxqyjw5qcqp9rzjqgkjyd3q5dv6gllh77kygly9c3kfy0d9xwyjyxsq2nq3c83u5vw4jqqqvuqqqqsqqqqqqqqpqqqqqzsqqc9qxpqysgqcuyr7qlyctf9w96fqg4wetqt7t5v938dagmv0r777n902utjufujzjxl3289r97yngft966zly3ehxfp469dh3lq0hkv6r684snvunqppuyvsl', 'created_at': 1730771812, 'destination': '035d2b1192dfba134e10e540875d366ebc8bc353d5aa766b80c090b39c3a5d885d', ...}]) tests/test_pay.py:5147: AssertionError ``` We fix this by creating a fresh channel, so it will try. Signed-off-by: Rusty Russell <rusty@rustcorp.com.au>
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@ -5134,13 +5134,19 @@ def test_sendpay_grouping(node_factory, bitcoind):
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assert(len(l1.db.query("SELECT * FROM payments")) == 0)
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assert(len(l1.rpc.listpays()['pays']) == 0)
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with pytest.raises(RpcError, match=r'Ran out of routes to try after [0-9]+ attempts'):
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with pytest.raises(RpcError, match=r'Ran out of routes to try after [1-9]+ attempts'):
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l1.rpc.pay(inv, amount_msat='100002msat')
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# After this one invocation we have one entry in `listpays`
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assert(len(l1.rpc.listpays()['pays']) == 1)
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with pytest.raises(RpcError, match=r'Ran out of routes to try after [0-9]+ attempts'):
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# Pay learns, and sometimes now refuses to even attempt. Give it a new channel.
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l3.start()
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node_factory.join_nodes([l2, l3], wait_for_announce=True)
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wait_for(lambda: len(l1.rpc.listchannels()['channels']) == 6)
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l3.stop()
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with pytest.raises(RpcError, match=r'Ran out of routes to try after [1-9]+ attempts'):
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l1.rpc.pay(inv, amount_msat='100001msat')
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# Surprise: we should have 2 entries after 2 invocations
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