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blockchain: change reorg utxo cache behavior
The assumption in the previous code was incorrect in that we were assuming that the chainLock is held throughout the entire chain reorg. This is not the case since the chainLock is let go of during the callback to the subscribers. Because of this, we need to ensure that the utxo set is consistent on each block disconnect. To achieve this, additional flushes are added during block disconnects. Also the utxocache is no longer avoided during block connects and when we're checking for the validity of the block connects and disconnects as we can just use the cache instead of trying to avoid it.
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@ -796,6 +796,15 @@ func (b *BlockChain) disconnectBlock(node *blockNode, block *btcutil.Block, view
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return err
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}
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// Flush the cache on every disconnect. Since the code for
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// reorganization modifies the database directly, the cache
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// will be left in an inconsistent state if we don't flush it
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// prior to the dbPutUtxoView that happends below.
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err = b.utxoCache.flush(dbTx, FlushRequired, state)
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if err != nil {
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return err
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}
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// Update the utxo set using the state of the utxo view. This
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// entails restoring all of the utxos spent and removing the new
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// ones created by the block.
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@ -880,6 +889,9 @@ func countSpentOutputs(block *btcutil.Block) int {
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//
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// This function may modify node statuses in the block index without flushing.
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//
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// This function never leaves the utxo set in an inconsistent state for block
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// disconnects.
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//
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// This function MUST be called with the chain state lock held (for writes).
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func (b *BlockChain) reorganizeChain(detachNodes, attachNodes *list.List) error {
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// Nothing to do if no reorganize nodes were provided.
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@ -887,15 +899,6 @@ func (b *BlockChain) reorganizeChain(detachNodes, attachNodes *list.List) error
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return nil
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}
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// The rest of the reorg depends on all STXOs already being in the database
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// so we flush before reorg.
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err := b.db.Update(func(dbTx database.Tx) error {
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return b.utxoCache.flush(dbTx, FlushRequired, b.BestSnapshot())
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})
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if err != nil {
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return err
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}
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// Ensure the provided nodes match the current best chain.
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tip := b.bestChain.Tip()
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if detachNodes.Len() != 0 {
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@ -957,7 +960,7 @@ func (b *BlockChain) reorganizeChain(detachNodes, attachNodes *list.List) error
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// Load all of the utxos referenced by the block that aren't
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// already in the view.
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err = view.fetchInputUtxos(b.db, nil, block)
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err = view.fetchInputUtxos(nil, b.utxoCache, block)
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if err != nil {
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return err
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}
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@ -1024,7 +1027,7 @@ func (b *BlockChain) reorganizeChain(detachNodes, attachNodes *list.List) error
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// checkConnectBlock gets skipped, we still need to update the UTXO
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// view.
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if b.index.NodeStatus(n).KnownValid() {
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err = view.fetchInputUtxos(b.db, nil, block)
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err = view.fetchInputUtxos(nil, b.utxoCache, block)
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if err != nil {
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return err
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}
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@ -1061,11 +1064,21 @@ func (b *BlockChain) reorganizeChain(detachNodes, attachNodes *list.List) error
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newBest = n
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}
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// Flush the utxo cache for the block disconnect below. The disconnect
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// code assumes that it's directly modifying the database so the cache
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// will be left in an inconsistent state. It needs to be flushed beforehand
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// in order for that to not happen.
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err := b.db.Update(func(dbTx database.Tx) error {
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return b.utxoCache.flush(dbTx, FlushRequired, b.BestSnapshot())
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})
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if err != nil {
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return err
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}
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// Reset the view for the actual connection code below. This is
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// required because the view was previously modified when checking if
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// the reorg would be successful and the connection code requires the
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// view to be valid from the viewpoint of each block being connected or
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// disconnected.
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// view to be valid from the viewpoint of each block being disconnected.
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view = NewUtxoViewpoint()
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view.SetBestHash(&b.bestChain.Tip().hash)
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@ -1076,7 +1089,7 @@ func (b *BlockChain) reorganizeChain(detachNodes, attachNodes *list.List) error
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// Load all of the utxos referenced by the block that aren't
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// already in the view.
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err := view.fetchInputUtxos(b.db, nil, block)
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err := view.fetchInputUtxos(nil, b.utxoCache, block)
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if err != nil {
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return err
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}
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@ -1089,51 +1102,39 @@ func (b *BlockChain) reorganizeChain(detachNodes, attachNodes *list.List) error
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return err
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}
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// Update the database and chain state.
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// Update the database and chain state. The cache will be flushed
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// here before the utxoview modifications happen to the database.
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err = b.disconnectBlock(n, block, view)
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if err != nil {
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return err
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}
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}
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// Connect the new best chain blocks.
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// Connect the new best chain blocks using the utxocache directly. It's more
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// efficient and since we already checked that the blocks are correct and that
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// the transactions connect properly, it's ok to access the cache. If we suddenly
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// crash here, we are able to recover as well.
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for i, e := 0, attachNodes.Front(); e != nil; i, e = i+1, e.Next() {
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n := e.Value.(*blockNode)
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block := attachBlocks[i]
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// Load all of the utxos referenced by the block that aren't
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// already in the view.
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err := view.fetchInputUtxos(b.db, nil, block)
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if err != nil {
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return err
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}
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// Update the view to mark all utxos referenced by the block
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// as spent and add all transactions being created by this block
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// to it. Also, provide an stxo slice so the spent txout
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// details are generated.
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stxos := make([]SpentTxOut, 0, countSpentOutputs(block))
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err = view.connectTransactions(block, &stxos)
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err := b.utxoCache.connectTransactions(block, &stxos)
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if err != nil {
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return err
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}
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// Update the database and chain state.
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err = b.connectBlock(n, block, view, stxos)
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err = b.connectBlock(n, block, nil, stxos)
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if err != nil {
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return err
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}
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}
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// We call the flush at the end to update the last flush hash to the new
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// best tip.
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err = b.db.Update(func(dbTx database.Tx) error {
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return b.utxoCache.flush(dbTx, FlushRequired, b.BestSnapshot())
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})
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if err != nil {
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return err
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}
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// Log the point where the chain forked and old and new best chain
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// heads.
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if forkNode != nil {
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