core-lightning/tests/test_wallet.py

from decimal import Decimal
from fixtures import *  # noqa: F401,F403
from fixtures import TEST_NETWORK
from flaky import flaky  # noqa: F401
from pyln.client import RpcError, Millisatoshi
from utils import (
    only_one, wait_for, sync_blockheight, EXPERIMENTAL_FEATURES, COMPAT,
    VALGRIND
)

import os
import pytest
import subprocess
import time
import unittest


@unittest.skipIf(TEST_NETWORK != 'regtest', "Test relies on a number of example addresses valid only in regtest")
def test_withdraw(node_factory, bitcoind):
    amount = 1000000
    # Don't get any funds from previous runs.
    l1 = node_factory.get_node(random_hsm=True)
    l2 = node_factory.get_node(random_hsm=True)
    addr = l1.rpc.newaddr()['bech32']

    # Add some funds to withdraw later
    for i in range(10):
        l1.bitcoin.rpc.sendtoaddress(addr, amount / 10**8 + 0.01)

    bitcoind.generate_block(1)
    wait_for(lambda: len(l1.rpc.listfunds()['outputs']) == 10)

    # Reach around into the db to check that outputs were added
    assert l1.db_query('SELECT COUNT(*) as c FROM outputs WHERE status=0')[0]['c'] == 10

    waddr = l1.bitcoin.rpc.getnewaddress()
    # Now attempt to withdraw some (making sure we collect multiple inputs)
    with pytest.raises(RpcError):
        l1.rpc.withdraw('not an address', amount)
    with pytest.raises(RpcError):
        l1.rpc.withdraw(waddr, 'not an amount')
    with pytest.raises(RpcError):
        l1.rpc.withdraw(waddr, -amount)
    with pytest.raises(RpcError, match=r'Cannot afford transaction'):
        l1.rpc.withdraw(waddr, amount * 100)

    out = l1.rpc.withdraw(waddr, 2 * amount)

    # Make sure bitcoind received the withdrawal
    unspent = l1.bitcoin.rpc.listunspent(0)
    withdrawal = [u for u in unspent if u['txid'] == out['txid']]

    assert(withdrawal[0]['amount'] == Decimal('0.02'))

    l1.bitcoin.generate_block(1)
    sync_blockheight(l1.bitcoin, [l1])

    # Check that there are no unconfirmed outputs (change should be confirmed)
    for o in l1.rpc.listfunds()['outputs']:
        assert o['status'] == 'confirmed'

    # Now make sure two of them were marked as spent
    assert l1.db_query('SELECT COUNT(*) as c FROM outputs WHERE status=2')[0]['c'] == 2

    # Now send some money to l2.
    # lightningd uses P2SH-P2WPKH
    waddr = l2.rpc.newaddr('bech32')['bech32']
    l1.rpc.withdraw(waddr, 2 * amount)
    bitcoind.generate_block(1)

    # Make sure l2 received the withdrawal.
    wait_for(lambda: len(l2.rpc.listfunds()['outputs']) == 1)
    outputs = l2.db_query('SELECT value FROM outputs WHERE status=0;')
    assert only_one(outputs)['value'] == 2 * amount

    # Now make sure an additional two of them were marked as spent
    assert l1.db_query('SELECT COUNT(*) as c FROM outputs WHERE status=2')[0]['c'] == 4

    # Simple test for withdrawal to P2WPKH
    # Address from: https://bc-2.jp/tools/bech32demo/index.html
    waddr = 'bcrt1qw508d6qejxtdg4y5r3zarvary0c5xw7kygt080'
    with pytest.raises(RpcError):
        l1.rpc.withdraw('xx1qw508d6qejxtdg4y5r3zarvary0c5xw7kxpjzsx', 2 * amount)
    with pytest.raises(RpcError):
        l1.rpc.withdraw('tb1pw508d6qejxtdg4y5r3zarvary0c5xw7kdl9fad', 2 * amount)
    with pytest.raises(RpcError):
        l1.rpc.withdraw('tb1qw508d6qejxtdg4y5r3zarvary0c5xw7kxxxxxx', 2 * amount)
    l1.rpc.withdraw(waddr, 2 * amount)
    bitcoind.generate_block(1)
    # Now make sure additional two of them were marked as spent
    assert l1.db_query('SELECT COUNT(*) as c FROM outputs WHERE status=2')[0]['c'] == 6

    # Simple test for withdrawal to P2WSH
    # Address from: https://bc-2.jp/tools/bech32demo/index.html
    waddr = 'bcrt1qrp33g0q5c5txsp9arysrx4k6zdkfs4nce4xj0gdcccefvpysxf3qzf4jry'
    with pytest.raises(RpcError):
        l1.rpc.withdraw('xx1qrp33g0q5c5txsp9arysrx4k6zdkfs4nce4xj0gdcccefvpysxf3q0sl5k7', 2 * amount)
    with pytest.raises(RpcError):
        l1.rpc.withdraw('tb1prp33g0q5c5txsp9arysrx4k6zdkfs4nce4xj0gdcccefvpysxf3qsm03tq', 2 * amount)
    with pytest.raises(RpcError):
        l1.rpc.withdraw('tb1qrp33g0q5c5txsp9arysrx4k6zdkfs4nce4xj0gdcccefvpysxf3qxxxxxx', 2 * amount)
    l1.rpc.withdraw(waddr, 2 * amount)
    bitcoind.generate_block(1)
    # Now make sure additional two of them were marked as spent
    assert l1.db_query('SELECT COUNT(*) as c FROM outputs WHERE status=2')[0]['c'] == 8

    # failure testing for invalid SegWit addresses, from BIP173
    # HRP character out of range
    with pytest.raises(RpcError):
        l1.rpc.withdraw(' 1nwldj5', 2 * amount)
    # overall max length exceeded
    with pytest.raises(RpcError):
        l1.rpc.withdraw('an84characterslonghumanreadablepartthatcontainsthenumber1andtheexcludedcharactersbio1569pvx', 2 * amount)
    # No separator character
    with pytest.raises(RpcError):
        l1.rpc.withdraw('pzry9x0s0muk', 2 * amount)
    # Empty HRP
    with pytest.raises(RpcError):
        l1.rpc.withdraw('1pzry9x0s0muk', 2 * amount)
    # Invalid witness version
    with pytest.raises(RpcError):
        l1.rpc.withdraw('BC13W508D6QEJXTDG4Y5R3ZARVARY0C5XW7KN40WF2', 2 * amount)
    # Invalid program length for witness version 0 (per BIP141)
    with pytest.raises(RpcError):
        l1.rpc.withdraw('BC1QR508D6QEJXTDG4Y5R3ZARVARYV98GJ9P', 2 * amount)
    # Mixed case
    with pytest.raises(RpcError):
        l1.rpc.withdraw('tb1qrp33g0q5c5txsp9arysrx4k6zdkfs4nce4xj0gdcccefvpysxf3q0sL5k7', 2 * amount)
    # Non-zero padding in 8-to-5 conversion
    with pytest.raises(RpcError):
        l1.rpc.withdraw('tb1qrp33g0q5c5txsp9arysrx4k6zdkfs4nce4xj0gdcccefvpysxf3pjxtptv', 2 * amount)

    # Should have 6 outputs available.
    assert l1.db_query('SELECT COUNT(*) as c FROM outputs WHERE status=0')[0]['c'] == 6

    # Test withdrawal to self.
    l1.rpc.withdraw(l1.rpc.newaddr('bech32')['bech32'], 'all', minconf=0)
    bitcoind.generate_block(1)
    assert l1.db_query('SELECT COUNT(*) as c FROM outputs WHERE status=0')[0]['c'] == 1

    l1.rpc.withdraw(waddr, 'all', minconf=0)
    assert l1.db_query('SELECT COUNT(*) as c FROM outputs WHERE status=0')[0]['c'] == 0

    # This should fail, can't even afford fee.
    with pytest.raises(RpcError, match=r'Cannot afford transaction'):
        l1.rpc.withdraw(waddr, 'all')

    # Add some funds to withdraw
    for i in range(10):
        l1.bitcoin.rpc.sendtoaddress(addr, amount / 10**8 + 0.01)

    bitcoind.generate_block(1)
    wait_for(lambda: len(l1.rpc.listfunds()['outputs']) == 10)

    # Try passing in a utxo set
    utxos = [utxo["txid"] + ":" + str(utxo["output"]) for utxo in l1.rpc.listfunds()["outputs"]][:4]

    withdrawal = l1.rpc.withdraw(waddr, 2 * amount, utxos=utxos)
    decode = bitcoind.rpc.decoderawtransaction(withdrawal['tx'])
    assert decode['txid'] == withdrawal['txid']

    # Check that correct utxos are included
    assert len(decode['vin']) == 4
    vins = ["{}:{}".format(v['txid'], v['vout']) for v in decode['vin']]
    for utxo in utxos:
        assert utxo in vins


def test_minconf_withdraw(node_factory, bitcoind):
    """Issue 2518: ensure that ridiculous confirmation levels don't overflow

    The number of confirmations is used to compute a maximum height that is to
    be accepted. If the current height is smaller than the number of
    confirmations we wrap around and just select everything. The fix is to
    clamp the maxheight parameter to a positive small number.

    """
    amount = 1000000
    # Don't get any funds from previous runs.
    l1 = node_factory.get_node(random_hsm=True)
    addr = l1.rpc.newaddr()['bech32']

    # Add some funds to withdraw later
    for i in range(10):
        l1.bitcoin.rpc.sendtoaddress(addr, amount / 10**8 + 0.01)

    bitcoind.generate_block(1)

    wait_for(lambda: len(l1.rpc.listfunds()['outputs']) == 10)
    with pytest.raises(RpcError):
        l1.rpc.withdraw(destination=addr, satoshi=10000, feerate='normal', minconf=9999999)


def test_addfunds_from_block(node_factory, bitcoind):
    """Send funds to the daemon without telling it explicitly
    """
    # Previous runs with same bitcoind can leave funds!
    l1 = node_factory.get_node(random_hsm=True)

    addr = l1.rpc.newaddr()['bech32']
    bitcoind.rpc.sendtoaddress(addr, 0.1)
    bitcoind.generate_block(1)

    wait_for(lambda: len(l1.rpc.listfunds()['outputs']) == 1)

    outputs = l1.db_query('SELECT value FROM outputs WHERE status=0;')
    assert only_one(outputs)['value'] == 10000000

    # The address we detect must match what was paid to.
    output = only_one(l1.rpc.listfunds()['outputs'])
    assert output['address'] == addr

    # Send all our money to a P2WPKH address this time.
    addr = l1.rpc.newaddr("bech32")['bech32']
    l1.rpc.withdraw(addr, "all")
    bitcoind.generate_block(1)
    time.sleep(1)

    # The address we detect must match what was paid to.
    output = only_one(l1.rpc.listfunds()['outputs'])
    assert output['address'] == addr


@unittest.skipIf(not COMPAT, "needs COMPAT=1")
def test_deprecated_txprepare(node_factory, bitcoind):
    """Test the deprecated old-style:
       txprepare {destination} {satoshi} {feerate} {minconf}
    """
    amount = 10**4
    l1 = node_factory.get_node(options={'allow-deprecated-apis': True})
    addr = l1.rpc.newaddr()['bech32']

    for i in range(7):
        l1.fundwallet(10**8)

    bitcoind.generate_block(1)
    sync_blockheight(bitcoind, [l1])

    wait_for(lambda: len(l1.rpc.listfunds()['outputs']) == 7)

    # Array type
    with pytest.raises(RpcError, match=r'.* should be an amount in satoshis or all, not .*'):
        l1.rpc.call('txprepare', [addr, 'slow'])

    with pytest.raises(RpcError, match=r'Need set \'satoshi\' field.'):
        l1.rpc.call('txprepare', [addr])

    with pytest.raises(RpcError, match=r'Could not parse destination address.*'):
        l1.rpc.call('txprepare', [Millisatoshi(amount * 100), 'slow', 1])

    l1.rpc.call('txprepare', [addr, Millisatoshi(amount * 100), 'slow', 1])
    l1.rpc.call('txprepare', [addr, Millisatoshi(amount * 100), 'normal'])
    l1.rpc.call('txprepare', [addr, Millisatoshi(amount * 100), None, 1])
    l1.rpc.call('txprepare', [addr, Millisatoshi(amount * 100)])

    # Object type
    with pytest.raises(RpcError, match=r'Need set \'outputs\' field.'):
        l1.rpc.call('txprepare', {'destination': addr, 'feerate': 'slow'})

    with pytest.raises(RpcError, match=r'Need set \'outputs\' field.'):
        l1.rpc.call('txprepare', {'satoshi': Millisatoshi(amount * 100), 'feerate': '10perkw', 'minconf': 2})

    l1.rpc.call('txprepare', {'destination': addr, 'satoshi': Millisatoshi(amount * 100), 'feerate': '2000perkw', 'minconf': 1})
    l1.rpc.call('txprepare', {'destination': addr, 'satoshi': Millisatoshi(amount * 100), 'feerate': '2000perkw'})
    l1.rpc.call('txprepare', {'destination': addr, 'satoshi': Millisatoshi(amount * 100)})


def test_txprepare_multi(node_factory, bitcoind):
    amount = 10000000
    l1 = node_factory.get_node(random_hsm=True)

    bitcoind.rpc.sendtoaddress(l1.rpc.newaddr()['bech32'], amount / 10**8)
    bitcoind.generate_block(1)
    wait_for(lambda: len(l1.rpc.listfunds()['outputs']) == 1)

    outputs = []
    for i in range(9):
        outputs.append({l1.rpc.newaddr()['bech32']: Millisatoshi(amount * 100)})
    prep = l1.rpc.txprepare(outputs=outputs)
    l1.rpc.txdiscard(prep['txid'])


@pytest.mark.xfail(strict=True)
def test_txprepare(node_factory, bitcoind, chainparams):
    amount = 1000000
    l1 = node_factory.get_node(random_hsm=True)
    addr = chainparams['example_addr']

    # Add some funds to withdraw later: both bech32 and p2sh
    for i in range(5):
        bitcoind.rpc.sendtoaddress(l1.rpc.newaddr()['bech32'],
                                   amount / 10**8)
        bitcoind.rpc.sendtoaddress(l1.rpc.newaddr('p2sh-segwit')['p2sh-segwit'],
                                   amount / 10**8)

    bitcoind.generate_block(1)
    wait_for(lambda: len(l1.rpc.listfunds()['outputs']) == 10)

    prep = l1.rpc.txprepare(outputs=[{addr: Millisatoshi(amount * 3 * 1000)}])
    decode = bitcoind.rpc.decoderawtransaction(prep['unsigned_tx'])
    assert decode['txid'] == prep['txid']
    # 4 inputs, 2 outputs (3 if we have a fee output).
    assert len(decode['vin']) == 4
    assert len(decode['vout']) == 2 if not chainparams['feeoutput'] else 3

    # One output will be correct.
    outnum = [i for i, o in enumerate(decode['vout']) if o['value'] == Decimal(amount * 3) / 10**8][0]

    for i, o in enumerate(decode['vout']):
        if i == outnum:
            assert o['scriptPubKey']['type'] == 'witness_v0_keyhash'
            assert o['scriptPubKey']['addresses'] == [addr]
        else:
            assert o['scriptPubKey']['type'] in ['witness_v0_keyhash', 'fee']

    # Now prepare one with no change.
    prep2 = l1.rpc.txprepare([{addr: 'all'}])
    decode = bitcoind.rpc.decoderawtransaction(prep2['unsigned_tx'])
    assert decode['txid'] == prep2['txid']
    # 6 inputs, 1 outputs.
    assert len(decode['vin']) == 6
    assert len(decode['vout']) == 1 if not chainparams['feeoutput'] else 2

    # Some fees will be paid.
    assert decode['vout'][0]['value'] < Decimal(amount * 6) / 10**8
    assert decode['vout'][0]['value'] > Decimal(amount * 6) / 10**8 - Decimal(0.0002)
    assert decode['vout'][0]['scriptPubKey']['type'] == 'witness_v0_keyhash'
    assert decode['vout'][0]['scriptPubKey']['addresses'] == [addr]

    # If I cancel the first one, I can get those first 4 outputs.
    discard = l1.rpc.txdiscard(prep['txid'])
    assert discard['txid'] == prep['txid']
    assert discard['unsigned_tx'] == prep['unsigned_tx']

    prep3 = l1.rpc.txprepare([{addr: 'all'}])
    decode = bitcoind.rpc.decoderawtransaction(prep3['unsigned_tx'])
    assert decode['txid'] == prep3['txid']
    # 4 inputs, 1 outputs.
    assert len(decode['vin']) == 4
    assert len(decode['vout']) == 1 if not chainparams['feeoutput'] else 2

    # Some fees will be taken
    assert decode['vout'][0]['value'] < Decimal(amount * 4) / 10**8
    assert decode['vout'][0]['value'] > Decimal(amount * 4) / 10**8 - Decimal(0.0002)
    assert decode['vout'][0]['scriptPubKey']['type'] == 'witness_v0_keyhash'
    assert decode['vout'][0]['scriptPubKey']['addresses'] == [addr]

    # Cannot discard twice.
    with pytest.raises(RpcError, match=r'not an unreleased txid'):
        l1.rpc.txdiscard(prep['txid'])

    # Discard everything, we should now spend all inputs.
    l1.rpc.txdiscard(prep2['txid'])
    l1.rpc.txdiscard(prep3['txid'])
    prep4 = l1.rpc.txprepare([{addr: 'all'}])
    decode = bitcoind.rpc.decoderawtransaction(prep4['unsigned_tx'])
    assert decode['txid'] == prep4['txid']
    # 10 inputs, 1 outputs.
    assert len(decode['vin']) == 10
    assert len(decode['vout']) == 1 if not chainparams['feeoutput'] else 2

    # Some fees will be taken
    assert decode['vout'][0]['value'] < Decimal(amount * 10) / 10**8
    assert decode['vout'][0]['value'] > Decimal(amount * 10) / 10**8 - Decimal(0.0003)
    assert decode['vout'][0]['scriptPubKey']['type'] == 'witness_v0_keyhash'
    assert decode['vout'][0]['scriptPubKey']['addresses'] == [addr]
    l1.rpc.txdiscard(prep4['txid'])

    # Try passing in a utxo set
    utxos = [utxo["txid"] + ":" + str(utxo["output"])
             for utxo in l1.rpc.listfunds()["outputs"]][:4]
    prep5 = l1.rpc.txprepare([{addr:
                             Millisatoshi(amount * 3.5 * 1000)}], utxos=utxos)

    # Try passing unconfirmed utxos
    unconfirmed_utxo = l1.rpc.withdraw(l1.rpc.newaddr()["bech32"], 10**5)
    utxos = [unconfirmed_utxo["txid"] + ":0"]
    l1.rpc.txprepare([{addr: Millisatoshi(amount * 3.5 * 1000)}], utxos=utxos)

    decode = bitcoind.rpc.decoderawtransaction(prep5['unsigned_tx'])
    assert decode['txid'] == prep5['txid']

    # Check that correct utxos are included
    assert len(decode['vin']) == 4
    vins = ["{}:{}".format(v['txid'], v['vout']) for v in decode['vin']]
    for utxo in utxos:
        assert utxo in vins

    # We should have a change output, so this is exact
    assert len(decode['vout']) == 3 if chainparams['feeoutput'] else 2
    assert decode['vout'][1]['value'] == Decimal(amount * 3.5) / 10**8
    assert decode['vout'][1]['scriptPubKey']['type'] == 'witness_v0_keyhash'
    assert decode['vout'][1]['scriptPubKey']['addresses'] == [addr]

    # Discard prep4 and get all funds again
    l1.rpc.txdiscard(prep5['txid'])
    with pytest.raises(RpcError, match=r'this destination wants all satoshi. The count of outputs can\'t be more than 1'):
        prep5 = l1.rpc.txprepare([{addr: Millisatoshi(amount * 3 * 1000)},
                                  {addr: 'all'}])
    prep5 = l1.rpc.txprepare([{addr: Millisatoshi(amount * 3 * 500 + 100000)},
                              {addr: Millisatoshi(amount * 3 * 500 - 100000)}])
    decode = bitcoind.rpc.decoderawtransaction(prep5['unsigned_tx'])
    assert decode['txid'] == prep5['txid']
    # 4 inputs, 3 outputs(include change).
    assert len(decode['vin']) == 4
    assert len(decode['vout']) == 4 if chainparams['feeoutput'] else 3

    # One output will be correct.
    for i in range(3 + chainparams['feeoutput']):
        if decode['vout'][i - 1]['value'] == Decimal('0.01500100'):
            outnum1 = i - 1
        elif decode['vout'][i - 1]['value'] == Decimal('0.01499900'):
            outnum2 = i - 1
        else:
            changenum = i - 1

    assert decode['vout'][outnum1]['scriptPubKey']['type'] == 'witness_v0_keyhash'
    assert decode['vout'][outnum1]['scriptPubKey']['addresses'] == [addr]

    assert decode['vout'][outnum2]['scriptPubKey']['type'] == 'witness_v0_keyhash'
    assert decode['vout'][outnum2]['scriptPubKey']['addresses'] == [addr]

    assert decode['vout'][changenum]['scriptPubKey']['type'] == 'witness_v0_keyhash'


def test_txsend(node_factory, bitcoind, chainparams):
    amount = 1000000
    l1 = node_factory.get_node(random_hsm=True)
    addr = chainparams['example_addr']

    # Add some funds to withdraw later: both bech32 and p2sh
    for i in range(5):
        bitcoind.rpc.sendtoaddress(l1.rpc.newaddr()['bech32'],
                                   amount / 10**8)
        bitcoind.rpc.sendtoaddress(l1.rpc.newaddr('p2sh-segwit')['p2sh-segwit'],
                                   amount / 10**8)
    bitcoind.generate_block(1)
    wait_for(lambda: len(l1.rpc.listfunds()['outputs']) == 10)

    prep = l1.rpc.txprepare([{addr: Millisatoshi(amount * 3 * 1000)}])
    out = l1.rpc.txsend(prep['txid'])

    # Cannot discard after send!
    with pytest.raises(RpcError, match=r'not an unreleased txid'):
        l1.rpc.txdiscard(prep['txid'])

    wait_for(lambda: prep['txid'] in bitcoind.rpc.getrawmempool())

    # Signed tx should have same txid
    decode = bitcoind.rpc.decoderawtransaction(out['tx'])
    assert decode['txid'] == prep['txid']

    bitcoind.generate_block(1)

    # Change output should appear.
    if decode['vout'][0]['value'] == Decimal(amount * 3) / 10**8:
        changenum = 1
    elif decode['vout'][1]['value'] == Decimal(amount * 3) / 10**8:
        changenum = 0
    else:
        assert False

    # Those spent outputs are gone, but change output has arrived.
    wait_for(lambda: len(l1.rpc.listfunds()['outputs']) == 10 - len(decode['vin']) + 1)

    # Change address should appear in listfunds()
    assert decode['vout'][changenum]['scriptPubKey']['addresses'][0] in [f['address'] for f in l1.rpc.listfunds()['outputs']]


def test_txprepare_restart(node_factory, bitcoind, chainparams):
    amount = 1000000
    l1 = node_factory.get_node(may_fail=True)
    addr = chainparams['example_addr']

    # Add some funds to withdraw later: both bech32 and p2sh
    for i in range(5):
        bitcoind.rpc.sendtoaddress(l1.rpc.newaddr()['bech32'],
                                   amount / 10**8)
        bitcoind.rpc.sendtoaddress(l1.rpc.newaddr('p2sh-segwit')['p2sh-segwit'],
                                   amount / 10**8)
    bitcoind.generate_block(1)
    wait_for(lambda: [o['status'] for o in l1.rpc.listfunds()['outputs']] == ['confirmed'] * 10)

    prep = l1.rpc.txprepare([{addr: 'all'}])
    decode = bitcoind.rpc.decoderawtransaction(prep['unsigned_tx'])
    assert decode['txid'] == prep['txid']
    # All 10 inputs
    assert len(decode['vin']) == 10

    # L1 will forget all about it.
    l1.restart()

    # It goes backwards in blockchain just in case there was a reorg.  Wait.
    wait_for(lambda: [o['status'] for o in l1.rpc.listfunds()['outputs']] == ['confirmed'] * 10)

    with pytest.raises(RpcError, match=r'not an unreleased txid'):
        l1.rpc.txdiscard(prep['txid'])

    prep = l1.rpc.txprepare([{addr: 'all'}])

    decode = bitcoind.rpc.decoderawtransaction(prep['unsigned_tx'])
    assert decode['txid'] == prep['txid']
    # All 10 inputs
    assert len(decode['vin']) == 10

    # This will also work if we simply kill it.
    l1.restart(clean=False)

    # It goes backwards in blockchain just in case there was a reorg.  Wait.
    wait_for(lambda: [o['status'] for o in l1.rpc.listfunds()['outputs']] == ['confirmed'] * 10)

    # It should have logged this for each output.
    for i in decode['vin']:
        assert l1.daemon.is_in_log('wallet: reserved output {}/{} reset to available'.format(i['txid'], i['vout']))

    prep = l1.rpc.txprepare([{addr: 'all'}])
    decode = bitcoind.rpc.decoderawtransaction(prep['unsigned_tx'])
    assert decode['txid'] == prep['txid']
    # All 10 inputs
    assert len(decode['vin']) == 10


@unittest.skipIf(TEST_NETWORK != 'regtest', "Fee outputs throw off our output matching logic")
@unittest.skipIf(not EXPERIMENTAL_FEATURES, "Tests annotations which are compiled only with experimental features")
def test_transaction_annotations(node_factory, bitcoind):
    l1, l2, l3 = node_factory.get_nodes(3)
    l1.fundwallet(10**6)

    # We should now have a transaction that gave us the funds in the
    # transactions table...
    outputs = l1.rpc.listfunds()['outputs']
    assert(len(outputs) == 1 and outputs[0]['status'] == 'confirmed')
    out = outputs[0]
    idx = out['output']
    assert(idx in [0, 1] and out['value'] == 10**6)

    # ... and it should have an annotation on the output reading 'deposit'
    txs = l1.rpc.listtransactions()['transactions']
    assert(len(txs) == 1)
    tx = txs[0]
    output = tx['outputs'][idx]
    assert(output['type'] == 'deposit' and output['satoshis'] == '1000000000msat')

    # ... and all other output should be change, and have no annotations
    types = []
    for i, o in enumerate(tx['outputs']):
        if i == idx:
            continue
        if 'type' in o:
            types.append(o['type'])
        else:
            types.append(None)

    assert(set([None]) == set(types))

    ##########################################################################
    # Let's now open a channel. The opener should get the funding transaction
    # annotated as channel open and deposit.
    l1.connect(l2)
    fundingtx = l1.rpc.fundchannel(l2.info['id'], 10**5)

    # We should have one output available, and it should be unconfirmed
    outputs = l1.rpc.listfunds()['outputs']
    assert(len(outputs) == 1 and outputs[0]['status'] == 'unconfirmed')

    # It should also match the funding txid:
    assert(outputs[0]['txid'] == fundingtx['txid'])

    # Confirm the channel and check that the output changed to confirmed
    bitcoind.generate_block(3)
    sync_blockheight(bitcoind, [l1, l2])
    outputs = l1.rpc.listfunds()['outputs']
    assert(len(outputs) == 1 and outputs[0]['status'] == 'confirmed')

    # We should have 2 transactions, the second one should be the funding tx
    # (we are ordering by blockheight and txindex, so that order should be ok)
    txs = l1.rpc.listtransactions()['transactions']
    assert(len(txs) == 2 and txs[1]['hash'] == fundingtx['txid'])

    # Check the annotated types
    types = [o['type'] for o in txs[1]['outputs']]
    changeidx = 0 if types[0] == 'deposit' else 1
    fundidx = 1 - changeidx
    assert(types[changeidx] == 'deposit' and types[fundidx] == 'channel_funding')

    # And check the channel annotation on the funding output
    peers = l1.rpc.listpeers()['peers']
    assert(len(peers) == 1 and len(peers[0]['channels']) == 1)
    scid = peers[0]['channels'][0]['short_channel_id']
    assert(txs[1]['outputs'][fundidx]['channel'] == scid)


@unittest.skipIf(VALGRIND, "It does not play well with prompt and key derivation.")
def test_hsm_secret_encryption(node_factory):
    l1 = node_factory.get_node(may_fail=True)  # May fail when started without key
    password = "reckful\n"
    # We need to simulate a terminal to use termios in `lightningd`.
    master_fd, slave_fd = os.openpty()

    # Test we can encrypt an already-existing and not encrypted hsm_secret
    l1.stop()
    l1.daemon.opts.update({"encrypted-hsm": None})
    l1.daemon.start(stdin=slave_fd, wait_for_initialized=False)
    l1.daemon.wait_for_log(r'The hsm_secret is encrypted')

    os.write(master_fd, password.encode("utf-8"))
    l1.daemon.wait_for_log("Server started with public key")
    id = l1.rpc.getinfo()["id"]
    l1.stop()

    # Test we cannot start the same wallet without specifying --encrypted-hsm
    l1.daemon.opts.pop("encrypted-hsm")
    with pytest.raises(subprocess.CalledProcessError, match=r'returned non-zero exit status 1'):
        subprocess.check_call(l1.daemon.cmd_line)

    # Test we cannot restore the same wallet with another password
    l1.daemon.opts.update({"encrypted-hsm": None})
    l1.daemon.start(stdin=slave_fd, stderr=subprocess.STDOUT,
                    wait_for_initialized=False)
    l1.daemon.wait_for_log(r'The hsm_secret is encrypted')
    os.write(master_fd, password[2:].encode("utf-8"))
    assert(l1.daemon.proc.wait() == 1)
    assert(l1.daemon.is_in_log("Wrong password for encrypted hsm_secret."))

    # Test we can restore the same wallet with the same password
    l1.daemon.start(stdin=slave_fd, wait_for_initialized=False)
    l1.daemon.wait_for_log(r'The hsm_secret is encrypted')
    os.write(master_fd, password.encode("utf-8"))
    l1.daemon.wait_for_log("Server started with public key")
    assert id == l1.rpc.getinfo()["id"]


@unittest.skipIf(VALGRIND, "It does not play well with prompt and key derivation.")
def test_hsmtool_secret_decryption(node_factory):
    l1 = node_factory.get_node()
    password = "reckless\n"
    hsm_path = os.path.join(l1.daemon.lightning_dir, TEST_NETWORK, "hsm_secret")
    # We need to simulate a terminal to use termios in `lightningd`.
    master_fd, slave_fd = os.openpty()

    # Encrypt the master seed
    l1.stop()
    l1.daemon.opts.update({"encrypted-hsm": None})
    l1.daemon.start(stdin=slave_fd, wait_for_initialized=False)
    l1.daemon.wait_for_log(r'The hsm_secret is encrypted')
    os.write(master_fd, password.encode("utf-8"))
    l1.daemon.wait_for_log("Server started with public key")
    node_id = l1.rpc.getinfo()["id"]
    l1.stop()

    # We can't use a wrong password !
    cmd_line = ["tools/hsmtool", "decrypt", hsm_path, "A wrong pass"]
    with pytest.raises(subprocess.CalledProcessError):
        subprocess.check_call(cmd_line)

    # Decrypt it with hsmtool
    cmd_line[3] = password[:-1]
    subprocess.check_call(cmd_line)
    # Then test we can now start it without password
    l1.daemon.opts.pop("encrypted-hsm")
    l1.daemon.start(stdin=slave_fd, wait_for_initialized=True)
    assert node_id == l1.rpc.getinfo()["id"]
    l1.stop()

    # Test we can encrypt it offline
    cmd_line[1] = "encrypt"
    subprocess.check_call(cmd_line)
    # Now we need to pass the encrypted-hsm startup option
    l1.stop()

    with pytest.raises(subprocess.CalledProcessError, match=r'returned non-zero exit status 1'):
        subprocess.check_call(l1.daemon.cmd_line)

    l1.daemon.opts.update({"encrypted-hsm": None})
    master_fd, slave_fd = os.openpty()
    l1.daemon.start(stdin=slave_fd, stderr=subprocess.STDOUT,
                    wait_for_initialized=False)

    l1.daemon.wait_for_log(r'The hsm_secret is encrypted')
    os.write(master_fd, password.encode("utf-8"))
    l1.daemon.wait_for_log("Server started with public key")
    assert node_id == l1.rpc.getinfo()["id"]
    l1.stop()

    # And finally test that we can also decrypt if encrypted with hsmtool
    cmd_line[1] = "decrypt"
    subprocess.check_call(cmd_line)
    l1.daemon.opts.pop("encrypted-hsm")
    l1.daemon.start(stdin=slave_fd, wait_for_initialized=True)
    assert node_id == l1.rpc.getinfo()["id"]


# this test does a 'listtransactions' on a yet unconfirmed channel
def test_fundchannel_listtransaction(node_factory, bitcoind):
    l1, l2 = node_factory.get_nodes(2)
    l1.fundwallet(10**6)

    l1.connect(l2)
    txid = l1.rpc.fundchannel(l2.info['id'], 10**5)['txid']

    # next call warned about SQL Accessing a null column
    # and crashed the daemon for accessing random memory or null
    txs = l1.rpc.listtransactions()['transactions']

    tx = [t for t in txs if t['hash'] == txid][0]
    assert tx['blockheight'] == 0


def test_withdraw_nlocktime(node_factory):
    """
    Test that we don't set the nLockTime to 0 for withdrawal transactions.
    """
    l1 = node_factory.get_node(1)
    l1.fundwallet(10**4)

    addr = l1.rpc.newaddr()["bech32"]
    tx = l1.rpc.withdraw(addr, 10**3)["tx"]
    nlocktime = node_factory.bitcoind.rpc.decoderawtransaction(tx)["locktime"]
    tip = node_factory.bitcoind.rpc.getblockcount()

    assert nlocktime > 0 and nlocktime <= tip


@flaky
@unittest.skipIf(VALGRIND, "A big loop is used to check fuzz.")
def test_withdraw_nlocktime_fuzz(node_factory, bitcoind):
    """
    Test that we eventually fuzz nLockTime for withdrawal transactions.
    Marked flaky "just in case" as we fuzz from 0 to 100 with a 10%
    probability.
    """
    l1 = node_factory.get_node(1)
    l1.fundwallet(10**8)

    for i in range(100):
        addr = l1.rpc.newaddr()["bech32"]
        withdraw = l1.rpc.withdraw(addr, 10**3)
        bitcoind.generate_block(1)
        l1.daemon.wait_for_log('Owning output .* txid {} CONFIRMED'.
                               format(withdraw["txid"]))
        decoded = bitcoind.rpc.decoderawtransaction(withdraw["tx"])
        tip = node_factory.bitcoind.rpc.getblockcount()
        assert decoded["locktime"] > 0
        if decoded["locktime"] < tip:
            return
    else:
        raise Exception("No transaction with fuzzed nLockTime !")