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pytest: add test for HTLC timeout on failed htlcs.

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Signed-off-by: Rusty Russell <rusty@rustcorp.com.au>
This commit is contained in:
Rusty Russell 2021-05-21 10:06:12 +09:30
parent 0d68febd8d
commit 11180e7aa1
1 changed files with 28 additions and 1 deletions
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29
tests/test_connection.py
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@ -11,7 +11,7 @@ from utils import (
scriptpubkey_addr,
EXPERIMENTAL_FEATURES
)
from pyln.testing.utils import SLOW_MACHINE, VALGRIND, EXPERIMENTAL_DUAL_FUND
from pyln.testing.utils import SLOW_MACHINE, VALGRIND, EXPERIMENTAL_DUAL_FUND, FUNDAMOUNT
import os
import pytest
@ -3284,3 +3284,30 @@ def test_openchannel_init_alternate(node_factory, executor):
fut = executor.submit(l2.rpc.openchannel_init, l1.info['id'], '1000000msat', psbt2)
with pytest.raises(RpcError):
fut.result(10)
@pytest.mark.xfail(strict=True)
def test_htlc_failed_noclose(node_factory):
"""Test a bug where the htlc timeout would kick in even if the HTLC failed"""
l1, l2 = node_factory.line_graph(2)
payment_hash = l2.rpc.invoice(1000, "test", "test")['payment_hash']
routestep = {
'msatoshi': FUNDAMOUNT * 1000,
'id': l2.info['id'],
'delay': 5,
'channel': '1x1x1' # note: can be bogus for 1-hop direct payments
}
# This fails at channeld
l1.rpc.sendpay([routestep], payment_hash)
with pytest.raises(RpcError, match="Capacity exceeded"):
l1.rpc.waitsendpay(payment_hash)
# Send a second one, too: make sure we don't crash.
l1.rpc.sendpay([routestep], payment_hash)
with pytest.raises(RpcError, match="Capacity exceeded"):
l1.rpc.waitsendpay(payment_hash)
time.sleep(35)
assert l1.rpc.getpeer(l2.info['id'])['connected']