core-lightning/tests/test_lightningd.py

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from binascii import hexlify, unhexlify
from concurrent import futures
2017-06-20 16:41:49 +02:00
from decimal import Decimal
from hashlib import sha256
from lightning import LightningRpc
import copy
import json
import logging
import queue
import os
import random
import re
2017-06-20 16:41:49 +02:00
import sqlite3
import string
import sys
import tempfile
import threading
import time
import unittest
import utils
bitcoind = None
TEST_DIR = tempfile.mkdtemp(prefix='lightning-')
VALGRIND = os.getenv("NO_VALGRIND", "0") == "0"
DEVELOPER = os.getenv("DEVELOPER", "0") == "1"
TEST_DEBUG = os.getenv("TEST_DEBUG", "0") == "1"
print("Testing results are in {}".format(TEST_DIR))
if TEST_DEBUG:
logging.basicConfig(level=logging.DEBUG, stream=sys.stdout)
logging.info("Tests running in '%s'", TEST_DIR)
def to_json(arg):
return json.loads(json.dumps(arg))
def setupBitcoind():
global bitcoind
bitcoind = utils.BitcoinD(rpcport=28332)
bitcoind.start()
info = bitcoind.rpc.getinfo()
# Make sure we have segwit and some funds
if info['blocks'] < 432:
logging.debug("SegWit not active, generating some more blocks")
bitcoind.rpc.generate(432 - info['blocks'])
elif info['balance'] < 1:
logging.debug("Insufficient balance, generating 1 block")
bitcoind.rpc.generate(1)
def wait_for(success, timeout=30, interval=0.1):
start_time = time.time()
while not success() and time.time() < start_time + timeout:
time.sleep(interval)
if time.time() > start_time + timeout:
raise ValueError("Error waiting for {}", success)
def sync_blockheight(nodes):
target = bitcoind.rpc.getblockcount()
for n in nodes:
wait_for(lambda: n.rpc.getinfo()['blockheight'] == target)
def tearDownBitcoind():
global bitcoind
try:
bitcoind.rpc.stop()
except:
bitcoind.proc.kill()
bitcoind.proc.wait()
def setUpModule():
setupBitcoind()
def tearDownModule():
tearDownBitcoind()
def breakpoint():
import pdb; pdb.set_trace()
class NodeFactory(object):
"""A factory to setup and start `lightningd` daemons.
"""
def __init__(self, func, executor):
self.func = func
self.next_id = 1
self.nodes = []
self.executor = executor
def get_node(self, disconnect=None, options=None, may_fail=False):
node_id = self.next_id
self.next_id += 1
lightning_dir = os.path.join(
TEST_DIR, self.func._testMethodName, "lightning-{}/".format(node_id))
socket_path = os.path.join(lightning_dir, "lightning-rpc").format(node_id)
port = 16330+node_id
daemon = utils.LightningD(lightning_dir, bitcoind.bitcoin_dir, port=port)
# If we have a disconnect string, dump it to a file for daemon.
if disconnect:
with open(os.path.join(lightning_dir, "dev_disconnect"), "w") as f:
f.write("\n".join(disconnect))
daemon.cmd_line.append("--dev-disconnect=dev_disconnect")
if DEVELOPER:
daemon.cmd_line.append("--dev-fail-on-subdaemon-fail")
if VALGRIND:
daemon.cmd_line.append("--dev-no-backtrace")
opts = [] if options is None else options
for opt in opts:
daemon.cmd_line.append(opt)
rpc = LightningRpc(socket_path, self.executor)
node = utils.LightningNode(daemon, rpc, bitcoind, self.executor, may_fail=may_fail)
self.nodes.append(node)
if VALGRIND:
node.daemon.cmd_line = [
'valgrind',
'-q',
'--trace-children=yes',
'--trace-children-skip=*bitcoin-cli*',
'--error-exitcode=7',
'--log-file={}/valgrind-errors.%p'.format(node.daemon.lightning_dir)
] + node.daemon.cmd_line
node.daemon.start()
# Cache `getinfo`, we'll be using it a lot
node.info = node.rpc.getinfo()
return node
def killall(self):
rcs = []
failed = False
for n in self.nodes:
try:
n.stop()
except:
failed = True
rcs.append(n.daemon.proc.returncode)
if failed:
raise Exception("At least one lightning exited with non-zero return code: {}".format(rcs))
class BaseLightningDTests(unittest.TestCase):
def setUp(self):
# Most of the executor threads will be waiting for IO, so
# let's have a few of them
self.executor = futures.ThreadPoolExecutor(max_workers=20)
self.node_factory = NodeFactory(self, self.executor)
def getValgrindErrors(self, node):
for error_file in os.listdir(node.daemon.lightning_dir):
if not re.fullmatch("valgrind-errors.\d+", error_file):
continue;
with open(os.path.join(node.daemon.lightning_dir, error_file), 'r') as f:
errors = f.read().strip()
if errors:
return errors, error_file
return None, None
def printValgrindErrors(self, node):
errors, fname = self.getValgrindErrors(node)
if errors:
print("-"*31, "Valgrind errors", "-"*32)
print("Valgrind error file:", fname)
print(errors)
print("-"*80)
return 1 if errors else 0
def getCrashLog(self, node):
if node.may_fail:
return None, None
try:
crashlog = os.path.join(node.daemon.lightning_dir, 'crash.log')
with open(crashlog, 'r') as f:
return f.readlines(), crashlog
except:
return None, None
def printCrashLog(self, node):
errors, fname = self.getCrashLog(node)
if errors:
print("-"*10, "{} (last 50 lines)".format(fname), "-"*10)
for l in errors[-50:]:
print(l, end='')
print("-"*80)
return 1 if errors else 0
def tearDown(self):
self.node_factory.killall()
self.executor.shutdown(wait=False)
err_count = 0
# Do not check for valgrind error files if it is disabled
if VALGRIND:
for node in self.node_factory.nodes:
err_count += self.printValgrindErrors(node)
if err_count:
raise ValueError(
"{} nodes reported valgrind errors".format(err_count))
for node in self.node_factory.nodes:
err_count += self.printCrashLog(node)
if err_count:
raise ValueError(
"{} nodes had crash.log files".format(err_count))
class LightningDTests(BaseLightningDTests):
def connect(self):
l1 = self.node_factory.get_node()
l2 = self.node_factory.get_node()
ret = l1.rpc.connect(l2.info['id'], 'localhost:{}'.format(l2.info['port']))
assert ret['id'] == l2.info['id']
l1.daemon.wait_for_log('WIRE_GOSSIPCTL_HANDLE_PEER')
l2.daemon.wait_for_log('WIRE_GOSSIPCTL_HANDLE_PEER')
return l1,l2
# Returns the short channel-id: <blocknum>:<txnum>:<outnum>
def fund_channel(self, l1, l2, amount):
addr = l1.rpc.newaddr()['address']
txid = l1.bitcoin.rpc.sendtoaddress(addr, amount / 10**8 + 0.01)
tx = l1.bitcoin.rpc.getrawtransaction(txid)
l1.rpc.addfunds(tx)
# Generate a block, so we know next tx will be first in block.
l1.bitcoin.rpc.generate(1)
tx = l1.rpc.fundchannel(l2.info['id'], amount)['tx']
# Technically, this is async to fundchannel.
l1.daemon.wait_for_log('sendrawtx exit 0')
l1.bitcoin.rpc.generate(1)
l1.daemon.wait_for_log('-> CHANNELD_NORMAL')
l2.daemon.wait_for_log('-> CHANNELD_NORMAL')
# Hacky way to find our output.
decoded=bitcoind.rpc.decoderawtransaction(tx)
for out in decoded['vout']:
test_lightning.py: fix float insanity with values. When is 0.01 != 0.01? When there are floats involved! Jenkins hit an error once, I have no idea why. This works around the following intermittant error: ERROR: test_closing_negotiation_reconnect (__main__.LightningDTests) ---------------------------------------------------------------------- Traceback (most recent call last): File "tests/test_lightningd.py", line 1601, in test_closing_negotiation_reconnect self.fund_channel(l1, l2, 10**6) File "tests/test_lightningd.py", line 241, in fund_channel raise ValueError("Can't find {} payment in {}".format(amount, tx)) ValueError: Can't find 1000000 payment in 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 For testing, that tx decodes to: { "txid": "0165e92be762b352b665b76b9872d5189e1b2a8faf4918ab3cca7cd5d4b6a5fa", "hash": "8af9a36c79ee5243468c5cbed1c80f10238fba405f0ad957a0c2cfc46fb632f5", "version": 2, "size": 257, "vsize": 176, "locktime": 0, "vin": [ { "txid": "26c00a67045b5bc585c3f2cd9ae5c0447baee163c297f159eefa1629e97bb2b0", "vout": 1, "scriptSig": { "asm": "001401fad90abcd66697e2592164722de4a95ebee165", "hex": "16001401fad90abcd66697e2592164722de4a95ebee165" }, "txinwitness": [ "3044022017bd19a0ee85532f67a280c71ed02d1321f08975334bd281527478022265225702202ec448bf9c0890a31a26f0ef4f03d298c8ec16b277faff09a70ddd335df44b6e01", "03d745445c9362665f22e0d96e9e766f273f3260dea39c8a76bfa05dd2684ddccf" ], "sequence": 4294967295 } ], "vout": [ { "value": 0.00990565, "n": 0, "scriptPubKey": { "asm": "0 c2ccab171c2a5be9dab52ec41b825863024c5466", "hex": "0014c2ccab171c2a5be9dab52ec41b825863024c5466", "type": "witness_v0_keyhash" } }, { "value": 0.01000000, "n": 1, "scriptPubKey": { "asm": "0 5b8cd3b914cf67cdd8fa6273c930353dd36476734fbd962102c2df53b90880cd", "hex": "00205b8cd3b914cf67cdd8fa6273c930353dd36476734fbd962102c2df53b90880cd", "type": "witness_v0_scripthash" } } ] } Signed-off-by: Rusty Russell <rusty@rustcorp.com.au>
2017-10-22 22:32:10 +02:00
# Sometimes a float? Sometimes a decimal? WTF Python?!
if out['scriptPubKey']['type'] == 'witness_v0_scripthash':
if out['value'] == Decimal(amount) / 10**8 or out['value'] * 10**8 == amount:
return "{}:1:{}".format(bitcoind.rpc.getblockcount(), out['n'])
# Intermittant decoding failure. See if it decodes badly twice?
decoded2=bitcoind.rpc.decoderawtransaction(tx)
raise ValueError("Can't find {} payment in {} (1={} 2={})".format(amount, tx, decoded, decoded2))
def pay(self, lsrc, ldst, amt, label=None, async=False):
if not label:
label = ''.join(random.choice(string.ascii_letters + string.digits) for _ in range(20))
rhash = ldst.rpc.invoice(amt, label)['rhash']
assert ldst.rpc.listinvoice(label)[0]['complete'] == False
routestep = {
'msatoshi' : amt,
'id' : ldst.info['id'],
'delay' : 5,
'channel': '1:1:1'
}
def wait_pay():
# Up to 10 seconds for payment to succeed.
start_time = time.time()
while not ldst.rpc.listinvoice(label)[0]['complete']:
if time.time() > start_time + 10:
raise TimeoutError('Payment timed out')
time.sleep(0.1)
if async:
self.executor.submit(lsrc.rpc.sendpay, to_json([routestep]), rhash, async=False)
return self.executor.submit(wait_pay)
else:
lsrc.rpc.sendpay(to_json([routestep]), rhash, async=False)
def test_shutdown(self):
l1 = self.node_factory.get_node()
l1.rpc.stop()
def test_connect(self):
l1,l2 = self.connect()
# These should be in gossipd.
assert l1.rpc.getpeer(l2.info['id'])['state'] == 'GOSSIPING'
assert l2.rpc.getpeer(l1.info['id'])['state'] == 'GOSSIPING'
# Both gossipds will have them as new peers once handed back.
l1.daemon.wait_for_log('handle_peer {}: new peer'.format(l2.info['id']))
l2.daemon.wait_for_log('handle_peer {}: new peer'.format(l1.info['id']))
def test_balance(self):
l1,l2 = self.connect()
self.fund_channel(l1, l2, 10**6)
p1 = l1.rpc.getpeer(l2.info['id'], 'info')
p2 = l2.rpc.getpeer(l1.info['id'], 'info')
assert p1['msatoshi_to_us'] == 10**6 * 1000
assert p1['msatoshi_total'] == 10**6 * 1000
assert p2['msatoshi_to_us'] == 0
assert p2['msatoshi_total'] == 10**6 * 1000
def test_sendpay(self):
l1,l2 = self.connect()
self.fund_channel(l1, l2, 10**6)
amt = 200000000
rhash = l2.rpc.invoice(amt, 'testpayment2')['rhash']
assert l2.rpc.listinvoice('testpayment2')[0]['complete'] == False
routestep = {
'msatoshi' : amt,
'id' : l2.info['id'],
'delay' : 5,
'channel': '1:1:1'
}
# Insufficient funds.
rs = copy.deepcopy(routestep)
rs['msatoshi'] = rs['msatoshi'] - 1
self.assertRaises(ValueError, l1.rpc.sendpay, to_json([rs]), rhash)
assert l2.rpc.listinvoice('testpayment2')[0]['complete'] == False
# Gross overpayment (more than factor of 2)
rs = copy.deepcopy(routestep)
rs['msatoshi'] = rs['msatoshi'] * 2 + 1
self.assertRaises(ValueError, l1.rpc.sendpay, to_json([rs]), rhash)
assert l2.rpc.listinvoice('testpayment2')[0]['complete'] == False
# Insufficient delay.
rs = copy.deepcopy(routestep)
rs['delay'] = rs['delay'] - 2
self.assertRaises(ValueError, l1.rpc.sendpay, to_json([rs]), rhash)
assert l2.rpc.listinvoice('testpayment2')[0]['complete'] == False
# Bad ID.
rs = copy.deepcopy(routestep)
rs['id'] = '00000000000000000000000000000000'
self.assertRaises(ValueError, l1.rpc.sendpay, to_json([rs]), rhash)
assert l2.rpc.listinvoice('testpayment2')[0]['complete'] == False
# FIXME: test paying via another node, should fail to pay twice.
p1 = l1.rpc.getpeer(l2.info['id'], 'info')
p2 = l2.rpc.getpeer(l1.info['id'], 'info')
assert p1['msatoshi_to_us'] == 10**6 * 1000
assert p1['msatoshi_total'] == 10**6 * 1000
assert p2['msatoshi_to_us'] == 0
assert p2['msatoshi_total'] == 10**6 * 1000
# This works.
l1.rpc.sendpay(to_json([routestep]), rhash)
assert l2.rpc.listinvoice('testpayment2')[0]['complete'] == True
# Balances should reflect it.
time.sleep(1)
p1 = l1.rpc.getpeer(l2.info['id'], 'info')
p2 = l2.rpc.getpeer(l1.info['id'], 'info')
assert p1['msatoshi_to_us'] == 10**6 * 1000 - amt
assert p1['msatoshi_total'] == 10**6 * 1000
assert p2['msatoshi_to_us'] == amt
assert p2['msatoshi_total'] == 10**6 * 1000
# Repeat will "succeed", but won't actually send anything (duplicate)
assert not l1.daemon.is_in_log('... succeeded')
l1.rpc.sendpay(to_json([routestep]), rhash)
l1.daemon.wait_for_log('... succeeded')
assert l2.rpc.listinvoice('testpayment2')[0]['complete'] == True
# Overpaying by "only" a factor of 2 succeeds.
rhash = l2.rpc.invoice(amt, 'testpayment3')['rhash']
assert l2.rpc.listinvoice('testpayment3')[0]['complete'] == False
routestep = { 'msatoshi' : amt * 2, 'id' : l2.info['id'], 'delay' : 5, 'channel': '1:1:1'}
l1.rpc.sendpay(to_json([routestep]), rhash)
assert l2.rpc.listinvoice('testpayment3')[0]['complete'] == True
def test_sendpay_cant_afford(self):
l1,l2 = self.connect()
# Note, this is in SATOSHI, rest are in MILLISATOSHI!
self.fund_channel(l1, l2, 10**6)
# Can't pay more than channel capacity.
self.assertRaises(ValueError, self.pay, l1, l2, 10**9 + 1)
# This is the fee, which needs to be taken into account for l1.
available = 10**9 - 13440
# Reserve is 1%.
reserve = 10**7
# Can't pay past reserve.
self.assertRaises(ValueError, self.pay, l1, l2, available)
self.assertRaises(ValueError, self.pay, l1, l2, available - reserve + 1)
# Can pay up to reserve (1%)
self.pay(l1, l2, available - reserve)
# And now it can't pay back, due to its own reserve.
self.assertRaises(ValueError, self.pay, l2, l1, available - reserve)
# But this should work.
self.pay(l2, l1, available - reserve*2)
def test_bad_opening(self):
# l1 asks for a too-long locktime
l1 = self.node_factory.get_node(options=['--locktime-blocks=100'])
l2 = self.node_factory.get_node(options=['--max-locktime-blocks=99'])
ret = l1.rpc.connect(l2.info['id'], 'localhost:{}'.format(l2.info['port']))
assert ret['id'] == l2.info['id']
l1.daemon.wait_for_log('WIRE_GOSSIPCTL_HANDLE_PEER')
l2.daemon.wait_for_log('WIRE_GOSSIPCTL_HANDLE_PEER')
addr = l1.rpc.newaddr()['address']
txid = l1.bitcoin.rpc.sendtoaddress(addr, 10**6 / 10**8 + 0.01)
tx = l1.bitcoin.rpc.getrawtransaction(txid)
l1.rpc.addfunds(tx)
self.assertRaises(ValueError, l1.rpc.fundchannel, l2.info['id'], 10**6)
l2.daemon.wait_for_log('to_self_delay 100 larger than 99')
def test_closing(self):
l1,l2 = self.connect()
self.fund_channel(l1, l2, 10**6)
self.pay(l1,l2,200000000)
assert l1.bitcoin.rpc.getmempoolinfo()['size'] == 0
# This should return, then close.
l1.rpc.close(l2.info['id']);
l1.daemon.wait_for_log('-> CHANNELD_SHUTTING_DOWN')
l2.daemon.wait_for_log('-> CHANNELD_SHUTTING_DOWN')
l1.daemon.wait_for_log('-> CLOSINGD_SIGEXCHANGE')
l2.daemon.wait_for_log('-> CLOSINGD_SIGEXCHANGE')
# And should put closing into mempool.
l1.daemon.wait_for_log('sendrawtx exit 0')
l2.daemon.wait_for_log('sendrawtx exit 0')
assert l1.bitcoin.rpc.getmempoolinfo()['size'] == 1
@unittest.skipIf(not DEVELOPER, "needs DEVELOPER=1")
def test_permfail(self):
l1,l2 = self.connect()
self.fund_channel(l1, l2, 10**6)
self.pay(l1,l2,200000000)
# Make sure l2 has received sig with 0 htlcs!
l2.daemon.wait_for_log('Received commit_sig with 0 htlc sigs')
# Make sure l1 has final revocation.
l1.daemon.wait_for_log('Sending commit_sig with 0 htlc sigs')
l1.daemon.wait_for_log('peer_in WIRE_REVOKE_AND_ACK')
# We fail l2, so l1 will reconnect to it.
l2.rpc.dev_fail(l1.info['id']);
l2.daemon.wait_for_log('Failing due to dev-fail command')
l2.daemon.wait_for_log('sendrawtx exit 0')
# "Internal error" in hex
l1.daemon.wait_for_log('WIRE_ERROR.*496e7465726e616c206572726f72')
# l2 will send out tx (l1 considers it a transient error)
bitcoind.rpc.generate(1)
l1.daemon.wait_for_log('Their unilateral tx, old commit point')
l1.daemon.wait_for_log('-> ONCHAIND_THEIR_UNILATERAL')
l2.daemon.wait_for_log('-> ONCHAIND_OUR_UNILATERAL')
l2.daemon.wait_for_log('Propose handling OUR_UNILATERAL/DELAYED_OUTPUT_TO_US by OUR_DELAYED_RETURN_TO_WALLET (.*) in 5 blocks')
# Now, mine 5 blocks so it sends out the spending tx.
bitcoind.rpc.generate(5)
# It should send the to-wallet tx.
l2.daemon.wait_for_log('Broadcasting OUR_DELAYED_RETURN_TO_WALLET')
l2.daemon.wait_for_log('sendrawtx exit 0')
# 100 after l1 sees tx, it should be done.
bitcoind.rpc.generate(95)
l1.daemon.wait_for_log('onchaind complete, forgetting peer')
# Now, 100 blocks l2 should be done.
bitcoind.rpc.generate(5)
l2.daemon.wait_for_log('onchaind complete, forgetting peer')
@unittest.skipIf(not DEVELOPER, "needs DEVELOPER=1")
def test_onchain_first_commit(self):
"""Onchain handling where funder immediately drops to chain"""
# HTLC 1->2, 1 fails just after funding.
disconnects = ['+WIRE_FUNDING_LOCKED', 'permfail']
l1 = self.node_factory.get_node(disconnect=disconnects)
l2 = self.node_factory.get_node()
l1.rpc.connect(l2.info['id'], 'localhost:{}'.format(l2.info['port']))
# Like fundchannel, but we'll probably fail before CHANNELD_NORMAL.
addr = l1.rpc.newaddr()['address']
txid = l1.bitcoin.rpc.sendtoaddress(addr, 10**6 / 10**8 + 0.01)
tx = l1.bitcoin.rpc.getrawtransaction(txid)
l1.rpc.addfunds(tx)
l1.rpc.fundchannel(l2.info['id'], 10**6)
l1.daemon.wait_for_log('sendrawtx exit 0')
l1.bitcoin.rpc.generate(1)
# l1 will drop to chain.
l1.daemon.wait_for_log('permfail')
l1.daemon.wait_for_log('sendrawtx exit 0')
l1.bitcoin.rpc.generate(1)
l1.daemon.wait_for_log('-> ONCHAIND_OUR_UNILATERAL')
l2.daemon.wait_for_log('-> ONCHAIND_THEIR_UNILATERAL')
# 6 later, l1 should collect its to-self payment.
bitcoind.rpc.generate(6)
l1.daemon.wait_for_log('Broadcasting OUR_DELAYED_RETURN_TO_WALLET .* to resolve OUR_UNILATERAL/DELAYED_OUTPUT_TO_US')
l1.daemon.wait_for_log('sendrawtx exit 0')
# 94 later, l2 is done.
bitcoind.rpc.generate(94)
l2.daemon.wait_for_log('onchaind complete, forgetting peer')
# Now, 100 blocks and l1 should be done.
bitcoind.rpc.generate(6)
l1.daemon.wait_for_log('onchaind complete, forgetting peer')
@unittest.skipIf(not DEVELOPER, "needs DEVELOPER=1")
def test_onchain_dust_out(self):
"""Onchain handling of outgoing dust htlcs (they should fail)"""
# HTLC 1->2, 1 fails after it's irrevocably committed
disconnects = ['@WIRE_REVOKE_AND_ACK', 'permfail']
l1 = self.node_factory.get_node(disconnect=disconnects)
l2 = self.node_factory.get_node()
l1.rpc.connect(l2.info['id'], 'localhost:{}'.format(l2.info['port']))
self.fund_channel(l1, l2, 10**6)
# Must be dust!
rhash = l2.rpc.invoice(1, 'onchain_dust_out')['rhash']
routestep = {
'msatoshi' : 1,
'id' : l2.info['id'],
'delay' : 5,
'channel': '1:1:1'
}
payfuture = self.executor.submit(l1.rpc.sendpay, to_json([routestep]), rhash)
# l1 will drop to chain.
l1.daemon.wait_for_log('permfail')
l1.daemon.wait_for_log('sendrawtx exit 0')
l1.bitcoin.rpc.generate(1)
l1.daemon.wait_for_log('-> ONCHAIND_OUR_UNILATERAL')
l2.daemon.wait_for_log('-> ONCHAIND_THEIR_UNILATERAL')
# We use 3 blocks for "reasonable depth"
bitcoind.rpc.generate(3)
# It should fail.
self.assertRaises(ValueError, payfuture.result, 5)
l1.daemon.wait_for_log('WIRE_PERMANENT_CHANNEL_FAILURE: missing in commitment tx')
# 6 later, l1 should collect its to-self payment.
bitcoind.rpc.generate(6)
l1.daemon.wait_for_log('Broadcasting OUR_DELAYED_RETURN_TO_WALLET .* to resolve OUR_UNILATERAL/DELAYED_OUTPUT_TO_US')
l1.daemon.wait_for_log('sendrawtx exit 0')
# 94 later, l2 is done.
bitcoind.rpc.generate(94)
l2.daemon.wait_for_log('onchaind complete, forgetting peer')
# Now, 100 blocks and l1 should be done.
bitcoind.rpc.generate(6)
l1.daemon.wait_for_log('onchaind complete, forgetting peer')
# Payment failed, BTW
assert l2.rpc.listinvoice('onchain_dust_out')[0]['complete'] == False
@unittest.skipIf(not DEVELOPER, "needs DEVELOPER=1")
def test_onchain_timeout(self):
"""Onchain handling of outgoing failed htlcs"""
# HTLC 1->2, 1 fails just after it's irrevocably committed
disconnects = ['+WIRE_REVOKE_AND_ACK', 'permfail']
l1 = self.node_factory.get_node(disconnect=disconnects)
l2 = self.node_factory.get_node()
l1.rpc.connect(l2.info['id'], 'localhost:{}'.format(l2.info['port']))
self.fund_channel(l1, l2, 10**6)
rhash = l2.rpc.invoice(10**8, 'onchain_timeout')['rhash']
# We underpay, so it fails.
routestep = {
'msatoshi' : 10**8 - 1,
'id' : l2.info['id'],
'delay' : 5,
'channel': '1:1:1'
}
payfuture = self.executor.submit(l1.rpc.sendpay, to_json([routestep]), rhash)
# l1 will drop to chain.
l1.daemon.wait_for_log('permfail')
l1.daemon.wait_for_log('sendrawtx exit 0')
l1.bitcoin.rpc.generate(1)
l1.daemon.wait_for_log('-> ONCHAIND_OUR_UNILATERAL')
l2.daemon.wait_for_log('-> ONCHAIND_THEIR_UNILATERAL')
# Wait for timeout.
l1.daemon.wait_for_log('Propose handling OUR_UNILATERAL/DELAYED_OUTPUT_TO_US by OUR_DELAYED_RETURN_TO_WALLET .* in 5 blocks')
bitcoind.rpc.generate(5)
# (l1 will also collect its to-self payment.)
l1.daemon.wait_for_log('sendrawtx exit 0')
l1.daemon.wait_for_log('sendrawtx exit 0')
# We use 3 blocks for "reasonable depth"
bitcoind.rpc.generate(3)
# It should fail.
self.assertRaises(ValueError, payfuture.result, 5)
l1.daemon.wait_for_log('WIRE_PERMANENT_CHANNEL_FAILURE: timed out')
# 91 later, l2 is done.
bitcoind.rpc.generate(91)
l2.daemon.wait_for_log('onchaind complete, forgetting peer')
# Now, 100 blocks and l1 should be done.
bitcoind.rpc.generate(6)
l1.daemon.wait_for_log('onchaind complete, forgetting peer')
# Payment failed, BTW
assert l2.rpc.listinvoice('onchain_timeout')[0]['complete'] == False
@unittest.skipIf(not DEVELOPER, "needs DEVELOPER=1")
def test_onchain_middleman(self):
# HTLC 1->2->3, 1->2 goes down after 2 gets preimage from 3.
disconnects = ['-WIRE_UPDATE_FULFILL_HTLC', 'permfail']
l1 = self.node_factory.get_node()
l2 = self.node_factory.get_node(disconnect=disconnects)
l3 = self.node_factory.get_node()
# l2 connects to both, so l1 can't reconnect and thus l2 drops to chain
l2.rpc.connect(l1.info['id'], 'localhost:{}'.format(l1.info['port']))
l2.rpc.connect(l3.info['id'], 'localhost:{}'.format(l3.info['port']))
self.fund_channel(l2, l1, 10**6)
self.fund_channel(l2, l3, 10**6)
# Give l1 some money to play with.
self.pay(l2, l1, 2 * 10**8)
# Must be bigger than dust!
rhash = l3.rpc.invoice(10**8, 'middleman')['rhash']
# Wait for route propagation.
l1.bitcoin.rpc.generate(5)
l1.daemon.wait_for_log('Received node_announcement for node {}'
.format(l3.info['id']))
route = l1.rpc.getroute(l3.info['id'], 10**8, 1)["route"]
assert len(route) == 2
q = queue.Queue()
def try_pay():
try:
l1.rpc.sendpay(to_json(route), rhash, async=False)
q.put(None)
except Exception as err:
q.put(err)
t = threading.Thread(target=try_pay)
t.daemon = True
t.start()
# l2 will drop to chain.
l2.daemon.wait_for_log('sendrawtx exit 0')
l1.bitcoin.rpc.generate(1)
l2.daemon.wait_for_log('-> ONCHAIND_OUR_UNILATERAL')
l1.daemon.wait_for_log('-> ONCHAIND_THEIR_UNILATERAL')
l2.daemon.wait_for_log('OUR_UNILATERAL/THEIR_HTLC')
# l2 should fulfill HTLC onchain, and spend to-us (any order)
l2.daemon.wait_for_log('Propose handling OUR_UNILATERAL/THEIR_HTLC by OUR_HTLC_SUCCESS_TX .* in 0 blocks')
l2.daemon.wait_for_log('sendrawtx exit 0')
# Payment should succeed.
l1.bitcoin.rpc.generate(1)
l1.daemon.wait_for_log('THEIR_UNILATERAL/OUR_HTLC gave us preimage')
err = q.get(timeout = 10)
if err:
print("Got err from sendpay thread")
raise err
t.join(timeout=1)
assert not t.isAlive()
# Three more, l2 can spend to-us.
bitcoind.rpc.generate(3)
l2.daemon.wait_for_log('Broadcasting OUR_DELAYED_RETURN_TO_WALLET .* to resolve OUR_UNILATERAL/DELAYED_OUTPUT_TO_US')
l2.daemon.wait_for_log('sendrawtx exit 0')
# One more block, HTLC tx is now spentable.
l1.bitcoin.rpc.generate(1)
l2.daemon.wait_for_log('Broadcasting OUR_DELAYED_RETURN_TO_WALLET .* to resolve OUR_HTLC_SUCCESS_TX/DELAYED_OUTPUT_TO_US')
l2.daemon.wait_for_log('sendrawtx exit 0')
# 100 blocks after last spend, l2 should be done.
l1.bitcoin.rpc.generate(100)
l2.daemon.wait_for_log('onchaind complete, forgetting peer')
@unittest.skipIf(not DEVELOPER, "needs DEVELOPER=1")
def test_penalty_inhtlc(self):
"""Test penalty transaction with an incoming HTLC"""
# We suppress each one after first commit; HTLC gets added not fulfilled.
l1 = self.node_factory.get_node(disconnect=['=WIRE_COMMITMENT_SIGNED-nocommit'], may_fail=True)
l2 = self.node_factory.get_node(disconnect=['=WIRE_COMMITMENT_SIGNED-nocommit'])
l1.rpc.connect(l2.info['id'], 'localhost:{}'.format(l2.info['port']))
self.fund_channel(l1, l2, 10**6)
# Now, this will get stuck due to l1 commit being disabled..
t = self.pay(l1,l2,100000000,async=True)
# They should both have commitments blocked now.
l1.daemon.wait_for_log('=WIRE_COMMITMENT_SIGNED-nocommit')
l2.daemon.wait_for_log('=WIRE_COMMITMENT_SIGNED-nocommit')
# Make sure l1 got l2's commitment to the HTLC, and sent to master.
l1.daemon.wait_for_log('UPDATE WIRE_CHANNEL_GOT_COMMITSIG')
# Take our snapshot.
tx = l1.rpc.dev_sign_last_tx(l2.info['id'])['tx']
# Let them continue
l1.rpc.dev_reenable_commit(l2.info['id'])
l2.rpc.dev_reenable_commit(l1.info['id'])
# Should fulfill.
l1.daemon.wait_for_log('peer_in WIRE_UPDATE_FULFILL_HTLC')
l1.daemon.wait_for_log('peer_out WIRE_REVOKE_AND_ACK')
l2.daemon.wait_for_log('peer_out WIRE_UPDATE_FULFILL_HTLC')
l1.daemon.wait_for_log('peer_in WIRE_REVOKE_AND_ACK')
# Payment should now complete.
t.result(timeout=10)
# Now we really mess things up!
bitcoind.rpc.sendrawtransaction(tx)
bitcoind.rpc.generate(1)
l2.daemon.wait_for_log('-> ONCHAIND_CHEATED')
# FIXME: l1 should try to stumble along!
# l2 should spend all of the outputs (except to-us).
# Could happen in any order, depending on commitment tx.
l2.daemon.wait_for_logs(['Propose handling THEIR_REVOKED_UNILATERAL/DELAYED_OUTPUT_TO_THEM by OUR_PENALTY_TX .* in 0 blocks',
'sendrawtx exit 0',
'Propose handling THEIR_REVOKED_UNILATERAL/THEIR_HTLC by OUR_PENALTY_TX .* in 0 blocks',
'sendrawtx exit 0'])
# FIXME: test HTLC tx race!
# 100 blocks later, all resolved.
bitcoind.rpc.generate(100)
# FIXME: Test wallet balance...
l2.daemon.wait_for_log('onchaind complete, forgetting peer')
@unittest.skip("flaky test causing CI fails too often")
def test_penalty_outhtlc(self):
"""Test penalty transaction with an outgoing HTLC"""
# First we need to get funds to l2, so suppress after second.
l1 = self.node_factory.get_node(disconnect=['=WIRE_COMMITMENT_SIGNED*3-nocommit'], may_fail=True)
l2 = self.node_factory.get_node(disconnect=['=WIRE_COMMITMENT_SIGNED*3-nocommit'])
l1.rpc.connect(l2.info['id'], 'localhost:{}'.format(l2.info['port']))
self.fund_channel(l1, l2, 10**6)
# Move some across to l2.
self.pay(l1,l2,200000000)
assert not l1.daemon.is_in_log('=WIRE_COMMITMENT_SIGNED')
assert not l2.daemon.is_in_log('=WIRE_COMMITMENT_SIGNED')
# Now, this will get stuck due to l1 commit being disabled..
t = self.pay(l2,l1,100000000,async=True)
# Make sure we get signature from them.
l1.daemon.wait_for_log('peer_in WIRE_UPDATE_ADD_HTLC')
l1.daemon.wait_for_log('peer_in WIRE_COMMITMENT_SIGNED')
# They should both have commitments blocked now.
l1.daemon.wait_for_log('dev_disconnect: =WIRE_COMMITMENT_SIGNED')
l2.daemon.wait_for_log('dev_disconnect: =WIRE_COMMITMENT_SIGNED')
# Take our snapshot.
tx = l1.rpc.dev_sign_last_tx(l2.info['id'])['tx']
# Let the continue
l1.rpc.dev_reenable_commit(l2.info['id'])
l2.rpc.dev_reenable_commit(l1.info['id'])
# Thread should complete.
t.result(timeout=10)
# Make sure both sides got revoke_and_ack for final.
l1.daemon.wait_for_log('peer_in WIRE_REVOKE_AND_ACK')
l2.daemon.wait_for_log('peer_in WIRE_REVOKE_AND_ACK')
# Now we really mess things up!
bitcoind.rpc.sendrawtransaction(tx)
bitcoind.rpc.generate(1)
l2.daemon.wait_for_log('-> ONCHAIND_CHEATED')
# FIXME: l1 should try to stumble along!
# l2 should spend all of the outputs (except to-us).
# Could happen in any order, depending on commitment tx.
l2.daemon.wait_for_logs(['Ignoring output.*: THEIR_REVOKED_UNILATERAL/OUTPUT_TO_US',
'Propose handling THEIR_REVOKED_UNILATERAL/DELAYED_OUTPUT_TO_THEM by OUR_PENALTY_TX .* in 0 blocks',
'sendrawtx exit 0',
'Propose handling THEIR_REVOKED_UNILATERAL/OUR_HTLC by OUR_PENALTY_TX .* in 0 blocks',
'sendrawtx exit 0'])
# FIXME: test HTLC tx race!
# 100 blocks later, all resolved.
bitcoind.rpc.generate(100)
# FIXME: Test wallet balance...
l2.daemon.wait_for_log('onchaind complete, forgetting peer')
@unittest.skipIf(not DEVELOPER, "needs DEVELOPER=1")
def test_permfail_new_commit(self):
# Test case where we have two possible commits: it will use new one.
disconnects = ['-WIRE_REVOKE_AND_ACK', 'permfail']
l1 = self.node_factory.get_node()
l2 = self.node_factory.get_node(disconnect=disconnects)
l1.rpc.connect(l2.info['id'], 'localhost:{}'.format(l2.info['port']))
self.fund_channel(l1, l2, 10**6)
# This will fail at l2's end.
t=self.pay(l1,l2,200000000,async=True)
l2.daemon.wait_for_log('dev_disconnect permfail')
l2.daemon.wait_for_log('sendrawtx exit 0')
bitcoind.rpc.generate(1)
l1.daemon.wait_for_log('Their unilateral tx, new commit point')
l1.daemon.wait_for_log('-> ONCHAIND_THEIR_UNILATERAL')
l2.daemon.wait_for_log('-> ONCHAIND_OUR_UNILATERAL')
l2.daemon.wait_for_log('Propose handling OUR_UNILATERAL/THEIR_HTLC by THEIR_HTLC_TIMEOUT_TO_THEM \\(IGNORING\\) in 5 blocks')
l1.daemon.wait_for_log('Propose handling THEIR_UNILATERAL/OUR_HTLC by OUR_HTLC_TIMEOUT_TO_US (.*) in 5 blocks')
# OK, time out HTLC.
bitcoind.rpc.generate(5)
l1.daemon.wait_for_log('sendrawtx exit 0')
bitcoind.rpc.generate(1)
l1.daemon.wait_for_log('Resolved THEIR_UNILATERAL/OUR_HTLC by our proposal OUR_HTLC_TIMEOUT_TO_US')
l2.daemon.wait_for_log('Ignoring output.*: OUR_UNILATERAL/THEIR_HTLC')
t.cancel()
# Now, 100 blocks it should be done.
bitcoind.rpc.generate(100)
l1.daemon.wait_for_log('onchaind complete, forgetting peer')
l2.daemon.wait_for_log('onchaind complete, forgetting peer')
@unittest.skipIf(not DEVELOPER, "needs DEVELOPER=1")
def test_permfail_htlc_in(self):
# Test case where we fail with unsettled incoming HTLC.
disconnects = ['-WIRE_UPDATE_FULFILL_HTLC', 'permfail']
l1 = self.node_factory.get_node()
l2 = self.node_factory.get_node(disconnect=disconnects)
l1.rpc.connect(l2.info['id'], 'localhost:{}'.format(l2.info['port']))
self.fund_channel(l1, l2, 10**6)
# This will fail at l2's end.
t=self.pay(l1, l2, 200000000, async=True)
l2.daemon.wait_for_log('dev_disconnect permfail')
l2.daemon.wait_for_log('sendrawtx exit 0')
bitcoind.rpc.generate(1)
l1.daemon.wait_for_log('Their unilateral tx, old commit point')
l1.daemon.wait_for_log('-> ONCHAIND_THEIR_UNILATERAL')
l2.daemon.wait_for_log('-> ONCHAIND_OUR_UNILATERAL')
l2.daemon.wait_for_log('Propose handling OUR_UNILATERAL/THEIR_HTLC by THEIR_HTLC_TIMEOUT_TO_THEM \\(IGNORING\\) in 5 blocks')
l1.daemon.wait_for_log('Propose handling THEIR_UNILATERAL/OUR_HTLC by OUR_HTLC_TIMEOUT_TO_US (.*) in 5 blocks')
# l2 then gets preimage, uses it instead of ignoring
l2.daemon.wait_for_log('Propose handling OUR_UNILATERAL/THEIR_HTLC by OUR_HTLC_SUCCESS_TX .* in 0 blocks')
l2.daemon.wait_for_log('sendrawtx exit 0')
bitcoind.rpc.generate(1)
# OK, l1 sees l2 fulfill htlc.
l1.daemon.wait_for_log('THEIR_UNILATERAL/OUR_HTLC gave us preimage')
l2.daemon.wait_for_log('Propose handling OUR_HTLC_SUCCESS_TX/DELAYED_OUTPUT_TO_US by OUR_DELAYED_RETURN_TO_WALLET .* in 5 blocks')
bitcoind.rpc.generate(5)
l2.daemon.wait_for_log('sendrawtx exit 0')
t.cancel()
# Now, 100 blocks it should be done.
bitcoind.rpc.generate(95)
l1.daemon.wait_for_log('onchaind complete, forgetting peer')
assert not l2.daemon.is_in_log('onchaind complete, forgetting peer')
bitcoind.rpc.generate(5)
l2.daemon.wait_for_log('onchaind complete, forgetting peer')
@unittest.skipIf(not DEVELOPER, "needs DEVELOPER=1")
def test_permfail_htlc_out(self):
# Test case where we fail with unsettled outgoing HTLC.
disconnects = ['+WIRE_REVOKE_AND_ACK', 'permfail']
l1 = self.node_factory.get_node()
l2 = self.node_factory.get_node(disconnect=disconnects)
l1.rpc.connect(l2.info['id'], 'localhost:{}'.format(l2.info['port']))
self.fund_channel(l2, l1, 10**6)
# This will fail at l2's end.
t=self.pay(l2,l1,200000000,async=True)
l2.daemon.wait_for_log('dev_disconnect permfail')
l2.daemon.wait_for_log('sendrawtx exit 0')
bitcoind.rpc.generate(1)
l1.daemon.wait_for_log('Their unilateral tx, old commit point')
l1.daemon.wait_for_log('-> ONCHAIND_THEIR_UNILATERAL')
l2.daemon.wait_for_log('-> ONCHAIND_OUR_UNILATERAL')
l2.daemon.wait_for_logs(['Propose handling OUR_UNILATERAL/OUR_HTLC by OUR_HTLC_TIMEOUT_TO_US \\(.*\\) in 5 blocks',
'Propose handling OUR_UNILATERAL/DELAYED_OUTPUT_TO_US by OUR_DELAYED_RETURN_TO_WALLET .* in 5 blocks'])
l1.daemon.wait_for_log('Propose handling THEIR_UNILATERAL/THEIR_HTLC by THEIR_HTLC_TIMEOUT_TO_THEM \\(IGNORING\\) in 5 blocks')
# l1 then gets preimage, uses it instead of ignoring
l1.daemon.wait_for_log('Propose handling THEIR_UNILATERAL/THEIR_HTLC by THEIR_HTLC_FULFILL_TO_US .* in 0 blocks')
l1.daemon.wait_for_log('sendrawtx exit 0')
# l2 sees l1 fulfill tx.
bitcoind.rpc.generate(1)
l2.daemon.wait_for_log('OUR_UNILATERAL/OUR_HTLC gave us preimage')
t.cancel()
# l2 can send OUR_DELAYED_RETURN_TO_WALLET after 4 more blocks.
bitcoind.rpc.generate(4)
l2.daemon.wait_for_log('Broadcasting OUR_DELAYED_RETURN_TO_WALLET .* to resolve OUR_UNILATERAL/DELAYED_OUTPUT_TO_US')
l2.daemon.wait_for_log('sendrawtx exit 0')
# Now, 100 blocks they should be done.
bitcoind.rpc.generate(94)
assert not l1.daemon.is_in_log('onchaind complete, forgetting peer')
assert not l2.daemon.is_in_log('onchaind complete, forgetting peer')
bitcoind.rpc.generate(1)
l1.daemon.wait_for_log('onchaind complete, forgetting peer')
assert not l2.daemon.is_in_log('onchaind complete, forgetting peer')
bitcoind.rpc.generate(5)
assert not l2.daemon.is_in_log('onchaind complete, forgetting peer')
bitcoind.rpc.generate(1)
l2.daemon.wait_for_log('onchaind complete, forgetting peer')
def test_gossip_jsonrpc(self):
l1,l2 = self.connect()
self.fund_channel(l1,l2,10**5)
# Shouldn't send announce signatures until 6 deep.
assert not l1.daemon.is_in_log('peer_out WIRE_ANNOUNCEMENT_SIGNATURES')
l1.bitcoin.rpc.generate(5)
# Could happen in either order.
l1.daemon.wait_for_logs(['peer_out WIRE_ANNOUNCEMENT_SIGNATURES',
'peer_in WIRE_ANNOUNCEMENT_SIGNATURES'])
# Could happen in either order.
l1.daemon.wait_for_logs(['peer_out WIRE_CHANNEL_ANNOUNCEMENT',
'peer_in WIRE_CHANNEL_ANNOUNCEMENT'])
nodes = l1.rpc.getnodes()['nodes']
assert set([n['nodeid'] for n in nodes]) == set([l1.info['id'], l2.info['id']])
l1.daemon.wait_for_log('peer_in WIRE_CHANNEL_UPDATE')
l2.daemon.wait_for_log('peer_in WIRE_CHANNEL_UPDATE')
channels = l1.rpc.getchannels()['channels']
assert len(channels) == 2
assert [c['active'] for c in channels] == [True, True]
def ping_tests(self, l1, l2):
# 0-byte pong gives just type + length field.
ret = l1.rpc.dev_ping(l2.info['id'], 0, 0)
assert ret['totlen'] == 4
# 1000-byte ping, 0-byte pong.
ret = l1.rpc.dev_ping(l2.info['id'], 1000, 0)
assert ret['totlen'] == 4
# 1000 byte pong.
ret = l1.rpc.dev_ping(l2.info['id'], 1000, 1000)
assert ret['totlen'] == 1004
# Maximum length pong.
ret = l1.rpc.dev_ping(l2.info['id'], 1000, 65531)
assert ret['totlen'] == 65535
# Overlength -> no reply.
for s in range(65532, 65536):
ret = l1.rpc.dev_ping(l2.info['id'], 1000, s)
assert ret['totlen'] == 0
@unittest.skipIf(not DEVELOPER, "needs DEVELOPER=1")
def test_ping(self):
l1,l2 = self.connect()
# Test gossip pinging.
self.ping_tests(l1, l2)
self.fund_channel(l1, l2, 10**5)
# channeld pinging
self.ping_tests(l1, l2)
@unittest.skipIf(not DEVELOPER, "needs DEVELOPER=1")
def test_routing_gossip_reconnect(self):
# Connect two peers, reconnect and then see if we resume the
# gossip.
disconnects = ['-WIRE_CHANNEL_ANNOUNCEMENT']
l1 = self.node_factory.get_node(disconnect=disconnects)
l2 = self.node_factory.get_node()
l3 = self.node_factory.get_node()
l1.rpc.connect(l2.info['id'], 'localhost:{}'.format(l2.info['port']))
l1.openchannel(l2, 20000)
# Now open new channels and everybody should sync
l2.rpc.connect(l3.info['id'], 'localhost:{}'.format(l3.info['port']))
l2.openchannel(l3, 20000)
# Settle the gossip
for n in [l1, l2, l3]:
wait_for(lambda: len(n.rpc.getchannels()['channels']) == 4)
def test_second_channel(self):
l1 = self.node_factory.get_node()
l2 = self.node_factory.get_node()
l3 = self.node_factory.get_node()
l1.rpc.connect(l2.info['id'], 'localhost:{}'.format(l2.info['port']))
l1.rpc.connect(l3.info['id'], 'localhost:{}'.format(l3.info['port']))
self.fund_channel(l1, l2, 10**6)
self.fund_channel(l1, l3, 10**6)
@unittest.skipIf(not DEVELOPER, "needs DEVELOPER=1 for --dev-broadcast-interval")
def test_routing_gossip(self):
nodes = [self.node_factory.get_node() for _ in range(5)]
l1 = nodes[0]
l5 = nodes[4]
for i in range(len(nodes)-1):
src, dst = nodes[i], nodes[i+1]
src.rpc.connect(dst.info['id'], 'localhost:{}'.format(dst.info['port']))
src.openchannel(dst, 20000)
# Allow announce messages.
l1.bitcoin.rpc.generate(5)
def settle_gossip(n):
"""Wait for gossip to settle at the node
"""
expected_connections = 2*(len(nodes) - 1)
start_time = time.time()
# Wait at most 10 seconds, broadcast interval is 1 second
while time.time() - start_time < 10:
channels = n.rpc.getchannels()['channels']
if len(channels) == expected_connections:
break
else:
time.sleep(0.1)
for n in nodes:
settle_gossip(n)
# Deep check that all channels are in there
comb = []
for i in range(len(nodes) - 1):
comb.append((nodes[i].info['id'], nodes[i+1].info['id']))
comb.append((nodes[i+1].info['id'], nodes[i].info['id']))
for n in nodes:
seen = []
channels = n.rpc.getchannels()['channels']
for c in channels:
seen.append((c['source'],c['destination']))
assert set(seen) == set(comb)
def test_forward(self):
# Connect 1 -> 2 -> 3.
l1,l2 = self.connect()
l3 = self.node_factory.get_node()
ret = l2.rpc.connect(l3.info['id'], 'localhost:{}'.format(l3.info['port']))
assert ret['id'] == l3.info['id']
l3.daemon.wait_for_log('WIRE_GOSSIPCTL_HANDLE_PEER')
self.fund_channel(l1, l2, 10**6)
self.fund_channel(l2, l3, 10**6)
# Allow announce messages.
l1.bitcoin.rpc.generate(5)
# If they're at different block heights we can get spurious errors.
sync_blockheight([l1, l2, l3])
chanid1 = l1.rpc.getpeer(l2.info['id'])['channel']
chanid2 = l2.rpc.getpeer(l3.info['id'])['channel']
assert l2.rpc.getpeer(l1.info['id'])['channel'] == chanid1
assert l3.rpc.getpeer(l2.info['id'])['channel'] == chanid2
rhash = l3.rpc.invoice(100000000, 'testpayment1')['rhash']
assert l3.rpc.listinvoice('testpayment1')[0]['complete'] == False
# Fee for node2 is 10 millionths, plus 1.
amt = 100000000
fee = amt * 10 // 1000000 + 1
baseroute = [ { 'msatoshi' : amt + fee,
'id' : l2.info['id'],
'delay' : 12,
'channel' : chanid1 },
{ 'msatoshi' : amt,
'id' : l3.info['id'],
'delay' : 6,
'channel' : chanid2 } ]
# Unknown other peer
route = copy.deepcopy(baseroute)
route[1]['id'] = '031a8dc444e41bb989653a4501e11175a488a57439b0c4947704fd6e3de5dca607'
self.assertRaises(ValueError, l1.rpc.sendpay, to_json(route), rhash)
# Delay too short (we always add one internally anyway, so subtract 2 here).
route = copy.deepcopy(baseroute)
route[0]['delay'] = 8
self.assertRaises(ValueError, l1.rpc.sendpay, to_json(route), rhash)
# Final delay too short
route = copy.deepcopy(baseroute)
route[1]['delay'] = 3
self.assertRaises(ValueError, l1.rpc.sendpay, to_json(route), rhash)
# This one works
route = copy.deepcopy(baseroute)
l1.rpc.sendpay(to_json(route), rhash)
@unittest.skipIf(not DEVELOPER, "needs DEVELOPER=1 for --dev-broadcast-interval")
def test_forward_different_fees_and_cltv(self):
# FIXME: Check BOLT quotes here too
# BOLT #7:
# ```
# B
# / \
# / \
# A C
# \ /
# \ /
# D
# ```
#
# Each advertises the following `cltv_expiry_delta` on its end of every
# channel:
#
# 1. A: 10 blocks
# 2. B: 20 blocks
# 3. C: 30 blocks
# 4. D: 40 blocks
#
# C also uses a minimum `cltv_expiry` of 9 (the default) when requesting
# payments.
#
# Also, each node has the same fee scheme which it uses for each of its
# channels:
#
# 1. A: 100 base + 1000 millionths
# 1. B: 200 base + 2000 millionths
# 1. C: 300 base + 3000 millionths
# 1. D: 400 base + 4000 millionths
# We don't do D yet.
l1 = self.node_factory.get_node(options=['--cltv-delta=10', '--fee-base=100', '--fee-per-satoshi=1000'])
l2 = self.node_factory.get_node(options=['--cltv-delta=20', '--fee-base=200', '--fee-per-satoshi=2000'])
l3 = self.node_factory.get_node(options=['--cltv-delta=30', '--cltv-final=9', '--fee-base=300', '--fee-per-satoshi=3000'])
ret = l1.rpc.connect(l2.info['id'], 'localhost:{}'.format(l2.info['port']))
assert ret['id'] == l2.info['id']
l1.daemon.wait_for_log('WIRE_GOSSIPCTL_HANDLE_PEER')
l2.daemon.wait_for_log('WIRE_GOSSIPCTL_HANDLE_PEER')
ret = l2.rpc.connect(l3.info['id'], 'localhost:{}'.format(l3.info['port']))
assert ret['id'] == l3.info['id']
l2.daemon.wait_for_log('WIRE_GOSSIPCTL_HANDLE_PEER')
l3.daemon.wait_for_log('WIRE_GOSSIPCTL_HANDLE_PEER')
c1 = self.fund_channel(l1, l2, 10**6)
c2 = self.fund_channel(l2, l3, 10**6)
# Allow announce messages.
l1.bitcoin.rpc.generate(5)
# Make sure l1 has seen announce for all channels.
l1.daemon.wait_for_logs([
'Received channel_update for channel {}\\(0\\)'.format(c1),
'Received channel_update for channel {}\\(1\\)'.format(c1),
'Received channel_update for channel {}\\(0\\)'.format(c2),
'Received channel_update for channel {}\\(1\\)'.format(c2)])
# BOLT #7:
#
# If B were to send 4,999,999 millisatoshi directly to C, it wouldn't
# charge itself a fee nor add its own `cltv_expiry_delta`, so it would
# use C's requested `cltv_expiry` of 9. We also assume it adds a
# "shadow route" to give an extra CLTV of 42. It could also add extra
# cltv deltas at other hops, as these values are a minimum, but we don't
# here for simplicity:
# FIXME: Add shadow route
shadow_route=0
route = l2.rpc.getroute(l3.info['id'], 4999999, 1)["route"]
assert len(route) == 1
# BOLT #7:
#
# * `amount_msat`: 4999999
# * `cltv_expiry`: current-block-height + 9 + 42
# * `onion_routing_packet`:
# * `amt_to_forward` = 4999999
# * `outgoing_cltv_value` = current-block-height + 9 + 42
#
assert route[0]['msatoshi'] == 4999999
assert route[0]['delay'] == 9 + shadow_route
# BOLT #7:
# If A were to send an 4,999,999 millisatoshi to C via B, it needs to
# pay B the fee it specified in the B->C `channel_update`, calculated as
# per [HTLC Fees](#htlc_fees):
#
# 200 + 4999999 * 2000 / 1000000 = 10199
#
# Similarly, it would need to add the `cltv_expiry` from B->C's
# `channel_update` (20), plus C's requested minimum (9), plus 42 for the
# "shadow route". Thus the `update_add_htlc` message from A to B would
# be:
#
# * `amount_msat`: 5010198
# * `cltv_expiry`: current-block-height + 20 + 9 + 42
# * `onion_routing_packet`:
# * `amt_to_forward` = 4999999
# * `outgoing_cltv_value` = current-block-height + 9 + 42
route = l1.rpc.getroute(l3.info['id'], 4999999, 1)["route"]
assert len(route) == 2
assert route[0]['msatoshi'] == 5010198
assert route[0]['delay'] == 20 + 9 + shadow_route
assert route[1]['msatoshi'] == 4999999
assert route[1]['delay'] == 9 + shadow_route
rhash = l3.rpc.invoice(4999999, 'test_forward_different_fees_and_cltv')['rhash']
assert l3.rpc.listinvoice('test_forward_different_fees_and_cltv')[0]['complete'] == False
# This should work.
l1.rpc.sendpay(to_json(route), rhash)
# We add one to the blockcount for a bit of fuzz (FIXME: Shadowroute would fix this!)
shadow_route = 1
l1.daemon.wait_for_log("Adding HTLC 0 msat=5010198 cltv={} gave 0"
.format(bitcoind.rpc.getblockcount() + 20 + 9 + shadow_route))
l2.daemon.wait_for_log("Adding HTLC 0 msat=4999999 cltv={} gave 0"
.format(bitcoind.rpc.getblockcount() + 9 + shadow_route))
l3.daemon.wait_for_log("test_forward_different_fees_and_cltv: Actual amount 4999999msat, HTLC expiry {}"
.format(bitcoind.rpc.getblockcount() + 9 + shadow_route))
assert l3.rpc.listinvoice('test_forward_different_fees_and_cltv')[0]['complete'] == True
@unittest.skipIf(not DEVELOPER, "needs DEVELOPER=1 for --dev-broadcast-interval")
def test_forward_pad_fees_and_cltv(self):
"""Test that we are allowed extra locktime delta, and fees"""
l1 = self.node_factory.get_node(options=['--cltv-delta=10', '--fee-base=100', '--fee-per-satoshi=1000'])
l2 = self.node_factory.get_node(options=['--cltv-delta=20', '--fee-base=200', '--fee-per-satoshi=2000'])
l3 = self.node_factory.get_node(options=['--cltv-delta=30', '--cltv-final=9', '--fee-base=300', '--fee-per-satoshi=3000'])
ret = l1.rpc.connect(l2.info['id'], 'localhost:{}'.format(l2.info['port']))
assert ret['id'] == l2.info['id']
l1.daemon.wait_for_log('WIRE_GOSSIPCTL_HANDLE_PEER')
l2.daemon.wait_for_log('WIRE_GOSSIPCTL_HANDLE_PEER')
ret = l2.rpc.connect(l3.info['id'], 'localhost:{}'.format(l3.info['port']))
assert ret['id'] == l3.info['id']
l2.daemon.wait_for_log('WIRE_GOSSIPCTL_HANDLE_PEER')
l3.daemon.wait_for_log('WIRE_GOSSIPCTL_HANDLE_PEER')
c1 = self.fund_channel(l1, l2, 10**6)
c2 = self.fund_channel(l2, l3, 10**6)
# Allow announce messages.
l1.bitcoin.rpc.generate(5)
# Make sure l1 has seen announce for all channels.
l1.daemon.wait_for_logs([
'Received channel_update for channel {}\\(0\\)'.format(c1),
'Received channel_update for channel {}\\(1\\)'.format(c1),
'Received channel_update for channel {}\\(0\\)'.format(c2),
'Received channel_update for channel {}\\(1\\)'.format(c2)])
route = l1.rpc.getroute(l3.info['id'], 4999999, 1)["route"]
assert len(route) == 2
assert route[0]['msatoshi'] == 5010198
assert route[0]['delay'] == 20 + 9
assert route[1]['msatoshi'] == 4999999
assert route[1]['delay'] == 9
# Modify so we overpay, overdo the cltv.
route[0]['msatoshi'] += 2000
route[0]['delay'] += 20
route[1]['msatoshi'] += 1000
route[1]['delay'] += 10
# This should work.
rhash = l3.rpc.invoice(4999999, 'test_forward_pad_fees_and_cltv')['rhash']
l1.rpc.sendpay(to_json(route), rhash)
assert l3.rpc.listinvoice('test_forward_pad_fees_and_cltv')[0]['complete'] == True
@unittest.skipIf(not DEVELOPER, "needs DEVELOPER=1")
def test_disconnect(self):
# These should all make us fail, and retry.
# FIXME: Configure short timeout for reconnect!
disconnects = ['-WIRE_INIT',
'@WIRE_INIT',
'+WIRE_INIT']
l1 = self.node_factory.get_node(disconnect=disconnects)
l2 = self.node_factory.get_node()
l1.rpc.connect(l2.info['id'], 'localhost:{}'.format(l2.info['port']))
# Should have 3 connect fails.
for d in disconnects:
l1.daemon.wait_for_log('Failed connected out for {}, will try again'
.format(l2.info['id']))
@unittest.skipIf(not DEVELOPER, "needs DEVELOPER=1")
def test_disconnect_funder(self):
# Now error on funder side duringchannel open.
disconnects = ['-WIRE_OPEN_CHANNEL',
'@WIRE_OPEN_CHANNEL',
'+WIRE_OPEN_CHANNEL',
'-WIRE_FUNDING_CREATED',
'@WIRE_FUNDING_CREATED']
l1 = self.node_factory.get_node(disconnect=disconnects)
l2 = self.node_factory.get_node()
addr = l1.rpc.newaddr()['address']
txid = l1.bitcoin.rpc.sendtoaddress(addr, 20000 / 10**6)
tx = l1.bitcoin.rpc.getrawtransaction(txid)
l1.rpc.addfunds(tx)
for d in disconnects:
l1.rpc.connect(l2.info['id'], 'localhost:{}'.format(l2.info['port']))
self.assertRaises(ValueError, l1.rpc.fundchannel, l2.info['id'], 20000)
assert l1.rpc.getpeer(l2.info['id']) == None
@unittest.skipIf(not DEVELOPER, "needs DEVELOPER=1")
def test_disconnect_fundee(self):
# Now error on fundee side during channel open.
disconnects = ['-WIRE_ACCEPT_CHANNEL',
'@WIRE_ACCEPT_CHANNEL',
'+WIRE_ACCEPT_CHANNEL']
l1 = self.node_factory.get_node()
l2 = self.node_factory.get_node(disconnect=disconnects)
addr = l1.rpc.newaddr()['address']
txid = l1.bitcoin.rpc.sendtoaddress(addr, 20000 / 10**6)
tx = l1.bitcoin.rpc.getrawtransaction(txid)
l1.rpc.addfunds(tx)
for d in disconnects:
l1.rpc.connect(l2.info['id'], 'localhost:{}'.format(l2.info['port']))
self.assertRaises(ValueError, l1.rpc.fundchannel, l2.info['id'], 20000)
assert l1.rpc.getpeer(l2.info['id']) == None
@unittest.skipIf(not DEVELOPER, "needs DEVELOPER=1")
def test_disconnect_half_signed(self):
# Now, these are the corner cases. Fundee sends funding_signed,
# but funder doesn't receive it.
disconnects = ['@WIRE_FUNDING_SIGNED']
l1 = self.node_factory.get_node()
l2 = self.node_factory.get_node(disconnect=disconnects)
addr = l1.rpc.newaddr()['address']
txid = l1.bitcoin.rpc.sendtoaddress(addr, 20000 / 10**6)
tx = l1.bitcoin.rpc.getrawtransaction(txid)
l1.rpc.addfunds(tx)
l1.rpc.connect(l2.info['id'], 'localhost:{}'.format(l2.info['port']))
self.assertRaises(ValueError, l1.rpc.fundchannel, l2.info['id'], 20000)
# Fundee remembers, funder doesn't.
assert l1.rpc.getpeer(l2.info['id']) == None
assert l2.rpc.getpeer(l1.info['id'])['peerid'] == l1.info['id']
@unittest.skipIf(not DEVELOPER, "needs DEVELOPER=1")
def test_reconnect_signed(self):
# This will fail *after* both sides consider channel opening.
disconnects = ['+WIRE_FUNDING_SIGNED']
l1 = self.node_factory.get_node()
l2 = self.node_factory.get_node(disconnect=disconnects)
addr = l1.rpc.newaddr()['address']
txid = l1.bitcoin.rpc.sendtoaddress(addr, 20000 / 10**6)
tx = l1.bitcoin.rpc.getrawtransaction(txid)
l1.rpc.addfunds(tx)
l1.rpc.connect(l2.info['id'], 'localhost:{}'.format(l2.info['port']))
l1.rpc.fundchannel(l2.info['id'], 20000)
# They haven't forgotten each other.
assert l1.rpc.getpeer(l2.info['id'])['peerid'] == l2.info['id']
assert l2.rpc.getpeer(l1.info['id'])['peerid'] == l1.info['id']
# Technically, this is async to fundchannel.
l1.daemon.wait_for_log('sendrawtx exit 0')
# Wait for reconnect, awaiting lockin..
l1.daemon.wait_for_log('Peer has reconnected, state CHANNELD_AWAITING_LOCKIN');
l1.bitcoin.rpc.generate(6)
l1.daemon.wait_for_log('-> CHANNELD_NORMAL')
l2.daemon.wait_for_log('-> CHANNELD_NORMAL')
@unittest.skipIf(not DEVELOPER, "needs DEVELOPER=1")
def test_reconnect_openingd(self):
# Openingd thinks we're still opening; funder reconnects..
disconnects = ['0WIRE_ACCEPT_CHANNEL']
l1 = self.node_factory.get_node()
l2 = self.node_factory.get_node(disconnect=disconnects)
l1.rpc.connect(l2.info['id'], 'localhost:{}'.format(l2.info['port']))
addr = l1.rpc.newaddr()['address']
txid = l1.bitcoin.rpc.sendtoaddress(addr, 20000 / 10**6)
tx = l1.bitcoin.rpc.getrawtransaction(txid)
l1.rpc.addfunds(tx)
# l2 closes on l1, l1 forgets.
self.assertRaises(ValueError, l1.rpc.fundchannel, l2.info['id'], 20000)
assert l1.rpc.getpeer(l2.info['id']) == None
# Reconnect.
l1.rpc.connect(l2.info['id'], 'localhost:{}'.format(l2.info['port']))
# We should get a message about reconnecting.
l2.daemon.wait_for_log('Peer has reconnected, state OPENINGD')
# Should work fine.
l1.rpc.fundchannel(l2.info['id'], 20000)
l1.daemon.wait_for_log('sendrawtx exit 0')
# Just to be sure, second openingd hand over to channeld.
l2.daemon.wait_for_log('lightning_openingd.*REPLY WIRE_OPENING_FUNDEE_REPLY with 2 fds')
@unittest.skipIf(not DEVELOPER, "needs DEVELOPER=1")
def test_reconnect_normal(self):
# Should reconnect fine even if locked message gets lost.
disconnects = ['-WIRE_FUNDING_LOCKED',
'@WIRE_FUNDING_LOCKED',
'+WIRE_FUNDING_LOCKED']
l1 = self.node_factory.get_node(disconnect=disconnects)
l2 = self.node_factory.get_node()
ret = l1.rpc.connect(l2.info['id'], 'localhost:{}'.format(l2.info['port']))
self.fund_channel(l1, l2, 10**6)
@unittest.skipIf(not DEVELOPER, "needs DEVELOPER=1")
def test_reconnect_sender_add1(self):
# Fail after add is OK, will cause payment failure though.
disconnects = ['-WIRE_UPDATE_ADD_HTLC-nocommit',
'+WIRE_UPDATE_ADD_HTLC-nocommit',
'@WIRE_UPDATE_ADD_HTLC-nocommit']
l1 = self.node_factory.get_node(disconnect=disconnects)
l2 = self.node_factory.get_node()
ret = l1.rpc.connect(l2.info['id'], 'localhost:{}'.format(l2.info['port']))
self.fund_channel(l1, l2, 10**6)
amt = 200000000
rhash = l2.rpc.invoice(amt, 'test_reconnect_sender_add1')['rhash']
assert l2.rpc.listinvoice('test_reconnect_sender_add1')[0]['complete'] == False
route = [ { 'msatoshi' : amt, 'id' : l2.info['id'], 'delay' : 5, 'channel': '1:1:1'} ]
for i in range(0,len(disconnects)):
self.assertRaises(ValueError, l1.rpc.sendpay, to_json(route), rhash)
# Wait for reconnection.
l1.daemon.wait_for_log('Already have funding locked in')
# This will send commit, so will reconnect as required.
l1.rpc.sendpay(to_json(route), rhash)
@unittest.skipIf(not DEVELOPER, "needs DEVELOPER=1")
def test_reconnect_sender_add(self):
disconnects = ['-WIRE_COMMITMENT_SIGNED',
'@WIRE_COMMITMENT_SIGNED',
'+WIRE_COMMITMENT_SIGNED',
'-WIRE_REVOKE_AND_ACK',
'@WIRE_REVOKE_AND_ACK',
'+WIRE_REVOKE_AND_ACK']
l1 = self.node_factory.get_node(disconnect=disconnects)
l2 = self.node_factory.get_node()
ret = l1.rpc.connect(l2.info['id'], 'localhost:{}'.format(l2.info['port']))
self.fund_channel(l1, l2, 10**6)
amt = 200000000
rhash = l2.rpc.invoice(amt, 'testpayment')['rhash']
assert l2.rpc.listinvoice('testpayment')[0]['complete'] == False
route = [ { 'msatoshi' : amt, 'id' : l2.info['id'], 'delay' : 5, 'channel': '1:1:1'} ]
# This will send commit, so will reconnect as required.
l1.rpc.sendpay(to_json(route), rhash)
# Should have printed this for every reconnect.
for i in range(0,len(disconnects)):
l1.daemon.wait_for_log('Already have funding locked in')
@unittest.skipIf(not DEVELOPER, "needs DEVELOPER=1")
def test_reconnect_receiver_add(self):
disconnects = ['-WIRE_COMMITMENT_SIGNED',
'@WIRE_COMMITMENT_SIGNED',
'+WIRE_COMMITMENT_SIGNED',
'-WIRE_REVOKE_AND_ACK',
'@WIRE_REVOKE_AND_ACK',
'+WIRE_REVOKE_AND_ACK']
l1 = self.node_factory.get_node()
l2 = self.node_factory.get_node(disconnect=disconnects)
ret = l1.rpc.connect(l2.info['id'], 'localhost:{}'.format(l2.info['port']))
self.fund_channel(l1, l2, 10**6)
amt = 200000000
rhash = l2.rpc.invoice(amt, 'testpayment2')['rhash']
assert l2.rpc.listinvoice('testpayment2')[0]['complete'] == False
route = [ { 'msatoshi' : amt, 'id' : l2.info['id'], 'delay' : 5, 'channel': '1:1:1'} ]
l1.rpc.sendpay(to_json(route), rhash)
for i in range(len(disconnects)):
l1.daemon.wait_for_log('Already have funding locked in')
assert l2.rpc.listinvoice('testpayment2')[0]['complete'] == True
@unittest.skipIf(not DEVELOPER, "needs DEVELOPER=1")
def test_reconnect_receiver_fulfill(self):
# Ordering matters: after +WIRE_UPDATE_FULFILL_HTLC, channeld
# will continue and try to send WIRE_COMMITMENT_SIGNED: if
# that's the next failure, it will do two in one run.
disconnects = ['@WIRE_UPDATE_FULFILL_HTLC',
'+WIRE_UPDATE_FULFILL_HTLC',
'-WIRE_UPDATE_FULFILL_HTLC',
'-WIRE_COMMITMENT_SIGNED',
'@WIRE_COMMITMENT_SIGNED',
'+WIRE_COMMITMENT_SIGNED',
'-WIRE_REVOKE_AND_ACK',
'@WIRE_REVOKE_AND_ACK',
'+WIRE_REVOKE_AND_ACK']
l1 = self.node_factory.get_node()
l2 = self.node_factory.get_node(disconnect=disconnects)
ret = l1.rpc.connect(l2.info['id'], 'localhost:{}'.format(l2.info['port']))
self.fund_channel(l1, l2, 10**6)
amt = 200000000
rhash = l2.rpc.invoice(amt, 'testpayment2')['rhash']
assert l2.rpc.listinvoice('testpayment2')[0]['complete'] == False
route = [ { 'msatoshi' : amt, 'id' : l2.info['id'], 'delay' : 5, 'channel': '1:1:1'} ]
l1.rpc.sendpay(to_json(route), rhash)
for i in range(len(disconnects)):
l1.daemon.wait_for_log('Already have funding locked in')
assert l2.rpc.listinvoice('testpayment2')[0]['complete'] == True
@unittest.skipIf(not DEVELOPER, "needs DEVELOPER=1")
def test_shutdown_reconnect(self):
disconnects = ['-WIRE_SHUTDOWN',
'@WIRE_SHUTDOWN',
'+WIRE_SHUTDOWN']
l1 = self.node_factory.get_node(disconnect=disconnects)
l2 = self.node_factory.get_node()
l1.rpc.connect(l2.info['id'], 'localhost:{}'.format(l2.info['port']))
self.fund_channel(l1, l2, 10**6)
self.pay(l1,l2,200000000)
assert l1.bitcoin.rpc.getmempoolinfo()['size'] == 0
# This should return, then close.
l1.rpc.close(l2.info['id']);
l1.daemon.wait_for_log('-> CHANNELD_SHUTTING_DOWN')
l2.daemon.wait_for_log('-> CHANNELD_SHUTTING_DOWN')
l1.daemon.wait_for_log('-> CLOSINGD_SIGEXCHANGE')
l2.daemon.wait_for_log('-> CLOSINGD_SIGEXCHANGE')
# And should put closing into mempool (happens async, so
# CLOSINGD_COMPLETE may come first).
l1.daemon.wait_for_logs(['sendrawtx exit 0', '-> CLOSINGD_COMPLETE'])
l2.daemon.wait_for_logs(['sendrawtx exit 0', '-> CLOSINGD_COMPLETE'])
assert l1.bitcoin.rpc.getmempoolinfo()['size'] == 1
@unittest.skipIf(not DEVELOPER, "needs DEVELOPER=1")
def test_closing_negotiation_reconnect(self):
disconnects = ['-WIRE_CLOSING_SIGNED',
'@WIRE_CLOSING_SIGNED',
'+WIRE_CLOSING_SIGNED']
l1 = self.node_factory.get_node(disconnect=disconnects)
l2 = self.node_factory.get_node()
l1.rpc.connect(l2.info['id'], 'localhost:{}'.format(l2.info['port']))
self.fund_channel(l1, l2, 10**6)
self.pay(l1,l2,200000000)
assert l1.bitcoin.rpc.getmempoolinfo()['size'] == 0
# This should return, then close.
l1.rpc.close(l2.info['id']);
l1.daemon.wait_for_log('-> CHANNELD_SHUTTING_DOWN')
l2.daemon.wait_for_log('-> CHANNELD_SHUTTING_DOWN')
l1.daemon.wait_for_log('-> CLOSINGD_SIGEXCHANGE')
l2.daemon.wait_for_log('-> CLOSINGD_SIGEXCHANGE')
# And should put closing into mempool (happens async, so
# CLOSINGD_COMPLETE may come first).
l1.daemon.wait_for_logs(['sendrawtx exit 0', '-> CLOSINGD_COMPLETE'])
l2.daemon.wait_for_logs(['sendrawtx exit 0', '-> CLOSINGD_COMPLETE'])
assert l1.bitcoin.rpc.getmempoolinfo()['size'] == 1
2017-05-31 13:15:03 +02:00
def test_json_addfunds(self):
sat = 10**6
l1 = self.node_factory.get_node()
2017-05-31 13:15:03 +02:00
addr = l1.rpc.newaddr()['address']
txid = l1.bitcoin.rpc.sendtoaddress(addr, 0.01)
tx = l1.bitcoin.rpc.getrawtransaction(txid)
# The first time should succeed
assert l1.rpc.addfunds(tx) == { "outputs" : 1, "satoshis" : sat }
# Second time should fail, we already have those funds
self.assertRaises(ValueError, l1.rpc.addfunds, tx)
2017-06-20 16:41:49 +02:00
def test_withdraw(self):
amount = 1000000
l1 = self.node_factory.get_node()
2017-06-20 16:41:49 +02:00
addr = l1.rpc.newaddr()['address']
# Add some funds to withdraw later
for i in range(10):
txid = l1.bitcoin.rpc.sendtoaddress(addr, amount / 10**8 + 0.01)
tx = l1.bitcoin.rpc.getrawtransaction(txid)
l1.rpc.addfunds(tx)
# Reach around into the db to check that outputs were added
db = sqlite3.connect(os.path.join(l1.daemon.lightning_dir, "lightningd.sqlite3"))
c = db.cursor()
c.execute('SELECT COUNT(*) FROM outputs WHERE status=0')
assert(c.fetchone()[0] == 10)
waddr = l1.bitcoin.rpc.getnewaddress()
# Now attempt to withdraw some (making sure we collect multiple inputs)
self.assertRaises(ValueError, l1.rpc.withdraw, 'not an address', amount)
self.assertRaises(ValueError, l1.rpc.withdraw, waddr, 'not an amount')
self.assertRaises(ValueError, l1.rpc.withdraw, waddr, -amount)
out = l1.rpc.withdraw(waddr, 2*amount)
# Make sure bitcoind received the withdrawal
unspent = l1.bitcoin.rpc.listunspent(0)
withdrawal = [u for u in unspent if u['txid'] == out['txid']]
assert(len(withdrawal) == 1)
assert(withdrawal[0]['amount'] == Decimal('0.02'))
# Now make sure two of them were marked as spent
c = db.cursor()
c.execute('SELECT COUNT(*) FROM outputs WHERE status=2')
assert(c.fetchone()[0] == 2)
def test_funding_change(self):
"""Add some funds, fund a channel, and make sure we remember the change
"""
l1, l2 = self.connect()
addr = l1.rpc.newaddr()['address']
txid = l1.bitcoin.rpc.sendtoaddress(addr, 0.1)
tx = l1.bitcoin.rpc.getrawtransaction(txid)
l1.rpc.addfunds(tx)
outputs = l1.db_query('SELECT value FROM outputs WHERE status=0;')
assert len(outputs) == 1 and outputs[0]['value'] == 10000000
l1.rpc.fundchannel(l2.info['id'], 1000000)
outputs = {r['status']: r['value'] for r in l1.db_query(
'SELECT status, SUM(value) AS value FROM outputs GROUP BY status;')}
# The 10m out is spent and we have a change output of 9m-fee
assert outputs[0] > 8990000
assert outputs[2] == 10000000
@unittest.skipIf(not DEVELOPER, "needs DEVELOPER=1")
def test_channel_persistence(self):
# Start two nodes and open a channel (to remember). l2 will
# mysteriously die while committing the first HTLC so we can
# check that HTLCs reloaded from the DB work.
l1 = self.node_factory.get_node()
l2 = self.node_factory.get_node(disconnect=['=WIRE_COMMITMENT_SIGNED-nocommit'])
l1.rpc.connect(l2.info['id'], 'localhost:{}'.format(l2.info['port']))
# Neither node should have a channel open, they are just connected
for n in (l1, l2):
assert(n.db_query('SELECT COUNT(id) as count FROM channels;')[0]['count'] == 0)
self.fund_channel(l1, l2, 100000)
peers = l1.rpc.getpeers()['peers']
assert(len(peers) == 1 and peers[0]['state'] == 'CHANNELD_NORMAL')
# Both nodes should now have exactly one channel in the database
for n in (l1, l2):
assert(n.db_query('SELECT COUNT(id) as count FROM channels;')[0]['count'] == 1)
# Fire off a sendpay request, it'll get interrupted by a restart
fut = self.executor.submit(self.pay, l1, l2, 10000)
# Wait for it to be committed to, i.e., stored in the DB
l1.daemon.wait_for_log('peer_in WIRE_COMMITMENT_SIGNED')
# Stop l2, l1 will reattempt to connect
print("Killing l2 in mid HTLC")
l2.daemon.proc.terminate()
# Clear the disconnect and timer stop so we can proceed normally
l2.daemon.cmd_line = [e for e in l2.daemon.cmd_line if 'disconnect' not in e]
print(" ".join(l2.daemon.cmd_line + ['--dev-debugger=channeld']))
# Wait for l1 to notice
wait_for(lambda: not l1.rpc.getpeers()['peers'][0]['connected'])
# Now restart l1 and it should reload peers/channels from the DB
l2.daemon.start()
wait_for(lambda: len(l2.rpc.getpeers()['peers']) == 1)
# Wait for the restored HTLC to finish
wait_for(lambda: l1.rpc.getpeers()['peers'][0]['msatoshi_to_us'] == 99990000, interval=1)
wait_for(lambda: len([p for p in l1.rpc.getpeers()['peers'] if p['connected']]), interval=1)
wait_for(lambda: len([p for p in l2.rpc.getpeers()['peers'] if p['connected']]), interval=1)
# Now make sure this is really functional by sending a payment
self.pay(l1, l2, 10000)
time.sleep(1)
assert l1.rpc.getpeers()['peers'][0]['msatoshi_to_us'] == 99980000
assert l2.rpc.getpeers()['peers'][0]['msatoshi_to_us'] == 20000
# Finally restart l1, and make sure it remembers
l1.stop()
l1.daemon.start()
assert l1.rpc.getpeers()['peers'][0]['msatoshi_to_us'] == 99980000
def test_gossip_badsig(self):
l1 = self.node_factory.get_node()
l2 = self.node_factory.get_node()
l3 = self.node_factory.get_node()
# l2 connects to both, so l1 can't reconnect and thus l2 drops to chain
l2.rpc.connect(l1.info['id'], 'localhost:{}'.format(l1.info['port']))
l2.rpc.connect(l3.info['id'], 'localhost:{}'.format(l3.info['port']))
self.fund_channel(l2, l1, 10**6)
self.fund_channel(l2, l3, 10**6)
# Wait for route propagation.
l1.bitcoin.rpc.generate(5)
l1.daemon.wait_for_log('Received node_announcement for node {}'
.format(l3.info['id']))
assert not l1.daemon.is_in_log('signature verification failed')
assert not l2.daemon.is_in_log('signature verification failed')
assert not l3.daemon.is_in_log('signature verification failed')
if __name__ == '__main__':
unittest.main(verbosity=2)