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46 lines
2.5 KiB
Plaintext
46 lines
2.5 KiB
Plaintext
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==== Two Withdrawals at Once ====
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Currently, the documentation and code describe a situation where only one withdrawal can proceed at a time. As a result, one "train" (carrying everyone's withdrawals) leaves the station every 3 months, and takes 3-6 months to reach its destination.
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Thus, if a withdrawing-user is very unlucky, and "just misses" the train, this user must wait double-long. First, (s)he must wait for the missed-train to reach its destination. Second, (s)he must board the new train, and wait for *it* to reach its destination. Each of these steps takes 3-6 months.
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So, even when withdrawals always go as quickly as possible (3 months each), the total time varies, from 3 months (0 months waiting + 3 months travel) to 6 months (3 months waiting + 3 months travel). The average is 4.5 months.
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To improve this, we allow for slightly different behavior if the highest-ACK-withdrawal [1st] has an ACK score >= 6575; and [2nd] is not tied with any other withdrawal.
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Basically: a second train can leave, if the furthest train is 50+% of the way to its destination.
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So, previously, for m trains, M4 could be any of the following:
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abstain
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alarm (move all trains backwards)
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move train #1 forward (and others backwards)
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move train #2 forward (and others backwards)
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...
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move train #3 forward (and others backwards)
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If our new special conditions apply, we now double the (m-1) elements, to accommodate a second train:
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|abstain
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|alarm (move all trains backwards)
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|advance furthest train + advance train #1 (regress all others)
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|advance furthest train + advance train #2 (regress all others)
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|...
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|advance furthest train + advance train #(m-1) (regress all others)
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|regress furthest train + advance train #1 (regress all others)
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|regress furthest train + advance train #2 (regress all others)
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|...
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|regress furthest train + advance train #(m-1) (regress all others)
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It is theoretically possible (but in practice probably impossible) to troll this rule, by getting two (or even three) withdrawals to have >6575 ACK scores, and then getting these to *tie* for first place. Then they'd both be furthest. Hence the second condition prohibiting this new behavior, if the furthest trains have any ACK-score ties.
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This simple change, which has almost zero impact on the security assumptions, improves the monthly total wait times drastically:
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Worst-case: 6 --> 4.5
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Average: 4.5 --> 3.75
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Std Dev: ~.91 --> ~.45
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