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pytest: test for bad 'tx' result from close.

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We print it without the witness!

Reported-by: https://github.com/wtogami
Signed-off-by: Rusty Russell <rusty@rustcorp.com.au>
This commit is contained in:
Rusty Russell 2023-07-31 21:01:22 +09:30
parent aa2f4a1fa0
commit 673d81adde
1 changed files with 29 additions and 0 deletions
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29
tests/test_closing.py
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@ -3870,3 +3870,32 @@ def test_htlc_no_force_close(node_factory, bitcoind, anchors):
sync_blockheight(bitcoind, [l1, l2, l3])
# FIXME: l2 should complain!
@pytest.mark.xfail(strict=True)
@pytest.mark.developer("needs dev-no-reconnect")
def test_closing_tx_valid(node_factory, bitcoind):
l1, l2 = node_factory.line_graph(2, opts={'may_reconnect': True,
'dev-no-reconnect': None})
# First, mutual close.
close = l1.rpc.close(l2.info['id'])
wait_for(lambda: len(bitcoind.rpc.getrawmempool()) == 1)
assert only_one(bitcoind.rpc.getrawmempool()) == close['txid']
assert bitcoind.rpc.getrawtransaction(close['txid']) == close['tx']
bitcoind.generate_block(1)
# Change output and the closed channel output.
wait_for(lambda: len(l1.rpc.listfunds()['outputs']) == 2)
# Now, unilateral close.
l1.rpc.connect(l2.info['id'], 'localhost', l2.port)
l1.rpc.fundchannel(l2.info['id'], 10**6)
bitcoind.generate_block(1, wait_for_mempool=1)
l1.rpc.disconnect(l2.info['id'], force=True)
close = l1.rpc.close(l2.info['id'], 1)
wait_for(lambda: len(bitcoind.rpc.getrawmempool()) == 1)
assert only_one(bitcoind.rpc.getrawmempool()) == close['txid']
assert bitcoind.rpc.getrawtransaction(close['txid']) == close['tx']