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pytest: remove old test_tlv_or_legacy

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We no longer support legacy at all, so this test doesn't really
test anything.

Signed-off-by: Rusty Russell <rusty@rustcorp.com.au>
This commit is contained in:
Rusty Russell 2023-10-02 14:22:57 +10:30
parent 7d3f13ec0d
commit 7bb6609f9a
1 changed files with 0 additions and 42 deletions
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42
tests/test_pay.py
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@ -2745,48 +2745,6 @@ def test_error_returns_blockheight(node_factory, bitcoind):
== '400f{:016x}{:08x}'.format(100, bitcoind.rpc.getblockcount()))
def test_tlv_or_legacy(node_factory, bitcoind):
# Ideally we'd test with l2 NOT var-onion, but then it can no longer connect
# to us!
l1, l2, l3 = node_factory.line_graph(3,
opts={'plugin': os.path.join(os.getcwd(), 'tests/plugins/print_htlc_onion.py')})
scid12 = l1.get_channel_scid(l2)
scid23 = l2.get_channel_scid(l3)
# We need to force l3 to provide route hint from l2 (it won't normally,
# since it sees l2 as a dead end).
inv = l3.dev_invoice(amount_msat=10000,
label="test_tlv1",
description="test_tlv1",
dev_routes=[[{'id': l2.info['id'],
'short_channel_id': scid23,
'fee_base_msat': 1,
'fee_proportional_millionths': 10,
'cltv_expiry_delta': 6}]])['bolt11']
l1.rpc.pay(inv)
# Since L1 hasn't seen broadcast, it doesn't know L2 isn't TLV, but invoice tells it about L3
l2.daemon.wait_for_log("Got onion.*'type': 'tlv'")
l3.daemon.wait_for_log("Got onion.*'type': 'tlv'")
# We need 5 more blocks to announce l1->l2 channel.
mine_funding_to_announce(bitcoind, [l1, l2, l3])
# Make sure l1 knows about l2
wait_for(lambda: 'alias' in l1.rpc.listnodes(l2.info['id'])['nodes'][0])
# Make sure l3 knows about l1->l2, so it will add route hint now.
wait_for(lambda: len(l3.rpc.listchannels(scid12)['channels']) > 0)
# Now it should send TLV to l2.
inv = l3.rpc.invoice(10000, "test_tlv2", "test_tlv2")['bolt11']
l1.rpc.pay(inv)
l2.daemon.wait_for_log("Got onion.*'type': 'tlv'")
l3.daemon.wait_for_log("Got onion.*'type': 'tlv'")
@unittest.skipIf(TEST_NETWORK != 'regtest', "Invoice is network specific")
def test_pay_no_secret(node_factory, bitcoind):
l1, l2 = node_factory.line_graph(2, wait_for_announce=True)