pytest: fix flake in test_onchain_different_fees

Sometimes, we haven't reconnected, and so the peer does not exist at all after
the channel is forgotten:

```
2022-09-22T22:49:59.3985374Z         # Now, 100 blocks it should be done.
2022-09-22T22:49:59.3985656Z         bitcoind.generate_block(100)
2022-09-22T22:49:59.3986112Z >       wait_for(lambda: only_one(l1.rpc.listpeers()['peers'])['channels'] == [])
2022-09-22T22:49:59.3986338Z 
2022-09-22T22:49:59.3986523Z tests/test_closing.py:2715: 
2022-09-22T22:49:59.3986810Z _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ 
2022-09-22T22:49:59.3987241Z contrib/pyln-testing/pyln/testing/utils.py:90: in wait_for
2022-09-22T22:49:59.3987568Z     while not success():
2022-09-22T22:49:59.3987917Z tests/test_closing.py:2715: in <lambda>
2022-09-22T22:49:59.3988389Z     wait_for(lambda: only_one(l1.rpc.listpeers()['peers'])['channels'] == [])
2022-09-22T22:49:59.3988737Z _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ 
2022-09-22T22:49:59.3988908Z 
2022-09-22T22:49:59.3988979Z arr = []
2022-09-22T22:49:59.3989106Z 
2022-09-22T22:49:59.3989209Z     def only_one(arr):
2022-09-22T22:49:59.3989545Z         """Many JSON RPC calls return an array; often we only expect a single entry
2022-09-22T22:49:59.3989849Z         """
2022-09-22T22:49:59.3990063Z >       assert len(arr) == 1
2022-09-22T22:49:59.3990388Z E       AssertionError
```

You can see it's empty from the call here:

```
2022-09-22T22:49:59.6697941Z DEBUG:root:{
2022-09-22T22:49:59.6698106Z   "id": "-c:listpeers#42",
2022-09-22T22:49:59.6698179Z   "result": {
2022-09-22T22:49:59.6698270Z     "peers": []
2022-09-22T22:49:59.6698346Z   }
2022-09-22T22:49:59.6698422Z }
```

Signed-off-by: Rusty Russell <rusty@rustcorp.com.au>
This commit is contained in:
Rusty Russell 2022-09-23 14:32:30 +09:30 committed by neil saitug
parent 9b5bc81541
commit 57002f3381

View file

@ -2712,8 +2712,10 @@ def test_onchain_different_fees(node_factory, bitcoind, executor):
# Now, 100 blocks it should be done.
bitcoind.generate_block(100)
wait_for(lambda: only_one(l1.rpc.listpeers()['peers'])['channels'] == [])
wait_for(lambda: only_one(l2.rpc.listpeers()['peers'])['channels'] == [])
# May reconnect, may not: if not, peer does not exist!
wait_for(lambda: all(p['channels'] == [] for p in l1.rpc.listpeers()['peers']))
wait_for(lambda: all(p['channels'] == [] for p in l2.rpc.listpeers()['peers']))
@pytest.mark.developer("needs DEVELOPER=1")