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Make use of removeChildNode function.

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Rather than duplicating this code in the removeBlockNode function,
use the existing function.
This commit is contained in:
Dave Collins 2013-08-01 22:28:25 -05:00
parent 1a5683e220
commit 0c2d4435ca
1 changed files with 1 additions and 7 deletions
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8
chain.go
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@ -445,13 +445,7 @@ func (b *BlockChain) removeBlockNode(node *blockNode) error {
if children, ok := b.depNodes[*prevHash]; ok {
// Find the node amongst the children of the
// dependencies for the parent hash and remove it.
for i, child := range children {
if child == node {
copy(children[i:], children[i+1:])
children[len(children)-1] = nil
b.depNodes[*prevHash] = children[:len(children)-1]
}
}
b.depNodes[*prevHash] = removeChildNode(children, node)
// Remove the map entry altogether if there are no
// longer any nodes which depend on the parent hash.