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Authorize invoice refund route

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The customer gets a pull payment route to initiate the refund, so this one is only for merchants and needs to be authorized.
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Dennis Reimann 2021-12-16 15:05:47 +01:00 • committed by Andrew Camilleri
parent b68eae6f7d
commit a4fa61e5f6
1 changed files with 9 additions and 8 deletions
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17
BTCPayServer/Controllers/InvoiceController.UI.cs
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@ -157,7 +157,7 @@ namespace BTCPayServer.Controllers
}
[HttpGet("invoices/{invoiceId}/refund")]
[AllowAnonymous]
[Authorize(Policy = Policies.CanModifyStoreSettings, AuthenticationSchemes = AuthenticationSchemes.Cookie)]
public async Task<IActionResult> Refund([FromServices]IEnumerable<IPayoutHandler> payoutHandlers, string invoiceId, CancellationToken cancellationToken)
{
await using var ctx = _dbContextFactory.CreateContext();
@ -183,8 +183,6 @@ namespace BTCPayServer.Controllers
new { pullPaymentId = ppId });
}
HttpContext.SetStoreData(invoice.StoreData);
var paymentMethods = invoice.GetBlob(_NetworkProvider).GetPaymentMethods();
var pmis = paymentMethods.Select(method => method.GetId()).ToList();
var options = (await payoutHandlers.GetSupportedPaymentMethods(invoice.StoreData)).Where(id => pmis.Contains(id)).ToList();
@ -203,11 +201,14 @@ namespace BTCPayServer.Controllers
.Select(p => p?.GetPaymentMethodId())
.FirstOrDefault(p => p != null && options.Contains(p));
// TODO: What if no option?
var refund = new RefundModel();
refund.Title = "Select a payment method";
refund.AvailablePaymentMethods =
new SelectList(options.Select(id => new SelectListItem(id.ToPrettyString(), id.ToString())), "Value", "Text");
refund.SelectedPaymentMethod = defaultRefund?.ToString() ?? options.First().ToString();
var refund = new RefundModel
{
Title = "Select a payment method",
AvailablePaymentMethods =
new SelectList(options.Select(id => new SelectListItem(id.ToPrettyString(), id.ToString())),
"Value", "Text"),
SelectedPaymentMethod = defaultRefund?.ToString() ?? options.First().ToString()
};
// Nothing to select, skip to next
if (refund.AvailablePaymentMethods.Count() == 1)