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tests/test_gossip.py: Add test to check that duplicated exclusions in getroute have no lasting effect.

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ZmnSCPxj 2019-08-02 09:45:35 +00:00 • committed by Christian Decker
parent 359433f374
commit a5fb37298c
1 changed files with 25 additions and 0 deletions
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25
tests/test_gossip.py
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@ -1057,6 +1057,31 @@ def test_gossip_notices_close(node_factory, bitcoind):
assert(l1.rpc.listnodes()['nodes'] == [])
@pytest.mark.xfail(strict=True)
def test_getroute_exclude_duplicate(node_factory):
"""Test that accidentally duplicating the same channel in
the exclude list will not have permanent effects.
"""
l1, l2 = node_factory.line_graph(2, wait_for_announce=True)
# Starting route
route = l1.rpc.getroute(l2.info['id'], 1, 1)['route']
# l1 id is > l2 id, so 1 means l1->l2
chan_l1l2 = route[0]['channel'] + '/1'
# This should fail to find a route as the only viable channel
# is excluded, and worse, is excluded twice.
with pytest.raises(RpcError):
l1.rpc.getroute(l2.info['id'], 1, 1, exclude=[chan_l1l2, chan_l1l2])
# This should still succeed since nothing is excluded anymore
# and in particular should return the exact same route as
# earlier.
route2 = l1.rpc.getroute(l2.info['id'], 1, 1)['route']
assert route == route2
@unittest.skipIf(not DEVELOPER, "gossip propagation is slow without DEVELOPER=1")
def test_getroute_exclude(node_factory, bitcoind):
"""Test getroute's exclude argument"""